In sitecore I want to delete the newly added child.
item.DeleteChildren();
Delete all the children under item But I want to delete the most updated child or the newly added child.
I would just loop through the items and see which one was created most recently. Something like this:
Item newestItem = null;
foreach(Item child in parent.Children)
{
if (newestItem == null || child.Statistics.Created > newestItem.Statistics.Created)
{
newestItem = child;
}
}
if (newestItem != null)
{
newestItem.Delete();
}
I've used Item.Statistics.Created here, but Item.Statistics.Updated is also available
You can also use Linq:
var newestItem = item.Children.OrderByDescending(child => child.Statistics.Created).FirstOrDefault();
If (newestItem != null)
newestItem.Delete();
Related
So I'm having trouble with removing a QGraphicsPixMapItem. I add it to my view by setting it's parent so I expected that if I would change the parent to nullptr it would be removed but it didn't work. I read online that I could also use functions like hide but when I use these the program crashes. Whats the best way to fix this?
Btw I'm sure the code crashes when I call the hide function and the rest of my code is good.
A left click should add a 'stamlid' (QGraphicsPixMapItem) to the QGraphicsEllipsItem (this). And It should be removed with a right click.
void Vakje::mousePressEvent(QGraphicsSceneMouseEvent *event) {
Speler *speler = m_spel->getAanDeBeurt();
if (event->button() == Qt::LeftButton && m_stamlid == nullptr) {
m_stamlid = speler->getVrijeStamleden()[0]; //stamlid van speler dat niet op bord staat
m_stamlid->getStamlidView()->setParentItem(this);
m_stamlid->setOpBord(true);
m_stamlid->getStamlidView()->setVisible(true);
speler->getSpelerView()->updateMembers();
} else if (event->button() == Qt::RightButton && m_stamlid != nullptr) { //verwijder pion
m_stamlid->setOpBord(false);
m_stamlid->getStamlidView()->setParentItem(nullptr);
m_stamlid = nullptr;
speler->getSpelerView()->updateMembers();
}
}
The Qt documentation for the base class QGraphicsItem explains that setting the parent item to 0 does not remove the item, but makes it a top-level item instead.
Perhaps what you should do is get the item's scene and use it to remove the item.
if (m_stamlid->scene())
m_stamlid->scene()->removeItem(m_stamlid);
delete m_stamlid;
m_stamlid = nullptr;
Can I somehow attach one QTreeWidgetItem to two (or more) nodes at once? Just like this:
parent1
└child1
parent2
└child1
If I just do addChild() on both parents, the child appears only on the first parent. Is that even possible? Or such result can be achieved only by completely copying of descendant?
The instructions say:
If the child has already been inserted somewhere else it won't be
inserted again.
This means that only option is to copy the child completely. Roughly so:
QTreeWidgetItem* copy(QTreeWidgetItem* item)
{
if (item == nullptr)
{
return nullptr;
}
QTreeWidgetItem* out = new QTreeWidgetItem(*item);
for (int i = 0; i < item->childCount(); i++)
{
out->addChild(copy(item->child(i)));
}
return out;
}
I have a list of layouts with items inside. It forms a custom table.
To clean the table i loop through all the layouts and take out the items one by one. Then delete the layout.
// Delete all items
QHBoxLayout* row = NULL;
while( !rowLyts_.isEmpty() && (row = rowLyts_.takeAt(0)) != 0 )
{
QLayoutItem *item;
while ((item = row->takeAt(0)) != 0)
delete item;
delete row;
}
This seems to work. But when i start filling the table again i see "ghosts" of the items that were there before cleaning. Most of the times they are between lines, behind the new objets. And they still work.
This happens too when you use only a layout with widgets.
I just want to clean the whole layout of layouts without deleting the content widget. A safe way to clean a layout!.
You are deleting the layout items, but not the widgets that the items used to manage. You must delete the widgets. All of the non-layout items will be deleted automatically when you delete the layout itself.
QHBoxLayout* row;
while(!rowLyts_.isEmpty() && (row = rowLyts_.takeAt(0)))
{
QLayoutItem *item;
while ((item = row->takeAt(0))) {
// The item will be deleted when the layout itself is
// destructed. Items such as spacers will return a null
// widget, its deletion is a safe no-op.
delete item->widget();
// We don't handle recursion into sublayouts.
// We check for it so that we won't leak the layout.
Q_ASSERT(!item->layout());
}
delete row;
}
The assert is there to make sure the layout that the code works on matches the implied precondition: there must be no sub-layouts, since the code as written doesn't recurse into them. Any sub-layouts, with their widgets, would leak (not memory leak, but resource leak). The assert will abort the execution if the precondition is violated.
clearing the layout can be done by:
QLayoutItem* item;
while ( ( item = row->takeAt( 0 ) ) != NULL )
{
delete item->widget();
delete item;
}
I'm sending a bundle of cards to Glass with the Mirror API (c# library)
I know that you can use the default delete menu item on single cards, but is there a way to provide delete functionality for an entire bundle, ideally the result of one action by the users?
I have successfully used the DELETE action on a menu item with the code below
MenuItem mi = new MenuItem();
mi.Action = "DELETE";
TimelineItem tli = new TimelineItem()
{
Html = itemHtml.ToString(),
Notification = new NotificationConfig() { Level = "DEFAULT" },
MenuItems = new List<MenuItem>() { mi }
};
Is there a way to add this delete menu item to a bundle cover? I know this may be tricky because clicking the bundle cover causes you to navigate into the child cards thus no menu is present like on single cards. I'm looking for something (which I did try but it just ignored the menu item) like this:
MenuItem mi = new MenuItem();
mi.Action = "DELETE";
TimelineItem tli = new TimelineItem()
{
Html = itemHtml.ToString(),
Notification = new NotificationConfig() { Level = "DEFAULT" },
IsBundleCover = true,
BundleId = bundleId,
MenuItems = new List<MenuItem>() { mi }
};
If not possible on a cover card, is there a way to do this for a bundle by adding delete menu items to the child cards?
Any suggestions would be appreciated
You can use customized menu to do this. The code below is using Java but C# should be similar:
Add customized menu item to the card:
List<MenuValue> menuValueList = new ArrayList<MenuValue>();
menuValueList.add(new MenuValue().setIconUrl(iconUrl).setDisplayName("Delete All"));
MenuItem menuItem = new MenuItem();
menuItem.setValues(menuValueList).setId("delete_bundle_A").setAction("CUSTOM");
List<MenuItem> menuItemList = new ArrayList<MenuItem>();
menuItemList.add(menuItem);
timelineItem.setMenuItems(menuItemList);
Define the controller which handles the callback request of Mirror server notification:
if (notification.getCollection().equals("timeline") && notification.getUserActions().contains(new UserAction().setType("CUSTOM").setPayload("delete_bundle_A"))) {
deleteCards(credential, bundleId);
}
The delete card function:
// if bundleId is null or "", delete all cards
public static void deleteCards(Credential credential, String bundleId) throws IOException {
if (bundleId == null) {
bundleId = "";
}
Mirror.Timeline timelineItems = MirrorClient.getMirror(credential).timeline();
Mirror.Timeline.List list = timelineItems.list();
List<TimelineItem> timelineItemList = null;
do {
TimelineListResponse response = list.execute();
timelineItemList = response.getItems();
if (timelineItemList != null && timelineItemList.size() > 0) {
for (TimelineItem item : timelineItemList) {
if (bundleId == "" || bundleId.equalsIgnoreCase(item.getBundleId())) {
LOG.info("Deleting card " + item.getId());
MirrorClient.deleteTimelineItem(credential, item.getId());
}
}
list.setPageToken(response.getNextPageToken());
} else {
break;
}
} while (list.getPageToken() != null && list.getPageToken().length() > 0);
}
Finally, don't forget to subscribe timeline notification when application starts up:
String notifyUrl = "https://mirrornotifications.appspot.com/forward?url=" + "http://yourServer.com/notify";
Subscription subscription = MirrorClient.insertSubscription(credential, notifyUrl, userId, "timeline");
It isn't clear if you're asking how to create the menu items to delete the entire bundle at once, or if you're looking for code to do the actual delete.
Yuan provides some very good answers to both (not least of which because he actually provides code, which I won't), but there are three things you might also want to consider.
1) You can't have a menu on the bundle cover, but if you don't explicitly specify a bundle cover, then the most recent card will be shown as the cover and will also be shown as the first card in the bundle. You'd be able to get to the menu this way. (The default messaging app works this way, for example, but the first card has the same menu as the rest.)
2) You don't need to create a new menu item. You can leverage the DELETE menu item, if you wish. You'll get a delete notification for one of the cards in the bundle and you can then read the bundleId and delete the rest.
3) You don't need to loop through all the cards you've inserted just to find ones that have that bundleId. That is horribly inefficient. I am not fluent in C#, but from reading the documentation at https://developers.google.com/resources/api-libraries/documentation/mirror/v1/csharp/latest/classGoogle_1_1Apis_1_1Mirror_1_1v1_1_1TimelineResource_1_1ListRequest.html, I get the sense that you can create a ListRequest and then set the bundleId before executing the query and get the results.
So I think you can change Yuan's code to something like:
Mirror.Timeline.List list = timelineItems.list();
list.BundleId = bundleId;
List<TimelineItem> timelineItemList = null;
do {
TimelineListResponse response = list.execute();
timelineItemList = response.getItems();
if (timelineItemList != null && timelineItemList.size() > 0) {
for (TimelineItem item : timelineItemList) {
LOG.info("Deleting card " + item.getId());
MirrorClient.deleteTimelineItem(credential, item.getId());
}
list.setPageToken(response.getNextPageToken());
} else {
break;
}
} while (list.getPageToken() != null && list.getPageToken().length() > 0);
(this should be treated as pseudo-code, at best)
If you're confident how many items you've put into a bundle, you might also be able to just set list.MaxResults and not have to iterate over the pages of results. So perhaps something more like
Mirror.Timeline.List list = timelineItems.list();
list.BundleId = bundleId;
list.MaxResults = 20; // Set to more than the max number of items in a bundle
TimelineListResponse response = list.execute();
List<TimelineItem> timelineItemList = response.getItems();
if (timelineItemList != null && timelineItemList.size() > 0) {
for (TimelineItem item : timelineItemList) {
LOG.info("Deleting card " + item.getId());
MirrorClient.deleteTimelineItem(credential, item.getId());
}
}
There doesn't appear to be a way to delete a bundle in one step but it's still possible...
You can do a GET on /Timeline to get a list of items your app has pushed to the users timeline. Filter that out to find the entries with the bundleId you want to delete. For each of those items, call DELETE /Timeline/{itemid}
I have a QVBoxLayout inside a scrollArea. I dynamically add QFormLayouts.
widgetTreeStruct* tree = new widgetTreeStruct(QString::number(numberOfGraphs));
QFormLayout* layout = tree->getTree(); // get QFormLayout
ui->verticalLayout_2->addLayout(layout); //add to the vertical layout
At one point I need to remove all the added QFormLayouts from the QVBoxLayout.
I tried several ways to do this.
Using qDeleteAll()
qDeleteAll(ui->verticalLayout_2->children());
2.delete item one by one
QLayoutItem* child;
while((child = ui->verticalLayout_2->takeAt(0)) != 0)
{
if(child->widget() != 0)
{
delete child->widget();
}
delete child;
}
But nothing happened. Only thing is when I try to add items to QVBoxLayout again new items are added on top of the previously added items.
I sense that I have to redraw, repaint, update, refresh or something. I tried ui->verticalLayout_2->update(); but didn't work for me.
So, What should I do?
I recursively deleted all the children and it worked for me.
This is my code.
void Widget::remove(QLayout* layout)
{
QLayoutItem* child;
while(layout->count()!=0)
{
child = layout->takeAt(0);
if(child->layout() != 0)
{
remove(child->layout());
}
else if(child->widget() != 0)
{
delete child->widget();
}
delete child;
}
}
remove(ui->verticalLayout_2);
Probably the widgets's parent is the containing widget, not their layout (what is passed to their constructors for the parent parameter?).
Maybe QObject::dumpObjectTree() can help you to understand the parent-child relationships.
What happens with your approach 2 (which does not rely on the widgets being children in the QObject-sense of the layout) is that it removes all items from the layout with the takeAt() method but deletes none of them: The children of your toplevel QVBoxLayout are the QFormLayouts, so calling widget() on their QLayoutItems returns 0. Just use delete child unconditionally to delete the child QLayouts. However, this still does not delete the child widgets. You could either recursively call takeAt() on the child layouts or delete all children of the parent widget (your QScrollArea) or keep a list of widgets and/or layouts yourself.