Create a variable inside another statement [closed] - c++

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Is there a way to allocate a variable within the scope of a parameter list? By using new we can do the following :
Class A{ /*... snip ...*/ };
void myFunc(A* a){ }
int main(...){
myFunc(new A());
return 0;
}
This will create a new A. What if the signature of myFunc was
void myFunc(A a);
instead. Is there a syntax to create local instance inside the myFunc() parameter list? I'm looking for something like
myFunc(A());
or
myFunc(A a());
Another use would be for something like :
A a(123);
if(a == A(123)){ }
The net effect is to save one line, but it also creates a scope within the parameters list which makes me wonder if it is allowed at all.

Answer 1

If you just want to create a variable to pass to the function you can use a aggregate initialization / list initialization
#include <iostream>
#include <cmath>
using namespace std;
class A{ /*... snip ...*/ };
void myFunc(A a){ }
int main(){
myFunc(A{});
return 0;
}
Live Example
You can also use this with classes that have constructors that take multiple parameters
#include <iostream>
#include <cmath>
using namespace std;
class A
{
private:
int foo;
int bar;
double foobar;
public:
A(int a, int b, double c) : foo(a), bar(b), foobar(c) {}
};
void myFunc(A a){ }
int main(){
myFunc(A{1,2,3.0});
return 0;
}
Live Example

Answer 2

C++ supports this with the myFunc(A()); syntax you posed in your question.
#include <stdio.h>
char lazybuff[500];
class Point
{
public:
Point (double x, double y) : m_x(x), m_y(y) { }
char * ToString (void) { sprintf (lazybuff, "%f, %f", m_x, m_y); return lazybuff; }
private:
double m_x, m_y;
};
void print_point (Point print_me)
{
printf ("%s\n", print_me.ToString());
}
int main (void)
{
print_point (Point(5, 3));
return 0;
}