I just start to learn opencv, I have defined a vector like:
vector<Point2f> cornersB;
and after that i have done some calculations like:goodFeaturesToTrack,cornerSubPix and calcOpticalFlowPyrLK using cornersB.
And now I want to show cornerB to see the points that has been drawn, my code is:
pointmat = Mat(cornersB);
imshow("Window", pointmat);
But I got error said that bad number of channels (Source image must have 1, 3 or 4 channels) in cvConvertImage.
Anyone can teach me how to show the points of cornerB in an image?
I just want to see the points (points in white and the background in black).
The simpler is to use cv::drawKeypoints
drawKeypoints( InputArray image, const std::vector<KeyPoint>& keypoints, InputOutputArray outImage,const Scalar& color=Scalar::all(-1), int flags=DrawMatchesFlags::DEFAULT );
In your case, let define a black image as image:
cv::Mat image(512,512,CV_8U)
image.setTo(0);
Then convert cornersB to cv::KeyPoint kp_cornerB and define the color as white with CV_RGB(255, 255, 255)
std::vector<cv::KeyPoint> kp_cornerB ;
// TODO convert cornersB to kp_cornerB
cv::Mat pointmat;
cv::drawKeypoints(image, kp_cornerB, pointmat, CV_RGB(255, 255, 255));
imshow("Window", pointmat);
The conversion can be done with a for loop on the vector:
for(vector<Point2f>::const_iterator it = cornersB.begin();
it != cornersB.end(); it++) {
cv::KeyPoint kp(*it, 8);
kp_cornerB.push_back(kp);
}
Here, the value '8' is the 'size' of the keypoint.
Related
Problem : Watershed algorithm
I started app project, for image processing, using OpenCv 4.5.3 and Swift ( with C++ ). I'm fighting with watershaded alg. for a really long time... And i have no clue what did i do wrong. Just don't know...
Error :
libc++abi.dylib: terminating with uncaught exception of type cv::Exception: OpenCV(4.5.3)
/Volumes/build-storage/build/master_iOS-mac/opencv/modules/imgproc/src/segmentation.cpp:161:
error: (-215:Assertion failed) src.type()
== CV_8UC3 && dst.type() == CV_32SC1 in function 'watershed'
terminating with uncaught exception of type cv::Exception: OpenCV(4.5.3)
/Volumes/build-storage/build/master_iOS-mac/opencv/modules/imgproc/src/segmentation.cpp:161: error:
(-215:Assertion failed) src.type()
== CV_8UC3 && dst.type() == CV_32SC1 in function 'watershed'
In the definition of openCv's watershed we can find :
#param image Input 8-bit 3-channel image.
#param markers Input/output 32-bit single-channel image (map) of markers. It should have the same size as image .
Code
+(UIImage *) watershed:(UIImage *)src{
cv::Mat img, mask;
UIImageToMat(src, img);
// Change the background from white to black, since that will help later to extract
// better results during the use of Distance Transform
cv::inRange(img, cv::Scalar(255,255,255), cv::Scalar(255,255,255), mask);
img.setTo(cv::Scalar(0,0,0), mask);
// Create a kernel that we will use to sharpen our image
// an approximation of second derivative, a quite strong kernel
cv::Mat kernel = (cv::Mat_<float>(3,3) <<
1, 1, 1,
1, -8, 1,
1, 1, 1);
// do the laplacian filtering as it is
// well, we need to convert everything in something more deeper then CV_8U
// because the kernel has some negative values,
// and we can expect in general to have a Laplacian image with negative values
// BUT a 8bits unsigned int (the one we are working with) can contain values from 0 to 255
// so the possible negative number will be truncated
cv::Mat lapl;
cv::filter2D(img, lapl, CV_32F, kernel);
cv::Mat sharp;
img.convertTo(sharp, CV_32F);
cv::Mat result = sharp - lapl;
// convert back to 8bits gray scale
result.convertTo(result, CV_8UC3);
lapl.convertTo(lapl, CV_8UC3);
cv::Mat bw;
cv::cvtColor(result, bw, cv::COLOR_BGR2GRAY);
cv::threshold(bw, bw, 40, 255, cv::THRESH_BINARY | cv::THRESH_OTSU);
// Perform the distance transform algorithm
cv::Mat dist;
cv::distanceTransform(bw, dist, cv::DIST_L2, cv::DIST_MASK_3);
// Normalize the distance image for range = {0.0, 1.0}
// so we can visualize and threshold it
cv::normalize(dist, dist, 0, 1.0, cv::NORM_MINMAX);
// Threshold to obtain the peaks
// This will be the markers for the foreground objects
cv::threshold(dist, dist, 0.4, 1.0, cv::THRESH_BINARY);
// Dilate a bit the dist image
cv::Mat kernel1 = cv::Mat::ones(3, 3, CV_8U);
dilate(dist, dist, kernel1);
// Create the CV_8U version of the distance image
// It is needed for findContours()
cv::Mat dist_8u;
dist.convertTo(dist_8u, CV_8U);
// Find total markers
std::vector<std::vector<cv::Point> > contours;
findContours(dist_8u, contours, cv::RETR_EXTERNAL, cv::CHAIN_APPROX_SIMPLE);
// Create the marker image for the watershed algorithm
cv::Mat markers = cv::Mat::zeros(dist.size(), CV_32S);
// Draw the foreground markers
for (size_t i = 0; i < contours.size(); i++)
{
drawContours(markers, contours, static_cast<int>(i), cv::Scalar(static_cast<int>(i)+1), -1);
}
// Draw the background marker
circle(markers, cv::Point(5,5), 3, cv::Scalar(255), -1);
cv::Mat markers8u;
markers.convertTo(markers8u, CV_8U, 10);
// Perform the watershed algorithm
watershed(result, markers);
return MatToUIImage(result);
}
You can clearly see, that variables has proper type, as in descr. of function:
result.convertTo(result, CV_8UC3);
cv::Mat markers = cv::Mat::zeros(dist.size(), CV_32S);
The convertTo can not add channels as well can not reduce/convert image to image with smaller amount of channels.
The key in this case is to use :
cvtColor(src, src, COLOR_BGRA2BGR); // change 4 to 3 channels
How can I crop a non rectangular region from image?
Imagine I have four points and I want to crop it, this shape wouldn't be a triangle somehow!
For example I have the following image :
and I want to crop this from image :
How can I do this?
regards..
The procedure for cropping an arbitrary quadrilateral (or any polygon for that matter) part of an image is summed us as:
Generate a "mask". The mask is black where you want to keep the image, and white where you don't want to keep it
Compute the "bitwise_and" between your input image and the mask
So, lets assume you have an image. Throughout this I'll use an image size of 30x30 for simplicity, you can change this to suit your use case.
cv::Mat source_image = cv::imread("filename.txt");
And you have four points you want to use as the corners:
cv::Point corners[1][4];
corners[0][0] = Point( 10, 10 );
corners[0][1] = Point( 20, 20 );
corners[0][2] = Point( 30, 10 );
corners[0][3] = Point( 20, 10 );
const Point* corner_list[1] = { corners[0] };
You can use the function cv::fillPoly to draw this shape on a mask:
int num_points = 4;
int num_polygons = 1;
int line_type = 8;
cv::Mat mask(30,30,CV_8UC3, cv::Scalar(0,0,0));
cv::fillPoly( mask, corner_list, &num_points, num_polygons, cv::Scalar( 255, 255, 255 ), line_type);
Then simply compute the bitwise_and of the image and mask:
cv::Mat result;
cv::bitwise_and(source_image, mask, result);
result now has the cropped image in it. If you want the edges to end up white instead of black you could instead do:
cv::Mat result_white(30,30,CV_8UC3, cv::Scalar(255,255,255));
cv::bitwise_and(source_image, mask, result_white, mask);
In this case we use bitwise_and's mask parameter to only do the bitwise_and inside the mask. See this tutorial for more information and links to all the functions I mentioned.
You may use cv::Mat::copyTo() like this:
cv::Mat img = cv::imread("image.jpeg");
// note mask may be single channel, even if img is multichannel
cv::Mat mask = cv::Mat::zeros(img.rows, img.cols, CV_8UC1);
// fill mask with nonzero values, e.g. as Tim suggests
// cv::fillPoly(...)
cv::Mat result(img.size(), img.type(), cv::Scalar(255, 255, 255));
img.copyTo(result, mask);
I create a Bird-View-Image with the warpPerspective()-function like this:
warpPerspective(frame, result, H, result.size(), CV_WARP_INVERSE_MAP, BORDER_TRANSPARENT);
The result looks very good and also the border is transparent:
Bird-View-Image
Now I want to put this image on top of another image "out". I try doing this with the function warpAffine like this:
warpAffine(result, out, M, out.size(), CV_INTER_LINEAR, BORDER_TRANSPARENT);
I also converted "out" to a four channel image with alpha channel according to a question which was already asked on stackoverflow:
Convert Image
This is the code: cvtColor(out, out, CV_BGR2BGRA);
I expected to see the chessboard but not the gray background. But in fact, my result looks like this:
Result Image
What am I doing wrong? Do I forget something to do? Is there another way to solve my problem? Any help is appreciated :)
Thanks!
Best regards
DamBedEi
I hope there is a better way, but here it is something you could do:
Do warpaffine normally (without the transparency thing)
Find the contour that encloses the image warped
Use this contour for creating a mask (white values inside the image warped, blacks in the borders)
Use this mask for copy the image warped into the other image
Sample code:
// load images
cv::Mat image2 = cv::imread("lena.png");
cv::Mat image = cv::imread("IKnowOpencv.jpg");
cv::resize(image, image, image2.size());
// perform warp perspective
std::vector<cv::Point2f> prev;
prev.push_back(cv::Point2f(-30,-60));
prev.push_back(cv::Point2f(image.cols+50,-50));
prev.push_back(cv::Point2f(image.cols+100,image.rows+50));
prev.push_back(cv::Point2f(-50,image.rows+50 ));
std::vector<cv::Point2f> post;
post.push_back(cv::Point2f(0,0));
post.push_back(cv::Point2f(image.cols-1,0));
post.push_back(cv::Point2f(image.cols-1,image.rows-1));
post.push_back(cv::Point2f(0,image.rows-1));
cv::Mat homography = cv::findHomography(prev, post);
cv::Mat imageWarped;
cv::warpPerspective(image, imageWarped, homography, image.size());
// find external contour and create mask
std::vector<std::vector<cv::Point> > contours;
cv::Mat imageWarpedCloned = imageWarped.clone(); // clone the image because findContours will modify it
cv::cvtColor(imageWarpedCloned, imageWarpedCloned, CV_BGR2GRAY); //only if the image is BGR
cv::findContours (imageWarpedCloned, contours, CV_RETR_EXTERNAL, CV_CHAIN_APPROX_NONE);
// create mask
cv::Mat mask = cv::Mat::zeros(image.size(), CV_8U);
cv::drawContours(mask, contours, 0, cv::Scalar(255), -1);
// copy warped image into image2 using the mask
cv::erode(mask, mask, cv::Mat()); // for avoid artefacts
imageWarped.copyTo(image2, mask); // copy the image using the mask
//show images
cv::imshow("imageWarpedCloned", imageWarpedCloned);
cv::imshow("warped", imageWarped);
cv::imshow("image2", image2);
cv::waitKey();
One of the easiest ways to approach this (not necessarily the most efficient) is to warp the image twice, but set the OpenCV constant boundary value to different values each time (i.e. zero the first time and 255 the second time). These constant values should be chosen towards the minimum and maximum values in the image.
Then it is easy to find a binary mask where the two warp values are close to equal.
More importantly, you can also create a transparency effect through simple algebra like the following:
new_image = np.float32((warp_const_255 - warp_const_0) *
preferred_bkg_img) / 255.0 + np.float32(warp_const_0)
The main reason I prefer this method is that openCV seems to interpolate smoothly down (or up) to the constant value at the image edges. A fully binary mask will pick up these dark or light fringe areas as artifacts. The above method acts more like true transparency and blends properly with the preferred background.
Here's a small test program that warps with transparent "border", then copies the warped image to a solid background.
int main()
{
cv::Mat input = cv::imread("../inputData/Lenna.png");
cv::Mat transparentInput, transparentWarped;
cv::cvtColor(input, transparentInput, CV_BGR2BGRA);
//transparentInput = input.clone();
// create sample transformation mat
cv::Mat M = cv::Mat::eye(2,3, CV_64FC1);
// as a sample, just scale down and translate a little:
M.at<double>(0,0) = 0.3;
M.at<double>(0,2) = 100;
M.at<double>(1,1) = 0.3;
M.at<double>(1,2) = 100;
// warp to same size with transparent border:
cv::warpAffine(transparentInput, transparentWarped, M, transparentInput.size(), CV_INTER_LINEAR, cv::BORDER_TRANSPARENT);
// NOW: merge image with background, here I use the original image as background:
cv::Mat background = input;
// create output buffer with same size as input
cv::Mat outputImage = input.clone();
for(int j=0; j<transparentWarped.rows; ++j)
for(int i=0; i<transparentWarped.cols; ++i)
{
cv::Scalar pixWarped = transparentWarped.at<cv::Vec4b>(j,i);
cv::Scalar pixBackground = background.at<cv::Vec3b>(j,i);
float transparency = pixWarped[3] / 255.0f; // pixel value: 0 (0.0f) = fully transparent, 255 (1.0f) = fully solid
outputImage.at<cv::Vec3b>(j,i)[0] = transparency * pixWarped[0] + (1.0f-transparency)*pixBackground[0];
outputImage.at<cv::Vec3b>(j,i)[1] = transparency * pixWarped[1] + (1.0f-transparency)*pixBackground[1];
outputImage.at<cv::Vec3b>(j,i)[2] = transparency * pixWarped[2] + (1.0f-transparency)*pixBackground[2];
}
cv::imshow("warped", outputImage);
cv::imshow("input", input);
cv::imwrite("../outputData/TransparentWarped.png", outputImage);
cv::waitKey(0);
return 0;
}
I use this as input:
and get this output:
which looks like ALPHA channel isn't set to ZERO by warpAffine but to something like 205...
But in general this is the way I would do it (unoptimized)
So far i have managed to use masks and get the second image from the first. But what i want is the black area in second image to be transparent (i.e the output i an trying to get is the third image) Here is the code so far. Please advice me on this.
EDIT: Third one is from photoshop
//imwrite parameters
compression_params.push_back(CV_IMWRITE_JPEG_QUALITY);
compression_params.push_back(100);
//reading image to be masked
image = imread(main_img, -1);
//CV_LOAD_IMAGE_COLOR
namedWindow("output", WINDOW_NORMAL);
//imshow("output", image);
//Creating mask image with same size as original image
Mat mask(image.rows, image.cols, CV_8UC1, Scalar(0));
// Create Polygon from vertices
ROI_Vertices.push_back(Point2f(float(3112),float(58)));
ROI_Vertices.push_back(Point2f(float(3515),float(58)));
ROI_Vertices.push_back(Point2f(float(3515),float(1332)));
ROI_Vertices.push_back(Point2f(float(3112),float(958)));
approxPolyDP(ROI_Vertices, ROI_Poly, 1, true);
// Fill polygon white
fillConvexPoly(mask, &ROI_Poly[0] , ROI_Poly.size(), 255, 8, 0);
//imshow("output", mask);
// Create new image for result storage
imageDest = cvCreateMat(image.rows, image.cols, CV_8UC4);
// Cut out ROI and store it in imageDest
image.copyTo(imageDest, mask);
imwrite("masked.jpeg", imageDest, compression_params);
imshow("output", imageDest);
cvWaitKey(0);
This can be done by first setting its alpha value to 0 of the regions that you want to make them fully transparent (255 for others), and then save it to PNG.
To set the alpha value of pixel-(x,y), it can be done:
image.at<cv::Vec4b>(y, x)[3] = 0;
PS: you need to convert it to 4-channel format first if the image is not currently. For example:
cv::cvtColor(image, image, CV_BGR2BGRA);
Updated: It will be easier if you have already computed the mask for the ROI region, where you can simply merge it with the original image (assume having 3 channels) to get the final result. Like:
cv::Mat mask; // 0 for transparent regions, 255 otherwise (serve as the alpha channel)
std::vector<cv::Mat> channels;
cv::split(image, channels);
channels.push_back(mask);
cv::Mat result;
cv::merge(channels, result);
I got this image and I'd like to fill the upper left black area with white, but all I get is a completely white image … Any ideas what's wrong with my code?
Code:
...
cv::Rect rect;
roi = cv::floodFill(roi, cv::Point(1,1), cv::Scalar(0), &rect, cv::Scalar(0), cv::Scalar(0), 4);
...
Input image:
This is the image I get with the following code:
int main()
{
cv::Mat image = cv::imread("TF2XE.jpg", -1);
cv::imshow("image before filling", image);
int filling = cv::floodFill(image, cv::Point(0,0), 255, (cv::Rect*)0, cv::Scalar(), 200);
cv::imshow("image after filling", image);
cv::waitKey();
return 0;
}
Notice that I used 200 as upDiff parameter, since if you set it to 0 there will be some gray pixels that will not be considered inside the connected component, change that if that is indeed what you want.
Not sure, but according to the documentation I was able to dig up, it says that cv::floodFill() returns an int. So assuming that roi is a matrix and the openCV matrix class defines operator= for int parameters, you could be assigning some int to each element of the matrix.