Random Number Game - c++

Question

I'm making a small game in C++ where a user will type "roll" and the program should generate 5 numbers between 1-6. The objective of the game is to get all the numbers the same.
My problem I am having is fully understanding how to format the different algorithms need for a project like this and what type of different syntax's that allowed through the language.
I am a student learning this language and will appreciate any help anyone is willing to offer!
The code below is not finished in anyway and just wanted some extra advice!
Code:
// Random Number Game
// ***
// ***
#include <iostream>
#include <string>
#include <ctime>
#include <cstdlib>
#include <vector>
using namespace std;
using std::cout;
using std::cin;
using std::endl;
using std::string;
int main()
{
// Intro Instruction
cout << "Welcome to Random Number game!\n";
cout << "The objective of this game to get all 5 dice the same number.\n";
// Variables
char roll;
int dice1, dice2, dice3, dice4, dice5;
cout << "To begin the game please type roll. ";
cin >> roll;
srand((unsigned)time(0));
// Stating Low and High Numbers (Dice numbers)
int lowerrange = 1;
int upperrange = 7;
upperrange = 6;
dice1 = rand() % 6;
dice2 = rand() % 6;
dice3 = rand() % 6;
dice4 = rand() % 6;
dice5 = rand() % 6;
if ((roll == 'roll') || (roll == 'Roll'))
{
cout << dice1;
cout << dice2;
cout << dice3;
cout << dice4;
cout << dice5;
}
system("pause");
return 0;
}

Answer 1

Here is a possible solution.
The idea is to use a loop to repeatedly asking from user to "roll" the dices, for testing purposes only I put 3 dices here, but you can extend to 5 dices.
I maintain a boolean variable that will be true if and only if all the dices has the same value, if that the case, the program will break out from loop, and will print a successful message.
#include <iostream>
#include <string>
using namespace std;
int main()
{
// Intro Instruction
cout << "Welcome to Random Number game!\n";
cout << "The objective of this game to get all 5 dice the same number.\n";
string command;
int magic = 0;
do
{
cout << "To begin the game please type roll: ";
cin >> command;
if(command == "roll")
{
int dice1 = rand() % 6 + 1;
int dice2 = rand() % 6 + 1;
int dice3 = rand() % 6 + 1;
cout << "First Dice: " << dice1 << endl;
cout << "Second Dice: " << dice2 << endl;
cout << "Third Dice: " << dice3 << endl;
cout << "Which Dice do you want to keep? : (Enter 1, 2 or 3)" << endl;
int keep_dice;
cin >> keep_dice;
if(keep_dice == 1)
{
magic = dice1;
break;
}
else if(keep_dice == 2)
{
magic = dice2;
break;
}
else if(keep_dice == 3)
{
magic = dice3;
break;
}
}
}
while(true);
cout << "You choose the number: " << magic << ". Roll the other dices until you get for both this number." << endl;
do
{
cout << "Type roll: ";
cin >> command;
if(command == "roll")
{
int dice1 = rand() % 6 + 1;
int dice2 = rand() % 6 + 1;
cout << "First Dice: " << dice1 << endl;
cout << "Second Dice: " << dice2 << endl;
if(dice1 == magic && dice2 == magic)
{
break;
}
}
}
while(true);
cout << "You won !" << endl;
}
Alternative Solution:
My idea is to create a function that will accept two parameters: num_dice the remaining dices to be rolled if you have 5 dices that will be 4, if you have n dices this will be n-1 and so on.
The other parameter will be the lucky number that the user will choose (easy with an if or with switch statement)
You will then repeat that with the same logic within your function until you get your n-1 dices equal to lucky number.
Moreover, think that my code may need a bit alteration, so that the first roll of all dices will happen once and not repeatedly, and then with the function you will do the repeat "job".

Answer 2

To check if all the dices are the same, use the code below:
int magicValue = dice1;
cout << "You got:" << endl;
cout << "Dice 1: " << dice1 << endl;
cout << "Dice 2: " << dice2 << endl;
cout << "Dice 3: " << dice3 << endl;
cout << "Dice 4: " << dice4 << endl;
cout << "Dice 5: " << dice5 << endl;
if(dice2 == magicValue && dice3 == magicValue
&& dice4 == magicValue && dice5 == magicValue){
cout << "Congratulations! You Win!" << endl;
} else {
cout << "Sorry, try again next time!" << endl;
}
What this does is it sets magicValue to dice1 and checks if all other dice variables are equal. Not the fanciest way to do it, but I hope this helps you!

Answer 3

Since you have at the top ‘Using namespace std`
You don’t have to specify using std::cout or anything like that.
Also you can just assign upperrange to 6 right away.
Besides this jut put it in a loop if you want, add some more output so they know they can keep playing.