Qt - Dialog in a DLL - c++

In my company, we are developing with Embarcadero-C++-IDE (which is very uncomfortable). To start moving away, we port individual dialogs in a dll to Qt. My qt-dll-code Looks like this for example
extern "C" ROBOTECHPOLYLINEDIALOGSHARED_EXPORT void popupRoboTechDialog()
{
if( ! QApplication::instance() )
{
int argc = 1;
char *argv[] = {"Design polyline"};
QApplication app(argc, argv);
RoboTechPolyline dialog;
dialog.show();
app.exec();
}
else
{
RoboTechPolyline Dialog;
Dialog.exec();
}
}
Trying to start the Dialog from another thread like here Starting Qt GUI from dll (in DLLStart function) did make my Dialog unresponsive, but I don't think the question and mine relate too much.
I'm loading this Dll dynamically from the main-application and it works fine. However, when I make the Dialog Pop up a second time I get an "Access Violation at address .. in module MSVCR110D.dll" and on the third time, I get "ASSERT failure in QCoreApplication , there should be only one application object". So I always Need to Close the whole application in order to make the Dialog appear a second time, which greaty slows down work.
If I add at the bottom the line
QApplication::quit()
the Dialog appears a second time, but the Programm crashes on closing this second Dialog.
The code to load the dll is as follows
HINSTANCE lib = ::LoadLibrary(L"RoboTechPolylineDialog.dll");
if(!lib)
{
ShowMessage("Unable to load RoboTechPolylineDialog.dll");
return;
}
typedef void ( *POPUP_ROBO_TECH_DIALOG )();
POPUP_ROBO_TECH_DIALOG fp = (POPUP_ROBO_TECH_DIALOG) ::GetProcAddress(lib, "popupRoboTechDialog");
if(!fp)
{
ShowMessage("Unable to load function popupRoboTechDialog from RoboTechPolylineDialog.dll");
::FreeLibrary(lib);
return;
}
(*fp)( );
FreeLibrary(lib);
So why am I constructing more than one QApplication at a time? I can in above code replace the line
(*fp)();
with
(*fp)();
(*fp)();
and the Dialog appears twice and everything works greatly. But how can the call to ::FreeLibrary(lib) make things fail.
Can anyone help me? Any help, Workarounds, etc.. is appreciated.

This should work:
#include <QApplication>
#include <QString>
#include <QDialog>
class App {
QApplication *_app;
public:
App(int argc = 0, char** argv = NULL)
: _app(new QApplication(argc, argv))
{
}
~App() {
delete _app;
}
};
void dialog()
{
static int argc = 1;
static char *argv[] = {"Design polyline"};
static App(argc, argv);
QDialog dlg;
dlg.exec();
}
void main()
{
dialog();
dialog();
dialog();
}

Another advice: load Qt libs from as subpath since you could find dll conflict with other apps using it on the same folder (personal experience)

Related

Trouble with QT timers: "function definition is not allowed here"

I am trying to make a program that takes images and puts them on your wallpaper using a timer, but I kept getting the error "Timers can only be started with QThread", so I am trying to make this timer with more QThread elements (simpler designs like QThread::msleep haven't worked). Currently, my problem is that my calling slot for when the timer goes off is not working where it currently is, but if I put it in any other location, then the program spits out more errors as it is designed to go in that specific spot. The code itself is mainly a copy/paste of a bunch of other code, and I am new to QT, so I may be going about this completely wrong. If I am, I will gladly accept help so I can understand this better!
#include <mainwindow.h>
#include <mythread.h>
QMediaPlayer * BadAppleS = new QMediaPlayer();
int main(int argc, char *argv[])
{
QApplication app(argc,argv);
int fileN = 0;
BadAppleS->setMedia(QUrl("qrc:/SongN/Bad Apple.mp3"));
BadAppleS->play();
mythread t;
t.start();
if (fileN <= 1625) {
void mythread::doIt(){ //Error here. No more errors elsewhere, though there may be in this function/signal.
QString fileNQ = QString::number(fileN);
QString filepath = (("qrc:/BAPics/scene (") + fileNQ + (")"));
char path[150];
wchar_t wtext[20];
strcpy_s(path, filepath.toStdString().c_str());
mbstowcs(wtext, path, strlen(path)+1);
LPWSTR pathp = wtext;
int result;
result = SystemParametersInfo(SPI_SETDESKWALLPAPER, 0, pathp, SPIF_UPDATEINIFILE);
fileN++;
}
return app.exec();
}
}
Thank you for the help!

Why QFileDialog::selectFile doesn't work?

I am using Qt 5.12 and trying to write test (using QTest) for opening of project stored in some xml format.
In test I use QTimer::singleShot to wait QFileDialog to appear as proposed in QT close window by QTest in locked thread.
The problem is that QFileDialog::selectFile doesn't select anything. This means that OK button is not active, so I can't click on it in my test.
I assume in the following example that full path to file is /tmp/project.xml. Notice that QFileDialog::setDirectory works great: when the following example starts, you are in /tmp dir instead of /.
#include <QApplication>
#include <QFileDialog>
#include <QTimer>
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
QTimer::singleShot(300, []() {
QWidget* window = nullptr;
while (!window) {
window = qApp->activeModalWidget();
}
QFileDialog* fd = qobject_cast<QFileDialog*>(window);
fd->setDirectory("/tmp");
fd->selectFile("project.xml");
});
QString path = QFileDialog::getOpenFileName(nullptr, "Open Project",
"/", QString(),
nullptr, QFileDialog::DontUseNativeDialog);
}
The function selectFile didn't work because of the file name text box (lineEdit) is focused. This behavior comes from the implementation of QFileDialog::selectFile() :
void QFileDialog::selectFile(const QString &filename)
{
// ... function body
//Put the filename into the lineEdit when :
//1. The dialog is not visible or
//2. The lineEdit is not focused.
if (!isVisible() || !d->lineEdit()->hasFocus())
d->lineEdit()->setText(index.isValid() ? index.data().toString() : fileFromPath(d->rootPath(), filename));
}
To make the program works, there are two ways :
Put the file name directly in the text box
Give the focus away then call selectFile
fd->setDirectory("/tmp");
QLineEdit * lineEdit = qobject_cast<QLineEdit*>(fd->focusWidget());
if( lineEdit ){
//Method 1
lineEdit->setText("project.xml");
//Method 2
lineEdit->nextInFocusChain()->setFocus();
fd->selectFile("project.xml");
}else { //no lineEdit focus found
fd->selectFile("project.xml");
}

how to take a screenshot Within a QT QTest setting

I'm trying to take a screen shot during some tests where the application is being ran on an iOS simulator.
The app looks something like this:
main.cpp
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
QQmlApplicationEngine engine;
#ifdef TEST
thingTests = new ThingTests(&engine);
tabletTests->startTestSuite(argv[1]);
#endif
...
engine.load(QUrl(QStringLiteral("qrc:/main.qml")));
return app.exec();
}
ThingTests.cpp
TabletTests::TabletTests(QQmlApplicationEngine *engine) : QObject(nullptr), m_testSuiteName(NULL)
{
m_engine = engine;
}
void TabletTests::startTestSuite(char *testSuiteName)
{
m_testSuiteName = testSuiteName;
connect(m_engine, SIGNAL(objectCreated(QObject*,QUrl)), this, SLOT(onObjectCreated(QObject*,QUrl)));
}
void TabletTests::onObjectCreated(QObject *, const QUrl &) {
// run settings test for now, later on control with command line arguments
SettingsTest *settingsTest = new SettingsTest(m_engine);
QTest::qExec(settingsTest);
}
SettingsTest.cpp
void SettingsTest::openWarningModeSelectionTest()
{
m_settingsTester->performTestOperation(SettingsTester::SettingsTestOperation::WarningModeSelection);
QTest::qWait(1000);
bool optionSelectorDisplayed = DialogController::getInstance()->optionSelectorShown();
// This clip came from here: https://stackoverflow.com/questions/21697185/how-to-take-screenshot-of-qml-application-without-qquickview
foreach(QObject* obj, this->m_engine->rootObjects()) {
QQuickWindow* window = qobject_cast<QQuickWindow*>(obj);
if (window) {
QImage image = window->grabWindow(); //<-- This line throws the assertion error
}
}
QVERIFY(optionSelectorDisplayed);
}
I've inherited this codebase and I'm not very familiar with QT, but I tried to only include relevant things in the above snippets.
What I want to be able to do is take some screenshots on what a page looks like at certain times in the tests.
When I have TEST defined, my tests for the app go and do their thing, but they blowup when the window->grabWindow() line is hit with an ASSERT error in assert w in scenegraph/qsgthreadedrenderloop.cpp in the qt libraries. This is the assert that is failing (https://code.woboq.org/qt5/qtdeclarative/src/quick/scenegraph/qsgthreadedrenderloop.cpp.html#1281)

Qt - confused on QDialog choice on main

I have the following Qt code:
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
ChoosingDialog cdlg;
if(!startWin.exec())
{
// nothing chosen
return 0;
}
if(cdlg.firstWindowSelected)
{
CFirstWindow win;
win.show();
return app.exec();
}
else
{
CSecondWindow win;
win.show();
return app.exec();
}
}
this seems to work but it's giving me an error on "event dispatcher cleanup" in some asm line. I tried to trick a bit and I saw that the problem is related to the app.exec() calling.
Update:
if I add these lines to the ChoosingDialog (this is a simple blank class auto-generated by Qt Creator)
void ChoosingDialog ::closeEvent(QCloseEvent *)
{
exit(1);
}
I receive no errors
Turns out I was using the "singleapplication" class before the QApplication.. and something went wrong on the shared memory lock.
As soon as I restarted my system the exception disappeared... bof.. do you believe in magic?

Console output in a Qt GUI app?

I have a Qt GUI application running on Windows that allows command-line options to be passed and under some circumstances I want to output a message to the console and then quit, for example:
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
if (someCommandLineParam)
{
std::cout << "Hello, world!";
return 0;
}
MainWindow w;
w.show();
return a.exec();
}
However, the console messages do not appear when I run the app from a command-prompt. Does anyone know how I can get this to work?
Windows does not really support dual mode applications.
To see console output you need to create a console application
CONFIG += console
However, if you double click on the program to start the GUI mode version then you will get a console window appearing, which is probably not what you want. To prevent the console window appearing you have to create a GUI mode application in which case you get no output in the console.
One idea may be to create a second small application which is a console application and provides the output. This can call the second one to do the work.
Or you could put all the functionality in a DLL then create two versions of the .exe file which have very simple main functions which call into the DLL. One is for the GUI and one is for the console.
Add:
#ifdef _WIN32
if (AttachConsole(ATTACH_PARENT_PROCESS)) {
freopen("CONOUT$", "w", stdout);
freopen("CONOUT$", "w", stderr);
}
#endif
at the top of main(). This will enable output to the console only if the program is started in a console, and won't pop up a console window in other situations. If you want to create a console window to display messages when you run the app outside a console you can change the condition to:
if (AttachConsole(ATTACH_PARENT_PROCESS) || AllocConsole())
void Console()
{
AllocConsole();
FILE *pFileCon = NULL;
pFileCon = freopen("CONOUT$", "w", stdout);
COORD coordInfo;
coordInfo.X = 130;
coordInfo.Y = 9000;
SetConsoleScreenBufferSize(GetStdHandle(STD_OUTPUT_HANDLE), coordInfo);
SetConsoleMode(GetStdHandle(STD_OUTPUT_HANDLE),ENABLE_QUICK_EDIT_MODE| ENABLE_EXTENDED_FLAGS);
}
int main(int argc, char *argv[])
{
Console();
std::cout<<"start##";
qDebug()<<"start!";
You can't use std::cout as others have said,my way is perfect even for some code can't include "qdebug" !
So many answers to this topic. 0.0
So I tried it with Qt5.x from Win7 to Win10. It took me some hours to have a good working solution which doesn't produce any problems somewhere in the chain:
#include "mainwindow.h"
#include <QApplication>
#include <windows.h>
#include <stdio.h>
#include <iostream>
//
// Add to project file:
// CONFIG += console
//
int main( int argc, char *argv[] )
{
if( argc < 2 )
{
#if defined( Q_OS_WIN )
::ShowWindow( ::GetConsoleWindow(), SW_HIDE ); //hide console window
#endif
QApplication a( argc, argv );
MainWindow *w = new MainWindow;
w->show();
int e = a.exec();
delete w; //needed to execute deconstructor
exit( e ); //needed to exit the hidden console
return e;
}
else
{
QCoreApplication a( argc, argv );
std::string g;
std::cout << "Enter name: ";
std::cin >> g;
std::cout << "Name is: " << g << std::endl;
exit( 0 );
return a.exec();
}
}
I tried it also without the "CONFIG += console", but then you need to redirect the streams and create the console on your own:
#ifdef _WIN32
if (AttachConsole(ATTACH_PARENT_PROCESS) || AllocConsole()){
freopen("CONOUT$", "w", stdout);
freopen("CONOUT$", "w", stderr);
freopen("CONIN$", "r", stdin);
}
#endif
BUT this only works if you start it through a debugger, otherwise all inputs are directed towards the system too. Means, if you type a name via std::cin the system tries to execute the name as a command. (very strange)
Two other warnings to this attempt would be, that you can't use ::FreeConsole() it won't close it and if you start it through a console the app won't close.
Last there is a Qt help section in QApplication to this topic. I tried the example there with an application and it doesn't work for the GUI, it stucked somewhere in an endless loop and the GUI won't be rendered or it simply crashes:
QCoreApplication* createApplication(int &argc, char *argv[])
{
for (int i = 1; i < argc; ++i)
if (!qstrcmp(argv[i], "-no-gui"))
return new QCoreApplication(argc, argv);
return new QApplication(argc, argv);
}
int main(int argc, char* argv[])
{
QScopedPointer<QCoreApplication> app(createApplication(argc, argv));
if (qobject_cast<QApplication *>(app.data())) {
// start GUI version...
} else {
// start non-GUI version...
}
return app->exec();
}
So if you are using Windows and Qt simply use the console option, hide the console if you need the GUI and close it via exit.
No way to output a message to console when using QT += gui.
fprintf(stderr, ...) also can't print output.
Use QMessageBox instead to show the message.
Oh you can Output a message when using QT += gui and CONFIG += console.
You need printf("foo bar") but cout << "foo bar" doesn't works
Something you may want to investigate, at least for windows, is the AllocConsole() function in the windows api. It calls GetStdHandle a few times to redirect stdout, stderr, etc. (A quick test shows this doesn't entirely do what we want it to do. You do get a console window opened alongside your other Qt stuff, but you can't output to it. Presumably, because the console window is open, there is some way to access it, get a handle to it, or access and manipulate it somehow. Here's the MSDN documentation for those interested in figuring this out:
AllocConsole():
http://msdn.microsoft.com/en-us/library/windows/desktop/ms681944%28v=vs.85%29.aspx
GetStdHandle(...):
http://msdn.microsoft.com/en-us/library/windows/desktop/ms683231%28v=vs.85%29.aspx
(I'd add this as a comment, but the rules prevent me from doing so...)
I used this header below for my projects. Hope it helps.
#ifndef __DEBUG__H
#define __DEBUG__H
#include <QtGui>
static void myMessageOutput(bool debug, QtMsgType type, const QString & msg) {
if (!debug) return;
QDateTime dateTime = QDateTime::currentDateTime();
QString dateString = dateTime.toString("yyyy.MM.dd hh:mm:ss:zzz");
switch (type) {
case QtDebugMsg:
fprintf(stderr, "Debug: %s\n", msg.toAscii().data());
break;
case QtWarningMsg:
fprintf(stderr, "Warning: %s\n", msg.toAscii().data());
break;
case QtCriticalMsg:
fprintf(stderr, "Critical: %s\n", msg.toAscii().data());
break;
case QtFatalMsg:
fprintf(stderr, "Fatal: %s\n", msg.toAscii().data());
abort();
}
}
#endif
PS: you could add dateString to output if you want in future.
First of all, why would you need to output to console in a release mode build? Nobody will think to look there when there's a gui...
Second, qDebug is fancy :)
Third, you can try adding console to your .pro's CONFIG, it might work.
In your .pro add
CONFIG += console
It may have been an oversight of other answers, or perhaps it is a requirement of the user to indeed need console output, but the obvious answer to me is to create a secondary window that can be shown or hidden (with a checkbox or button) that shows all messages by appending lines of text to a text box widget and use that as a console?
The benefits of such a solution are:
A simple solution (providing all it displays is a simple log).
The ability to dock the 'console' widget onto the main application window. (In Qt, anyhow).
The ability to create many consoles (if more than 1 thread, etc).
A pretty easy change from local console output to sending log over network to a client.
Hope this gives you food for thought, although I am not in any way yet qualified to postulate on how you should do this, I can imagine it is something very achievable by any one of us with a little searching / reading!
Make sure Qt5Core.dll is in the same directory with your application executable.
I had a similar issue in Qt5 with a console application:
if I start the application from Qt Creator, the output text is visible,
if I open cmd.exe and start the same application there, no output is visible.
Very strange!
I solved it by copying Qt5Core.dll to the directory with the application executable.
Here is my tiny console application:
#include <QCoreApplication>
#include <QDebug>
int main(int argc, char *argv[])
{
int x=343;
QString str("Hello World");
qDebug()<< str << x<<"lalalaa";
QTextStream out(stdout);
out << "aldfjals alsdfajs...";
}
I also played with this, discovering that redirecting output worked, but I never saw output to the console window, which is present for every windows application. This is my solution so far, until I find a Qt replacement for ShowWindow and GetConsoleWindow.
Run this from a command prompt without parameters - get the window. Run from command prompt with parameters (eg. cmd aaa bbb ccc) - you get the text output on the command prompt window - just as you would expect for any Windows console app.
Please excuse the lame example - it represents about 30 minutes of tinkering.
#include "mainwindow.h"
#include <QTextStream>
#include <QCoreApplication>
#include <QApplication>
#include <QWidget>
#include <windows.h>
QT_USE_NAMESPACE
int main(int argc, char *argv[])
{
if (argc > 1) {
// User has specified command-line arguments
QCoreApplication a(argc, argv);
QTextStream out(stdout);
int i;
ShowWindow (GetConsoleWindow(),SW_NORMAL);
for (i=1; i<argc; i++)
out << i << ':' << argv [i] << endl;
out << endl << "Hello, World" << endl;
out << "Application Directory Path:" << a.applicationDirPath() << endl;
out << "Application File Path:" << a.applicationFilePath() << endl;
MessageBox (0,(LPCWSTR)"Continue?",(LPCWSTR)"Silly Question",MB_YESNO);
return 0;
} else {
QApplication a(argc, argv);
MainWindow w;
w.setWindowTitle("Simple example");
w.show();
return a.exec();
}
}
After a rather long struggle with exactly the same problem I found that simply
CONFIG += console
really does the trick. It won't work until you explicitly tell QtCreator to execute qmake on the project (right click on project) AND change something inside the source file, then rebuild. Otherwise compilation is skipped and you still won't see the output on the command line.
Now my program works in both GUI and cmd line mode.
One solution is to run powershell and redirect the output to whatever stream you want.
Below is an example of running powershell from cmd.exe and redirecting my_exec.exe output to both the console and an output.txt file:
powershell ".\my_exec.exe | tee output.txt"
An example (from cmd.exe) which holds open stdout/stderr and doesn't require tee or a temporary file:
my_exec.exe > NUL 2>&1
Easy
Step1: Create new project. Go File->New File or Project --> Other Project -->Empty Project
Step2: Use the below code.
In .pro file
QT +=widgets
CONFIG += console
TARGET = minimal
SOURCES += \ main.cpp
Step3: Create main.cpp and copy the below code.
#include <QApplication>
#include <QtCore>
using namespace std;
QTextStream in(stdin);
QTextStream out(stdout);
int main(int argc, char *argv[]){
QApplication app(argc,argv);
qDebug() << "Please enter some text over here: " << endl;
out.flush();
QString input;
input = in.readLine();
out << "The input is " << input << endl;
return app.exec();
}
I created necessary objects in the code for your understanding.
Just Run It
If you want your program to get multiple inputs with some conditions. Then past the below code in Main.cpp
#include <QApplication>
#include <QtCore>
using namespace std;
QTextStream in(stdin);
QTextStream out(stdout);
int main(int argc, char *argv[]){
QApplication app(argc,argv);
qDebug() << "Please enter some text over here: " << endl;
out.flush();
QString input;
do{
input = in.readLine();
if(input.size()==6){
out << "The input is " << input << endl;
}
else
{
qDebug("Not the exact input man");
}
}while(!input.size()==0);
qDebug(" WE ARE AT THE END");
// endif
return app.exec();
} // end main
Hope it educates you.
Good day,
First of all you can try flushing the buffer
std::cout << "Hello, world!"<<std::endl;
For more Qt based logging you can try using qDebug.