How to list objects in many to many Django - django

Question

Considerer this model
class Dealership(models.Model):
dealership = models.CharField(max_length=50)
class Ordered(models.Model):
customer = models.ForeignKey("Customer")
dealership = models.ManyToManyField("Dealership")
status = models.CharField(max_length=2, choices=status_list, default='p')
I try
$ ./manage.py shell
>>> from new_way.core.models import Ordered, Dealership
>>> q = Ordered.objects.all()[:5]
>>> [i.dealership for i in q.dealership.all]
And generate error
Traceback (most recent call last):
File "<console>", line 1, in <module>
AttributeError: 'QuerySet' object has no attribute 'dealership'
How to return
Ordered.dealership.dealership
all dealership by Ordered.

Answer 1

You're very close:
Change:
[i.dealership for i in q.dealership.all]
to:
[dealership for dealership in q.dealership.all()]
Here's sample output from one of my model's M2M relationships on a project which demonstrates what you should see from the list comprehension. shared_with is an M2M field to a model called Profile:
>>> from polls.models import Poll
>>> polls = Poll.objects.all()
>>> for p in polls:
... print([sw for sw in p.shared_with.all()])
...
[<Profile: kerri>]
[<Profile: kerri>]
[]
[<Profile: jake>, <Profile: kerri>]
[<Profile: jake>, <Profile: kerri>]
[<Profile: jake>, <Profile: kerri>]
[<Profile: btaylor>]
[<Profile: jake>, <Profile: kerri>]

Answer 2

It should be:
q.dealership.all() #gives a list of objects
You can directly do this instead of using list comprehension(in the above ans).
Example: (Taken from docs)
from django.db import models
class Publication(models.Model):
title = models.CharField(max_length=30)
def __str__(self): # __unicode__ on Python 2
return self.title
class Meta:
ordering = ('title',)
class Article(models.Model):
headline = models.CharField(max_length=100)
publications = models.ManyToManyField(Publication)
def __str__(self): # __unicode__ on Python 2
return self.headline
class Meta:
ordering = ('headline',)
Create a couple of Publications:
p1 = Publication(title='The Python Journal')
p1.save()
p2 = Publication(title='Science News')
p2.save()
p3 = Publication(title='Science Weekly')
p3.save()
Now, create an Article and the associate the Article with a Publication:
a1 = Article(headline='NASA uses Python')
a1.save()
a1.publications.add(p1, p2)
a1.publications.add(p3)
a1.publications.all()
[<Publication: Science News>, <Publication: Science Weekly>, <Publication: The Python Journal>]