In the following example(not all the code included just the necessary portions):
class A
{
public:
void FlushToDisk(char* pData, unsigned int uiSize)
{
char* pTmp = new char[uiSize];
memcpy(pTmp, pData, uiSize);
m_Thread = boost::thread(&CSimSwcFastsimExporter::WriteToDisk, this, pTmp, uiSize);
}
void WriteToDisk(char* pData, unsigned int uiSize)
{
m_Mtx.lock();
m_ExportFile.write(pData, uiSize);
delete[] pData;
m_Mtx.unlock();
}
boost::thread m_Thread;
boost::mutex m_Mtx
}
is it safe to use the m_Thread that way since the FlushToDisk method can be called while the created thread is executing the WriteToDisk method.
Or should I do something like:
m_Thread.join();
m_Thread = boost::thread(&CSimSwcFastsimExporter::WriteToDisk, this, pTmp, uiSize);
Would this second solution be slower than the first?
From what i saw at http://www.boost.org/doc/libs/1_59_0/doc/html/thread/thread_management.html#thread.thread_management.tutorial
"When the boost::thread object that represents a thread of execution is destroyed the thread becomes detached. Once a thread is detached, it will continue executing until the invocation of the function or callable object supplied on construction has completed, or the program is terminated".
So in my case the threads should not be interrupted or?
Thanks in advance.
The second solution will pause the main thread to wait until the writer thread completes. You would be able to remove mutex if you go this way. You are guaranteed to have one file writing thread.
The first solution is going to allow main thread to continue, and will create an uncontrolled writing thread - serialized on the mutex. While you might believe this is better (main thread will not wait) I do not like this solution for several reasons.
First, you do not have any control over the number of created threads. If the function is called often, and the operation is slow, you can easily run out of threads! Second, and much more important, you will accumulate a backlog of detached threads waiting on mutex. If your main application decides to exit, all those threads will be silently killed and the updates will be lost.
Suppose we have two workers. Each worker has an id of 0 and 1. Also suppose that we have jobs arriving all the time, each job has also an identifier 0 or 1 which specifies which worker will have to do this job.
I would like to create 2 threads that are initially locked, and then when two jobs arrive, unlock them, each of them does their job and then lock them again until other jobs arrive.
I have the following code:
#include <iostream>
#include <thread>
#include <mutex>
using namespace std;
struct job{
thread jobThread;
mutex jobMutex;
};
job jobs[2];
void executeJob(int worker){
while(true){
jobs[worker].jobMutex.lock();
//do some job
}
}
void initialize(){
int i;
for(i=0;i<2;i++){
jobs[i].jobThread = thread(executeJob, i);
}
}
int main(void){
//initialization
initialize();
int buffer[2];
int bufferSize = 0;
while(true){
//jobs arrive here constantly,
//once the buffer becomes full,
//we unlock the threads(workers) and they start working
bufferSize = 2;
if(bufferSize == 2){
for(int i = 0; i<2; i++){
jobs[i].jobMutex.unlock();
}
}
break;
}
}
I started using std::thread a few days ago and I'm not sure why but Visual Studio gives me an error saying abort() has been called. I believe there's something missing however due to my ignorance I can't figure out what.
I would expect this piece of code to actually
Initialize the two threads and then lock them
Inside the main function unlock the two threads, the two threads will do their job(in this case nothing) and then they will become locked again.
But it gives me an error instead. What am I doing wrong?
Thank you in advance!
For this purpose you can use boost's threadpool class.
It's efficient and well tested. opensource library instead of you writing newly and stabilizing it.
http://threadpool.sourceforge.net/
main()
{
pool tp(2); //number of worker threads-currently its 2.
// Add some tasks to the pool.
tp.schedule(&first_task);
tp.schedule(&second_task);
}
void first_task()
{
...
}
void second_task()
{
...
}
Note:
Suggestion for your example:
You don't need to have individual mutex object for each thread. Single mutex object lock itself will does the synchronization between all the threads. You are locking mutex of one thread in executejob function and without unlocking another thread is calling lock with different mutex object leading to deadlock or undefined behaviour.
Also since you are calling mutex.lock() inside whileloop without unlocking , same thread is trying to lock itself with same mutex object infinately leading to undefined behaviour.
If you donot need to execute threads parallel you can have one global mutex object can be used inside executejob function to lock and unlock.
mutex m;
void executeJob(int worker)
{
m.lock();
//do some job
m.unlock();
}
If you want to execute job parallel use boost threadpool as I suggested earlier.
In general you can write an algorithm similar to the following. It works with pthreads. I'm sure it would work with c++ threads as well.
create threads and make them wait on a condition variable, e.g. work_exists.
When work arrives you notify all threads that are waiting on that condition variable. Then in the main thread you start waiting on another condition variable work_done
Upon receiving work_exists notification, worker threads wake up, and grab their assigned work from jobs[worker], they execute it, they send a notification on work_done variable, and then go back to waiting on the work_exists condition variable
When main thread receives work_done notification it checks if all threads are done. If not, it keeps waiting till the notification from last-finishing thread arrives.
From cppreference's page on std::mutex::unlock:
The mutex must be unlocked by all threads that have successfully locked it before being destroyed. Otherwise, the behavior is undefined.
Your approach of having one thread unlock a mutex on behalf of another thread is incorrect.
The behavior you're attempting would normally be done using std::condition_variable. There are examples if you look at the links to the member functions.
recently I set out to port ucos-ii to Ubuntu PC.
As we know, it's not possible to simulate the "process" in the ucos-ii by simply adding a flag in "while" loop in the pthread's call-back function to perform pause and resume(like the solution below). Because the "process" in ucos-ii can be paused or resumed at any time!
How to sleep or pause a PThread in c on Linux
I have found one solution on the web-site below, but it can't be built because it's out of date. It uses the process in Linux to simulate the task(acts like the process in our Linux) in ucos-ii.
http://www2.hs-esslingen.de/~zimmerma/software/index_uk.html
If pthread can act like the process which can be paused and resumed at any time, please tell me some related functions, I can figure it out myself. If it can't, I think I should focus on the older solution. Thanks a lot.
The Modula-3 garbage collector needs to suspend pthreads at an arbitrary time, not just when they are waiting on a condition variable or mutex. It does it by registering a (Unix) signal handler that suspends the thread and then using pthread_kill to send a signal to the target thread. I think it works (it has been reliable for others but I'm debugging an issue with it right now...) It's a bit kludgy, though....
Google for ThreadPThread.m3 and look at the routines "StopWorld" and "StartWorld". Handler itself is in ThreadPThreadC.c.
If stopping at specific points with a condition variable is insufficient, then you can't do this with pthreads. The pthread interface does not include suspend/resume functionality.
See, for example, answer E.4 here:
The POSIX standard provides no mechanism by which a thread A can suspend the execution of another thread B, without cooperation from B. The only way to implement a suspend/restart mechanism is to have B check periodically some global variable for a suspend request and then suspend itself on a condition variable, which another thread can signal later to restart B.
That FAQ answer goes on to describe a couple of non-standard ways of doing it, one in Solaris and one in LinuxThreads (which is now obsolete; do not confuse it with current threading on Linux); neither of those apply to your situation.
On Linux you can probably setup custom signal handler (eg. using signal()) that will contain wait for another signal (eg. using sigsuspend()). You then send the signals using pthread_kill() or tgkill(). It is important to use so-called "realtime signals" for this, because normal signals like SIGUSR1 and SIGUSR2 don't get queued, which means that they can get lost under high load conditions. You send a signal several times, but it gets received only once, because before while signal handler is running, new signals of the same kind are ignored. So if you have concurent threads doing PAUSE/RESUME , you can loose RESUME event and cause deadlock. On the other hand, the pending realtime signals (like SIGRTMIN+1 and SIGRTMIN+2) are not deduplicated, so there can be several same rt signals in queue at the same time.
DISCLAIMER: I had not tried this yet. But in theory it should work.
Also see man 7 signal-safety. There is a list of calls that you can safely call in signal handlers. Fortunately sigsuspend() seems to be one of them.
UPDATE: I have working code right here:
//Filename: pthread_pause.c
//Author: Tomas 'Harvie' Mudrunka 2021
//Build: CFLAGS=-lpthread make pthread_pause; ./pthread_pause
//Test: valgrind --tool=helgrind ./pthread_pause
//I've wrote this code as excercise to solve following stack overflow question:
// https://stackoverflow.com/questions/9397068/how-to-pause-a-pthread-any-time-i-want/68119116#68119116
#define _GNU_SOURCE //pthread_yield() needs this
#include <signal.h>
#include <pthread.h>
//#include <pthread_extra.h>
#include <semaphore.h>
#include <stdio.h>
#include <stdlib.h>
#include <assert.h>
#include <unistd.h>
#include <errno.h>
#include <sys/resource.h>
#include <time.h>
#define PTHREAD_XSIG_STOP (SIGRTMIN+0)
#define PTHREAD_XSIG_CONT (SIGRTMIN+1)
#define PTHREAD_XSIGRTMIN (SIGRTMIN+2) //First unused RT signal
pthread_t main_thread;
sem_t pthread_pause_sem;
pthread_once_t pthread_pause_once_ctrl = PTHREAD_ONCE_INIT;
void pthread_pause_once(void) {
sem_init(&pthread_pause_sem, 0, 1);
}
#define pthread_pause_init() (pthread_once(&pthread_pause_once_ctrl, &pthread_pause_once))
#define NSEC_PER_SEC (1000*1000*1000)
// timespec_normalise() from https://github.com/solemnwarning/timespec/
struct timespec timespec_normalise(struct timespec ts)
{
while(ts.tv_nsec >= NSEC_PER_SEC) {
++(ts.tv_sec); ts.tv_nsec -= NSEC_PER_SEC;
}
while(ts.tv_nsec <= -NSEC_PER_SEC) {
--(ts.tv_sec); ts.tv_nsec += NSEC_PER_SEC;
}
if(ts.tv_nsec < 0) { // Negative nanoseconds isn't valid according to POSIX.
--(ts.tv_sec); ts.tv_nsec = (NSEC_PER_SEC + ts.tv_nsec);
}
return ts;
}
void pthread_nanosleep(struct timespec t) {
//Sleep calls on Linux get interrupted by signals, causing premature wake
//Pthread (un)pause is built using signals
//Therefore we need self-restarting sleep implementation
//IO timeouts are restarted by SA_RESTART, but sleeps do need explicit restart
//We also need to sleep using absolute time, because relative time is paused
//You should use this in any thread that gets (un)paused
struct timespec wake;
clock_gettime(CLOCK_MONOTONIC, &wake);
t = timespec_normalise(t);
wake.tv_sec += t.tv_sec;
wake.tv_nsec += t.tv_nsec;
wake = timespec_normalise(wake);
while(clock_nanosleep(CLOCK_MONOTONIC, TIMER_ABSTIME, &wake, NULL)) if(errno!=EINTR) break;
return;
}
void pthread_nsleep(time_t s, long ns) {
struct timespec t;
t.tv_sec = s;
t.tv_nsec = ns;
pthread_nanosleep(t);
}
void pthread_sleep(time_t s) {
pthread_nsleep(s, 0);
}
void pthread_pause_yield() {
//Call this to give other threads chance to run
//Wait until last (un)pause action gets finished
sem_wait(&pthread_pause_sem);
sem_post(&pthread_pause_sem);
//usleep(0);
//nanosleep(&((const struct timespec){.tv_sec=0,.tv_nsec=1}), NULL);
//pthread_nsleep(0,1); //pthread_yield() is not enough, so we use sleep
pthread_yield();
}
void pthread_pause_handler(int signal) {
//Do nothing when there are more signals pending (to cleanup the queue)
//This is no longer needed, since we use semaphore to limit pending signals
/*
sigset_t pending;
sigpending(&pending);
if(sigismember(&pending, PTHREAD_XSIG_STOP)) return;
if(sigismember(&pending, PTHREAD_XSIG_CONT)) return;
*/
//Post semaphore to confirm that signal is handled
sem_post(&pthread_pause_sem);
//Suspend if needed
if(signal == PTHREAD_XSIG_STOP) {
sigset_t sigset;
sigfillset(&sigset);
sigdelset(&sigset, PTHREAD_XSIG_STOP);
sigdelset(&sigset, PTHREAD_XSIG_CONT);
sigsuspend(&sigset); //Wait for next signal
} else return;
}
void pthread_pause_enable() {
//Having signal queue too deep might not be necessary
//It can be limited using RLIMIT_SIGPENDING
//You can get runtime SigQ stats using following command:
//grep -i sig /proc/$(pgrep binary)/status
//This is no longer needed, since we use semaphores
//struct rlimit sigq = {.rlim_cur = 32, .rlim_max=32};
//setrlimit(RLIMIT_SIGPENDING, &sigq);
pthread_pause_init();
//Prepare sigset
sigset_t sigset;
sigemptyset(&sigset);
sigaddset(&sigset, PTHREAD_XSIG_STOP);
sigaddset(&sigset, PTHREAD_XSIG_CONT);
//Register signal handlers
//signal(PTHREAD_XSIG_STOP, pthread_pause_handler);
//signal(PTHREAD_XSIG_CONT, pthread_pause_handler);
//We now use sigaction() instead of signal(), because it supports SA_RESTART
const struct sigaction pause_sa = {
.sa_handler = pthread_pause_handler,
.sa_mask = sigset,
.sa_flags = SA_RESTART,
.sa_restorer = NULL
};
sigaction(PTHREAD_XSIG_STOP, &pause_sa, NULL);
sigaction(PTHREAD_XSIG_CONT, &pause_sa, NULL);
//UnBlock signals
pthread_sigmask(SIG_UNBLOCK, &sigset, NULL);
}
void pthread_pause_disable() {
//This is important for when you want to do some signal unsafe stuff
//Eg.: locking mutex, calling printf() which has internal mutex, etc...
//After unlocking mutex, you can enable pause again.
pthread_pause_init();
//Make sure all signals are dispatched before we block them
sem_wait(&pthread_pause_sem);
//Block signals
sigset_t sigset;
sigemptyset(&sigset);
sigaddset(&sigset, PTHREAD_XSIG_STOP);
sigaddset(&sigset, PTHREAD_XSIG_CONT);
pthread_sigmask(SIG_BLOCK, &sigset, NULL);
sem_post(&pthread_pause_sem);
}
int pthread_pause(pthread_t thread) {
sem_wait(&pthread_pause_sem);
//If signal queue is full, we keep retrying
while(pthread_kill(thread, PTHREAD_XSIG_STOP) == EAGAIN) usleep(1000);
pthread_pause_yield();
return 0;
}
int pthread_unpause(pthread_t thread) {
sem_wait(&pthread_pause_sem);
//If signal queue is full, we keep retrying
while(pthread_kill(thread, PTHREAD_XSIG_CONT) == EAGAIN) usleep(1000);
pthread_pause_yield();
return 0;
}
void *thread_test() {
//Whole process dies if you kill thread immediately before it is pausable
//pthread_pause_enable();
while(1) {
//Printf() is not async signal safe (because it holds internal mutex),
//you should call it only with pause disabled!
//Will throw helgrind warnings anyway, not sure why...
//See: man 7 signal-safety
pthread_pause_disable();
printf("Running!\n");
pthread_pause_enable();
//Pausing main thread should not cause deadlock
//We pause main thread here just to test it is OK
pthread_pause(main_thread);
//pthread_nsleep(0, 1000*1000);
pthread_unpause(main_thread);
//Wait for a while
//pthread_nsleep(0, 1000*1000*100);
pthread_unpause(main_thread);
}
}
int main() {
pthread_t t;
main_thread = pthread_self();
pthread_pause_enable(); //Will get inherited by all threads from now on
//you need to call pthread_pause_enable (or disable) before creating threads,
//otherwise first (un)pause signal will kill whole process
pthread_create(&t, NULL, thread_test, NULL);
while(1) {
pthread_pause(t);
printf("PAUSED\n");
pthread_sleep(3);
printf("UNPAUSED\n");
pthread_unpause(t);
pthread_sleep(1);
/*
pthread_pause_disable();
printf("RUNNING!\n");
pthread_pause_enable();
*/
pthread_pause(t);
pthread_unpause(t);
}
pthread_join(t, NULL);
printf("DIEDED!\n");
}
I am also working on library called "pthread_extra", which will have stuff like this and much more. Will publish soon.
UPDATE2: This is still causing deadlocks when calling pause/unpause rapidly (removed sleep() calls). Printf() implementation in glibc has mutex, so if you suspend thread which is in middle of printf() and then want to printf() from your thread which plans to unpause that thread later, it will never happen, because printf() is locked. Unfortunately i've removed the printf() and only run empty while loop in the thread, but i still get deadlocks under high pause/unpause rates. and i don't know why. Maybe (even realtime) Linux signals are not 100% safe. There is realtime signal queue, maybe it just overflows or something...
UPDATE3: i think i've managed to fix the deadlock, but had to completely rewrite most of the code. Now i have one (sig_atomic_t) variable per each thread which holds state whether that thread should be running or not. Works kinda like condition variable. pthread_(un)pause() transparently remembers this for each thread. I don't have two signals. now i only have one signal. handler of that signal looks at that variable and only blocks on sigsuspend() when that variable says the thread should NOT run. otherwise it returns from signal handler. in order to suspend/resume the thread i now set the sig_atomic_t variable to desired state and call that signal (which is common for both suspend and resume). It is important to use realtime signals to be sure handler will actualy run after you've modified the state variable. Code is bit complex because of the thread status database. I will share the code in separate solution as soon as i manage to simplify it enough. But i want to preserve the two signal version in here, because it kinda works, i like the simplicity and maybe people will give us more insight on how to optimize it.
UPDATE4: I've fixed the deadlock in original code (no need for helper variable holding the status) by using single handler for two signals and optimizing signal queue a bit. There is still some problem with printf() shown by helgrind, but it is not caused by my signals, it happens even when i do not call pause/unpause at all. Overall this was only tested on LINUX, not sure how portable the code is, because there seem to be some undocumented behaviour of signal handlers which was originaly causing the deadlock.
Please note that pause/unpause cannot be nested. if you pause 3 times, and unpause 1 time, the thread WILL RUN. If you need such behaviour, you should create some kind of wrapper which will count the nesting levels and signal the thread accordingly.
UPDATE5: I've improved robustness of the code by following changes: I ensure proper serialization of pause/unpause calls by use of semaphores. This hopefuly fixes last remaining deadlocks. Now you can be sure that when pause call returns, the target thread is actualy already paused. This also solves issues with signal queue overflowing. Also i've added SA_RESTART flag, which prevents internal signals from causing interuption of IO waits. Sleeps/delays still have to be restarted manualy, but i provide convenient wrapper called pthread_nanosleep() which does just that.
UPDATE6: i realized that simply restarting nanosleep() is not enough, because that way timeout does not run when thread is paused. Therefore i've modified pthread_nanosleep() to convert timeout interval to absolute time point in the future and sleep until that. Also i've hidden semaphore initialization, so user does not need to do that.
Here is example of thread function within a class with pause/resume functionality...
class SomeClass
{
public:
// ... construction/destruction
void Resume();
void Pause();
void Stop();
private:
static void* ThreadFunc(void* pParam);
pthread_t thread;
pthread_mutex_t mutex;
pthread_cond_t cond_var;
int command;
};
SomeClass::SomeClass()
{
pthread_mutex_init(&mutex, NULL);
pthread_cond_init(&cond_var, NULL);
// create thread in suspended state..
command = 0;
pthread_create(&thread, NULL, ThreadFunc, this);
}
SomeClass::~SomeClass()
{
// we should stop the thread and exit ThreadFunc before calling of blocking pthread_join function
// also it prevents the mutex staying locked..
Stop();
pthread_join(thread, NULL);
pthread_cond_destroy(&cond_var);
pthread_mutex_destroy(&mutex);
}
void* SomeClass::ThreadFunc(void* pParam)
{
SomeClass* pThis = (SomeClass*)pParam;
timespec time_ns = {0, 50*1000*1000}; // 50 milliseconds
while(1)
{
pthread_mutex_lock(&pThis->mutex);
if (pThis->command == 2) // command to stop thread..
{
// be sure to unlock mutex before exit..
pthread_mutex_unlock(&pThis->mutex);
return NULL;
}
else if (pThis->command == 0) // command to pause thread..
{
pthread_cond_wait(&pThis->cond_var, &pThis->mutex);
// dont forget to unlock the mutex..
pthread_mutex_unlock(&pThis->mutex);
continue;
}
if (pThis->command == 1) // command to run..
{
// normal runing process..
fprintf(stderr, "*");
}
pthread_mutex_unlock(&pThis->mutex);
// it's important to give main thread few time after unlock 'this'
pthread_yield();
// ... or...
//nanosleep(&time_ns, NULL);
}
pthread_exit(NULL);
}
void SomeClass::Stop()
{
pthread_mutex_lock(&mutex);
command = 2;
pthread_cond_signal(&cond_var);
pthread_mutex_unlock(&mutex);
}
void SomeClass::Pause()
{
pthread_mutex_lock(&mutex);
command = 0;
// in pause command we dont need to signal cond_var because we not in wait state now..
pthread_mutex_unlock(&mutex);
}
void SomeClass::Resume()
{
pthread_mutex_lock(&mutex);
command = 1;
pthread_cond_signal(&cond_var);
pthread_mutex_unlock(&mutex);
}
I am trying to make a small thread example. I want to have a variable and each thread try to increment it and then stop once it gets to a certain point. Whenever the variable is locked, I want some sort of message to be printed out like "thread x trying to lock, but cannot" so that I KNOW it's working correctly. This is my first day coding threads so feel free to point out anything unnecessary in the code here -
#include <iostream>
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
using namespace std;
#define NUM_THREADS 2
pthread_t threads[NUM_THREADS];
pthread_mutex_t mutexsum;
int NUMBER = 0;
void* increaseByHundred(void* threadid) {
if(pthread_mutex_lock(&mutexsum))
cout<<"\nTHREAD "<<(int)threadid<<" TRYING TO LOCK BUT CANNOT";
else {
for(int i=0;i<100;i++) {
NUMBER++;
cout<<"\nNUMBER: "<<NUMBER;
}
pthread_mutex_unlock(&mutexsum);
pthread_exit((void*)0);
}
}
int main(int argc, char** argv) {
int rc;
int rc1;
void* status;
pthread_attr_t attr;
pthread_mutex_init(&mutexsum, NULL);
pthread_attr_init(&attr);
pthread_attr_setdetachstate(&attr, PTHREAD_CREATE_JOINABLE);
rc = pthread_create(&threads[0], &attr, increaseByHundred, (void*)0);
rc1 = pthread_create(&threads[1], &attr, increaseByHundred, (void*)1);
pthread_attr_destroy(&attr);
while(NUMBER < 400)
pthread_join(threads[0], &status);
pthread_mutex_destroy(&mutexsum);
pthread_exit(NULL);
}
I was following a tutorial found here https://computing.llnl.gov/tutorials...reatingThreads
and tried to adapt their mutex example to this idea. The code increments it up to 199 and then stops. I'm guessing because the threads are only doing their routine once. Is there a way make them just do their routine other than when you create them so I could say
while something
do your routine
?
I have the pthread_join there just because it was similar to what that tutorial had on theirs. I don't really even get it that clearly though. I'm pretty sure that line is the problem...I just don't know how to fix it. Any help is appreciated.
Whenever the variable is locked, I want some sort of message to be printed out like "thread x trying to lock, but cannot" so that I KNOW it's working correctly.
Why do you want that? You are just learning about threads. Learn the basics first. Don't go diving off the deep end into pthread_mutex_trylock or mutexes configured for error checking. You need to learn to walk before you can learn how to run.
The basics involves a mutex initialized use with default settings and using pthread_mutex_lock to grab the lock. With the default settings, pthread_mutex_lock will only return non-zero if there are big, big problems. There are only two problems that can occur here: Deadlock, and a bad mutex pointer. There is no recovery from either; the only real solution is to fix the code. About the only thing you can do here is to throw an exception that you don't catch, call exit() or abort(), etc.
That some other thread has locked the mutex is not a big problem. It is not a problem at all. pthread_mutex_lock will block (e.g., go to sleep) until the lock becomes available. A zero return from pthread_mutex_lock means that the calling thread now has the lock. Just make sure you release the lock when you are done working with the protected memory.
Edit
Here's a suggestion that will let you see that the threading mechanism is working as advertised.
Upon entry to increaseByHundred print a time-stamped message indicating entry to the function. You probably want to use C printf here rather than C++ I/O. printf() and related functions are thread-safe. C++ 2003 I/O is not.
After a successful return from pthread_mutex_lock print another time-stamped message indicating that a successful lock.
sleep() for a few seconds and then print yet another time-stamped message prior to calling pthread_mutex_unlock().
Do the same before calling pthread_exit().
One last comment: You are checking for an error return from pthread_mutex_lock. For completeness, and because every good programmer is paranoid as all get out, you should also check the return status from pthread_mutex_unlock.
What about pthread_exit? It doesn't have a return status. You could print some message after calling pthread_exit, but you will only reach that statement if you are using a non-compliant version of the threads library. The function pthread_exit() cannot return to the calling function. Period. Worrying about what happens when pthreads_exit() returns is a tinfoil hat exercise. While good programmers should be paranoid beyond all get out, they should not be paranoid schizophrenic.
pthread_mutex_lock will normally just block until it acquire the lock, and that's why the line cout<<"\nTHREAD "<<(int)threadid<<" TRYING TO LOCK BUT CANNOT"; is not ran.
You also have problems in
while(NUMBER < 400)
pthread_join(threads[0], &status);
because you just have 2 threads and number will never reach 400. You also want to join thread[0] on first iteration, then thread[1]...
pthread_mutex_trylock():
if (pthread_mutex_trylock(&mutex) == EBUSY) {
cout << "OMG NO WAY ITS LOCKED" << endl;
}
It is also worth noting that if the mutex is not locked, it will be able to acquire the lock and then it will behave like a regular pthread_mutex_lock().
The following code ends with a segmentation fault on the first call to pthread_cancel but only under linux. Under Mac OS it runs fine. Am I not allowed to call pthread_cancel on a thread that has finished running? Maybe I should not call pthread_cancel at all?
#include <iostream>
#include <pthread.h>
using namespace std;
void* run(void *args) {
cerr << "Hallo, Running" << endl;
}
int main() {
int n = 100;
pthread_t* pool = new pthread_t[n];
for(int i=0;i<n;i++) {
pthread_t tmp;
pthread_create(&tmp,NULL,&run,NULL);
pool[i] = (tmp);
}
for(int i=0;i<n;i++) {
pthread_join(pool[i],0);
}
for(int i=0;i<n;i++) {
pthread_cancel(pool[i]);
}
}
See POSIX XSH 2.9.2:
Although implementations may have thread IDs that are unique in a system, applications should only assume that thread IDs are usable and unique within a single process. The effect of calling any of the functions defined in this volume of POSIX.1-2008 and passing as an argument the thread ID of a thread from another process is unspecified. The lifetime of a thread ID ends after the thread terminates if it was created with the detachstate attribute set to PTHREAD_CREATE_DETACHED or if pthread_detach() or pthread_join() has been called for that thread. A conforming implementation is free to reuse a thread ID after its lifetime has ended. If an application attempts to use a thread ID whose lifetime has ended, the behavior is undefined.
If a thread is detached, its thread ID is invalid for use as an argument in a call to pthread_detach() or pthread_join().
You may not use a pthread_t after the thread it refers to has been joined, or if the thread has terminated while detached. Simply remove the pthread_cancel code from your program. It's wrong. pthread_cancel is for cancelling an in-progress thread, and has very tricky requirements for using it safely without causing resource leaks. It's not useful for threads which exit on their own.