C++ - Variable Decrement - c++

Question

Heys.
I have this code, which sets a table for some mystery reason. Size is 6x60. Which means SIZEY defined as 6, and SIZEX as 60.
void set_table(char** table)
{
int i,j,k=0;
for(i=0;i<SIZEY;i+=3){
for(j=0;j<SIZEX;j++){
switch(k++%5){
case 0:
table[i][j]='|';
break;
case 1:
table[i][j]=' ';
break;
case 2:
table[i][j]=(char)((((k-2)/50)%10)+48);
break;
case 3:
table[i][j]=(char)((((k-3)/5)%10)+48);
break;
case 4:
table[i][j]=' ';
break;
default:
continue;
}
}
}
}
I am doing this with 3 variables, as you can see. Question is, can i do that with 2 variables, or even with only 1 ?
Thanks in advance.

Answer 1

Here's a simplification for you:
switch(k++%5){
case 0:
table[i][j]='|';
break;
case 1:
case 4:
table[i][j]=' ';
break;
case 2:
case 3:
table[i][j]= '0';
break;
default:
continue;
}
With C++, one case can fall into another, such as with cases 1 and 2 above.
Your expressions for case 2 and 3 can be simplified. I'll use case 2 as an example:
((((k-2)/50)%10)+48)
Substituting 2 for k yields
((((2-2)/50)%10)+48)
Simplify:
((((0)/50)%10)+48)
Zero divided by anything is zero, simplifying again:
(((0)%10)+48)
Zero mod anything is zero, since it involves division:
((0)+48)
Simplifying:
(48)
Replacing with the equivalent character (since your array is char):
'0'