how can i make the loop and change number to string - c++

Question

#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
int number=0;
cout<<"enter an number to cumpute";
cin>>number;
if(number=0)
cout<<"0"<<endl;
for(number>0;51>number;) {
number--;
cout<<"=";
}
for(number>10;number%10==0;) {
cout<<"|";
}
for(number>5;number%5==0;) {
cout<<"+";
}
cout<<endl;
system("PAUSE");
return 0;
}
(i got textbook called by Y.Daniel Liang. I can not find any thing like this) I have no idea how to make this loop work and I try use "while" and not working either. Should i just cout the "=" "+" "|", or start as string. I hope the output look like this.
BarPlot – A Simple Bar Graph Plotter:
Input a number in range [0 50] or a negative number to terminate:
| Enter Number: 6
| ====+> 6
| Enter Number: 12
| ====+====|=> 12
| Enter Number: 50
| ====+====|====+====|====+====|====+====|====+====> 50
| Enter Number: 53
| ERROR: 53 is not in acceptable range.
| Enter Number: 33
| ====+====|====+====|====+====|==> 33
| Enter Number: 0
| 0
| Enter Number: 5
| ====> 5
| Enter Number: -1
------------------------------------------------
BarPlot – End Plot by User Request

Answer 1

There is no need for you to convert a number to a string in order to solve the problem. The object cout can handle printing both numbers and strings without you needing to cast between them.
//example
int number = 1;
string str = "hello;
char c = '!';
//print hello1!
cout << str << number << c;
Here is a solution to the problem that does not require the need to cast an integer to a string.
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
//output inital prompt
cout << "BarPlot – A Simple Bar Graph Plotter:\n";
cout << "Input a number in range [0 50] or a negative number to terminate.\n\n";
//read in input
int number = 0;
cout << "Enter Number: ";
cin >> number;
//continue asking for input until a negative number is given
while (number >= 0){
for (int i = 1; i < number; ++i){
//special symbol every 10th char
if (i % 10 == 0) cout << "|";
//special symbol every 5th char
else if (i % 5 == 0) cout << "+";
//every other char
else cout << "=";
}
//print 0 or the number with an arrow before it
if (number == 0) cout << 0;
else cout << "> " << number << "\n";
//re-ask for input
cout << "\nEnter Number: ";
cin >> number;
}
//output ending message
cout << "BarPlot – End Plot by User Request\n";
return EXIT_SUCCESS;
}