modelformset_factory: display more fields for specific instances - django

I'm using a modelformset_factory to edit multiple instances of Product in the same form:
ProductFormSet = modelformset_factory(Product, fields=('code', 'state'))
form_products = ProductFormSet()
It works well.
But now I need to display an additional field of the Product model in the form but only for a specific instance of Product. I'm not sure if it can be done in a simple manner in Django. Is it possible to do so using a modelformset_factory?

You can specify the form in the modelformset_factory, so create a model form (in forms.py if you have one) override the __init__method to add extra fields.
I would move the fields from the formsetfactory arguments to the form
in forms.py (assuming you have one)
class ProductForm(forms.ModelForm):
model = Product
def __init__(self, *args, **kwargs):
super(ProductForm, self).__init__(*args, **kwargs)
if 'instance' in kwargs :
product = kwargs['instance']
# to add an extra field, add something like this
self.fields['extra_field'] = forms.CharField(max_length=30)
class Meta:
fields = ('code', 'state')
Then pass that to your modelformset factory with the form argument
ProductFormSet = modelformset_factory(Product, form=ProductForm )
form_products = ProductFormSet()

Related

how to dynamically set visible fields of a django modelform?

I would like the visible fields of a ModelForm to be determined by the instance of the model class it is built upon.
The ModelForm is built upon the model protocol which has a method (protocol.visiblefields())which returns an array of strings corresponding to the fields to be made visible.
forms.py
class ListForm(ModelForm):
class Meta():
model = protocol
fields = []
views.py
newProtocol = protocol()
form = ListForm(instance=newProtocol)
You have a couple of options to do this, one is mostly in the view and the other is in the form __init__.
Option 1: Pop the fields after initializing the form. Although you would need to specify all fields in the form Meta and remove the ones you don't want in the view.
newProtocol = protocol()
form = ListForm(instance=newProtocol)
visible_fields = newProtocol.visiblefields()
for field in form.fields:
if field not in visible_fields:
form.fields.pop(field)
Option 2: Overwrite the __init__ method and pass the fields in. We include all fields and remove the ones we don't want.
forms.py
class ListForm(ModelForm):
class Meta:
model = protocol
fields = '__all__'
def __init__(self, *args, **kwargs):
visible_fields = kwargs.pop('visible_fields')
super(ListForm, self).__init__(*args, **kwargs)
for field in self.fields:
if field not in visible_fields:
self.fields.pop(field)
views.py
newProtocol = protocol()
form = ListForm(instance=newProtocol, visible_fields=newProtocol.visiblefields())

Creating a generic search view in Django

I am struggling to create my custom generic view in django to easily create search pages for certain models. I'd like to use it like this:
class MyModelSearchView(SearchView):
template_name = 'path/to/template.html'
model = MyModel
fields = ['name', 'email', 'whatever']
which will result in a view that returns a search form on GET and both form and results on POST.
The fields specifies which fields of MyModel will be available for a user to search.
class SearchView(FormView):
def get_form(self, form_class=None):
# what I'v already tried:
class SearchForm(ModelForm):
class Meta:
model = self.model
fields = self.fields
return SearchForm()
def post(self, request, *args, **kwargs):
# perform searching and return results
The problem with the code above is that form will not be submitted if certain fields are not be properly filled. User should be allowed to provide only part of fields to search but with the code I provided the form generated with ModelForm prevents that (for example because a field in a model cannot be blank).
My questions are:
Is it possible to generate a form based on a model to omit this behaviour?
Or is there any simpler way to create SearchView class?
I don't want to manually write forms if it's possible.
One way to accomplish this is to set blank=True on the field in MyModel, as indicated in the docs:
If the model field has blank=True, then required is set to False on the form field. Otherwise, required=True.
But for this to be a generic solution, you can't count on being able to modify the model fields. You can instead set the fields' required attribute to False immediately after the instance is created:
class SearchForm(ModelForm):
class Meta:
model = self.model
fields = self.fields
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
for (field_name, field) in self.fields.items():
field.required = False
Since you're using the ModelForm for searching, you should set all the fields as required=False, by overriding the __init__ method:
def get_form(self, form_class=None):
# what I'v already tried:
class SearchForm(ModelForm):
class Meta:
model = self.model
fields = self.fields
def __init__(self, *args, **kwargs):
super(SearchForm, self).__init__(*args, **kwargs)
for field in self.fields:
self.fields[field].required = False
return SearchForm()
Though I suggest you should user django-filter, which makes it easier and cleaner to filter your searches. First you need to install it:
pip install django-filter
Then add it to your INSTALLED_APPS. After that you can create a filters.py file in your app:
# myapp/filters.py
import django_filters as filters
from .models import MyModel
MyModelFilterSet(filters.FilterSet):
class Meta:
model = MyModel
fields = ['name', 'email', 'whatever']
By default it's going to filter with the __exact lookup. You can change this in a couple of ways, just take a look here and here. To know which lookups you can use, take a look here.
After creating your filters.py file you can add it to a View, like a ListView:
# myapp/views.py
from django.views.generic import ListView
from .filters import MyModelFilterSet
from .models import MyModel
class MyModelSearchView(ListView):
template_name = 'path/to/template.html'
model = MyModel
def get_queryset(self):
qs = self.model.objects.all()
filtered_model_list = MyModelFilterSet(self.request.GET, queryset=qs)
return filtered_model_list.qs
There's a lot more you can do with django-filter. Here's the full documentation.

Django model form - Exclude a field that has no model field

I have a simple model form what I use through the admin interface. Some of my model fields store datas that require a bit more time to calculate (they come from other sites). So I decided to put an extra boolean field to the form to decide to crawl these datas again or not.
class MyModelForm(forms.ModelForm):
update_values = forms.BooleanField(required=False) #this field has no model field
class Meta:
model = MyModel
This extra field doesn't exist in the model because only the form needs it.
The problem is that I only want it to appear if it's an existing record in the database.
def __init__(self, *args, **kwargs):
super(MyModelForm, self).__init__(*args, **kwargs)
if self.instance.pk is None:
#remove that field somehow
I tried nearly everything. Exclude it, delete the variable but nothing wants to work. I also tried dynamically add the field if self.instance.pk is exists but that didn't work too.
Any idea how to do the trick?
Thanks for your answers.
You could subclass the form and add the extra field in the subclass:
class MyModelForm(forms.ModelForm):
class Meta:
model = MyModel
class MyUpdateModelForm(MyModelForm):
update_values = forms.BooleanField(required=False) #this field has no model field
class Meta:
model = MyModel
You can then override the get_form method of your admin, which is passed the current instance: get_form(self, request, obj=None, **kwargs)
Rather than removing the field in __init__ if instance.pk is not None, how about adding it if it is None? Remove the class-level declaration and just change the logic:
class MyModelForm(forms.ModelForm):
class Meta:
model = MyModel
def __init__(self, *args, **kwargs):
super(MyModelForm, self).__init__(*args, **kwargs)
if self.instance and self.instance.pk is not None:
self.fields['update_values'] = forms.BooleanField(required=False)

Django different forms for admin model

Is there any way to load different admin forms for editing an objects depending of what object is needed to be updated?
For example - we have an MPTTModelAdmin objects. And for root objects we don't want to see some fields:
class RootObjectForm(ModelForm):
class Meta:
model = Author
exclude = ('title',)
class ChildObjectForm(ModelForm):
class Meta:
model = Author
fields = ('name', 'birth_date')
But I don't know how to get object fields in forms.py or admin.py.
You can always supply your own form class for a ModelAdmin class: https://docs.djangoproject.com/en/1.5/ref/contrib/admin/#django.contrib.admin.ModelAdmin.form
From there you can access fields by key, just like any other Django form:
class MyModelForm(forms.ModelForm):
class Meta:
model = MyModel
def __init__(self, *args, **kwargs):
super(MyModeForm, self).__init__(*args, **kwargs)
# access whatever field by key
# self.fields['field-name']
In forms.py file you can get object fields and their value at two stages.
1 : when form is submitted.
clean method does initial validations.
def clean(self):
""" validation of address form """
cleaned_data = super(WebsiteAddressForm, self).clean()
field1_value = self.cleaned_data.get("field1")
print field1_value
return cleaned_data
2 : when form is initialized. ____init____ method will call.
class MyForm(forms.ModelForm):
class Meta:
model = Model1
def __init__(self, *args, **kwargs):
super(MyForm, self).__init__(*args, **kwargs)
#self.fields['field1']

CBV Django Form View set data for ChoiceField

I'm using the Django Form View and I want to enter custom choices per user to my Choicefield.
How can I do this?
Can I use maybe the get_initial function?
Can I overwrite the field?
When I want to change certain things about a form such as the label text, adding required fields or filtering a list of choices etc. I follow a pattern where I use a ModelForm and add a few utility methods to it which contain my overriding code (this helps keep __init__ tidy). These methods are then called from __init__ to override the defaults.
class ProfileForm(forms.ModelForm):
class Meta:
model = Profile
fields = ('country', 'contact_phone', )
def __init__(self, *args, **kwargs):
super(ProfileForm, self).__init__(*args, **kwargs)
self.set_querysets()
self.set_labels()
self.set_required_values()
self.set_initial_values()
def set_querysets(self):
"""Filter ChoiceFields here."""
# only show active countries in the ‘country’ choices list
self.fields["country"].queryset = Country.objects.filter(active=True)
def set_labels(self):
"""Override field labels here."""
pass
def set_required_values(self):
"""Make specific fields mandatory here."""
pass
def set_initial_values(self):
"""Set initial field values here."""
pass
If the ChoiceField is the only thing you're going to be customising, this is all you need:
class ProfileForm(forms.ModelForm):
class Meta:
model = Profile
fields = ('country', 'contact_phone', )
def __init__(self, *args, **kwargs):
super(ProfileForm, self).__init__(*args, **kwargs)
# only show active countries in the ‘country’ choices list
self.fields["country"].queryset = Country.objects.filter(active=True)
You can then make your FormView use this form with like this:
class ProfileFormView(FormView):
template_name = "profile.html"
form_class = ProfileForm