using std::unique_ptr pimpl with explicit default destructor [duplicate] - c++

I'm using the pimpl-idiom with std::unique_ptr:
class window {
window(const rectangle& rect);
private:
class window_impl; // defined elsewhere
std::unique_ptr<window_impl> impl_; // won't compile
};
However, I get a compile error regarding the use of an incomplete type, on line 304 in <memory>:
Invalid application of 'sizeof' to an incomplete type 'uixx::window::window_impl'
For as far as I know, std::unique_ptr should be able to be used with an incomplete type. Is this a bug in libc++ or am I doing something wrong here?

Here are some examples of std::unique_ptr with incomplete types. The problem lies in destruction.
If you use pimpl with unique_ptr, you need to declare a destructor:
class foo
{
class impl;
std::unique_ptr<impl> impl_;
public:
foo(); // You may need a def. constructor to be defined elsewhere
~foo(); // Implement (with {}, or with = default;) where impl is complete
};
because otherwise the compiler generates a default one, and it needs a complete declaration of foo::impl for this.
If you have template constructors, then you're screwed, even if you don't construct the impl_ member:
template <typename T>
foo::foo(T bar)
{
// Here the compiler needs to know how to
// destroy impl_ in case an exception is
// thrown !
}
At namespace scope, using unique_ptr will not work either:
class impl;
std::unique_ptr<impl> impl_;
since the compiler must know here how to destroy this static duration object. A workaround is:
class impl;
struct ptr_impl : std::unique_ptr<impl>
{
~ptr_impl(); // Implement (empty body) elsewhere
} impl_;

As Alexandre C. mentioned, the problem comes down to window's destructor being implicitly defined in places where the type of window_impl is still incomplete. In addition to his solutions, another workaround that I've used is to declare a Deleter functor in the header:
// Foo.h
class FooImpl;
struct FooImplDeleter
{
void operator()(FooImpl *p);
};
class Foo
{
...
private:
std::unique_ptr<FooImpl, FooImplDeleter> impl_;
};
// Foo.cpp
...
void FooImplDeleter::operator()(FooImpl *p)
{
delete p;
}
Note that using a custom Deleter function precludes the use of std::make_unique (available from C++14), as already discussed here.

use a custom deleter
The problem is that unique_ptr<T> must call the destructor T::~T() in its own destructor, its move assignment operator, and unique_ptr::reset() member function (only). However, these must be called (implicitly or explicitly) in several PIMPL situations (already in the outer class's destructor and move assignment operator).
As already pointed out in another answer, one way to avoid that is to move all operations that require unique_ptr::~unique_ptr(), unique_ptr::operator=(unique_ptr&&), and unique_ptr::reset() into the source file where the pimpl helper class is actually defined.
However, this is rather inconvenient and defies the very point of the pimpl idoim to some degree. A much cleaner solution that avoids all that is to use a custom deleter and only move its definition into the source file where the pimple helper class lives. Here is a simple example:
// file.h
class foo
{
struct pimpl;
struct pimpl_deleter { void operator()(pimpl*) const; };
std::unique_ptr<pimpl,pimpl_deleter> m_pimpl;
public:
foo(some data);
foo(foo&&) = default; // no need to define this in file.cc
foo&operator=(foo&&) = default; // no need to define this in file.cc
//foo::~foo() auto-generated: no need to define this in file.cc
};
// file.cc
struct foo::pimpl
{
// lots of complicated code
};
void foo::pimpl_deleter::operator()(foo::pimpl*ptr) const { delete ptr; }
Instead of a separate deleter class, you can also use a free function or static member of foo:
class foo {
struct pimpl;
static void delete_pimpl(pimpl*);
using deleter = void(&)(pimpl*);
std::unique_ptr<pimpl,deleter> m_pimpl;
public:
foo(some data);
};

Probably you have some function bodies within .h file within class that uses incomplete type.
Make sure that within your .h for class window you have only function declaration. All function bodies for window must be in .cpp file. And for window_impl as well...
Btw, you have to explicitly add destructor declaration for windows class in your .h file.
But you CANNOT put empty dtor body in you header file:
class window {
virtual ~window() {};
}
Must be just a declaration:
class window {
virtual ~window();
}

To add to the other's replies about the custom deleter, in our internal "utilities library" I added a helper header to implement this common pattern (std::unique_ptr of an incomplete type, known only to some of the TU to e.g. avoid long compile times or to provide just an opaque handle to clients).
It provides the common scaffolding for this pattern: a custom deleter class that invokes an externally-defined deleter function, a type alias for a unique_ptr with this deleter class, and a macro to declare the deleter function in a TU that has a complete definition of the type. I think that this has some general usefulness, so here it is:
#ifndef CZU_UNIQUE_OPAQUE_HPP
#define CZU_UNIQUE_OPAQUE_HPP
#include <memory>
/**
Helper to define a `std::unique_ptr` that works just with a forward
declaration
The "regular" `std::unique_ptr<T>` requires the full definition of `T` to be
available, as it has to emit calls to `delete` in every TU that may use it.
A workaround to this problem is to have a `std::unique_ptr` with a custom
deleter, which is defined in a TU that knows the full definition of `T`.
This header standardizes and generalizes this trick. The usage is quite
simple:
- everywhere you would have used `std::unique_ptr<T>`, use
`czu::unique_opaque<T>`; it will work just fine with `T` being a forward
declaration;
- in a TU that knows the full definition of `T`, at top level invoke the
macro `CZU_DEFINE_OPAQUE_DELETER`; it will define the custom deleter used
by `czu::unique_opaque<T>`
*/
namespace czu {
template<typename T>
struct opaque_deleter {
void operator()(T *it) {
void opaque_deleter_hook(T *);
opaque_deleter_hook(it);
}
};
template<typename T>
using unique_opaque = std::unique_ptr<T, opaque_deleter<T>>;
}
/// Call at top level in a C++ file to enable type %T to be used in an %unique_opaque<T>
#define CZU_DEFINE_OPAQUE_DELETER(T) namespace czu { void opaque_deleter_hook(T *it) { delete it; } }
#endif

May be not a best solution, but sometimes you may use shared_ptr instead.
If course it's a bit an overkill, but... as for unique_ptr, I'll perhaps wait 10 years more until C++ standard makers will decide to use lambda as a deleter.
Another side.
Per your code it may happen, that on destruction stage window_impl will be incomplete. This could be a reason of undefined behaviour.
See this:
Why, really, deleting an incomplete type is undefined behaviour?
So, if possible I would define a very base object to all your objects, with virtual destructor. And you're almost good. You just should keep in mind that system will call virtual destructor for your pointer, so you should define it for every ancestor. You should also define base class in inheritance section as a virtual (see this for details).

Using extern template
The issue with using std::unique_ptr<T> where T is an incomplete type is that unique_ptr needs to be able to delete an instance of T for various operations. The class unique_ptr uses std::default_delete<T> to delete the instance. Hence, in an ideal world, we would just write
extern template class std::default_delete<T>;
to prevent std::default_delete<T> from being instantiated. Then, declaring
template class std::default_delete<T>;
at a place where T is complete, would instantiate the template.
The issue here is that default_delete actually defines inline methods that will not be instantiated. So, this idea does not work. We can, however, work around this problem.
First, let us define a deleter that does not inline the call operator.
/* --- opaque_ptr.hpp ------------------------------------------------------- */
#ifndef OPAQUE_PTR_HPP_
#define OPAQUE_PTR_HPP_
#include <memory>
template <typename T>
class opaque_delete {
public:
void operator() (T* ptr);
};
// Do not move this method into opaque_delete, or it will be inlined!
template <typename T>
void opaque_delete<T>::operator() (T* ptr) {
std::default_delete<T>()(ptr);
}
Furthermore, for ease of use, define a type opaque_ptr which combines unique_ptr with opaque_delete, and analogously to std::make_unique, we define make_opaque.
/* --- opaque_ptr.hpp cont. ------------------------------------------------- */
template <typename T>
using opaque_ptr = std::unique_ptr<T, opaque_delete<T>>;
template<typename T, typename... Args>
inline opaque_ptr<T> make_opaque(Args&&... args)
{
return opaque_ptr<T>(new T(std::forward<Args>(args)...));
}
#endif
The type opaque_delete can now be used with the extern template construction. Here is an example.
/* --- foo.hpp -------------------------------------------------------------- */
#ifndef FOO_HPP_
#define FOO_HPP_
#include "opaque_ptr.hpp"
class Foo {
public:
Foo(int n);
void print();
private:
struct Impl;
opaque_ptr<Impl> m_ptr;
};
// Do not instantiate opaque_delete.
extern template class opaque_delete<Foo::Impl>;
#endif
Since we prevent opaque_delete from being instantiated this code compiles without errors. To make the linker happy, we instantiate opaque_delete in our foo.cpp.
/* --- foo.cpp -------------------------------------------------------------- */
#include "foo.hpp"
#include <iostream>
struct Foo::Impl {
int n;
};
// Force instantiation of opaque_delete.
template class opaque_delete<Foo::Impl>;
The remaining methods could be implemented as follows.
/* --- foo.cpp cont. -------------------------------------------------------- */
Foo::Foo(int n)
: m_ptr(new Impl)
{
m_ptr->n = n;
}
void Foo::print() {
std::cout << "n = " << m_ptr->n << std::endl;
}
The advantage of this solution is that, once opaque_delete is defined, the required boilerplate code is rather small.

Related

include a class that has std::unique_ptr<T> as a field, while "T" is incomplete type [duplicate]

I'm using the pimpl-idiom with std::unique_ptr:
class window {
window(const rectangle& rect);
private:
class window_impl; // defined elsewhere
std::unique_ptr<window_impl> impl_; // won't compile
};
However, I get a compile error regarding the use of an incomplete type, on line 304 in <memory>:
Invalid application of 'sizeof' to an incomplete type 'uixx::window::window_impl'
For as far as I know, std::unique_ptr should be able to be used with an incomplete type. Is this a bug in libc++ or am I doing something wrong here?
Here are some examples of std::unique_ptr with incomplete types. The problem lies in destruction.
If you use pimpl with unique_ptr, you need to declare a destructor:
class foo
{
class impl;
std::unique_ptr<impl> impl_;
public:
foo(); // You may need a def. constructor to be defined elsewhere
~foo(); // Implement (with {}, or with = default;) where impl is complete
};
because otherwise the compiler generates a default one, and it needs a complete declaration of foo::impl for this.
If you have template constructors, then you're screwed, even if you don't construct the impl_ member:
template <typename T>
foo::foo(T bar)
{
// Here the compiler needs to know how to
// destroy impl_ in case an exception is
// thrown !
}
At namespace scope, using unique_ptr will not work either:
class impl;
std::unique_ptr<impl> impl_;
since the compiler must know here how to destroy this static duration object. A workaround is:
class impl;
struct ptr_impl : std::unique_ptr<impl>
{
~ptr_impl(); // Implement (empty body) elsewhere
} impl_;
As Alexandre C. mentioned, the problem comes down to window's destructor being implicitly defined in places where the type of window_impl is still incomplete. In addition to his solutions, another workaround that I've used is to declare a Deleter functor in the header:
// Foo.h
class FooImpl;
struct FooImplDeleter
{
void operator()(FooImpl *p);
};
class Foo
{
...
private:
std::unique_ptr<FooImpl, FooImplDeleter> impl_;
};
// Foo.cpp
...
void FooImplDeleter::operator()(FooImpl *p)
{
delete p;
}
Note that using a custom Deleter function precludes the use of std::make_unique (available from C++14), as already discussed here.
use a custom deleter
The problem is that unique_ptr<T> must call the destructor T::~T() in its own destructor, its move assignment operator, and unique_ptr::reset() member function (only). However, these must be called (implicitly or explicitly) in several PIMPL situations (already in the outer class's destructor and move assignment operator).
As already pointed out in another answer, one way to avoid that is to move all operations that require unique_ptr::~unique_ptr(), unique_ptr::operator=(unique_ptr&&), and unique_ptr::reset() into the source file where the pimpl helper class is actually defined.
However, this is rather inconvenient and defies the very point of the pimpl idoim to some degree. A much cleaner solution that avoids all that is to use a custom deleter and only move its definition into the source file where the pimple helper class lives. Here is a simple example:
// file.h
class foo
{
struct pimpl;
struct pimpl_deleter { void operator()(pimpl*) const; };
std::unique_ptr<pimpl,pimpl_deleter> m_pimpl;
public:
foo(some data);
foo(foo&&) = default; // no need to define this in file.cc
foo&operator=(foo&&) = default; // no need to define this in file.cc
//foo::~foo() auto-generated: no need to define this in file.cc
};
// file.cc
struct foo::pimpl
{
// lots of complicated code
};
void foo::pimpl_deleter::operator()(foo::pimpl*ptr) const { delete ptr; }
Instead of a separate deleter class, you can also use a free function or static member of foo:
class foo {
struct pimpl;
static void delete_pimpl(pimpl*);
using deleter = void(&)(pimpl*);
std::unique_ptr<pimpl,deleter> m_pimpl;
public:
foo(some data);
};
Probably you have some function bodies within .h file within class that uses incomplete type.
Make sure that within your .h for class window you have only function declaration. All function bodies for window must be in .cpp file. And for window_impl as well...
Btw, you have to explicitly add destructor declaration for windows class in your .h file.
But you CANNOT put empty dtor body in you header file:
class window {
virtual ~window() {};
}
Must be just a declaration:
class window {
virtual ~window();
}
To add to the other's replies about the custom deleter, in our internal "utilities library" I added a helper header to implement this common pattern (std::unique_ptr of an incomplete type, known only to some of the TU to e.g. avoid long compile times or to provide just an opaque handle to clients).
It provides the common scaffolding for this pattern: a custom deleter class that invokes an externally-defined deleter function, a type alias for a unique_ptr with this deleter class, and a macro to declare the deleter function in a TU that has a complete definition of the type. I think that this has some general usefulness, so here it is:
#ifndef CZU_UNIQUE_OPAQUE_HPP
#define CZU_UNIQUE_OPAQUE_HPP
#include <memory>
/**
Helper to define a `std::unique_ptr` that works just with a forward
declaration
The "regular" `std::unique_ptr<T>` requires the full definition of `T` to be
available, as it has to emit calls to `delete` in every TU that may use it.
A workaround to this problem is to have a `std::unique_ptr` with a custom
deleter, which is defined in a TU that knows the full definition of `T`.
This header standardizes and generalizes this trick. The usage is quite
simple:
- everywhere you would have used `std::unique_ptr<T>`, use
`czu::unique_opaque<T>`; it will work just fine with `T` being a forward
declaration;
- in a TU that knows the full definition of `T`, at top level invoke the
macro `CZU_DEFINE_OPAQUE_DELETER`; it will define the custom deleter used
by `czu::unique_opaque<T>`
*/
namespace czu {
template<typename T>
struct opaque_deleter {
void operator()(T *it) {
void opaque_deleter_hook(T *);
opaque_deleter_hook(it);
}
};
template<typename T>
using unique_opaque = std::unique_ptr<T, opaque_deleter<T>>;
}
/// Call at top level in a C++ file to enable type %T to be used in an %unique_opaque<T>
#define CZU_DEFINE_OPAQUE_DELETER(T) namespace czu { void opaque_deleter_hook(T *it) { delete it; } }
#endif
May be not a best solution, but sometimes you may use shared_ptr instead.
If course it's a bit an overkill, but... as for unique_ptr, I'll perhaps wait 10 years more until C++ standard makers will decide to use lambda as a deleter.
Another side.
Per your code it may happen, that on destruction stage window_impl will be incomplete. This could be a reason of undefined behaviour.
See this:
Why, really, deleting an incomplete type is undefined behaviour?
So, if possible I would define a very base object to all your objects, with virtual destructor. And you're almost good. You just should keep in mind that system will call virtual destructor for your pointer, so you should define it for every ancestor. You should also define base class in inheritance section as a virtual (see this for details).
Using extern template
The issue with using std::unique_ptr<T> where T is an incomplete type is that unique_ptr needs to be able to delete an instance of T for various operations. The class unique_ptr uses std::default_delete<T> to delete the instance. Hence, in an ideal world, we would just write
extern template class std::default_delete<T>;
to prevent std::default_delete<T> from being instantiated. Then, declaring
template class std::default_delete<T>;
at a place where T is complete, would instantiate the template.
The issue here is that default_delete actually defines inline methods that will not be instantiated. So, this idea does not work. We can, however, work around this problem.
First, let us define a deleter that does not inline the call operator.
/* --- opaque_ptr.hpp ------------------------------------------------------- */
#ifndef OPAQUE_PTR_HPP_
#define OPAQUE_PTR_HPP_
#include <memory>
template <typename T>
class opaque_delete {
public:
void operator() (T* ptr);
};
// Do not move this method into opaque_delete, or it will be inlined!
template <typename T>
void opaque_delete<T>::operator() (T* ptr) {
std::default_delete<T>()(ptr);
}
Furthermore, for ease of use, define a type opaque_ptr which combines unique_ptr with opaque_delete, and analogously to std::make_unique, we define make_opaque.
/* --- opaque_ptr.hpp cont. ------------------------------------------------- */
template <typename T>
using opaque_ptr = std::unique_ptr<T, opaque_delete<T>>;
template<typename T, typename... Args>
inline opaque_ptr<T> make_opaque(Args&&... args)
{
return opaque_ptr<T>(new T(std::forward<Args>(args)...));
}
#endif
The type opaque_delete can now be used with the extern template construction. Here is an example.
/* --- foo.hpp -------------------------------------------------------------- */
#ifndef FOO_HPP_
#define FOO_HPP_
#include "opaque_ptr.hpp"
class Foo {
public:
Foo(int n);
void print();
private:
struct Impl;
opaque_ptr<Impl> m_ptr;
};
// Do not instantiate opaque_delete.
extern template class opaque_delete<Foo::Impl>;
#endif
Since we prevent opaque_delete from being instantiated this code compiles without errors. To make the linker happy, we instantiate opaque_delete in our foo.cpp.
/* --- foo.cpp -------------------------------------------------------------- */
#include "foo.hpp"
#include <iostream>
struct Foo::Impl {
int n;
};
// Force instantiation of opaque_delete.
template class opaque_delete<Foo::Impl>;
The remaining methods could be implemented as follows.
/* --- foo.cpp cont. -------------------------------------------------------- */
Foo::Foo(int n)
: m_ptr(new Impl)
{
m_ptr->n = n;
}
void Foo::print() {
std::cout << "n = " << m_ptr->n << std::endl;
}
The advantage of this solution is that, once opaque_delete is defined, the required boilerplate code is rather small.

Why is this type incomplete when using the PIMPL idiom?

I'm using the PIMPL idiom, and specifically I'm using the template provided from this post. Given the set of classes below and compiling with VS2015 Update 3, I'm getting compile errors:
Error C2027 use of undefined type 'C::C_impl' (compiling source file src\A.cpp)
Error C2338 can't delete an incomplete type (compiling source file src\A.cpp)
Warning C4150 deletion of pointer to incomplete type 'C::C_impl'; no destructor called (compiling source file src\A.cpp)
I can resolve this by uncommenting C::~C(), which leads me to believe that something is preventing ~C() from being automatically generated but I don't understand what. According to this reference, the destructor for type T is implicitly defined as deleted if any of the following is true:
T has a non-static data member that cannot be destructed (has deleted or inaccessible destructor)
T has direct or virtual base class that cannot be destructed (has deleted or inaccessible destructors)
T is a union and has a variant member with non-trivial destructor.
The implicitly-declared destructor is virtual (because the base class has a virtual destructor) and the lookup for the deallocation function (operator delete() results in a call to ambiguous, deleted, or inaccessible function.
Items #2, 3, and 4 obviously do not apply to C, and I don't believe that #1 applies because pimpl<> (C's only member) defines a destructor explicitly.
Can someone please explain what's going on?
A.h
#pragma once
#include <Pimpl.h>
class A
{
private:
struct A_impl;
pimpl<A_impl> m_pimpl;
};
B.h
#pragma once
#include "C.h"
class B
{
private:
C m_C;
};
C.h
#pragma once
#include <Pimpl.h>
class C
{
public:
// Needed for the PIMPL pattern
//~C();
private:
struct C_impl;
pimpl<C_impl> m_pimpl;
};
A.cpp
#include <memory>
#include "A.h"
#include "B.h"
#include <PimplImpl.h>
struct A::A_impl
{
std::unique_ptr<B> m_pB;
};
// Ensure all the code for the template is compiled
template class pimpl<A::A_impl>;
C.cpp
#include <C.h>
#include <PimplImpl.h>
struct C::C_impl { };
// Needed for the PIMPL pattern
//C::~C() = default;
// Ensure all the code for the template is compiled
template class pimpl<C::C_impl>;
For completeness, the PIMPL implementation from the post referenced above:
pimpl.h
#pragma once
#include <memory>
template<typename T>
class pimpl
{
private:
std::unique_ptr<T> m;
public:
pimpl();
template<typename ...Args> pimpl(Args&& ...);
~pimpl();
T* operator->();
T& operator*();
};
PimplImpl.h
#pragma once
#include <utility>
template<typename T>
pimpl<T>::pimpl() : m{ new T{} } {}
template<typename T>
template<typename ...Args>
pimpl<T>::pimpl(Args&& ...args)
: m{ new T{ std::forward<Args>(args)... } }
{
}
template<typename T>
pimpl<T>::~pimpl() {}
template<typename T>
T* pimpl<T>::operator->() { return m.get(); }
template<typename T>
T& pimpl<T>::operator*() { return *m.get(); }
A few notes about the code above:
I'm trying to expose A and C to consumers of my library and keep B internal.
There is no B.cpp here, it would be empy.
You have to define the C destructor manually after definition C::C_impl because for default compiler tries to generate C destructor in point of usage, but it can be point where C::C_impl definition can not be found (for example, it can be B.cpp).
I believe the problem is that std::unique_ptr requires knowing the destruction function (ie, the destructor) at time of instantiation.
With the default destructor ~C() the compiler generates it at point of usage, which means that it is trying to delete the pimpl<C_impl> object with the information available to it in A.cpp. Of course, since C_impl is only declared at that point the compiler does not know how to destroy a C_impl object and that is the error you receive.
Uncommenting ~C(); tells the compiler not to worry about how to destroy a C_impl, that will be defined somewhere else. In your case that is defined in C.cpp where the definition of C_impl is known.
In response to your edit, the destructor for pimpl<C_impl> has std::unique_ptr<C_impl> which has a non-static data member with inaccessible destructor (C_impl is an incomplete type at point of usage withing A.cpp).

What is the virtual function inside of shared_ptr's Control Block?

I've read an "Item" about shared_ptr in Scott Meyers' book "Effective Modern C++" where he says the following:
The usual control block implementation is more
sophisticated than you might expect. It makes use of inheritance, and there’s even a virtual function. (It’s used to ensure that the pointed-to object is properly destroyed.)
That means that using std::shared_ptrs also incurs the cost of the machinery for the virtual function used by the control block.
Then he doesn't explain what a virtual function does exactly. As far as I know, the proper way of deleting a pointed object is using deleters or type erasure. So, please explain what this is about.
The virtual function is required to ensure the object being shared is appropriately deleted. Unlike a unique_ptr, shared_ptr does not require full knowledge of the type when its template is instantiated. E.g. you can do this:
class Foo;
std::shared_ptr<Foo> foo = make_foo();
Note that in the code above we don't have the complete Foo type, just the forward declaration. If we let foo go out of scope, the object it is pointing to will be correctly deleted because when Foo was created in make_foo, a deleter was also created which knows the complete type of Foo, and hence can call the appropriate destructors. (E.g. Perhaps make_foo creates a Bar that inherits from Foo and returns that. shared_ptr's will handle this fine.)
The function on the deleter object that shared_ptr creates to manage the deletion of Foo will be virtual, allowing shared_ptr to call the correct destructor.
Roughly this could be something like this:
struct deleter_interface {
virtual void ~deleter_interface = default;
virtual void dispose() = 0;
};
template <typename T>
struct deleter : deleter_interface {
T* ptr_;
deleter(T* ptr) : ptr_(ptr) {}
virtual void dispose() { delete ptr_; }
};
template <typename T>
shared_ptr {
T* ptr_;
deleter_interface* deleter_;
...
};
template <typename T>
shared_ptr<T>::shared_ptr<T>(T* ptr)
: ptr_(ptr), deleter_(new deleter<T>(ptr)) {}
template <typename T>
shared_ptr<T>::~shared_ptr<T>() { deleter_->dispose(); delete deleter_; }
While this seems more complicated that is strictly necessary, it is to allow shared_ptr to be used without the complete type. For example what if you wanted to do this:
In a.h:
struct Foo;
std::shared_ptr<Foo> a = make_object();
// ... let a go out of scope
And in a.cc:
struct Foo { ... };
struct Bar : Foo { ... };
std::shared_ptr<Foo> make_object() { return std::shared_ptr<Foo>(new Bar); }
If we didn't have the virtual function used in the deleter code, then Bar would not be destructed correctly. With the virtual function it doesn't matter that the header (a.h) never sees the definition of Foo or Bar.

How to make a function run once at early time of the program?

As a static class member variable, it will be instantiated at the early time of the program. How to make this happens on a function? My example is that I have a factory class, which need register types before using it. And I'd like the registration happens earlier than I use it to create an object.
Typically we shall use the constructor of a "registration class" type to do this.
The "trick" is to recall that, when you initialise a file-static object you are — albeit indirectly — calling a function. It's the constructor for that object. You can use that.
registration.h
template <typename T>
class Registration
{
Registration();
};
#include <registration.ipp>
registration.ipp
template <typename T>
Registration::Registration()
{
//!! Do your work with `T` here.
}
myClass.h
class MyClass
{
public:
MyClass();
};
myClass.cpp
#include "myClass.h"
#include "registration.h"
// Static; instantiated once, before `main` runs
Registration<MyClass> reg;
MyClass::MyClass() {}
// ...

Hide implementation by using a pointer (Pimpl idiom)

Is it somehow possible, to accomplish the following:
x.hpp - this file is included by many other classes
class x_impl; //forward declare
class x {
public:
//methods...
private:
x_impl* impl_;
};
x.cpp - the implementation
#include <conrete_x>
typedef concrete_x x_impl; //obviously this doesn't work
//implementation of methods...
So basically, I want the users to include the file x.hpp, but be unaware of the conrete_x.hpp header.
Since I can use concrete_x only by a pointer and it appears only as a private data member, a forward declaration should be enough for the compiler to know how much space to prepare for it. It looks quite like the well-known "pimpl idiom".
Can you help me with this?
PS. I don't want to use a void* and cast it around..
Actually, it's even possible to completely hide from the user:
// Foo.hpp
class Foo {
public:
//...
private:
struct Impl;
Impl* _impl;
};
// Foo.cpp
struct Foo::Impl {
// stuff
};
I would just like to remind you that:
you will need to write a proper destructor
and thus you will also need a proper copy constructor, copy assignment operator, move constructor and move assignment operator
There are ways to automate PIMPL, at the cost of some black magic (similar to what std::shared_ptr does).
As an alternative to the answer from #Angew, if the name concrete_x should not be made known to users of class x, you could do this:
in x.hpp
class x_impl;
class x {
public:
x();
~x();
//methods...
private:
x_impl* impl_;
};
in x.cpp
#include <concrete_x>
class x_impl : public concrete_x { };
x:x() : impl_(new x_impl) {}
x:~x() { delete impl_; }
This will only work when the forward declaration declares the actual name of the class. So either change x.hpp to:
class concrete_x;
class x {
public:
//methods...
private:
concrete_x* impl_;
};
or use the name x_impl for the class defined in the header <concrete_x>.
That's what interfaces are for. Define an interface (pure virtual class) in your shared header file and give it to users. Inherit your concrete class from the interface and put it in the non-shared header file. Implement the concrete class in the cpp file (you can even define the concrete class inside the cpp).