The most occuring number in structure(array) - c++

Question

I cant find out whats wrong with this part of my program, i want to find out most occuring number in my structure(array), but it finds only the last number :/
void Daugiausiai(int n)
{
int max = 0;
int sk;
for(int i = 0; i < n; i++){
int kiek = 0;
for(int j=0; j < n; j++){
if(A[i].datamet == A[j].datamet){
kiek++;
if(kiek > max){
max = kiek;
sk = A[i].datamet;
}
}
}
}
}
ps. its only a part of my code

Answer 1

You haven't shown us enough of your code, but it is likely that you are not looking at the real result of your function. The result, sk is local to the function and you don't return it. If you have global variable that is also named sk, it will not be touched by Daugiausiai.
In the same way, you pass the number of elements in your struct array, but work on a global struct. It is good practice to "encapsulate" functions so that they receive the data they work on as arguments and return a result. Your function should therefore pass both array length and array and return the result.
(Such an encapsulation doesn't work in all cases, but here, it has the benefit that you can use the same function for many different arrays of the same structure tape.)
It is also enough to test whether the current number of elements is more than the maximum so far after your counting loop.
Putting all this together:
struct Data {
int datamet;
};
int Daugiausiai(const struct Data A[], int n)
{
int max = 0;
int sk;
for (int i = 0; i < n; i++){
int kiek = 0;
// Count occurrences
for(int j = 0; j < n; j++){
if(A[i].datamet == A[j].datamet) kiek++;
}
// Check for maximum
if (kiek > max) {
max = kiek;
sk = A[i].datamet;
}
}
return sk;
}
And you call it like this:
struct Data A[6] = {{1}, {2}, {1}, {4}, {1}, {2}};
int n = Daugiausiai(A, 6);
printf("%d\n", n); // 1

Answer 2

It would be nice if you had english variable names, so I could read them a bit better ^^. What should your paramter n do? Is that the array-length? And what should yout funtion do? It has no return value or something.
int getMostOccuring(int array[], int length)
{
int current_number;
int current_count = 0;
int most_occuring_number;
int most_occuring_count = 0;
for (int i = 0; i < length; i++)
{
current_number = array[i];
current_count = 0;
for (int j = i; j < length; j++)
{
int test_number = array[j];
if (test_number == current_number)
{
current_count ++;
if (current_count > most_occuring_count)
{
most_occuring_number = current_number;
most_occuring_count = current_count;
}
}
}
}
return most_occuring_number;
}
this should work and return the most occuring number in the given array (it has a bad runtime, but is very simple and good to understand).