Regular expression, get the rest of the text aswell - regex

I have a text file, a regular expression that looks in that file and gets the things I want. I also write this new information into a new file, however not everything is written to the new file! The file that my regex reads from looks like this:
"This is my text, it contains of 53 or so words file. That is a very
good number. However 80 is a better number. Hopefully I can write more
words soon enough. Hopefully very very soon "
What is written to the new text file is:
"This is my text, it contains of 53 or so words file. That is a very
good number. However 80 is a better number. Hopefully I can write more
words"
I want everything to be written. Any ideas?

Without the regex you were using, it's impossible to say.
I would hazard a guess though, that what you need to do is stick .*$ on the end of the capture group, in order to grab the rest of the text on the line.

^[\s\S]*$
should do it for you.

Related

How combine regex and find in shell script properly

I am trying to write a shell script which can take numbers from a text document and use these numbers to search for all pictures that include the numbers in their name.
I am working with find and it I got it to kinda work. If the name of the picture is exactly the same as the name in the text document, or if the name of the picture ends with whatever number is written in the text document it works. But if the number is in the middle of the name of the picture, it doesn't find it. So I have been trying to add regex to my find command but I haven't been successful.
input="/Users/unix/Desktop/pictures.txt"
input_2="/Users/unix/Desktop/2019/05/23"
while IFS= read -r -u3 line
do
find "$input_2" -iregex ".*${line}*.jpg"
done 3< "$input"
For example if the picture name is Right.jpg and my pictures.txt contains Right, it will find the file. If the picture is called leftRight.jpg, it will also find the File. But if it's something like leftRightleft.jpg, it won't find the picture, so I am a bit confused on how to use regex properly here.
Your regex is simply incorrect. If you break it down, it makes intuitive sense why:
.*${line}*.jpg
means:
.* -- any character repeated 0 or more times
${line}* -- the contents of ${line}, with the last character repeated 0 or more times
. -- any single character
jpg -- the literal characters jpg
So with your example, if you have Right in your file, you'd match actual files like these, which you probably don't want to match:
leftRigh.jpg
leftRighXjpg
leftRighttttttttt.jpg
leftRighttttttttttttttttttttttttttttttttjpg
What you probably want is:
.*${line}.*\.jpg

PowerShell isolating parts of strings

I have no experience with regular expressions and would love some help and suggestions on a possible solution to deleting parts of file names contained in a csv file.
Problem:
A list of exported file names contains a random unique identifier that I need isolated. The unique identifier has no predictable pattern, however the aspects which need removing do. Each file name ends with one of the following variations:
V, -V, or %20V followed by a random number sequence with possible spaces, additional "-","" and ending with .PDF
examples:
GTD-LVOE-43-0021 V10 0.PDF
GTD-LVOE-43-0021-V34-2.PDF
GTD-LVOE-43-0021_V02_9.PDF
GTD-LVOE-43-0021 V49.9.PDF
Solution:
My plan was to write a script to select of the first occurrence of a V from the end of the string and then delete it and everything to the right of it. Then the file names can be cleaned up by deleting any "-" or "_" and white space that occurs at the end of a string.
Question:
How can I do this with a regular expression and is my line of thinking even close to the right approach to solving this?
REGEX: [\s\-_]V.*?\.PDF
Might do the trick. You'd still need to replace away any leading - and _, but it should get you down the path, hopefully.
This would read as follows..
start with a whitespace, - OR _ followed by a V. Then take everything until you get to the first .PDF

RegEx for VB.net

I have a txt file with content
$NETS
P3V3_AUX_LGATE; PQ6.8 PU37.2
U335_PIN1; R3328.1 U335.1
$END
need to be updated in this format, and save back to another txt file
$NETS
'P3V3_AUX_LGATE'; PQ6.8 PU37.2
'U335_PIN1'; R3328.1 U335.1
$END
NOTE: number of lines may go up to 10,000 lines
My current solution is to read the txt file line by line, detect the presence of the ";" and newline character and do the changes.
Right now i have a variable that holds ALL the lines, is there other way something like Replace via RegEx to do the changes without looping thru each line, this way i can readily print the result
and follow up question, which one is more efficient?
Try
ResultString = Regex.Replace(SubjectString, "^([^;\r\n]+);", "'$1';", RegexOptions.Multiline)
on your multiline string.
This will find any string (length one or more) at the start of a line up until the first semicolon if there is one and replace it with its quoted equivalent.
It should be more efficient than looping through the string line by line as you're doing now, but if you're in doubt, you'd have to profile it.
You could probably find all the matches using something like \w+; but I don't know how you'd be able to do a replace on that using Regex.Replace to add the 's but keep the original match.
However, if you already have it as one variable, you don't have to read the file again, either you could make your code find all ;s and then find the previous newline for each, or you could use a String.Split on newlines to split the variable you've already got into lines.
And if you want to get it back to one variable you can just use String.Join.
Personally I'd normally use the String.Split (and possibly the String.Join if needed) method, since I think that would make the code easy to read.
I would say Yes! this can be done with Regular expressions. Make sure you got the "multiline" option turned on and craft your regular expression using some capture groups to ease the work.
I can however say this will NOT be the optimal one. Since you mention the amount of lines you could be processing, it seems 'resource wise' smarter to use a streaming approach instead of the in memory approach.
Taking the Regex approach (and this took 15 mins so please don't think this is an optimal solution, just prove it would work)
private static Regex matcher = new Regex(#"^\$NETS\r\n(?<entrytitle>.[^;]*);\s*(?<entryrest>.*)\r\n(?<entrytitle2>.[^;]*);\s*(?<entryrest2>.*)\r\n\$END\r\n", RegexOptions.Compiled | RegexOptions.Multiline);
static void Main(string[] args)
{
string newString = matcher.Replace(ExampleFileContent, new MatchEvaluator(evaluator));
}
static string evaluator(Match m)
{
return String.Format("$NETS\r\n'{0}'; {1}\r\n'{2}'; {3}\r\n$END\r\n",
m.Groups["entrytitle"].Value,
m.Groups["entryrest"].Value,
m.Groups["entrytitle2"].Value,
m.Groups["entryrest2"].Value);
}
Hope this helps,

Find Lines with N occurrences of a char

I have a txt file that I’m trying to import as flat file into SQL2008 that looks like this:
“123456”,”some text”
“543210”,”some more text”
“111223”,”other text”
etc…
The file has more than 300.000 rows and the text is large (usually 200-500 chars), so scanning the file by hand is very time consuming and prone to error. Other similar (and even more complex files) were successfully imported.
The problem with this one, is that “some lines” contain quotes in the text… (this came from an export from an old SuperBase DB that didn’t let you specify a text quantifier, there’s nothing I can do with the file other than clear it and try to import it).
So the “offending” lines look like this:
“123456”,”this text “contains” a quote”
“543210”,”And the “above” text is bad”
etc…
You can see the problem here.
Now, 300.000 is not too much if I could perform a search using a text editor that can use regex, I’d manually remove the quotes from each line. The problem is not the number of offending lines, but the impossibility to find them with a simple search. I’m sure there are less than 500, but spread those in a 300.000 lines txt file and you know what I mean.
Based upon that, what would be the best regex I could use to identify these lines?
My first thought is: Tell me which lines contain more than 4 quotes (“).
But I couldn’t come up with anything (I’m not good at Regex beyond the basics).
this pattern ^("[^"]+){4,} will match "lines containing more than 4 quotes"
you can experiment with replacing 4 with 5 or more, depending on your data.
I think that you can be more direct with a Regex than you're planning to be. Depending on your dialect of Regex, something like this should do it:
^"\d+",".*".*"
You could also use a regex to remove the outside quotes and use a better delimeter instead. For example, search for ^"([0-9]+)","(.*)"$ and replace it with \1+++++DELIM+++++\2.
Of course, this doesn't directly answer your question, but it might solve the problem.

Use cases for regular expression find/replace

I recently discussed editors with a co-worker. He uses one of the less popular editors and I use another (I won't say which ones since it's not relevant and I want to avoid an editor flame war). I was saying that I didn't like his editor as much because it doesn't let you do find/replace with regular expressions.
He said he's never wanted to do that, which was surprising since it's something I find myself doing all the time. However, off the top of my head I wasn't able to come up with more than one or two examples. Can anyone here offer some examples of times when they've found regex find/replace useful in their editor? Here's what I've been able to come up with since then as examples of things that I've actually had to do:
Strip the beginning of a line off of every line in a file that looks like:
Line 25634 :
Line 632157 :
Taking a few dozen files with a standard header which is slightly different for each file and stripping the first 19 lines from all of them all at once.
Piping the result of a MySQL select statement into a text file, then removing all of the formatting junk and reformatting it as a Python dictionary for use in a simple script.
In a CSV file with no escaped commas, replace the first character of the 8th column of each row with a capital A.
Given a bunch of GDB stack traces with lines like
#3 0x080a6d61 in _mvl_set_req_done (req=0x82624a4, result=27158) at ../../mvl/src/mvl_serv.c:850
strip out everything from each line except the function names.
Does anyone else have any real-life examples? The next time this comes up, I'd like to be more prepared to list good examples of why this feature is useful.
Just last week, I used regex find/replace to convert a CSV file to an XML file.
Simple enough to do really, just chop up each field (luckily it didn't have any escaped commas) and push it back out with the appropriate tags in place of the commas.
Regex make it easy to replace whole words using word boundaries.
(\b\w+\b)
So you can replace unwanted words in your file without disturbing words like Scunthorpe
Yesterday I took a create table statement I made for an Oracle table and converted the fields to setString() method calls using JDBC and PreparedStatements. The table's field names were mapped to my class properties, so regex search and replace was the perfect fit.
Create Table text:
...
field_1 VARCHAR2(100) NULL,
field_2 VARCHAR2(10) NULL,
field_3 NUMBER(8) NULL,
field_4 VARCHAR2(100) NULL,
....
My Regex Search:
/([a-z_])+ .*?,?/
My Replacement:
pstmt.setString(1, \1);
The result:
...
pstmt.setString(1, field_1);
pstmt.setString(1, field_2);
pstmt.setString(1, field_3);
pstmt.setString(1, field_4);
....
I then went through and manually set the position int for each call and changed the method to setInt() (and others) where necessary, but that worked handy for me. I actually used it three or four times for similar field to method call conversions.
I like to use regexps to reformat lists of items like this:
int item1
double item2
to
public void item1(int item1){
}
public void item2(double item2){
}
This can be a big time saver.
I use it all the time when someone sends me a list of patient visit numbers in a column (say 100-200) and I need them in a '0000000444','000000004445' format. works wonders for me!
I also use it to pull out email addresses in an email. I send out group emails often and all the bounced returns come back in one email. So, I regex to pull them all out and then drop them into a string var to remove from the database.
I even wrote a little dialog prog to apply regex to my clipboard. It grabs the contents applies the regex and then loads it back into the clipboard.
One thing I use it for in web development all the time is stripping some text of its HTML tags. This might need to be done to sanitize user input for security, or for displaying a preview of a news article. For example, if you have an article with lots of HTML tags for formatting, you can't just do LEFT(article_text,100) + '...' (plus a "read more" link) and render that on a page at the risk of breaking the page by splitting apart an HTML tag.
Also, I've had to strip img tags in database records that link to images that no longer exist. And let's not forget web form validation. If you want to make a user has entered a correct email address (syntactically speaking) into a web form this is about the only way of checking it thoroughly.
I've just pasted a long character sequence into a string literal, and now I want to break it up into a concatenation of shorter string literals so it doesn't wrap. I also want it to be readable, so I want to break only after spaces. I select the whole string (minus the quotation marks) and do an in-selection-only replace-all with this regex:
/.{20,60} /
...and this replacement:
/$0"¶ + "/
...where the pilcrow is an actual newline, and the number of spaces varies from one incident to the next. Result:
String s = "I recently discussed editors with a co-worker. He uses one "
+ "of the less popular editors and I use another (I won't say "
+ "which ones since it's not relevant and I want to avoid an "
+ "editor flame war). I was saying that I didn't like his "
+ "editor as much because it doesn't let you do find/replace "
+ "with regular expressions.";
The first thing I do with any editor is try to figure out it's Regex oddities. I use it all the time. Nothing really crazy, but it's handy when you've got to copy/paste stuff between different types of text - SQL <-> PHP is the one I do most often - and you don't want to fart around making the same change 500 times.
Regex is very handy any time I am trying to replace a value that spans multiple lines. Or when I want to replace a value with something that contains a line break.
I also like that you can match things in a regular expression and not replace the full match using the $# syntax to output the portion of the match you want to maintain.
I agree with you on points 3, 4, and 5 but not necessarily points 1 and 2.
In some cases 1 and 2 are easier to achieve using a anonymous keyboard macro.
By this I mean doing the following:
Position the cursor on the first line
Start a keyboard macro recording
Modify the first line
Position the cursor on the next line
Stop record.
Now all that is needed to modify the next line is to repeat the macro.
I could live with out support for regex but could not live without anonymous keyboard macros.