I am trying to autogenerate a file using cmm script for Lauterbach. Here is what I want to show up in the file:
{ "source": "XYZ" } // quotes included
However I cannot get the cmm script to accept the quotes. Using "\" doesnt work either. Is there a way to handle this in CMM scripts?
In PRACTICE (CMM scripts) double-quotes are escaped with double-quotes.
So this should work:
OPEN #1 "myfile.log" /Create
WRITE #1 "{ ""source"": ""XYZ"" }"
CLOSE #1
Related
I am not that good at bash scripting. I have a requirement to extract a substring between two words of a string. I tried different ways. Could some one help me pls?
This is my text "RegionName": "eu-west-1", "LatestAmiId": "ami-0ebfeadd9ccacfbb2",
Remember the the quotes and comma are the part of String. I need to extract the AMI ID alone, Means text between "LatestAmiId": " and ",
Any help pls?
Assuming you have this string stored in a variable name input_text you can get the AmiId using sed like this
ami_id=$(echo "$input_text" | sed -e 's/.*LatestAmiId": "//' -e 's/",$//')
this uses two different sed scripts:
s/.*LatestAmiId": "// replaces all text up to and including LatestAmiId": " with nothing
s/",$// replaces the ", at the end of the line with nothing
As I mentioned in comments, jq is a tool that I have found really helpful when working with JSON objects in bash scripts. Since your input string looks like a section out of a json response from an AWS api, I highly recommend using a json tool rather than a regex to extract this information.
I'm trying to write a bash function that would escape all double quotes within single quotes, eg:
'I need to escape "these" quotes with backslashes'
would become
'I need to escape \"these\" quotes with backslashes'
My take on it was:
Find pairs of single quotes in the input and extract them with grep
Pipe into sed, escape double quotes
Sed again the whole input and replace grep match with sedded match
I managed to get it working to the part of having correctly escaped quotes section, but replacing it in the whole input fails.
The script code copypaste:
# $1 - Full name, $2 - minified name
adjust_quotes ()
{
SINGLE_QUOTES=`grep -Eo "'.*'" $2`
ESCAPED_QUOTES=`echo $SINGLE_QUOTES | sed 's|"|\\\\"|g'`
sed -r "s|'.*'|$ESCAPED_QUOTES|g" "$2" > "$2.escaped"
mv "$2.escaped" $2
echo "Quotes escaped within single quotes on $2"
}
Random additional questions:
In the console, escaping the quote with only two backslashes works, but when code is put in the script - I need four. I'd love to know
Could I modify this code into a loop to escape all pairs of single quotes, one after another until EOF?
Thanks!
P.S. I know this would probably be easier to do in eg. python, but I really need to keep it in bash.
Using BASH string replacement:
s='I need to escape "these" quotes with backslashes'
r="${s//\"/\\\"}"
echo "$r"
I need to escape \"these\" quotes with backslashes
Here's a pure bash solution, which does the transformation on stdin, printing to stdout. It reads the entire input into memory, so it won't work with really enormous files.
escape_enclosed_quotes() (
IFS=\'
read -d '' -r -a fields
for ((i=1; i<${#fields[#]}; i+=2)); do
fields[i]=${fields[i]//\"/\\\"}
done
printf %s "${fields[*]}"
)
I deliberately enclosed the body of the function in parentheses rather than braces, in order to force the body to run in a subshell. That limits the modification of IFS to the body, as well as implicitly making the variables used local.
The function uses the read builtin to read the entire input (since the line delimiter is set to NUL with -d '') into an array (-a) using a single quote as the field separator (IFS=\'). The result is that the parts of the input surrounded with single quotes are in the odd positions of the array, so the function loops over the odd indices to do the substitution only for those fields. I use bash's find-and-replace syntax instead of deferring to an external utility like sed.
This being bash, there are a couple of gotchas:
If the file contains a NUL, the rest of the file will be ignored.
If the last line of the file does not end with a newline, and the last character of that line is a single quote, it will not be output.
Both of the above conditions are impossible in a portable text file, so it's probably OK. All the same, worth taking note.
The supplementary question: why are the extra backslashes needed in
ESCAPED_QUOTES=`echo $SINGLE_QUOTES | sed 's|"|\\\\"|g'`
Answer: It has nothing to do with that line being in a script. It has to do with your use of backticks (...) for command substitution, and the idiosyncratic and often unpredictable handling of backslashes inside backticks. This syntax is deprecated. Do not use it. (Not even if you see someone else using it in some random example on the internet.) If you had used the recommended $(...) syntax for command substitution, it would have worked as expected:
ESCAPED_QUOTES=$(echo $SINGLE_QUOTES | sed 's|"|\\"|g')
(More information is in the Bash FAQ linked above.)
What I want to achieve:
Suppose I have a file file with the following content:
ENV_VAR='/foo/`whoami`/bar/'
sh my_script.sh 'LOL'
I want to replace - using sed - the single quotes that surrounds the directory names, but not the ones that surrounds stuff that does not seem like a directory, for example, the arguments of a script.
That is, after running the sed command, I would expect the following output:
ENV_VAR="/foo/`whoami`/bar/"
sh my_script.sh 'LOL'
The idea is to make this happen without using tr to replace ' with ", nor sed like s/'/"/g, as I don't want to replace the lines that does not seem to be directories.
Please note that sed is running on AIX, so no GNU sed is available.
What I have tried:
If I use sed like this:
sed "s;'=.*/.*';&;g" file
... the & variable hold the regex previously matched, that is: ='/foo/`whoami`/bar/'. However, I can't figure out how to make the replacement so the single quotes gets transformed into double quotes.
I wonder if there's a way to make this work using sed only, via a one-liner.
This will do the job:
/usr/bin/sed -e "/='.*\/.*'/ s/'/\"/g" file
Basically, you just want the plain ' => " replacement, but not for all lines, just for those that match the pattern ='.*\/.*'/. And, in the s command you just need to escape the ".
This should work:
sed "s/'\(.*\/.*\)'/\"\1\"/g"
Captures the part between ' and uses a backreference.
Im trying to extract the last line of a text file using sed and move it to a variable. However, command substitution using quotes breaks the sed command which already uses quotes.
sed '$!d' cookie.txt
Returns: localhost FALSE /XSS/ FALSE ****** loggedIn No
However, trying to move it to a variable, like so:
varin='sed '$!d' cookie.txt'
provides no output for the variable $varin
For PHP, we can have nested quotes using double and single quotes, is there anything similar here?
Try this:
var=$(tail -1 cookie.txt)
or with sed:
var=$(sed '$!d' cookie.txt)
If you are getting an error like "localhost:command not found" with $(...), it sounds like you are nesting backticks inside the command substitution, like
variable=$(`sed '$!d' cookie.txt`)
The backticks would run the sed command to produce the string beginning with "localhost", then because that string is inside $(...), it would be treated as a command to run. Simply using
variable=$( sed '$!d' cookie.txt )
should do what you want.
I am trying to create an app that will let users find processes that are taking up to much memory. I am doing this with the following code:
system("tasklist /fi "status eq not responding"");
My compiler isn't liking where I put the commas in.
This is the cmd command (or shell script, whatever) that I am trying to execute: tasklist /fi "status eq not responding".
Where should I put the commas?
You need to properly quote the command line within system call like:
system("/bin/echo \"a, b, c\"");
This is called a "quote" not a comma. And if you want to insert a quote within a string you need to escape it with the escape character \
Like this:
system("tasklist /fi \"status eq not responding\"");
Use \ as a Escape character before ", such like
system("tasklist /fi \"status eq not responding\"");