How to tell a Django view who called it? - django

I have two Django views that render two separate templates. Each of these templates will contain a link to the same third view.
That third view will render a template that should display one button if the first Django view/template link redirected to it but render a different button if the second view/template link redirected to it.
The URI for the link in each of these templates will be something like this:
/members/near/<from_uid>/profile/<to_uid>/
What is the most robust or "best-practice" way to tell the third view who called it? Should I create links like the following?
/members/near/<from_uid>/profile/<to_uid>/from/<view_name>
/members/near/<from_uid>/profile/<to_uid>/from/<view_name>
Would it be better to examine the HTTP referer header field in the request? Or is there some other better technique for doing this?
By the way, I realize my URI isn't RESTful but I don't feel that I understand REST sufficiently well to create RESTful URIs, particularly when I have to pass multiple arguments as I do here with the from_uid and to_uid arguments.
Thanks!

You can have a part of the URL to be used as a parameters. Each parameter will be set based on the regex provided. an example here. One view can handle all your urls that contain the three parameters you mentioned.
url(r'^members/near/(?P<from_uid>\d+)/profile/(?P<to_uid>\d+)/from//(?P<view_name>\W+)/$', MyView.as_view(), name = 'my_named_view')
Then in your view you just pull these parameters from the url
from_uid = self.kwargs['from_uid']
to_uid = self.kwargs['to_uid']
view_name = self.kwargs['view_name']
if view_name == "....":
# render to template1
elif view_name == "....":
# render to template2

Use GET parameters like this...
Template 1:
Link
Template 2:
Link
And in your third view...
from_view = self.request.GET.pop('from')
if from_view == 'view1':
...
elif from_view == 'view2':
...
GET parameters are more appropriate than URL-captured parameters in a situation like this.

Related

Django pass known exact string as a url parameter

I have two urls in dispatcher pointing the same view
path('posts/top/', posts, name='top'),
path('posts/new/', posts, name='new'),
I want view start as follows:
def posts(request, ordering):
...
I guess, to pass top and new as a parameter it should be something like:
path('posts/<ordering:top>/', posts, name='top'),
path('posts/<ordering:new>/', posts, name='new'),
But it gives me:
django.core.exceptions.ImproperlyConfigured: URL route 'posts/<ordering:top>/' uses invalid converter 'ordering'.
So, as a work around I use this, but it looks a little bit dirty:
path('posts/top/', posts, name='top', kwargs={'order': 'top'}),
path('posts/new/', posts, name='new', kwargs={'order': 'top'}),
What is the right way to do it?
You've misunderstood the way path converters work. The first element is the type, which here is str, and the second is the parameter name to use when calling the view. At this point you don't constrain the permissible values themselves. So your path would be:
path('posts/<str:ordering>/', posts, name='posts')
and when you come to reverse you would pass in the relevant parameter:
{% url 'posts' ordering='top' %}
If you really want to ensure that people can only pass those two values, you can either check it programmatically in the view, or you can use re_path to use regex in your path:
re_path(r'^posts/(?P<ordering>top|new)/$', posts, name='posts')

Is it possible to give external URLs names in django

I have just started naming my URL patterns in Django, so that if I want to change the URL pattern, I just have to change it in one place. e.g:
url(r'^$', HomeListView.as_view(), name='home'),
And referencing it in my templates like this:
{% url home %}
Is this possible with external links in case they change or I change the a Facebook page link for example. How would this look?
Thanks
One way to do this could be to write an external_url template tag, and have an ExternalURL model that stores them.
This would give you the advantage of being able to have the urls editable without redeploying changed code.
The disadvantage is that there will be database lookups to see those urls. Also, you would need to {% load external_urls %} in templates you want to use it in.
# models.py pseudo-code
class ExternalURL(models.Model):
name = models.CharField(unique=True)
url = models.URLField()
Your template tag might look something like:
# app/templatetags/external_url.py
#library.register()
def external_url(name):
try:
return ExternalURL.objects.get(name=name).url
except ExternalURL.DoesNotExist:
return ''
Another alternative could be to have a Context Processor that stores them all in the context, allowing you to not have to pass them explicitly into views: would be useful if you had several external urls that were used in many places within your system.
def external_urls(request):
return {
'google': 'http://www.google.com/',
# more here
}
The advantages of this is no database lookup, no requirement to load the template tag, but you will need to add it to your settings.CONTEXT_PROCESSORS. Also, you could inspect request to see if the current user may see all the urls.
If its external links, and possibility of the change then you should define it in settings or separate static url file and pass those variable with request context.
urls.py should be recommended to use only for your app specific urls.
In this SO thread you can see how to approach defining constant

How to avoid hardcode URL in Django view

I am working on a simple project on Django. Currently the views that I am implementing always return a hardcode path:
def temp_view(request):
...
return render("app/detail.html")
or
def temp_view_2(request):
...
return redirect("/app/view2")
What I want to do is to get rid of the hardcode URL (for view URL and the template URL). Is there a proper way to do that?
Thanks.
Django provides a few different methods. In a view, the django.core.urlresolvers.reverse() function is most often used. A full discussion of this problem and the options provided by Django is here:
https://docs.djangoproject.com/en/dev/topics/http/urls/#reverse-resolution-of-urls

What is reverse()?

When I read Django code sometimes, I see in some templates reverse(). I am not quite sure what this is but it is used together with HttpResponseRedirect. How and when is this reverse() supposed to be used?
reverse() | Django documentation
Let's suppose that in your urls.py you have defined this:
url(r'^foo$', some_view, name='url_name'),
In a template you can then refer to this url as:
<!-- django <= 1.4 -->
link which calls some_view
<!-- django >= 1.5 or with {% load url from future %} in your template -->
link which calls some_view
This will be rendered as:
link which calls some_view
Now say you want to do something similar in your views.py - e.g. you are handling some other URL (not /foo/) in some other view (not some_view) and you want to redirect the user to /foo/ (often the case on successful form submission).
You could just do:
return HttpResponseRedirect('/foo/')
But what if you want to change the URL in the future? You'd have to update your urls.py and all references to it in your code. This violates the DRY (Don't Repeat Yourself) principle and the whole idea of editing in one place only - which is something to strive for.
Instead, you can say:
from django.http import HttpResponseRedirect
from django.urls import reverse
return HttpResponseRedirect(reverse('url_name'))
This looks through all URLs defined in your project for the URL defined with the name url_name and returns the actual URL /foo/.
This means that you refer to the URL only by its name attribute - if you want to change the URL itself or the view it refers to you can do this by editing one place only - urls.py.
The existing answers are quite clear. Just in case you do not know why it is called reverse: It takes an input of a url name and gives the actual url, which is reverse to having a url first and then give it a name.
Existing answers did a great job at explaining the what of this reverse() function in Django.
However, I'd hoped that my answer shed a different light at the why: why use reverse() in place of other more straightforward, arguably more pythonic approaches in template-view binding, and what are some legitimate reasons for the popularity of this "redirect via reverse() pattern" in Django routing logic.
One key benefit is the reverse construction of a url, as others have mentioned. Just like how you would use {% url "profile" profile.id %} to generate the url from your app's url configuration file: e.g. path('<int:profile.id>/profile', views.profile, name="profile").
But as the OP have noted, the use of reverse() is also commonly combined with the use of HttpResponseRedirect. But why?
I am not quite sure what this is but it is used together with HttpResponseRedirect. How and when is this reverse() supposed to be used?
Consider the following views.py:
from django.http import HttpResponseRedirect
from django.urls import reverse
def vote(request, question_id):
question = get_object_or_404(Question, pk=question_id)
try:
selected = question.choice_set.get(pk=request.POST['choice'])
except KeyError:
# handle exception
pass
else:
selected.votes += 1
selected.save()
return HttpResponseRedirect(reverse('polls:polls-results',
args=(question.id)
))
And our minimal urls.py:
from django.urls import path
from . import views
app_name = 'polls'
urlpatterns = [
path('<int:question_id>/results/', views.results, name='polls-results'),
path('<int:question_id>/vote/', views.vote, name='polls-vote')
]
In the vote() function, the code in our else block uses reverse along with HttpResponseRedirect in the following pattern:
HttpResponseRedirect(reverse('polls:polls-results',
args=(question.id)
This first and foremost, means we don't have to hardcode the URL (consistent with the DRY principle) but more crucially, reverse() provides an elegant way to construct URL strings by handling values unpacked from the arguments (args=(question.id) is handled by URLConfig). Supposed question has an attribute id which contains the value 5, the URL constructed from the reverse() would then be:
'/polls/5/results/'
In normal template-view binding code, we use HttpResponse() or render() as they typically involve less abstraction: one view function returning one template:
def index(request):
return render(request, 'polls/index.html')
But in many legitimate cases of redirection, we typically care about constructing the URL from a list of parameters. These include cases such as:
HTML form submission through POST request
User login post-validation
Reset password through JSON web tokens
Most of these involve some form of redirection, and a URL constructed through a set of parameters. Hope this adds to the already helpful thread of answers!
This is an old question, but here is something that might help someone.
From the official docs:
Django provides tools for performing URL reversing that match the
different layers where URLs are needed: In templates: Using the url
template tag. In Python code: Using the reverse() function. In higher
level code related to handling of URLs of Django model instances: The
get_absolute_url() method.
Eg. in templates (url tag)
2012 Archive
Eg. in python code (using the reverse function)
return HttpResponseRedirect(reverse('news-year-archive', args=(year,)))
The function supports the dry principle - ensuring that you don't hard code urls throughout your app. A url should be defined in one place, and only one place - your url conf. After that you're really just referencing that info.
Use reverse() to give you the url of a page, given either the path to the view, or the page_name parameter from your url conf. You would use it in cases where it doesn't make sense to do it in the template with {% url 'my-page' %}.
There are lots of possible places you might use this functionality. One place I've found I use it is when redirecting users in a view (often after the successful processing of a form)-
return HttpResponseRedirect(reverse('thanks-we-got-your-form-page'))
You might also use it when writing template tags.
Another time I used reverse() was with model inheritance. I had a ListView on a parent model, but wanted to get from any one of those parent objects to the DetailView of it's associated child object. I attached a get__child_url() function to the parent which identified the existence of a child and returned the url of it's DetailView using reverse().
There is a doc for that
https://docs.djangoproject.com/en/dev/topics/http/urls/#reverse-resolution-of-urls
it can be used to generate an URL for a given view
main advantage is that you do not hard code routes in your code.
The reverse() is used to adhere the django DRY principle i.e if you change the url in future then you can reference that url using reverse(urlname).

Use url args in views, is it possible?

I'd like to use url arguments in views (not templates, I know how to do that).
So is it possible to use them like:
def item_link(self, item):
return mainpage_url_name + "%s/%i" % (item.slug, item.cid)
mainpage_url_name - is of course defined in url patterns (as name variable)
I'm a total newb in Django...
Thanks
First you should use names for your url patterns as documented here.
Then you can use reverse() to use these names in your views or methods.
Following your comments you are using the syndication framework.
Therefore you should make sure that you define get_absolute_url() for you models, ideally using the permalink decorator (for a clean reversing of your urls).
Looking at the example from Django's docs that should be all that's necessary.
To specify the contents of <link>, you
have two options. For each item in
items(), Django first tries calling
the item_link() method on the Feed
class. In a similar way to the title
and description, it is passed it a
single parameter, item. If that method
doesn't exist, Django tries executing
a get_absolute_url() method on that
object.