Url from google: \75, reg exp - regex

I have such part of the code, which i'va got from google:
"
\u0438", '/webmasters/tools/backlinks-latest-dl?
hl\75ru\46siteUrl\75http://site.comt/\46security_token\75sMuiouiouWA-
TiuoiuoiuiocDo4:1489898898'); </script></div>
"
\75 is '=' but is it 16 digit? Why google don't use 'base64' or 'urlencode'
When i use such regexp
/backlinks-latest-dl.*security_token\\\75/
everything is ok.
But when i put the code to the file and then parse the file- i can't find data by the reg exp. I can find using only
/backlinks-latest-dl.*security_token(\\\)(75)/ HERE 3 '\' NOT 2
When i use
/backlinks-latest-dl.*security_token(\\\75)/
it is'n't work.
What is it?

I could hardly get your point but the problem could be that you put three backslashes instead of two or four. It you want to escape the initial slashes,you should use four of them in a row \\. Or, you need to leave only two of them if additional escaping is not needed. I just don't see any logic in using three backslashes.

Related

Splitting name/value pairs with regex to ignore special characters based on surrounding characters

I have this regex that's worked well so far that splits 'name=value' pairs separated by a given character.
(?s)([^\s=]+)=(.*?)(?=\s+[^\s=]+=|\Z)
I know the separator, but the problem is in the example below (tab separated):
usrName=Wilma sev=4 cat=Detection CommandLine="C:\powershell.exe" -Enc 0ATQBpAG0AAcABDAHIAZQBkAHMAIgA= IOCValue= ProcessEndTime=2023-01-18 15:51:05
https://regex101.com/r/1wgVxs/5
Some values can have no value in the case of 'IOCValue' which works as expected, however some values like the CommandLine are giving me up to -Enc as one match and the remainder to the next pair as another.
What I'm hoping to get out from the above is:
usrName=Wilma
sev=4
cat=Detection
CommandLine="C:\powershell.exe" -Enc 0ATQBpAG0AAcABDAHIAZQBkAHMAIgA=
IOCValue=
ProcessEndTime=2023-01-18 15:51:05
But I'm getting:
usrName=Wilma
sev=4
cat=Detection
CommandLine="C:\powershell.exe" -Enc
0ATQBpAG0AAcABDAHIAZQBkAHMAIgA=
IOCValue=
ProcessEndTime=2023-01-18 15:51:05
Given I know the separator is a tab I think what I need is to only look for name=value pairs when they are at the start of the line or proceeded by the separator (tab). Is this possible?
Note, I can expect a space separator too, but I have a less performant and messy non-regex version I can send these too, so presume tab.
You may use this simplified regex:
(?s)([^\s=]+)=(.*?)(?=\t|\Z)
Updated RegEx Demo
Here, lookahead (?=\t|\Z) will make sure that value part is followed by either a tab character or end position.

Extract string of numbers from URL using regex PIG

I'm using PIG to generate a list of URLs that have been recently visited. In each of the URLs, there is a string of numbers that represents the product page visited. I'm trying to use a regex_extract_all() function to extract just the string of numbers, which vary in length from 6-8. The string of digits can be found directly after jobs2/view/ and usually ends with +&cd but sometimes they may end with ).
Here are a few example URLs:
(http://a.com/search?q=cache:QD7vZRHkPQoJ:ca.xyz.com/jobs2/view/17069404+&cd=1&hl=en&ct=clnk&gl=ca)
(http://a.com/search?q=cache:G9323j2oNbAJ:ca.xyz.com/jobs2/view/5977065+&cd=1&hl=en&ct=clnk&gl=ca)
(http://a.com/search?q=cache:aNspmG11qAJ:hk.xyz.com/jobs2/view/16988928+&cd=2&hl=zh-TW&ct=clnk&gl=hk)
(http://a.com/search?q=cache:aNspmG11AJ:hk.xyz.com/jobs2/view/16988928+&cd=2&hl=zh-TW&ct=clnk&gl=hk)
(http://a.com/search?q=cache:aNspmG11qAJ:hk.xyz.com/jobs2/view/16988928+&cd=2&hl=zh-TW&ct=cl k&gl=hk)
Here is the current regex I am using:
J = FOREACH jpage GENERATE FLATTEN(REGEX_EXTRACT_ALL(TEXTCOLUMN, '\/view\/(\d+)\+\&')) as (output:chararray)
I have also tried other forms such as:
'[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]', 'view.([0-9]+)', 'view\/([\d]+)\+',
'[0-9][0-9][0-9]+', and
'[0-9][0-9][0-9]*'; none of which work.
Can anybody assist here or have another way of going about it?
Much appreciated,
MM
Reason for"Unexpected character 'D'" is, you need to put double backslash instead of single backslash. eg just replace [\d+] to [\\d+]
Here your solution, please validate all your inputs strings
input.txt
http://a.com/search?q=cache:QD7vZRHkPQoJ:ca.xyz.com/jobs2/view/17069404+&cd=1&hl=en&ct=clnk&gl=ca
http://a.com/search?q=cache:G9323j2oNbAJ:ca.xyz.com/jobs2/view/5977065+&cd=1&hl=en&ct=clnk&gl=ca
http://a.com/search?q=cache:aNspmG11qAJ:hk.xyz.com/jobs2/view/16988928+&cd=2&hl=zh-TW&ct=clnk&gl=hk
http://a.com/search?q=cache:aNspmG11AJ:hk.xyz.com/jobs2/view/16988928+&cd=2&hl=zh-TW&ct=clnk&gl=hk
http://a.com/search?q=cache:aNspmG11qAJ:hk.xyz.com/jobs2/view/16988928+&cd=2&hl=zh-TW&ct=clk&gl=hk
http://a.com/search?q=cache:aNspmG11qAJ:hk.xyz.com/jobs2/view/16988928)=2&hl=zh-TW&ct=clk&gl=hk
http://webcache.googleusercontent.com/search?q=cache:http://my.linkedin.com/jobs2/view/9919248
Updated Pigscript:
A = LOAD 'input.txt' as line;
B = FOREACH A GENERATE REGEX_EXTRACT(line,'.*/view/(\\d+)([+|&|cd|)?]+)?',1);
dump B;
(17069404)
(5977065)
(16988928)
(16988928)
(16988928)
(16988928)
I'm not familiar with PIG, but this regex will match your target:
(?<=/jobs2/view/)\d+
By using a (non-consuming) look behind, the entire match (not just a group of the match) is your number.

VB.Net Beginner: Replace with Wildcards, Possibly RegEx?

I'm converting a text file to a Tab-Delimited text file, and ran into a bit of a snag. I can get everything I need to work the way I want except for one small part.
One field I'm working with has the home addresses of the subjects as a single entry ("1234 Happy Lane Somewhere, St 12345") and I need each broken down by Street(Tab)City(Tab)State(Tab)Zip. The one part I'm hung up on is the Tab between the State and the Zip.
I've been using input=input.Replace throughout, and it's worked well so far, but I can't think of how to untangle this one. The wildcards I'm used to don't seem to be working, I can't replace ("?? #####") with ("??" + ControlChars.Tab + "#####")...which I honestly didn't expect to work, but it's the only idea on the matter I had.
I've read a bit about using Regex, but have no experience with it, and it seems a bit...overwhelming.
Is Regex my best option for this? If not, are there any other suggestions on solutions I may have missed?
Thanks for your time. :)
EDIT: Here's what I'm using so far. It makes some edits to the line in question, taking care of spaces, commas, and other text I don't need, but I've got nothing for the State/Zip situation; I've a bad habit of wiping something if it doesn't work, but I'll append the last thing I used to the very end, if that'll help.
If input Like "Guar*###/###-####" Then
input = input.Replace("Guar:", "")
input = input.Replace(" ", ControlChars.Tab)
input = input.Replace(",", ControlChars.Tab)
input = "C" + ControlChars.Tab + strAccount + ControlChars.Tab + input
End If
input = System.Text.RegularExpressions.Regex.Replace(" #####", ControlChars.Tab + "#####") <-- Just one example of something that doesn't work.
This is what's written to input in this example
" Guar: LASTNAME,FIRSTNAME 999 E 99TH ST CITY,ST 99999 Tel: 999/999-9999"
And this is what I can get as a result so far
C 99999/9 LASTNAME FIRSTNAME 999 E 99TH ST CITY ST 99999 999/999-9999
With everything being exactly what I need besides the "ST 99999" bit (with actual data obviously omitted for privacy and professional whatnots).
UPDATE: Just when I thought it was all squared away, I've got another snag. The raw data gives me this.
# TERMINOLOGY ######### ##/##/#### # ###.##
And the end result is giving me this, because this is a chunk of data that was just fine as-is...before I removed the Tabs. Now I need a way to replace them after they've been removed, or to omit this small group of code from a document-wide Tab genocide I initiate the code with.
#TERMINOLOGY###########/##/########.##
Would a variant on rgx.Replace work best here? Or can I copy the code to a variable, remove Tabs from the document, then insert the variable without losing the tabs?
I think what you're looking for is
Dim r As New System.Text.RegularExpressions.Regex(" (\d{5})(?!\d)")
Dim input As String = rgx.Replace(input, ControlChars.Tab + "$1")
The first line compiles the regular expression. The \d matches a digit, and the {5}, as you can guess, matches 5 repetitions of the previous atom. The parentheses surrounding the \d{5} is known as a capture group, and is responsible for putting what's captured in a pseudovariable named $1. The (?!\d) is a more advanced concept known as a negative lookahead assertion, and it basically peeks at the next character to check that it's not a digit (because then it could be a 6-or-more digit number, where the first 5 happened to get matched). Another version is
" (\d{5})\b"
where the \b is a word boundary, disallowing alphanumeric characters following the digits.

How to split CSV line according to specific pattern

In a .csv file I have lines like the following :
10,"nikhil,khandare","sachin","rahul",viru
I want to split line using comma (,). However I don't want to split words between double quotes (" "). If I split using comma I will get array with the following items:
10
nikhil
khandare
sachin
rahul
viru
But I don't want the items between double-quotes to be split by comma. My desired result is:
10
nikhil,khandare
sachin
rahul
viru
Please help me to sort this out.
The character used for separating fields should not be present in the fields themselves. If possible, replace , with ; for separating fields in the csv file, it'll make your life easier. But if you're stuck with using , as separator, you can split each line using this regular expression:
/((?:[^,"]|"[^"]*")+)/
For example, in Python:
import re
s = '10,"nikhil,khandare","sachin","rahul",viru'
re.split(r'((?:[^,"]|"[^"]*")+)', s)[1::2]
=> ['10', '"nikhil,khandare"', '"sachin"', '"rahul"', 'viru']
Now to get the exact result shown in the question, we only need to remove those extra " characters:
[e.strip('" ') for e in re.split(r'((?:[^,"]|"[^"]*")+)', s)[1::2]]
=> ['10', 'nikhil,khandare', 'sachin', 'rahul', 'viru']
If you really have such a simple structure always, you can use splitting with "," (yes, with quotes) after discarding first number and comma
If no, you can use a very simple form of state machine parsing your input from left to right. You will have two states: insides quotes and outside. Regular expressions is a also a good (and simpler) way if you already know them (as they are basically an equivalent of state machine, just in another form)

A regex to match between delimiters except when there is a colon that is not between double quotes?

This one is a little bit complicated and I'm not sure if it can be done.
The regex need to match everything between a , (comma) or [] (square brackets).
It must not match if there is a :
And now the tricky part.
If the : is between " " it can match.
I managed to create a regex that does everything except the last.
(?<=[[,])[^:]+?(?=[],])
So this is what it needs to match.
[ ItemName:Data, More Data, With a number "as: " item name]
I'm going to keep testing. Lets see if someone solves it.
It sounds like you're trying to specify a language that's really to complicated to parse using only regular expressions. Here's a pattern that matches what you've described, but probably won't work perfectly. It doesn't use look behinds so you need to select the first match group to get the contents.
/[\[,](("[^"\]]*"|[^:\[])*?)[\]\,]/
/[\[,] # Opening bracket or comma.
(("[^"\]]*" # Anything not including the closing bracket, in quotes...
|[^:\[] # or not including the colon...
))*? # repeated any number of times.
[\]\,]/x # Closing bracket or comma.
An example usage in Python:
import re
pattern = re.compile(r"""[\[,](("[^"\]]*"|[^:\[])*?)[\]\,]""", re.DEBUG)
for match in pattern.finditer('[1 2 3] [4 5] [6 : 7], "8 : 9", '):
print match.group(1)
Producing output:
1 2 3
4 5
"8 : 9"
I have good experience in using (perl) regexps in practise, so let me share my experience. If you are handling complex cases like this it is almost always best to do it step by step, unless you are in special ciscumstances (for example speed of execution is crucial).
So in this case I woud simply do it in two steps. First explode the data to chunks, i.e. something like (depending on your language)
split(/[][,]/)
and than accept or remove individual parts. In this case just remove parts which match this expression
/^([^"]*:.*|.*:[^"])$/
i.e. parts which include semicolon not surrounded with parantheses.
Clearly this deos not solve all the cases like With a number "as: " : "item" name, but I agree with Jeremy, than if you are trying to implement complicated syntax language, than it might not be the right thing to just throw few regexpes on it without deeper analysis (i.e. answering what exactly it should accept in wierd cases like [ 1:1, 2":"2,3":":3,4":":":"4,5":":"5], ...) and using appropriate aprroach to solve it (recursive syntax parser)