Match multiple line string in Perl - regex

I'm new to Perl and I was wondering if someone can help me.
I have an input like this:
a,b,
c,d,e,f,g,h,
i,j,q // Letras
I'm trying to get the letters before // separately and then print them between {} separated by :.
I tried with this RE ([\w,;:\s\t]*)(\n|\/\/)/m and I could get in $1 all letters for each line (as a string including separators) but not what I want.
I need to match that pattern more than one time in the same file so I was using /g.
Edit:
Here is my code block:
while ( <> ) {
if ( /([\w,;:\s\t]*)(\n|\/\/)/m ) {
print "$1\n";
}
}

/m is for using ^, and $ to match by line in a string with multiple lines.
On the other hand, you are reading the input line by line. You cannot expect to match across lines with a single expression if you only look at one line at a time.
Instead, read by chunks by setting $/ to an appropriate value. If the chunks always end in the exact string "// Letras\n\n", the task is even simpler.
#!/usr/bin/env perl
use strict;
use warnings;
local $/ = '//';
while (my $chunk = <DATA>) {
chomp $chunk;
my #fields = ($chunk =~ /([a-z])[, ]/g);
next unless #fields;
printf "{%s}\n", join(':', #fields);
}
__DATA__
a,b,
c,d,e,f,g,h,
i,j,q // Letras
a,b,
c,d,e,f,g,h,
i,j,q // Metras
Output:
{a:b:c:d:e:f:g:h:i:j:q}
{a:b:c:d:e:f:g:h:i:j:q}
You can also use File::Stream:
#!/usr/bin/env perl
use strict;
use warnings;
use File::Stream;
my $stream = File::Stream->new(
\*DATA,
separator => qr{ (?: \s+ // [^\n]+ ) \n\n }x
);
while (my $chunk = <$stream>) {
$chunk =~ s{ \s+ // .* \z }{}sx;
$chunk =~ s{ ,\n? }{:}gx;
print "{$chunk}\n";
}
__DATA__
a,b,
c,d,e,f,g,h,
i,j,q // Letras
a,b,
c,d,e,f,g,h,
i,j,q // Metras

I think what you're aiming for is to remove comments (denoted by a double slash) from each line, and print it out enclosed by braces, and with a colon : separator instead of commas
First of all you should remove the trailing linefeed character from each line using chomp
Then all you need to remove any trailing comment is s|\s*//.*||. That removes any spaces before the // as well. I'm using a pipe character | as the delimiter so as to avoid having to escape the slashes within the regex pattern. And the data is being processed one line at a time so there no need for the global /g modifier
This program reads from the file specified on the command line, which I've set up to contain the data you show in the question
use strict;
use warnings;
while ( <DATA> ) {
chomp;
s|\s*//.*||;
print "{$_}\n";
}
output
{a,b,}
{c,d,e,f,g,h,}
{i,j,q}
Update
Thanks to Sinan Ünür's solution I notice that you've asked to "print [the letters] between {} separated by :"
This is a modification of the while loop above, which finds all substrings within the current line that don't contain commas, and joins them together again using colons :
while ( <> ) {
chomp;
s|\s*//.*||;
my $values = join ':', /[^,]+/g;
print "{$values}\n";
}
output
{a:b}
{c:d:e:f:g:h}
{i:j:q}
I am sure the true solution is much more simple, but unless you elaborate your question we have to cater for all possibilities

Are you looking to combine the letters on all 3 lines into the output, or convert each line?
In other words, is your desired output
{a:b}
{c:d:e:f:g:h}
{i:j:q}
or
{a:b:c:d:e:f:g:h:i:j:q}
?
If you want the former, Borodin's answer works.
If you want the latter, then you should load the contents into an array, and print it using a join statement. To do that, I've modified Borodin's answer:
while ( <> ) { # read each line
chomp; # remove \n from line
s|\s*//.*||; # remove comment
push #values, ':', /[^,]+/g; # store letters in array
}
my $values = join ':', #values; # convert array to string
print "{$values}\n"; # print the results

my $str = "a,b,
c,d,e,f,g,h,
i,j,q // Letras";
$str = join "",map {s/,/:/g ;(split)[0]} split '\n', $str;
print "{$str}";
Sample output
{a:b:c:d:e:f:g:h:i:j:q}
I am considering a string with multilines separated by newline character.
join "",map {s/,/:/g ;(split)[0]} split '\n', $str
This is evaluated from right to left.
Split with \n on $str produces 3 elements which is input for map.
(split)[0] : default delimiter for split is whitespace. so each element is split for whitespace and 0th element is only considered discarding others.
Ex (split)[0] for i,j,q // Letras produces 3 elements "i,j,q" "//" "Letras" where only element 0 i.e., "i,j,q" is considered.
, is replaced with :
join is used to combine all the resulting elements from map.

Related

How to extract 2+ character words from string in perl

I assume some sort of regex would be used to accomplish this?
I need to get it where each word consists of 2 or more characters, start with a letter, and the remaining characters consist of letters, digits, and underscores.
This is the code I currently have, although it isn't very close to my desired output:
while (my $line=<>) {
# remove leading and trailing whitespace
$line =~ s/^\s+|\s+$//g;
$line = lc $line;
#array = split / /, $line;
foreach my $a (#array){
$a =~ s/[\$##~!&*()\[\];.,:?^ `\\\/]+//g;
push(#list, "$a");
}
}
A sample input would be:
#!/usr/bin/perl -w
use strict;
# This line will print a hello world line.
print "Hello world!\n";
exit 0;
And the desired output would be (alphabetical order):
bin
exit
hello
hello
line
perl
print
print
strict
this
use
usr
will
world
my #matches = $string =~ /\b([a-z][a-z0-9_]+)/ig;
If case-insensitive operation need be applied only to a subpattern, can embed it
/... \b((?i)[a-z][a-z0-9_]+) .../
(or, it can be turned off after the subpattern, (?i)pattern(?-i))
That [a-zA-Z0-9_] goes as \w, a "word character", if that's indeed exactly what is needed.
The above regex picks words as required without a need to first split the line on space, done in the shown program. Can apply it on the whole line (or on the whole text for that matter), perhaps after the shown stripping of the various special characters.†
There is a question of some other cases -- how about hyphens? Apostrophes? Tilde? Those aren't found in identifiers, while this appears to be intended to process programming text, but comments are included; what other legitimate characters may there be?
Note on split-ing on whitespace
The shown split / /, $line splits on exactly that one space. Better is split /\s+/, $line -- or, better yet is to use split's special pattern split ' ', $line: split on any number of any consecutive whitespace, and where leading and trailing spaces are discarded.
† The shown example is correctly processed as desired by the given regex alone
use strict;
use warnings;
use feature 'say';
use Path::Tiny qw(path); # convenience, to slurp the file
my $fn = shift // die "Usage: $0 filename\n";
my #matches = sort map { lc }
path($fn)->slurp =~ /\b([a-z][a-z0-9_]+)/ig;
say for #matches;
I threw in sorting and lower-casing to match the sample code in the question but all processing is done with the shown regex on the file's content in a string.
Output is as desired (except that line and world here come twice, what is correct).
Note that lc can be applied on the string with the file content, which is then processed with the regex, what is more efficient. While this is in principle not the same in this case it may be
perl -MPath::Tiny -wE'$f = shift // die "Need filename\n";
#m = sort lc(path($f)->slurp) =~ /\b([a-z]\w+)/ig;
say for #m'
Here I actually used \w. Adjust to the actual character to match, if different.
Curiously, this can be done with one of those long, typical Perl one-liners
$ perl -lwe'print for sort grep /^\pL/ && length > 1, map { split /\W+/ } map lc, <>' a.txt
bin
exit
hello
hello
line
line
perl
print
print
strict
this
use
usr
will
world
world
Lets go through that and see what we can learn. This line reads from right to left.
a.txt is the argument file to read
<> is the diamond operator, reading the lines from the file. Since this is list context, it will exhaust the file handle and return all the lines.
map lc, short for map { lc($_) } will apply the lc function on all the lines and return the result.
map { split /\W+/ } is a multi-purpose operation. It will remove the unwanted characters (the non-word characters), and also split the line there, and return a list of all those words.
grep /^\pL/ && length > 1 sorts out strings that begin with a letter \pL and are longer than 1 and returns them.
sort sorts alphabetically the list coming in from the right and returns it left
for is a for-loop, applied to the incoming list, in the post-fix style.
print is short for print $_, and it will print once for each list item in the for loop.
The -l switch in the perl command will "fix" line endings for us (remove them from input, add them in output). This will make the print pretty at the end.
I won't say this will produce a perfect result, but you should be able to pick up some techniques to finish your own program.

Using regex to extract a matching pattern from a string and assign it to a variable using perl

I am seeking advice on extracting a section of a string, that is always occurs as the first instance data between parenthesis using perl and regex and assign that value to a variable.
Here is the precise situation, I am using perl and regex to extract the courseID from a university catalog and assign it to a variable. Please consider the following:
BIO-2109-01 (12345) Introduction to Biology
CHM-3501-F2-01 (54321) Introduction to Chemistry
IDS-3250-01 (98765) History of US (1860-2000)
SPN-1234-02-F1 (45678) Spanish History (1900-2010)
The typical format is [course-section-name] [(courseID)] [courseName]
My goal is to create a script which can take each entry, one at a time, assign it to a variable and then use regex to extract only the courseID and assign only the courseID to a variable.
My approach has been to use search and replace to replace everything not matching that with '' and then saving what is left (the courseID) to the variable. Here are a few examples of what I have tried the following:
$string = "BIO-2109-01 (12345) Introduction to Biology";
($courseID = $string) =~ s/[^\d\d\d\d\d]//g;
print $courseID;
Result: 21090112345 --- printing the course-section-name and courseID
$string = "BIO-2109-01 (12345) Introduction to Biology";
$($courseID = $string) =~ s/[^\b\(\d{5}\)]\b//g;
print $courseID;
Result: 210901(12345) --- printing course-section-name, parens, and courseID
So I haven't had much luck with search and replace - however I found this nugget:
\(([^\)]+)\)
On http://regexr.com/ that will match the parens section. However, it would also match multiple parans, including for example (abc).
I'm not really sure at this point how to do something like this:
$string = "BIO-2109-01 (12345) Introduction to Biology";
($courseID = $string) =~ [magicRegex_goes_here];
print courseID;
result 12345
OR, better:
$string = IDS-3250-01 (98765) History of US (1860-2000)
($courseID = $string) =~ [magicRegex_goes_here];
print courseID;
result 98765
Any advice or direction would be greatly appreciated. I have tried everything I know and can research in regards to regex to solve this problem. If there is anymore information I can include please ask away.
UPDATE
use warnings 'all';
use strict;
use feature 'say';
my $file = './data/enrollment.csv'; #File this script generates
my $course = ""; #Complete course string [name-of-course] [(courseID)] [course_name]
my #arrayCourses = ""; #Array of courseIDs
my $i = ""; #i in for loop
my $courseID = ""; #Extracted course ID
my $userName = ""; #Username of person we are enrolling
my $action = "add,"; #What we are doing to user
my $permission = "teacher,"; #What permissions to assign to user
my $stringToPrint = ""; #Concatinated string to write to file
my $n = "\n"; #\n
my $c = ","; #,
#BEGIN PROGRAM
print "Enter the username \n";
chomp($userName = <STDIN>); #Get the enrollee username from user
print "\n";
print "Enter course name and press enter. Enter 'x' to end. \n"; #prompt for course names
while ($course ne 'x') {
chomp($course = <STDIN>);
if ($course ne "x") {
if (($courseID) = ($course =~ /[^(]+\(([^)]+)\)/) ) { #nasty regex to extract courseID - thnx PerlDuck and zdim
push #arrayCourses, $courseID; #put the courseID into array
}
else {
print "Cannot process last entry check it";
}
}
else {
last;
}
}
shift #arrayCourses; #Remove first entry from array - add,teacher,,username
open(my $fh,'>', $file); #open file
for $i (#arrayCourses) #write array to file
{
$stringToPrint= join "", $action, $permission, $i, $c, $userName, $n ;
print $fh $stringToPrint;
}
close $fh;
That'll do it! Suggestions or improvements are always welcome! Thanks #PerlDuck and #zdim
#!/usr/bin/env perl
use strict;
use warnings;
while( my $line = <DATA> ) {
if (my ($courseID) = ($line =~ /[^(]+\(([^)]+)\)/) ) {
print "course-ID = $courseID; -- line was $line";
}
}
__DATA__
BIO-2109-01 (12345) Introduction to Biology
CHM-3501-F2-01 (54321) Introduction to Chemistry
IDS-3250-01 (98765) History of US (1860-2000)
SPN-1234-02-F1 (45678) Spanish History (1900-2010)
Output:
course-ID = 12345; -- line was BIO-2109-01 (12345) Introduction to Biology
course-ID = 54321; -- line was CHM-3501-F2-01 (54321) Introduction to Chemistry
course-ID = 98765; -- line was IDS-3250-01 (98765) History of US (1860-2000)
course-ID = 45678; -- line was SPN-1234-02-F1 (45678) Spanish History (1900-2010)
The pattern I used, /[^(]+\(([^)]+)\)/, can also be written as
/ [^(]+ # 1 or more characters that are not a '('
\( # a literal '('. You must escape that because you don't want
# to start it a capture group.
([^)]+) # 1 or more chars that are not a ')'.
# The sorrounding '(' and ')' capture this match
\) # a literal ')'
/x
The /x modifier allows you to insert spaces, comments, and even newlines right in the pattern.
Just in case you're unsure about the /x. You can indeed write:
while( my $line = <DATA> ) {
if (my ($courseID) = ($line =~ / [^(]+ # …
\( # …
([^)]+) # …
\) # …
/x ) ) {
print "course-ID = $courseID; -- line was $line";
}
}
That's probably not nice to read but you can also store the regex in a separate variable:
my $pattern =
qr/ [^(]+ # 1 or more characters that are not a '('
\( # a literal '(' (you must escape it)
([^)]+) # 1 or more chars that are not a ')'.
# The sorrounding '(' and ')' capture this match
\) # a literal ')'
/x;
And then:
if (my ($courseID) = ($line =~ $pattern)) {
…
}
Since you nailed down the format
my ($section, $id, $name) =
$string =~ /^\s* ([^(]+) \(\s* ([^)]+) \)\s* (.+) $/x;
The key here is the negated character class, [^...], which matches any one character other than those listed inside following the ^ (which makes it "negated"). The un-escaped parenthesis capture the match, except inside a character class [] where they are taken as literal.
It first matches all consecutive characters other than (, so up to first (, what is captured by the pair of ( ) around it. Then all other than ), so up to the first closing paren, also captured by its own pair ( ). This comes between literal parenthesis \( ... \), which are outside of ( ) since we don't want them captured. Then all the rest is captured, (.+), requiring at least some characters since + means one or more. Note though that these can be spaces. We exclude possible leading white space from the first capture, by matching it specifically before the capturing parenthesis, and extract (some of) possible spaces around id-parenthesis.
The /x modifier allows use of spaces (and comments and newlines) inside, what helps reaadbility. The match operator returns a list of all matches, which we assign to variables. Note, even if there is only one match it still returns (it as) a list. See Regular Expressions Tutorial (perlretut).
Then, assuming that you have the catalog in a file
use warnings 'all';
use strict;
use feature 'say';
my $file = 'catalog.txt';
open my $fh, '<', $file or die "Can't open $file: $!";
while (my $line = <$fh>)
{
next if $line =~ /^\s*$/; # skip empty lines
# Strip leading and trailing white space
$line =~ s{^\s*|\s*$}{}g;
my ($section, $id, $name) =
$line =~ /^ ([^(]+) \(\s* ([^)]+) \)\s* (.+) $/x
or do {
warn "Error with expected format -- ";
next;
};
say "$section, $id, $name";
}
close $fh;
I use s{}{} delimiters since s/// confuse markup's syntax highlighter with this pattern, which is also a good demonstration since these sometimes help readability a lot.
You would store the retrieved variables in a suitable data structure. Any combination of arrays and hashes (and their references) comes to mind, depending on what need be done with them later. See Cookbook of Data Structures (perldsc).
Note on the error handling. Since none of the matches involve * (allowing zero matches -- nothing), if any component of your format isn't as expected there won't be a match at all and we get an error. The .+ is extremely permissive but it still requires something to be there. This is why the trailing space is first stripped, so that the last pattern (.+) cannot be satisfied by spaces alone.
If the only objective is the course id and we are certain that the first parenthesis are around it
my ($id) = $line =~ / \(\s* ([^)]+) \) /x or do { ... };
We now only need to match and capture the middle piece, something inside parenthesis.

Multiline match with irregular new line

I have text file with many entries like this:
[...]
Wind: 83,476,224
Solution: (category,runs)~
0.235,6.52312667,~
0.98962,14.33858333,~
sdasd,cccc,~
0.996052905,sdsd
EnterValues: 656,136,1
Speed: 48,32
State: 2,102,83,476,224
[...]
From above part I would like to extract:
Solution: (category,runs)~
0.235,6.52312667,~
0.98962,14.33858333,~
sdasd,cccc,~
0.996052905,sdsd
It would be simple if EnterValues: exists after every Solution:, unfortunately it doesn't. Sometime it is Speed, sometime something different. I don't know how to construct the end of regex (I assume it should be sth like this:Solution:.*?(?<!~)\n).
My file has \n as a delimiter of new line.
What you need is to apply a "record separator" that has the functionality of a regex. Unfortunately, you cannot use $/, because it cannot be a regex. You can however read the entire file into one line, and split that line using a regex:
use strict;
use warnings;
use Data::Dumper;
my $str = do {
local $/; # disable input record separator
<DATA>; # slurp the file
};
my #lines = split /^(?=\pL+:)/m, $str; # lines begin with letters + colon
print Dumper \#lines;
__DATA__
Wind: 83,476,224
Solution: (category,runs)~
0.235,6.52312667,~
0.98962,14.33858333,~
sdasd,cccc,~
0.996052905,sdsd
EnterValues: 656,136,1
Speed: 48,32
State: 2,102,83,476,224
Output:
$VAR1 = [
'Wind: 83,476,224
',
'Solution: (category,runs)~
0.235,6.52312667,~
0.98962,14.33858333,~
sdasd,cccc,~
0.996052905,sdsd
',
'EnterValues: 656,136,1
',
'Speed: 48,32
',
'State: 2,102,83,476,224
'
You will do some sort of post processing on these variables, I assume, but I will leave that to you. One way to go from here is to split the values on newline.
As I see you first read all file to memory, but this is not a good pracrice. Try use flip flop operator:
while ( <$fh> ) {
if ( /Solution:/ ... !/~$/ ) {
print $_, "\n";
}
}
I can't test it right now, but I think this should work fine.
You can match from Solution to word followed by colon,
my ($solution) = $text =~ /(Solution:.*?) \w+: /xs;

Substitute first character before match

For each line I need to add a semicolon exactly one character before the first match of an alphanumeric sign but only for the alphanumeric sign after the first appearance of a semicolon.
Example:
Input:
00000001;Root;;
00000002; Documents;;
00000003; oracle-advanced_plsql.zip;file;
00000004; Public;;
00000005; backup;;
00000006; 20110323-JM-F.7z.001;file;
00000007; 20110426-JM-F.7z.001;file;
00000008; 20110603-JM-F.7z.001;file;
00000009; 20110701-JM-F-via-summer_school;;
00000010; 20110701-JM-F-via-summer_school.7z.001;file;
Desired output:
00000001;;Root;;
00000002; ;Documents;;
00000003; ;oracle-advanced_plsql.zip;file;
00000004; ;Public;;
00000005; ;backup;;
00000006; ;20110323-JM-F.7z.001;file;
00000007; ;20110426-JM-F.7z.001;file;
00000008; ;20110603-JM-F.7z.001;file;
00000009; ;20110701-JM-F-via-summer_school;;
00000010; ;20110701-JM-F-via-summer_school.7z.001;file;
Could someone helps me please to create Perl regex for that? I'd need it in a program, not as a oneliner.
This is a way to insert a semi-colon after the first semi-colon and whitespace, but before the first non-whitespace.
s/;\s*\K(?=\S)/;/
If you feel the need, you can use \w instead of \S, but I felt with this input it was an unnecessary specification.
The \K (keep) escape is similar to a lookbehind assertion in that it does not remove what it matches. The same goes for the lookahead assertion, so all this substitution does is insert a semi-colon in the designated spot.
First of all, here is a program that seems to match your requirements:
#/usr/bin/perl -w
while(<>) {
s/^(.*?;.*?)(\w)/$1;$2/;
print $_;
}
Store it in a file 'program.pl', make it executable with 'chmod u+x program.pl' and run it on your input data like this:
program.pl input-data.txt
Here is an explanation of the regular expression:
s/ # start search-and-replace regexp
^ # start at the beginning of this line
( # save the matched characters until ')' in $1
.*?; # go forward until finding the first semicolon
.*? # go forward until finding... (to be continued below)
)
( # save the matched characters until ')' in $2
\w # ... the next alphanumeric character.
)
/ # continue with the replace part
$1;$2 # write all characters found above, but insert a ; before $2
/ # finish the search-and-replace regexp.
Based on your sample input, I would use a more specific regular expression:
s/^(\d*; *)(\w)/$1;$2/;
This expression starts at the beginning of the line, skips over numbers (\d*) followed by the first semicolon and space. Before the following word character, it inserts a semicolon.
Take what fits best to your needs!
First of all thank you for your really great answers!
Actually my code snippet looks like this:
our $seperator=";" # at the beginning of the file
#...
sub insert {
my ( $seperator, $line, #all_lines, $count, #all_out );
$count = 0;
#all_lines = read_file($filename);
foreach $line (#all_lines) {
$count = sprintf( "%08d", $count );
chomp $line;
$line =~ s/\:/$seperator/; # works
$line =~ s/\ file/file/; # works
#$line=~s/;\s*\K(?=\S)/;/; # doesn't work
$line =~ s/^(.*?$seperator.*?)(\w)/$1$seperator$2/; # doesn't work
say $count . $seperator . $line . $seperator;
$count++; # btw, is there maybe a hidden index variable in a foreach-loop I could us instead of a new variable??
push( #all_out, $count . $seperator . $line . $seperator . "\n" );
}
write_file( $csvfile, #all_out ); # using File::Slurp
}
In order to get the input which I presented you, I made already some small substitutions, as you can see in the beginning of the foreach-loop.
I am curious, why the regular expressions presented by TLP and Yaakov do not work in my code. In general they work, but only when written like in the example which Yaakov gave:
while(<>) {
s/^(.*?;.*?)(\w)/$1;$2/;
print $_;
}

How do I use Perl to intersperse characters between consecutive matches with a regex substitution?

The following lines of comma-separated values contains several consecutive empty fields:
$rawData =
"2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,,Clear\n
2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,,,,\n"
I want to replace these empty fields with 'N/A' values, which is why I decided to do it via a regex substitution.
I tried this first of all:
$rawdata =~ s/,([,\n])/,N\/A/g; # RELABEL UNAVAILABLE DATA AS 'N/A'
which returned
2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,N/A,Clear\n
2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,N/A,,N/A,\n
Not what I wanted. The problem occurs when more than two consecutive commas occur. The regex gobbles up two commas at a time, so it starts at the third comma rather than the second when it rescans the string.
I thought this could be something to do with lookahead vs. lookback assertions, so I tried the following regex out:
$rawdata =~ s/(?<=,)([,\n])|,([,\n])$/,N\/A$1/g; # RELABEL UNAVAILABLE DATA AS 'N/A'
which resulted in:
2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,,N/A,Clear\n
2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,,N/A,,N/A,,N/A,,N/A\n
That didn't work either. It just shifted the comma-pairings by one.
I know that washing this string through the same regex twice will do it, but that seems crude. Surely, there must be a way to get a single regex substitution to do the job. Any suggestions?
The final string should look like this:
2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,N/A,N/A,Clear\n
2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,,N/A,,N/A,N/A,N/A,N/A,N/A\n
EDIT: Note that you could open a filehandle to the data string and let readline deal with line endings:
#!/usr/bin/perl
use strict; use warnings;
use autodie;
my $str = <<EO_DATA;
2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,,Clear
2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,,,,
EO_DATA
open my $str_h, '<', \$str;
while(my $row = <$str_h>) {
chomp $row;
print join(',',
map { length $_ ? $_ : 'N/A'} split /,/, $row, -1
), "\n";
}
Output:
E:\Home> t.pl
2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,N/A,Clear
2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,N/A,N/A,N/A,N/A
You can also use:
pos $str -= 1 while $str =~ s{,(,|\n)}{,N/A$1}g;
Explanation: When s/// finds a ,, and replaces it with ,N/A, it has already moved to the character after the last comma. So, it will miss some consecutive commas if you only use
$str =~ s{,(,|\n)}{,N/A$1}g;
Therefore, I used a loop to move pos $str back by a character after each successful substitution.
Now, as #ysth shows:
$str =~ s!,(?=[,\n])!,N/A!g;
would make the while unnecessary.
I couldn't quite make out what you were trying to do in your lookbehind example, but I suspect you are suffering from a precedence error there, and that everything after the lookbehind should be enclosed in a (?: ... ) so the | doesn't avoid doing the lookbehind.
Starting from scratch, what you are trying to do sounds pretty simple: place N/A after a comma if it is followed by another comma or a newline:
s!,(?=[,\n])!,N/A!g;
Example:
my $rawData = "2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,,Clear\n2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,,,,\n";
use Data::Dumper;
$Data::Dumper::Useqq = $Data::Dumper::Terse = 1;
print Dumper($rawData);
$rawData =~ s!,(?=[,\n])!,N/A!g;
print Dumper($rawData);
Output:
"2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,,Clear\n2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,,,,\n"
"2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,N/A,Clear\n2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,N/A,N/A,N/A,N/A\n"
You could search for
(?<=,)(?=,|$)
and replace that with N/A.
This regex matches the (empty) space between two commas or between a comma and end of line.
The quick and dirty hack version:
my $rawData = "2008-02-06,8:00 AM,14.0,6.0,59,1027,-9999.0,West,6.9,-,N/A,,Clear
2008-02-06,9:00 AM,16,6,40,1028,12,WNW,10.4,,,,\n";
while ($rawData =~ s/,,/,N\/A,/g) {};
print $rawData;
Not the fastest code, but the shortest. It should loop through at max twice.
Not a regex, but not too complicated either:
$string = join ",", map{$_ eq "" ? "N/A" : $_} split (/,/, $string,-1);
The ,-1 is needed at the end to force split to include any empty fields at the end of the string.