How to read a input file in an array in c++ - c++

Question

I'm trying to store hexadecimal values into some form of an array from a file then change those numbers to binary. So far the program I wrote is only collects the last value. The file looks something like this. note(a 1 or 0 is before each hex value)
1 408ed4
0 10019d94
0 408ed8
1 10019d88
0 408edc
0 1001322
My code is #include
#include <fstream>
#include <string>
#include <cstdlib>
#include <bitset>
#include <sstream>
#define MAX_ADDRESSES 1000000
using namespace std;
int main(int argc, char **argv) {
//Declare variables
int szL1 = atoi(argv[2]);
int szL2 = atoi(argv[4]);
string type = argv[6]; //Determines the type of cache
//string fileN = argv[7];
int info, i = 1, j = 1; //info is what is read in, i & j are testing variables
string *rd_add = new string[MAX_ADDRESSES]; //set the max string length for what's read
string *wrt_add = new string[MAX_ADDRESSES]; //set the max string length for what's written
int total = 0; //total # of reads/writes
int rds = 0; //base # of reads
int wrt = 0; //base # of writes
int array_size = 1001024;
char *array = new char[array_size];
int position = 0;
ifstream fin("big_trace.txt");//open big trace file********
if (fin.is_open()){
cout << "File opened successfully" << endl;
while (!fin.eof() && position < array_size){
fin.get(array[position]);
position++;
}
array[position - 1] = '\0';
for (int x = 0; array[x] != '\0'; i++){
cout << array[i];
}
}
else{
cout << "File could not be opened" << endl;
}
//check for a power of 2 for szL1
while (1)
{
if (i == szL1)
break;
//Error Message
else if (i > szL1)
{
cout << "Error. sizeL1 must be a power of 2. Please try again." << endl << endl;
return 0;
}
i *= 2;
}
//cout << "size1 " << szL1 << endl;
//check for a power of 2 for szL2
while (1)
{
if (j == szL2)
break;
//Error
else if (j > szL2)
{
cout << "Error. sizeL2 must be a power of 2. Please try again." << endl << endl;
return 0;
}
j *= 2;
}
//cout << "size2 " << szL2 << endl;
//Check to see if szL2 is larger than szL1
if (szL2 <= szL1)
{
cout << "Error. sizeL2 must be larger than sizeL1. Please try again." << endl << endl;
return 0;
}
//Read file contents*****
while (cin >> info) //check this part
{
//If it is a 1, increment read files
if (info == 1)
{
cin >> rd_add[i++];
rds++;
}
else if (info == 0)
{
cin >> wrt_add[j++];
wrt++;
}
else
{
continue;
}
}
total = rds + wrt;
//Print the arguments read
cout << endl << "Input Parameters read:" << endl;
cout << "SizeL1: " << szL1 << endl;
cout << "SizeL2: " << szL2 << endl;
cout << "Type: " << type << endl;
//Print file stats
cout << endl << "Memory References Read from File" << endl;
cout << "Total: " << total << endl;
cout << rds << " Reads" << endl;
cout << wrt << " Writes" << endl;
return 0;
}

Answer 1

If you want to get only the hexadecimal values in a vector and your file is as you said you can just do it as below:
String hexValue, dummy;
Vector<String> hexValueVector;
ifstream fin("big_trace.txt");//open big trace file********
if (fin.is_open()){
cout << "File opened successfully" << endl;
while (!fin.eof()){
fin >> dummy >> hexValue;
hexValueVector.push_back(hexValue);
....//your remaining code
Do not forget to include the Vector library.
#include <vector>
Hope this will help you.
EDITED:
if you need the dummy too you have just to put both values in a structure:
struct myStructure{
String dummy;
String hexValue;
};
and instead of creating a vector of string you create a vector of myStructure:
Vector<myStructure> myStructureVector;
to fill your vector you have just to do this:
myStructure myStructure;
if(fin.is_open()){
...
while (!fin.eof()){
fin >> myStructure.dummy >> myStructure.hexValue;
myStructureVector.push_back(myStructure);
If this solves your problem, please vote for the answer.
About Vector, it is a STL container, if you want more details about it check http://www.cplusplus.com/reference/vector/vector/