How to create pagination in Django? - django

Question

I follow this Document of djangoproject.com : https://docs.djangoproject.com/en/1.8/topics/pagination/. But it is too simple. It is only Next and Previous button.
Now I want create pagination with more features such as http://i.imgur.com/ZiFeAqG.jpg.
This is code:
View.py
def hire(request):
hire_article_list = hire_article.objects.all().order_by('-id')
#hire_article_list = hire_article.objects.order_by("-publication_date")
paginator = Paginator(hire_article_list, 2) # Show 25 contacts per page
page = request.GET.get('page')
try:
hire_article_s = paginator.page(page)
except PageNotAnInteger:
# If page is not an integer, deliver first page.
hire_article_s = paginator.page(1)
except EmptyPage:
# If page is out of range (e.g. 9999), deliver last page of results.
hire_article_s = paginator.page(paginator.num_pages)
#return render_to_response('hire/list.html', {"page_list": page_list})
context = {'hire_article_s': hire_article_s}
return render(request, 'hire/list.html', context)
list.html
{% for j in hire_article_s %}
{# Each "j" is a page_list model object. #}
<li>{{ j.hiring}}</li>
{% endfor %}
{% if hire_article_s.has_previous %}
previous
{% endif %}
<span class="current">
Page {{ hire_article_s.number }} of {{ hire_article_s.paginator.num_pages }}.
</span>
{% if hire_article_s.has_next %}
next
{% endif %}
</span>
</div>

Answer 1

I had a similar need last week and found this super useful gist (https://gist.github.com/jsatt/8183993) that worked fine (though I'm not sure why it wouldn't work till I put request in the function parameters). It's a subclass of django's Paginator function. You could put this in a utility file and call it whenever you want to use Paginate with the range.
For instance, I had mine in a file called utils.py, which is in my core app.
views.py
from core.utils import paginate
def hire(request):
hire_article_list = hire_article.objects.all().order_by('-id')
'''
Show 25 contacts per page, with a page range of 5, which means if you are
on page 8, it shows links to pages 6,7,8,9,10.
'''
hire_article_s = paginate(request, hire_article_list, 25, 5)
context = {'hire_article_s': hire_article_s}
return render(request, 'hire/list.html', context)
list.html
{% if hire_article_s.has_previous %}
previous
{% endif %}
{% for range in hire_article_s.neighbor_range %}
{% if range == hire_article_s.number %}
<li class="pagination__item active ">{{ range }}</li>
{% else %}
<li class="{% if range == hire_article_s.number %}active {% endif %}">{{ range }}</li>
{% endif %}
{% endfor %}
{% if hire_article_s.has_next %}
next
{% endif %}
Hope this helps.
UPDATE
The above code has been edited a bit. I've added the context and the template format. Note that I'm using a loop to go through {{ hire_article_s.neighbor_range }} and print out the page numbers. I also do a check to highlight the current page's number. the This should work, as it's pretty much my own code with your own variable names.