Random Walk with MPI: Why are my messages getting lost? - c++

I am trying to develop a parallel random walker simulation with MPI and C++.
In my simulation, each process can be thought of as a cell which can contain particles (random walkers). The cells are aligned in one dimension with periodic boundary conditions (i.e. ring topology).
In each time step, a particle can stay in its cell or go into the left or right neighbour cell with a certain probability. To make it a bit easier, only the last particle in each cell's list can walk. If the particle walks, it has to be sent to the process with the according rank (MPI_Isend + MPI_Probe + MPI_Recv + MPI_Waitall).
However, after the first step my particles start disappearing, i.e. the messages are getting 'lost' somehow.
Below is a minimal example (sorry if it's still rather long). To better track the particle movements, each particle has an ID which corresponds to the rank of the process in which it started. After each step, each cell prints the IDs of the particles stored in it.
#include <mpi.h>
#include <vector>
#include <iostream>
#include <random>
#include <string>
#include <sstream>
#include <chrono>
#include <algorithm>
using namespace std;
class Particle
{
public:
int ID; // this is the rank of the process which initialized the particle
Particle () : ID(0) {};
Particle (int ID) : ID(ID) {};
};
stringstream msg;
string msgString;
int main(int argc, char** argv)
{
// Initialize the MPI environment
MPI_Init(NULL, NULL);
// Get the number of processes
int world_size;
MPI_Comm_size(MPI_COMM_WORLD, &world_size);
// Get the rank of the process
int world_rank;
MPI_Comm_rank(MPI_COMM_WORLD, &world_rank);
// communication declarations
MPI_Status status;
// get the ranks of neighbors (periodic boundary conditions)
int neighbors[2];
neighbors[0] = (world_size + world_rank - 1) % world_size; // left neighbor
neighbors[1] = (world_size + world_rank + 1) % world_size; // right neighbor
// declare particle type
MPI_Datatype type_particle;
MPI_Type_contiguous (1, MPI_INT, &type_particle);
MPI_Type_commit (&type_particle);
// every process inits 1 particle with ID = world_rank
vector<Particle> particles;
particles.push_back (Particle(world_rank));
// obtain a seed from the timer
typedef std::chrono::high_resolution_clock myclock;
myclock::time_point beginning = myclock::now();
myclock::duration d = myclock::now() - beginning;
unsigned seed2 = d.count();
default_random_engine generator (seed2);
uniform_real_distribution<double> distribution (0, 1);
// ------------------------------------------------------------------
// begin time loop
//-------------------------------------------------------------------
for (int t=0; t<10; t++)
{
// ------------------------------------------------------------------
// 1) write a message string containing the current list of particles
//-------------------------------------------------------------------
// write the rank and the particle IDs into the msgString
msg << "rank " << world_rank << ": ";
for (auto& i : particles)
{
msg << i.ID << " ";
}
msg << "\n";
msgString = msg.str();
msg.str (string()); msg.clear ();
// to print the messages in order, the messages are gathered by root (rank 0) and then printed
// first, gather nums to root
int num = msgString.size();
int rcounts[world_size];
MPI_Gather( &num, 1, MPI_INT, rcounts, 1, MPI_INT, 0, MPI_COMM_WORLD);
// root now has correct rcounts, using these we set displs[] so
// that data is placed contiguously (or concatenated) at receive end
int displs[world_size];
displs[0] = 0;
for (int i=1; i<world_size; ++i)
{
displs[i] = displs[i-1]+rcounts[i-1]*sizeof(char);
}
// create receive buffer
int rbuf_size = displs[world_size-1]+rcounts[world_size-1];
char *rbuf = new char[rbuf_size];
// gather the messages
MPI_Gatherv( &msgString[0], num, MPI_CHAR, rbuf, rcounts, displs, MPI_CHAR,
0, MPI_COMM_WORLD);
// root prints the messages
if (world_rank == 0)
{
cout << endl << "step " << t << endl;
for (int i=0; i<rbuf_size; i++)
cout << rbuf[i];
}
// ------------------------------------------------------------------
// 2) send particles randomly to neighbors
//-------------------------------------------------------------------
Particle snd_buf;
int sndDest = -1;
// 2a) if there are particles left, prepare a message. otherwise, proceed to step 2b)
if (!particles.empty ())
{
// write the last particle in the list to a buffer
snd_buf = particles.back ();
// flip a coin. with a probability of 50 %, the last particle in the list gets sent to a random neighbor
double rnd = distribution (generator);
if (rnd <= .5)
{
particles.pop_back ();
// pick random neighbor
if (rnd < .25)
{
sndDest = neighbors[0]; // send to the left
}
else
{
sndDest = neighbors[1]; // send to the right
}
}
}
// 2b) always send a message to each neighbor (even if it's empty)
MPI_Request requests[2];
for (int i=0; i<2; i++)
{
int dest = neighbors[i];
MPI_Isend (
&snd_buf, // void* data
sndDest==dest ? 1 : 0, // int count <---------------- send 0 particles to every neighbor except the one specified by sndDest
type_particle, // MPI_Datatype
dest, // int destination
0, // int tag
MPI_COMM_WORLD, // MPI_Comm
&requests[i]
);
}
// ------------------------------------------------------------------
// 3) probe and receive messages from each neighbor
//-------------------------------------------------------------------
for (int i=0; i<2; i++)
{
int src = neighbors[i];
// probe to determine if the message is empty or not
MPI_Probe (
src, // int source,
0, // int tag,
MPI_COMM_WORLD, // MPI_Comm comm,
&status // MPI_Status* status
);
int nRcvdParticles = 0;
MPI_Get_count (&status, type_particle, &nRcvdParticles);
// if the message if non-empty, receive it
if (nRcvdParticles > 0) // this proc can receive max. 1 particle from each neighbor
{
Particle rcv_buf;
MPI_Recv (
&rcv_buf, // void* data
1, // int count
type_particle, // MPI_Datatype
src, // int source
0, // int tag
MPI_COMM_WORLD, // MPI_Comm comm
MPI_STATUS_IGNORE // MPI_Status* status
);
// add received particle to the list
particles.push_back (rcv_buf);
}
}
MPI_Waitall (2, requests, MPI_STATUSES_IGNORE);
}
// ------------------------------------------------------------------
// end time loop
//-------------------------------------------------------------------
// Finalize the MPI environment.
MPI_Finalize();
if (world_rank == 0)
cout << "\nMPI_Finalize()\n";
return 0;
}
I ran the simulation with 8 processes and below is a sample of the output. In step 1, it still seems to work well, but beginning with step 2 the particles begin disappearing.
step 0
rank 0: 0
rank 1: 1
rank 2: 2
rank 3: 3
rank 4: 4
rank 5: 5
rank 6: 6
rank 7: 7
step 1
rank 0: 0
rank 1: 1
rank 2: 2 3
rank 3:
rank 4: 4 5
rank 5:
rank 6: 6 7
rank 7:
step 2
rank 0: 0
rank 1:
rank 2: 2
rank 3:
rank 4: 4
rank 5:
rank 6: 6 7
rank 7:
step 3
rank 0: 0
rank 1:
rank 2: 2
rank 3:
rank 4:
rank 5:
rank 6: 6
rank 7:
step 4
rank 0: 0
rank 1:
rank 2: 2
rank 3:
rank 4:
rank 5:
rank 6: 6
rank 7:
I have no ideas what's wrong with the code... Somehow, the combination MPI_Isend + MPI_Probe + MPI_Recv + MPI_Waitall seems not to work... Any help is really appreciated!

There is an error in your code. The following logic (irrelevant code and arguments omitted) is wrong:
MPI_Probe(..., &status);
MPI_Get_count (&status, type_particle, &nRcvdParticles);
// if the message if non-empty, receive it
if (nRcvdParticles > 0)
{
MPI_Recv();
}
MPI_Probe does not remove zero-sized messages from the message queue. The only MPI calls that do so is MPI_Recv and the combination of MPI_Irecv + MPI_Test/MPI_Wait. You must receive all messages, including zero-sized ones, otherwise they will prevent the reception of further messages with the same (source, tag) combination. Although reception of a zero-sized message writes nothing into the receive buffer, it removes the message envelope from the queue and the next matching message could be received.
Solution: move the call to MPI_Recv before the conditional operator.

Related

Deadlock caused by point-to-point communication in MPI, using a loop to send from master to children

I'm attempting to solve a homework problem to debug the following unit test.
Basically the master process generates random integers and sends them to child processes to check for primality, the result is communicated back to the master process, and the algorithm ends.
I know that the loops should be replaced with collective communication, however that is a different part of the question. I want to understand why this code I have here is causing deadlock.
From reading other questions, I know that the number of sends/receives should match each other. However I don't see how this isn't the case in my code.
The current behaviour is that a prime is found, sent back to the master process, at which point the program just hangs - until it's canceled manually using ctrl-C.
I understand that this isn't the idiomatic way of solving this problem, but would really like to know exactly where the bug is in this approach.
thanks!
TEST_CASE("3a - Finding prime numbers", "[MPI]" )
{
int rank, size;
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &size);
// Random number generation
std::minstd_rand generator;
unsigned min(2342), max(12342340);
std::uniform_int_distribution<> distribution(min, max);
// candidates too big, one of the size values is the master node
std::vector<unsigned> candidates(size - 1);
// Main loop continues until a prime is found
int found_prime(0);
while (found_prime == 0) {
if (rank == 0) {
// Create some candidate numbers for each process to test
std::generate(candidates.begin(), candidates.end(),
[&]() { return distribution(generator); });
// Send one to each worker
for (int worker(1); worker < size; ++worker) {
int rc = MPI_Ssend(&candidates[worker - 1], 1, MPI_UNSIGNED,
worker, 0, MPI_COMM_WORLD);
REQUIRE(rc == MPI_SUCCESS);
}
// Receive whether it was prime
for (int worker(1); worker < size; ++worker) {
unsigned result;
int rc = MPI_Recv(&result, 1, MPI_UNSIGNED, worker, 0,
MPI_COMM_WORLD, MPI_STATUS_IGNORE);
REQUIRE(rc == MPI_SUCCESS);
if (result == 1) {
found_prime = candidates[worker - 1];
std::cout << "Worker " << worker << " found prime "
<< found_prime << std::endl;
}
}
} else {
// Receive the candidate to check
unsigned candidate;
int rc = MPI_Recv(&candidate, 1, MPI_UNSIGNED, 0, 0, MPI_COMM_WORLD,
MPI_STATUS_IGNORE);
REQUIRE(rc == MPI_SUCCESS);
// Do the check
unsigned is_prime = mp::IsPrime(candidate) ? 1 : 0;
// Return the result
rc = MPI_Ssend(&is_prime, 1, MPI_UNSIGNED, 0, 0, MPI_COMM_WORLD);
REQUIRE(rc == MPI_SUCCESS);
}
}
std::cout << "Finished" << rank << std::endl;
}
I know nothing about MPI, but in your code, if rank != 0, the while loop can never be exited because found_prime is never set in the else branch (and rank is never changed too).
Edit:
As #DanielLangr said, the slaves will need a way to find out that there's no more work to come and exit (the loop).

MPI (Summation)

I am writing a program that calculates the sum of every number up to 1000. For example, 1+2+3+4+5....+100. First, I assign summation jobs to 10 processors: Processor 0 gets 1-100, Processor 1 gets 101-200 and so on. The sums are stored in an array.
After all summations have been done parallelly, processors send their values to Processor 0 (Processor 0 receives values using nonblocking send/recv) and Processor 0 sums up all the values and displays the result.
Here is the code:
#include <mpi.h>
#include <iostream>
using namespace std;
int summation(int, int);
int main(int argc, char ** argv)
{
int * array;
int total_proc;
int curr_proc;
int limit = 0;
int partial_sum = 0;
int upperlimit = 0, lowerlimit = 0;
MPI_Init(&argc, &argv);
MPI_Comm_size(MPI_COMM_WORLD, &total_proc);
MPI_Comm_rank(MPI_COMM_WORLD, &curr_proc);
MPI_Request send_request, recv_request;
/* checking if 1000 is divisible by number of procs, else quit */
if(1000 % total_proc != 0)
{
MPI_Finalize();
if(curr_proc == 0)
cout << "**** 1000 is not divisible by " << total_proc << " ...quitting..."<< endl;
return 0;
}
/* number of partial summations */
limit = 1000/total_proc;
array = new int [total_proc];
/* assigning jobs to processors */
for(int i = 0; i < total_proc; i++)
{
if(curr_proc == i)
{
upperlimit = upperlimit + limit;
lowerlimit = (upperlimit - limit) + 1;
partial_sum = summation(upperlimit, lowerlimit);
array[i] = partial_sum;
}
else
{
upperlimit = upperlimit + limit;
lowerlimit = (upperlimit - limit) + 1;
}
}
cout << "** Partial Sum From Process " << curr_proc << " is " << array[curr_proc] << endl;
/* send and receive - non blocking */
for(int i = 1; i < total_proc; i++)
{
if(curr_proc == i) /* (i = current processor) */
{
MPI_Isend(&array[i], 1, MPI_INT, 0, i, MPI_COMM_WORLD, &send_request);
cout << "-> Process " << i << " sent " << array[i] << " to Process 0" << endl;
MPI_Irecv(&array[i], 1, MPI_INT, i, i, MPI_COMM_WORLD, &recv_request);
//cout << "<- Process 0 received " << array[i] << " from Process " << i << endl;
}
}
MPI_Finalize();
if(curr_proc == 0)
{
for(int i = 1; i < total_proc; i++)
array[0] = array[0] + array[i];
cout << "Sum is " << array[0] << endl;
}
return 0;
}
int summation(int u, int l)
{
int result = 0;
for(int i = l; i <= u; i++)
result = result + i;
return result;
}
Output:
** Partial Sum From Process 0 is 5050
** Partial Sum From Process 3 is 35050
-> Process 3 sent 35050 to Process 0
<- Process 0 received 35050 from Process 3
** Partial Sum From Process 4 is 45050
-> Process 4 sent 45050 to Process 0
<- Process 0 received 45050 from Process 4
** Partial Sum From Process 5 is 55050
-> Process 5 sent 55050 to Process 0
<- Process 0 received 55050 from Process 5
** Partial Sum From Process 6 is 65050
** Partial Sum From Process 8 is 85050
-> Process 8 sent 85050 to Process 0
<- Process 0 received 85050 from Process 8
-> Process 6 sent 65050 to Process 0
** Partial Sum From Process 1 is 15050
** Partial Sum From Process 2 is 25050
-> Process 2 sent 25050 to Process 0
<- Process 0 received 25050 from Process 2
<- Process 0 received 65050 from Process 6
** Partial Sum From Process 7 is 75050
-> Process 1 sent 15050 to Process 0
<- Process 0 received 15050 from Process 1
-> Process 7 sent 75050 to Process 0
<- Process 0 received 75050 from Process 7
** Partial Sum From Process 9 is 95050
-> Process 9 sent 95050 to Process 0
<- Process 0 received 95050 from Process 9
Sum is -1544080023
Printing the contents of the array:
5050
536870912
-1579286148
-268433415
501219332
32666
501222192
32666
1
0
I'd like to know what is causing this.
If I print the array before MPI_Finalize is invoked it works fine.
The most important flaw your program has is how you divide the work. In MPI, every process is executing the main function. Therefore, you must ensure that all the processes execute your summation function if you want them to collaborate on building the result.
You don't need the for loop. Every process is executing the main separately. They just have different curr_proc values, and you can compute which portion of the job they have to perform based on that:
/* assigning jobs to processors */
int chunk_size = 1000 / total_proc;
lowerlimit = curr_proc * chunk_size;
upperlimit = (curr_proc+1) * chunk_size;
partial_sum = summation(upperlimit, lowerlimit);
Then, how the master process receives all the other processes' partial sum is not correct.
MPI rank values (curr_proc) start form 0 up to MPI_Comm_size output value (total_proc-1).
Only the process #1 is sending/receiving data.
You are using the immediate version of send and receive: MPI_Isend and MPI_recv but you are not waiting until those requests are completed. You should use MPI_Waitall for that purpose.
The correct version would be something like the following:
if( curr_proc == 0 ) {
// master process receives all data
for( int i = 1; i < total_proc; i++ )
MPI_Recv( &array[i], MPI_INT, 1, i, 0, MPI_COMM_WORLD );
} else {
// other processes send data to the master
MPI_Send( &partial_sum, MPI_INT, 1, 0, 0, MPI_COMM_WORLD );
}
This all-to-one communication pattern is known as gather. In MPI there is a function which already performs this functionality: MPI_Gather.
Finally, what you intent to perform is known as reduction: take a given amount of numeric values and generate a single output value by continuously performing a single operation (a sum, in your case). In MPI there is a function which does that, too: MPI_Reduce.
I strongly suggest you to do some basic guided exercises before trying to make your own. MPI is difficult to understand at the beginning. Building a good base is vital for you to be able to add complexity later on. A hands on tutorial is also a good way of getting started into MPI.
EDIT: Forgot to mention that you don't need to enforce an even divission of the problem size (1000 in this case) by the number of resources (total_proc). Depending on the case, you can either assign the remainder to a single process:
chunk_size = 1000 / total_proc;
if( curr_proc == 0 )
chunk_size += 1000 % total_proc;
Or balance it as much as possible:
int remainder = curr_proc < ( 1000 % proc )? 1 : 0;
lowerlimit = curr_proc * chunk_size /* as usual */
+ curr_proc; /* cumulative remainder */
upperlimit = (curr_proc + 1) * chunk_size /* as usual */
+ remainder; /* curr_proc remainder */
The second case, the load unbalance will be as much as 1, while in the first case the load unbalance can reach total_proc-1 in the worst case.
You're only initializing array[i], the element that corresponds to the curr_proc id. The other elements in that array will be uninitialized, resulting in random values. In your send/receive print loop, you only access the initialized element.
I'm not that familiar with MPI so I'm guessing, but you might want to allocate array before calling MPI_Init. Or call MPI_Receive on process 0, not each individual one.

MPI_Scatterv: segmentation fault 11 on process 0 only

I'm trying to scatter values among processes belonging to an hypercube group (quicksort project).
Depending on the amount of processes I either create a new communicator excluding excessive processes, or I duplicate MPI_COMM_WORLD if it fits exactly any hypercube (power of 2).
In both cases, processes other than 0 receive their data, but:
- On first scenario, process 0 throws a segmentation fault 11
- On second scenario, nothing faults, but process 0 received values are gibberish.
NOTE: If I try a regular MPI_Scatter everything works well.
//Input
vector<int> LoadFromFile();
int d; //dimension of hypercube
int p; //active processes
int idle; //idle processes
vector<int> values; //values loaded
int arraySize; //number of total values to distribute
int main(int argc, char* argv[])
{
int mpiWorldRank;
int mpiWorldSize;
int mpiRank;
int mpiSize;
MPI_Init(&argc, &argv);
MPI_Comm_rank(MPI_COMM_WORLD, &mpiWorldRank);
MPI_Comm_size(MPI_COMM_WORLD, &mpiWorldSize);
MPI_Comm MPI_COMM_HYPERCUBE;
d = log2(mpiWorldSize);
p = pow(2, d); //Number of processes belonging to the hypercube
idle = mpiWorldSize - p; //number of processes in excess
int toExclude[idle]; //array of idle processes to exclude from communicator
int sendCounts[p]; //array of values sizes to be sent to processes
//
int i = 0;
while (i < idle)
{
toExclude[i] = mpiWorldSize - 1 - i;
++i;
}
//CREATING HYPERCUBE GROUP: Group of size of power of 2 -----------------
MPI_Group world_group;
MPI_Comm_group(MPI_COMM_WORLD, &world_group);
// Remove excessive processors if any from communicator
if (idle > 0)
{
MPI_Group newGroup;
MPI_Group_excl(world_group, 1, toExclude, &newGroup);
MPI_Comm_create(MPI_COMM_WORLD, newGroup, &MPI_COMM_HYPERCUBE);
//Abort any processor not part of the hypercube.
if (mpiWorldRank > p)
{
cout << "aborting: " << mpiWorldRank <<endl;
MPI_Finalize();
return 0;
}
}
else
{
MPI_Comm_dup(MPI_COMM_WORLD, &MPI_COMM_HYPERCUBE);
}
MPI_Comm_rank(MPI_COMM_HYPERCUBE, &mpiRank);
MPI_Comm_size(MPI_COMM_HYPERCUBE, &mpiSize);
//END OF: CREATING HYPERCUBE GROUP --------------------------
if (mpiRank == 0)
{
//STEP1: Read input
values = LoadFromFile();
arraySize = values.size();
}
//Transforming input vector into an array
int valuesArray[values.size()];
if(mpiRank == 0)
{
copy(values.begin(), values.end(), valuesArray);
}
//Broadcast input size to all processes
MPI_Bcast(&arraySize, 1, MPI_INT, 0, MPI_COMM_HYPERCUBE);
//MPI_Scatterv: determining size of arrays to be received and displacement
int nmin = arraySize / p;
int remainingData = arraySize % p;
int displs[p];
int recvCount;
int k = 0;
for (i=0; i<p; i++)
{
sendCounts[i] = i < remainingData
? nmin+1
: nmin;
displs[i] = k;
k += sendCounts[i];
}
recvCount = sendCounts[mpiRank];
int recvValues[recvCount];
//Following MPI_Scatter works well:
// MPI_Scatter(&valuesArray, 13, MPI_INT, recvValues , 13, MPI_INT, 0, MPI_COMM_HYPERCUBE);
MPI_Scatterv(&valuesArray, sendCounts, displs, MPI_INT, recvValues , recvCount, MPI_INT, 0, MPI_COMM_HYPERCUBE);
int j = 0;
while (j < recvCount)
{
cout << "rank " << mpiRank << " received: " << recvValues[j] << endl;
++j;
}
MPI_Finalize();
return 0;
}
First of all, you are supplying wrong arguments to MPI_Group_excl:
MPI_Group_excl(world_group, 1, toExclude, &newGroup);
// ^
The second argument specifies the number of entries in the exclusion list and should therefore be equal to idle. Since you are excluding a single rank only, the resulting group has mpiWorldSize-1 ranks and hence MPI_Scatterv expects that both sendCounts[] and displs[] have that many elements. Of those only p elements are properly initialised and and the rest are random, therefore MPI_Scatterv crashes in the root.
Another error is the code that aborts the idle processes: it should read if (mpiWorldRank >= p).
I would recommend that the entire exclusion code is replaced by a single call to MPI_Comm_split instead:
MPI_Comm comm_hypercube;
int colour = mpiWorldRank >= p ? MPI_UNDEFINED : 0;
MPI_Comm_split(MPI_COMM_WORLD, colour, mpiWorldRank, &comm_hypercube);
if (comm_hypercube == MPI_COMM_NULL)
{
MPI_Finalize();
return 0;
}
When no process supplies MPI_UNDEFINED as its colour, the call is equivalent to MPI_Comm_dup.
Note that you should avoid using in your code names starting with MPI_ as those could clash with symbols from the MPI implementation.
Additional note: std::vector<T> uses contiguous storage, therefore you could do without copying the elements into a regular array and simply provide the address of the first element in the call to MPI_Scatter(v):
MPI_Scatterv(&values[0], ...);

MPI's Scatterv operation

I'm not sure that I am correctly understanding what MPI_Scatterv is supposed to do. I have 79 items to scatter amounts a variable amount of nodes. However, when I use the MPI_Scatterv command I get ridiculous numbers (as if the array elements of my receiving buffer are uninitialized). Here is the relevant code snippet:
MPI_Init(&argc, &argv);
int id, procs;
MPI_Comm_rank(MPI_COMM_WORLD, &id);
MPI_Comm_size(MPI_COMM_WORLD, &procs);
//Assign each file a number and figure out how many files should be
//assigned to each node
int file_numbers[files.size()];
int send_counts[nodes] = {0};
int displacements[nodes] = {0};
for (int i = 0; i < files.size(); i++)
{
file_numbers[i] = i;
send_counts[i%nodes]++;
}
//figure out the displacements
int sum = 0;
for (int i = 0; i < nodes; i++)
{
displacements[i] = sum;
sum += send_counts[i];
}
//Create a receiving buffer
int *rec_buf = new int[79];
if (id == 0)
{
MPI_Scatterv(&file_numbers, send_counts, displacements, MPI_INT, rec_buf, 79, MPI_INT, 0, MPI_COMM_WORLD);
}
cout << "got here " << id << " checkpoint 1" << endl;
cout << id << ": " << rec_buf[0] << endl;
cout << "got here " << id << " checkpoint 2" << endl;
MPI_Barrier(MPI_COMM_WORLD);
free(rec_buf);
MPI_Finalize();
When I run that code I receive this output:
got here 1 checkpoint 1
1: -1168572184
got here 1 checkpoint 2
got here 2 checkpoint 1
2: 804847848
got here 2 checkpoint 2
got here 3 checkpoint 1
3: 1364787432
got here 3 checkpoint 2
got here 4 checkpoint 1
4: 903413992
got here 4 checkpoint 2
got here 0 checkpoint 1
0: 0
got here 0 checkpoint 2
I read the documentation for OpenMPI and looked through some code examples, I'm not sure what I'm missing any help would be great!
One of the most common MPI mistakes strikes again:
if (id == 0) // <---- PROBLEM
{
MPI_Scatterv(&file_numbers, send_counts, displacements, MPI_INT,
rec_buf, 79, MPI_INT, 0, MPI_COMM_WORLD);
}
MPI_SCATTERV is a collective MPI operation. Collective operations must be executed by all processes in the specified communicator in order to complete successfully. You are executing it only in rank 0 and that's why only it gets the correct values.
Solution: remove the conditional if (...).
But there is another subtle mistake here. Since collective operations do not provide any status output, the MPI standard enforces strict matching of the number of elements sent to some rank and the number of elements the rank is willing to receive. In your case the receiver always specifies 79 elements which might not match the corresponding number in send_counts. You should instead use:
MPI_Scatterv(file_numbers, send_counts, displacements, MPI_INT,
rec_buf, send_counts[id], MPI_INT,
0, MPI_COMM_WORLD);
Also note the following discrepancy in your code that might as well be a typo while posting the question here:
MPI_Comm_size(MPI_COMM_WORLD, &procs);
^^^^^
int send_counts[nodes] = {0};
^^^^^
int displacements[nodes] = {0};
^^^^^
While you obtain the number of ranks in the procs variable, nodes is used in the rest of your code. I guess nodes should be replaced by procs.

MPI double rings, max, min and average

We only have been working on MPI for about one day in my computer programming class, and I now have to write a program for it. I am to write a program that organizes processes into two rings.
The first ring begins with process 0 and proceeds to send a message to the next even process and the last process sending its message back to process 0. For example, 0--> 2 --> 4 --> 6 --> 8 --> 0 (but it goes all the way up to 32 instead of 8). The next ring is the same, but begins with process 1 and sends to the previous off process and then back to 1. For example, 1--> 9--> 7--> 5 --> 3--> 1.
Also, I am supposed to find the max, min, and average of a very large array of integer numbers. I will have to scatter the array into pieces to each process, have each process compute a partial answer, and then reduce back the answer together on process 0 after everyone is done.
Finally, I am to scatter across the processes and each process will have to count how many of each letter appears in a section. That part really makes no sense to me. But we have just learned the very basics, so no fancy stuff please! Here's what I have so far, I have commented out some things to just remind myself of some stuff, so please ignore if necessary.
#include <iostream>
#include "mpi.h"
using namespace std;
// compile: mpicxx program.cpp
// run: mpirun -np 4 ./a.out
int main(int argc, char *argv[])
{
int rank; // unique number associated with each core
int size; // total number of cores
char message[80];
char recvd[80];
int prev_node, next_node;
int tag;
MPI_Status status;
// start MPI interface
MPI_Init(&argc, &argv);
MPI_Comm_size(MPI_COMM_WORLD, &size);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
sprintf(message, "Heeeelp! from %d", rank);
MPI_Barrier(MPI_COMM_WORLD);
next_node = (rank + 2) % size;
prev_node = (size + rank - 2) % size;
tag = 0;
if (rank % 2) {
MPI_Send(&message, 80, MPI_CHAR, prev_node, tag, MPI_COMM_WORLD);
MPI_Recv(&recvd, 80, MPI_CHAR, next_node, tag, MPI_COMM_WORLD, &status);
} else {
MPI_Send(&message, 80, MPI_CHAR, next_node, tag, MPI_COMM_WORLD);
MPI_Recv(&recvd, 80, MPI_CHAR, prev_node, tag, MPI_COMM_WORLD, &status);
}
cout << "* Rank " << rank << ": " << recvd << endl;
//max
int large_array[100];
rank == 0;
int max = 0;
MPI_Scatter(&large_array, 1, MPI_INT, large_array, 1, MPI_INT, 0, MPI_COMM_WORLD);
MPI_Reduce(&message, max, 1, MPI_INT, MPI_MAX, 0, MPI_COMM_WORLD);
MPI_Finalize();
return 0;
}
I have a small suggestion about this:
dest = rank + 2;
if (rank == size - 1)
dest = 0;
source = rank - 2;
if (rank == 0)
source = size - 1;
I think dest and source, as names, are going to be confusing (as both are destinations of messages, depending on the value of rank). Using the % operator might help improve clarity:
next_node = (rank + 2) % size;
prev_node = (size + rank - 2) % size;
You can select whether to receive or send to next_node and prev_node based on the value of rank % 2:
if (rank % 2) {
MPI_Send(&message, 80, MPI_CHAR, prev_node, tag, MPI_COMM_WORLD);
MPI_Recv(&message, 80, MPI_CHAR, next_node, tag, MPI_COMM_WORLD, &status);
} else {
MPI_Send(&message, 80, MPI_CHAR, next_node, tag, MPI_COMM_WORLD);
MPI_Recv(&message, 80, MPI_CHAR, prev_node, tag, MPI_COMM_WORLD, &status);
}
Doing this once or twice is fine, but if you find your code littered with these sorts of switches, it'd make sense to place these ring routines in a function and pass in the next and previous nodes as parameters.
When it comes time to distribute your arrays of numbers and arrays of characters, keep in mind that n / size will leave a remainder of n % size elements at the end of your array that also need to be handled. (Probably on the master node, just for simplicity.)
I added a few more output statements (and a place to store the message from the other nodes) and the simple rings program works as expected:
$ mpirun -np 16 ./a.out | sort -k3n
* Rank 0: Heeeelp! from 14
* Rank 1: Heeeelp! from 3
* Rank 2: Heeeelp! from 0
* Rank 3: Heeeelp! from 5
* Rank 4: Heeeelp! from 2
* Rank 5: Heeeelp! from 7
* Rank 6: Heeeelp! from 4
* Rank 7: Heeeelp! from 9
* Rank 8: Heeeelp! from 6
* Rank 9: Heeeelp! from 11
* Rank 10: Heeeelp! from 8
* Rank 11: Heeeelp! from 13
* Rank 12: Heeeelp! from 10
* Rank 13: Heeeelp! from 15
* Rank 14: Heeeelp! from 12
* Rank 15: Heeeelp! from 1
You can see the two rings there, each in their own direction:
#include <iostream>
#include "mpi.h"
using namespace std;
// compile: mpicxx program.cpp
// run: mpirun -np 4 ./a.out
int main(int argc, char *argv[])
{
int rank; // unique number associated with each core
int size; // total number of cores
char message[80];
char recvd[80];
int prev_node, next_node;
int tag;
MPI_Status status;
// start MPI interface
MPI_Init(&argc, &argv);
MPI_Comm_size(MPI_COMM_WORLD, &size);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
sprintf(message, "Heeeelp! from %d", rank);
// cout << "Rank " << rank << ": " << message << endl;
MPI_Barrier(MPI_COMM_WORLD);
next_node = (rank + 2) % size;
prev_node = (size + rank - 2) % size;
tag = 0;
if (rank % 2) {
MPI_Send(&message, 80, MPI_CHAR, prev_node, tag, MPI_COMM_WORLD);
MPI_Recv(&recvd, 80, MPI_CHAR, next_node, tag, MPI_COMM_WORLD, &status);
} else {
MPI_Send(&message, 80, MPI_CHAR, next_node, tag, MPI_COMM_WORLD);
MPI_Recv(&recvd, 80, MPI_CHAR, prev_node, tag, MPI_COMM_WORLD, &status);
}
cout << "* Rank " << rank << ": " << recvd << endl;
//cout << "After - Rank " << rank << ": " << message << endl;
// end MPI interface
MPI_Finalize();
return 0;
}
When it comes time to write the larger programs (array min, max, avg, and word counts), you'll need to change things slightly: only rank == 0 will be sending messages at the start; it will send to all the other processes their pieces of the puzzle. All the other processes will receive, do the work, then send back the results. rank == 0 will then need to integrate the results from all of them into a coherent single answer.