Strange pointer behaviour with chars - c++

Question

I was playing around with structures and their pointers when I observed a strange behaviour. In the following code I made a structure containing: id, last_name_inital, full_name and first_name_inital. Looking at the memory addresses of the int and string works fine but looking at the chars gives broken output. I added to chars outside the structure which show the same behaviour. Looking at just a char output and it's pointer output gives the same char back so no address.
#include <iostream>
#include <string>
using namespace std;
struct entry
{
int id = 1;
char last_name_inital = 'S';
string full_name = "August Smith";
char first_name_inital = 'A';
};
int main()
{
entry aug;
entry *p_aug = &aug;
char alpha ='A';
char *p_alpha = α
char sirra ='S';
char *p_sirra = &sirra;
cout << "Printing structure address" << endl;
cout << p_aug << endl;
cout << "\n";
cout << "Printing id and it's address" << endl;
cout << p_aug->id << " " << aug.id << endl;
cout << &p_aug->id << " " << &aug.id << endl;
cout << "\n";
cout << "Printing last_name_inital and it's address" << endl;
cout << p_aug->last_name_inital <<" "<< aug.last_name_inital << endl;
cout <<&p_aug->last_name_inital<<" "<< &aug.last_name_inital << endl;
cout << "\n";
cout << "Printing full_name and it's address" << endl;
cout << p_aug->full_name << " " << aug.full_name << endl;
cout << &p_aug->full_name << " " << &aug.full_name << endl;
cout << "\n";
cout << "Printing first_name_inital and it's address" << endl;
cout << p_aug->first_name_inital <<" "<<aug.first_name_inital<< endl;
cout <<&p_aug->first_name_inital<<" "<<&aug.first_name_inital<< endl;
cout << "\n";
cout << "Printing alpha and it's address" << endl;
cout << *p_alpha << " " << alpha << endl;
cout << p_alpha << " " << &alpha << endl;
cout << "\n";
cout << "Printing sirra and it's address" << endl;
cout << *p_sirra << " " << sirra << endl;
cout << p_sirra << " " << &sirra << endl;
cout << "\n";
}
which gives the following output (compiled and written with geany, g++, linux):
Printing structure address
0x7fff01772360
Printing id and it's address
1 1
0x7fff01772360 0x7fff01772360
Printing full_name and it's address
S S
S S
Printing last_name_inital and it's address
August Smith August Smith
0x7fff01772368 0x7fff01772368
Printing last_name_inital and it's address
A A
A# A#
Printing alpha and it's address
A A
AS#w� AS#w�
Printing alpha and it's address
S S
S#w� S#w�
on every run the last output changes, so obviously something is changing.
An online search gave only this question, which sort of touches the same background but not really or I don't get it. character pointers in C++
Basically my main questions are what is happening there and is it possible to output a char pointer, so where it is stored?
Thank you
EDIT:
The quick responses solve the question of how to print out the pointer address of a char. By using:(void*)(&char_name)
However it leaves me wondering why the cout values of the normal chars change but the values of the chars inside the structure stay the same on rerun. Especially also because the behaviour for the char 'S' in the structure with cout is the mentioned operator-overloaded-just-give-back-the-char-itself but not for 'A' and also not for the normal chars outside the structure.
Can anyone explain those differences? Or even does this not occur for you?

Answer 1

You could cast the char * to a void *. The problem is, that the operator<< is overloaded to read char * as c_string.
cout << "Printing last_name_inital and it's address" << endl;
cout << p_aug->last_name_inital <<" "<< aug.last_name_inital << endl;
cout << (void*)(&p_aug->last_name_inital) <<" "<< (void*)(&aug.last_name_inital) << endl;
cout << "\n";

Answer 2

ostream& operator<< (ostream& os, const char* s); is to write sequence of char not address, cast to void* to get address.

Answer 3

Typically, addresses vary between program executions because the operating system happens to have different memory locations available or deliberately shuffles around data for security reasons.
Inspecting pointer values is only useful for comparing pointers in the same program instance: for example, p_aug and &aug have the same value.