I need a regular expression to check that an input can contain only digits,but cannot be 0, the number should be a digit between 1 and 12 digits.
So far I have tried that:
data-ng-patern="/^[1-9]{1,12}$/"
However doing that I don't allow 0 in any case so for example the input 120, would not match my pattern.
How can I accomplish that?
Thank you very much.
You must use /^[1-9][0-9]{0,11}$/
Please have a look at the working demo.
Input:
0
123
120
023
Matches:
123
120
Related
I'm a regex newbie and I've got a valid regex for SSNs:
/^(\d{3}(\s|-)?\d{2}(\s|-)?\d{4})|[\d{9}]*$/
But I now need to expand it to accept either an SSN or another alphanumeric ID of 7 characters, like this:
/^[a-zA-Z0-9]{7}$/
I thought it'd be as simple as grouping the SSN and adding an OR | but my tests are still failing. This is what I've got now:
/^((\d{3}(\s|-)?\d{2}(\s|-)?\d{4})|[\d{9}])|[a-zA-Z0-9]{7}$/
What am I doing wrong? And is there a more elegant way to say either SSN or my other ID?
Thanks for any helpful tips.
Valid SSNs:
123-45-6789
123456789
123 45 6789
Valid ID: aCe8999
I have modified your first regex also a bit, below is demo program. This is as per my understanding of the problem. Let me know if any modification is needed.
my #ids = (
'123-45-6789',
'123456789',
'123 45 6789',
'1234567893434', # invalid
'123456789wwsd', # invalid
'aCe8999',
'aCe8999asa' # invalid
);
for (#ids) {
say "match = $&" if $_ =~ /^ (?:\d{3} ([ \-])? \d{2} \1? \d{4})$ | ^[a-zA-Z0-9]{7}$/x ;
}
Output:
match = 123-45-6789
match = 123456789
match = 123 45 6789
match = aCe8999
Your first regex got some problems. The important thing about it is that it accepts {{{{}}}}} which means you have built a wrong character class. Also it matches 123-45 6789 (notice the mixture of space and dash).
To mean OR in regular expressions you need to use pipe | and remember that each symbol belongs to the side that it resides. So for example ^1|2$ checks for strings beginning with 1 or ending with 2 not only two individual input strings 1 and 2.
To apply the exact match you need to do ^1$|^2$ or ^(1|2)$.
With the second regex ^[a-zA-Z0-9]{7}$ you are not saying alphanumeric ID of 7 characters but you are saying numeric, alphabetic or alphanumeric. So it matches 1234567 too. If this is not a problem, the following regex is the solution by eliminating the said issues:
^\d{3}([ -]?)\d\d\1\d{4}$|^[a-zA-Z0-9]{7}$
I am working on siebel CRM. I have space issues in my regex.
I have SSN numbers in these formats
123 456 789
123-456-789
123 45 6789
I need to dispaly my SSN Like XXX-XX-4567. My regex looks like
([\s.:])(?!000)(?!666)(?!9[0-9][0-9])\d{3}[- ]?(?!00)\d{2}[- ]?(?!0000)\d{4})([\s.:]) |
([\s.:])(?!000)(?!666)(?!9[0-9][0-9])\d{3}[- ]?(?!00)\d{3}[- ]?(?!00)\d{3})([\s.:]).
How can I remove all blank spaces in the above expression and display the format as i mentioned above?
It looks like there are syntax errors in your RegEx. There are a couple of unmatched brackets, at (?!0000)\d{4}) on the first section, the last bracket is unmatched.
I think I've managed to write the regex you're looking for, but a bit shorter than the one you were using:
([\s.:])((?!000)(?!666)(?!9[0-9]{2})\d{3})[- ]?((?!00)\d{2,3})[- ]?((?!00)\d{3,4})([\s.:])
This will match the following strings:
123-12-1234
123 456 789
123-456-789
123 45 6789
But will not match the following:
666-45-1234
abc-12-1232
123-00-1233
123-224-0011
123 224 0000
There are several capture groups here:
Matches any character (you may want to change this).
Matches the first three digit number.
Matches the second, two or three digit number.
Matches the third, three or four digit number.
Matches any character (you may want to change this).
You should be able to reconstruct the SSN in the format you need with the result of this RegEx.
I have been trying with a regex ^\d{0,12}(\.{0,1}\d{0,2})$.
Valid matches:
.22
0.22
123456789012.01
123.2
123.
125
120.00
125444
123456789123.
Invalid match
1234567891232
12345678912345
How to restrict invalid matches as this regex is working fine for all other cases
now i have to restrict the digits before decimal to just 12, i hope now u all will get what i need.
I think you want something like this,
^(?:\d{0,12}\.\d{0,2}|\d{0,12})$
DEMO
Well I tried to sum it up in the title.
I need a reg ex to match numbers and commas, but not numbers starting with 0 unless it's 0,number
My users enter hours in a field, so they have to be able to enter 0,3 hours, but they are not allowed to write 002 or 09.
I have this reg ex
^[0-9]*\,?[0-9]+$
How can I extend it to not allow start with 0 unless the 0 is followed by a comma
Another one :)
^(0|[1-9]\d*(|,\d+)|0,\d+)$
This one should suit your needs:
^0,\d*[1-9]|[1-9]\d*$
either 0,\d*[1-9]: a 0, followed by a comma, followed by 0 or more digit, followed by one digit between 1 and 9
or [1-9]\d*: a digit between 1 and 9, followed by zero or more digit
Matches:
0,3
0,03
3
30
Doesn't match:
0
0,0
0,30
03
You don't need to force everything into a single regex to do this.
It will be far clearer if you use multiple regexes, each one making a specific check.
if ( /^[0-9]+,[0-9]+$/ || /^[1-9][0-9]*$/ )
Here we are making two different checks. "Either this one matches, or the other one matches", and then you don't have to jam both conditions into one regex.
Let the expressive form of your host language be used, rather than trying to cram logic into a regex.
Can someone give me a regular expression for a number to be between 1 and 5, single digit
e.g. input has to be a number between 1 and 5 , 55 or 23 would not match
Try using anchors:
/^[1-5]$/
Explanation:
^ Start of line/string.
[1-5] A digit between 1 and 5.
$ End of line/string.
Would it not be simpler to check it as a number (ie if(x>=1 && x<=5) or something similar) rather than using a regex?
Much more concise to say
if(x> 0 and x<5)
IMHO
Maybe this should do
[1-5]