I want to convert text to sha1 in django. But, i'm not find the way how to do it if field attribut wrapped by the form.
This is my views:
def ubah_password_email(request, pk):
#cek session
if 'username' in request.session and request.session['hak_akses'] == 'user':
user = get_object_or_404(User, pk=pk) #ambil id dengan get
profile = UserProfile.objects.filter(user=user).first()
email_form = EmailForm(data=request.POST, instance=profile) #gunakan instance untuk mengambil data yang sudah ada
users = User.objects.all()
if request.POST:
if email_form.is_valid():
email = email_form.save(commit=False)
email.save()
return redirect('home')
else:
email_form = EmailForm(instance=profile)
data = {
'email_form': email_form,
'object_list': users,
}
return render(request, 'ubah_password_email.html', data)
else:
return HttpResponseRedirect('/simofa/logout')
This is my model
class UserProfile(models.Model):
user = models.OneToOneField(User) #digunakan untuk relasi ke model User (default) alias UserProfile adalah sebagai extending model
CATEGORY_CHOICES = (
('admin','Admin'),
('user','User'),
)
hak_akses = models.CharField(max_length=100, choices = CATEGORY_CHOICES)
password_email = models.CharField(max_length=100, blank=True)
password_pckelas = models.CharField(max_length=100, blank=True)
# Override the __unicode__() method to return out something meaningful!
def __unicode__(self):
return self.user.username
This is my forms
class EmailForm(forms.ModelForm):
password_email = forms.CharField(widget=forms.PasswordInput())
class Meta:
model = UserProfile
fields = ('password_email',)
i'm trying using this and this reference. But, i still can't convert text to sha1?
I'm very grateful for your input. So, please help me :)
I'm not sure why you want or need a second password field. But make_password allows you to generate a hashed password:
from django.contrib.auth.hashers import make_password
Docs: https://docs.djangoproject.com/en/1.7/topics/auth/passwords/#django.contrib.auth.hashers.make_password
Source: https://github.com/django/django/blob/master/django/contrib/auth/hashers.py#L58
Related
im trying to create a child and parent objects at the same time with same form.
After migrations, i have two tables, user as always and doctor, whith the relationship with user in a extra column called user_ptr_id.
models.py:
class Doctor(User):
collegiated = models.CharField(verbose_name="Nº Colegiado", max_length=20, null=True, blank=True)
phone = models.CharField(verbose_name="Teléfono", max_length=12, null=True, blank=True)
class Patient(User):
age = models.PositiveIntegerField(verbose_name="Edad", blank=True)
forms.py:
class DoctorForm(forms.ModelForm):
class Meta:
model = app_models.Doctor
fields = ['username', 'email', 'password']
view.py:
if request.method == 'POST:
form = DoctorForm(request.POST.copy())
if form.is_valid():
forms.save()
else:
form = DoctorForm()
return ...
The two objects are created, doctor and user, well related with user_ptr_id but the user password appears unencrypted.
¿ How can i integrate UserCreationForm on child models ?
¿ How can i solve this issue ?
Anybody could help me please?
Thanks in advance.
use this in your views.py like this
also import make password
from django.contrib.auth.hashers import make_password
def user_signup(request):
if request.method == "POST":
user_form = userSignup(request.POST)
phone = request.POST['phone']
address = request.POST['address']
pincode = request.POST['pincode']
if user_form.is_valid() :
# Hash password using make_password() function
user = user_form.save(commit=False)
user.password = make_password(user.password)
user.save()
...
I'm trying to use a ModelChoiceField to display options populated from model, and when a user selects a choice, store that method in a different model.
I'm using a standard form instead of a ModelForm, because I wasn't able to get the form to display how I wanted to when using a Modelform.
My issue is that in my form save method, a new instance is created, which is not what I want.
Here are the relevant models:
class Client(models.Model):
client_email = models.EmailField(max_length = 254)
first_name = models.CharField(max_length=200)
last_name = models.CharField(max_length=200)
phone = PhoneField(blank=True)
assigned_manager = models.ForeignKey(Manager, on_delete=models.CASCADE, blank=True, null=True)
created_date = models.DateTimeField(default=timezone.now)
#property
def full_name(self):
return '{0} {1}'.format(self.first_name, self.last_name)
class Manager(models.Model):
first_name = models.CharField(max_length=200)
last_name = models.CharField(max_length=200)
manager_email = models.EmailField(max_length = 254)
username = models.OneToOneField(settings.AUTH_USER_MODEL, on_delete=models.CASCADE, blank=True, null=True)
#property
def full_name(self):
return '{0} {1}'.format(self.first_name, self.last_name)
My view:
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
form = AssignManagerForm()
if request.method == "POST":
form = AssignManagerForm(request.POST)
if form.is_valid():
form.save()
return render(request, 'mysite/manageclient.html', {})
else:
form = AssignManagerForm()
context = {
'client': client,
'urlid': urlid,
'form': form,
}
return render(request, 'mysite/manageclient.html', context)
And my forms.py
class AssignManagerForm(forms.Form):
full_name = forms.ModelChoiceField(queryset=Manager.objects.all())
def save(self):
data = self.cleaned_data
client = Client(assigned_manager=data['full_name'])
client.save()
What I need to do is pass the urlid in my view to my save method in my forms.py, but I am unsure how to do that. Even if i could do that, I'm not sure how to modify form save to use urlid to refer to a specific record and set only the assigned_manager record.
Additionally, while I want the meta field to be used to display the form, I know it isn't what should be being passed to the assigned_manager field. How would I pass a Manager of instance to establish the foreign key relationship?
edit: edited to correct queryset in forms.py as per comments
Here is a solution using a ModelForm, by using a ModelForm you no longer have to manually set attributes on save or provide initial values when updating an existing instance.
The field assigned_manager will still be named assigned_manager but it's label can be overridden to be whatever you want it to be by passing labels in the ModelForm.Meta
class AssignManagerForm(forms.ModelForm):
class Meta:
model = Client
fields = ['assigned_manager']
labels = {'assigned_manager': 'Full name'}
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
if request.method == "POST":
form = AssignManagerForm(request.POST, instance=client)
if form.is_valid():
client = form.save()
# The general convention is to redirect after a successful POST
else:
form = AssignManagerForm(instance=client)
context = {
'client': client,
'urlid': urlid,
'form': form,
}
return render(request, 'mysite/manageclient.html', context)
Instead of saving it in form, you can directly do this operation in view. For example:
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
if request.method == "POST":
form = AssignManagerForm(request.POST)
if form.is_valid():
client.assigned_manager = form.cleaned_data['full_name']
client.save()
return render(request, 'mysite/manageclient.html', {})
I'm trying to display a form (ModelForm) with a select field filtered by currently logged in user. The select field in this case contains a list of categories. I want to display only the categories which "belong" to the currently logged in user. The category field is a foreign key to the IngredienceCategory model.
Here is what I've come up with so far but it's giving me an error (unexpected keyword queryset). Any ideas what I'm doing wrong?
# models.py
class IngredienceCategory(models.Model):
name = models.CharField(max_length=30)
user = models.ForeignKey(User, null=True, blank=True)
class Meta:
verbose_name_plural = "Ingredience Categories"
def __unicode__(self):
return self.name
class Ingredience(models.Model):
name = models.CharField(max_length=30)
user = models.ForeignKey(User, null=True, blank=True)
category = models.ForeignKey(IngredienceCategory, null=True, blank=True)
class Meta:
verbose_name_plural = "Ingredients"
def __unicode__(self):
return self.name
class IngredienceForm(ModelForm):
class Meta:
model = Ingredience
fields = ('name', 'category')
# views.py
def home(request):
if request.user.is_authenticated():
username = request.user.username
email = request.user.email
foods = Food.objects.filter(user=request.user).order_by('name')
ingredients = Ingredience.objects.filter(user=request.user).order_by('name')
ingrcat = IngredienceCategory.objects.filter(user=request.user)
if request.method == 'POST':
form = IngredienceForm(request.POST)
if form.is_valid():
# Create an instance of Ingredience without saving to the database
ingredience = form.save(commit=False)
ingredience.user = request.user
ingredience.save()
else:
# How to display form with 'category' select list filtered by current user?
form = IngredienceForm(queryset=IngredienceCategory.objects.filter(user=request.user))
context = {}
for i in ingredients:
context[i.category.name.lower()] = context.get(i.category.name.lower(), []) + [i]
context2 = {'username': username, 'email': email, 'foods': foods, 'ingrcat': ingrcat, 'form': form,}
context = dict(context.items() + context2.items())
else:
context = {}
return render_to_response('home.html', context, context_instance=RequestContext(request))
That's happening because ModelForm does not take a queryset keyword.
You can probably achieve this by setting the queryset on the view:
form = IngredienceForm()
form.fields["category"].queryset =
IngredienceCategory.objects.filter(user=request.user)
See related question here.
Here i have another suggestion to solve the problem. You can pass request object in your form object inside view.
In view.py just pass the request object.
form = IngredienceForm(request)
In your forms.py __init__ function also add request object
from models import IngredienceCategory as IC
class IngredienceForm(ModelForm):
class Meta:
model = Ingredience
fields = ('name', 'category')
def __init__(self, request, *args, **kwargs):
super(IngredienceForm, self).__init__(*args, **kwargs)
self.fields['name'].queryset = IC.objects.filter(user=request.user)
This filter always will be applied whenever you initialize your form .
I have a simple model with 2 classes:
class Company(models.Model):
company_name = models.CharField(default='', max_length=128, blank=True, null=True)
class Visitor(models.Model):
visitor_company = models.ForeignKey(Company)
visitor_name = models.CharField(default='', max_length=128, blank=False, null=False)
I also have a simple form:
class VisitorForm(forms.ModelForm):
visitor_company = forms.CharField()
class Meta:
model = Visitor
fields = "__all__"
And here is the view.py code:
def home(request):
form = Visitor()
if request.method == "POST":
form = Visitor(request.POST)
if form.is_valid():
obj, created = Visitor.objects.get_or_create(**form.cleaned_data)
if created:
messages.add_message(request, messages.SUCCESS, 'Visitor added.')
else:
messages.add_message(request, messages.INFO, 'Visitor exists : %s' % obj.visitor_name)
return redirect('visitors')
context = { 'form': form }
return render(request, "visitors/home.html", context)
I have set visitor_company as a CharField as I want to use Typeahead for users to specify the ForeignKey, rather than Django's built in dropdown (which would appear if I did not set the input type).
However, when I use this method, even if I input a valid company_name in the visitor_company field, I get Cannot assign "XXX": "Visitor.visitor_company" must be a "Company" instance.
How do I input a Company instance? Is it also possible to use get_or_create on a ForeignKey like this if the Company record doesn't exist?
This is untested code, so consider this a starting point, no real solution:
forms.py
class VisitorForm(forms.ModelForm):
visitor_company = forms.CharField()
def clean_visitor_company(self):
vc = self.cleanded_data['visitor_company']
try:
vc_object = Company.objects.get(company_name=vc)
except Company.DoesNotExist:
vc_object = Company.objects.create(company_name=vc)
return vc_object
class Meta:
model = Visitor
fields = "__all__"
views.py
def home(request):
form = VisitorForm(request.POST or None)
if form.is_valid():
form.save()
return redirect('visitors')
return render(request, "visitors/home.html", { 'form': form })
I'm trying to display a form (ModelForm) with a select field filtered by currently logged in user. The select field in this case contains a list of categories. I want to display only the categories which "belong" to the currently logged in user. The category field is a foreign key to the IngredienceCategory model.
Here is what I've come up with so far but it's giving me an error (unexpected keyword queryset). Any ideas what I'm doing wrong?
# models.py
class IngredienceCategory(models.Model):
name = models.CharField(max_length=30)
user = models.ForeignKey(User, null=True, blank=True)
class Meta:
verbose_name_plural = "Ingredience Categories"
def __unicode__(self):
return self.name
class Ingredience(models.Model):
name = models.CharField(max_length=30)
user = models.ForeignKey(User, null=True, blank=True)
category = models.ForeignKey(IngredienceCategory, null=True, blank=True)
class Meta:
verbose_name_plural = "Ingredients"
def __unicode__(self):
return self.name
class IngredienceForm(ModelForm):
class Meta:
model = Ingredience
fields = ('name', 'category')
# views.py
def home(request):
if request.user.is_authenticated():
username = request.user.username
email = request.user.email
foods = Food.objects.filter(user=request.user).order_by('name')
ingredients = Ingredience.objects.filter(user=request.user).order_by('name')
ingrcat = IngredienceCategory.objects.filter(user=request.user)
if request.method == 'POST':
form = IngredienceForm(request.POST)
if form.is_valid():
# Create an instance of Ingredience without saving to the database
ingredience = form.save(commit=False)
ingredience.user = request.user
ingredience.save()
else:
# How to display form with 'category' select list filtered by current user?
form = IngredienceForm(queryset=IngredienceCategory.objects.filter(user=request.user))
context = {}
for i in ingredients:
context[i.category.name.lower()] = context.get(i.category.name.lower(), []) + [i]
context2 = {'username': username, 'email': email, 'foods': foods, 'ingrcat': ingrcat, 'form': form,}
context = dict(context.items() + context2.items())
else:
context = {}
return render_to_response('home.html', context, context_instance=RequestContext(request))
That's happening because ModelForm does not take a queryset keyword.
You can probably achieve this by setting the queryset on the view:
form = IngredienceForm()
form.fields["category"].queryset =
IngredienceCategory.objects.filter(user=request.user)
See related question here.
Here i have another suggestion to solve the problem. You can pass request object in your form object inside view.
In view.py just pass the request object.
form = IngredienceForm(request)
In your forms.py __init__ function also add request object
from models import IngredienceCategory as IC
class IngredienceForm(ModelForm):
class Meta:
model = Ingredience
fields = ('name', 'category')
def __init__(self, request, *args, **kwargs):
super(IngredienceForm, self).__init__(*args, **kwargs)
self.fields['name'].queryset = IC.objects.filter(user=request.user)
This filter always will be applied whenever you initialize your form .