Hello I'm working on a project and I'm a beginner in C++
I have a list of map
list<map<int,double>> voisin;
And I would like to know if it's possible to check if the element is present in my map.
This is a C# code and could you tell me how to do it in C++ please.
var res = voisin[a].Find(Map<int, double> x)
Thanks
Take a look at http://www.cplusplus.com/reference/map/map/find/
This should clear things up.
// map::find
#include <iostream>
#include <map>
int main ()
{
std::map<char,int> mymap;
std::map<char,int>::iterator it;
mymap['a']=50;
mymap['b']=100;
mymap['c']=150;
mymap['d']=200;
it=mymap.find('b');
mymap.erase (it);
mymap.erase (mymap.find('d'));
// print content:
std::cout << "elements in mymap:" << '\n';
std::cout << "a => " << mymap.find('a')->second << '\n';
std::cout << "c => " << mymap.find('c')->second << '\n';
return 0;
}
Output:
elements in mymap:
a => 50
c => 150
Use std::map::find:
std::map<int,double>::iterator it = m.find(e);
Where m is the map and e is of the same type as the keys in m.
find returns an iterator to map::end if it doesn't find the specified key.
Note that std::list in C++ is not the same as List in C#. std::list is a linked list. Use std::vector if you want a container that's equivalent to the C# List.
Related
I have a fairly easy problem: I have an std::map<int,T> and another std::set<int> (can be std::vector or similar too).
In the map I store items, and in the other container I'm storing favorites (of the map).
At some point, I'd need to retrieve (all) items from the map, but starting with the favorites defined by the other container.
Here is my minimal repro, I solved it very ugly, and ineffective:
#include <iostream>
#include <string>
#include <set>
#include <map>
using namespace std;
map<int, string> myMap;
set<int> myFavorites;
int main()
{
myMap.emplace(1, "but I don't like this");
myMap.emplace(12, "So it will go below");
myMap.emplace(31, "This one will come first, and");
myMap.emplace(44, "under my favorites");
myMap.emplace(52, "then this will follow");
myFavorites.insert(52);
myFavorites.insert(31);
cout << "My map:" << endl;
for(auto p : myMap) {
cout << "#" << p.first << "=" << p.second << endl;
}
cout << endl << "My favorites:" << endl;
for(auto p : myFavorites) {
cout << "#" << p << endl;
}
cout << endl << "All items starting with my favorites:" << endl;
for(auto p : myFavorites) {
auto item = myMap.find(p);
if (item != myMap.end()) cout << "#" << item->first << "=" << item->second << endl;
}
for(auto p : myMap) {
if (myFavorites.find(p.first) != myFavorites.end()) continue;
cout << "#" << p.first << "=" << p.second << endl;
}
}
What really bothers me is the last loop, where each iterations would call find on the set.
Required output is:
All items starting with my favorites:
#31=This one will come first, and
#52=then this will follow
#1=but I don't like this
#12=So it will go below
#44=under my favorites
Here is the above source in Coliru for making it easier: https://coliru.stacked-crooked.com/a/731fa76d90bfab00
Both map and set might be changed, but replacements needs to implement the same interfaces as originals.
I'm looking for a way to solve this more efficient than my original "brute-force" one.
Please note: map must not be "reordered"! I just need to query (retrieve) its items with custom sorting!
Note2: I know map can have a comparison operator. But I'd need to have the original order usually, and sometimes I'd need to have the custom sort!
Note3: Boost is not available and compiler is C++14 capable.
Both std::map and std::set use the same strict weak ordering for ordering its contents.
You can take advantage of this. You know that if you iterate over the map you will get the keys in the same order as they are in the set, therefore all it takes is a little bit of clever logic, something like:
auto map_iter=myMap.begin();
for(auto p : myFavorites) {
while (map_iter != myMap.end())
{
if (map_iter->first == p)
cout << "#" << map_iter->first << "=" << map_iter->second << endl;
if (map_iter->first > p)
break;
++map_iter;
}
}
It may still make sense to use find() in some edge cases, specifically when myFavorites is significantly smaller than myMap, in which case a few calls to find() might be faster than iterating over (most of) the entire map.
How to iterate through the contents of map["a"] to retrieve call and call1 ?
std::vector<std::string> point
std::map<std::string, point> alloc
map["a"] = call, call1
map["i"] = call
I have tried using for loop using map iterator and inside that for loop another for loop on the vector and then checking whether the value of map iterator map equals "a" but keep getting an error.
I think you are misunderstanding some syntax and of the programming language and the semantics of the standard library containers a little bit. I will explain what I think you are doing wrong.
First thing is that you have a vector of string objects called point, this is an object not a type. An object is a variable of a type, for example
string name = "curious";
Here name is an object of type/class string, so you cannot type in point as the template parameter to the map, you have to type in a type. So that should be a string.
Second thing is that you are using the comma operator, I am not sure if you knew that you were doing that. The comma operator works as follows
#include <iostream>
using std::cout;
using std::endl;
#include <string>
using std::string;
int main() {
cout << ("Hello", "World") << endl;
return 0;
}
^ this will generate a compiler error because the "Hello" is not used but the point is that the comma operator evaluates the first part of the expression and then returns the thing on the right; so this will print
World
Third thing is how you iterate through the map. When you iterate through a std::map in C++ you are actually iterating through a series of std::pairs so the following code
#include <iostream>
using std::cout;
using std::endl;
#include <string>
using std::string;
#include <map>
using std::map;
int main() {
map<string, int> map_string_int {{"curious", 1}, {"op", 2}};
for (auto iter = map_string_int.begin(); iter != map_string_int.end();
++iter) {
cout << iter->first << " : " << iter->second << endl;
}
return 0;
}
will produce the following output
curious : 1
op : 2
the keys will be ordered alphabetically because they are stored in a binary search tree (https://en.wikipedia.org/wiki/Binary_search_tree)
Now I think you wanted to have a map from string objects to vectors, so you would structure your code as such
std::vector<string> point
std::map<string, std::vector<string>> alloc;
alloc["a"] = {"call", "call1"};
alloc["i"] = {"call"};
and you would iterate through this like so
for (auto iter = alloc.begin(); iter != alloc.end(); ++iter) {
cout << iter->first << " : " << iter->second << endl;
}
You would iterate through alloc["a"] like so
// sanity check
assert(alloc.find("a") != alloc.end());
for (auto iter = alloc["a"].begin(); iter != alloc["a"].end(); ++iter) {
cout << *iter << endl;
}
Hope that helped!
I assume you mean std::multimap instead of std::map, based on your use case (multiple values under the same key). It's in the same <map> header.
std::multimap<std::string, int> map;
map.insert(std::make_pair("first", 123));
map.insert(std::make_pair("first", 456));
auto result = map.equal_range("first");
for (auto it = result.first; it != result.second; ++it)
std::cout << " " << it->second;
Reference: std::multimap::equal_range
This should do what you want if I understand correctly.
std::vector<string> point = { "Hello", "World" };
std::map<std::string, decltype(point)> my_map;
//if you dont wan't to use decltype (or cant):
//std::map<std::string, std::vector<std::string>> my_map;
my_map["A"] = point;
my_map["B"] = { "Something", "Else" };
//this will iterate only trought my_map["A"]
for (const auto &vector_val : my_map["A"])
std::cout << vector_val << std::endl;
//this will iterate trought the whole map
for (const auto &map_pair : my_map)
{
std::cout << "map: " << map_pair.first << std::endl;
for (const auto &vector_val : map_pair.second)
std::cout << vector_val << std::endl;
std::cout << "---------------------------------" << std::endl;
}
I'm curious about knowing what is more suitable in such situations i.e multimap or map_of_vectors .
If sequencially someone want to iterate vector associated to a particular/all keys in map
what will be more efficient/optimal.
map<string ,vector<string>> mp;
// initialize your map...
for(auto itr=mp.begin(); itr!=mp.end() ;itr++)
for(auto itr2=itr->second.begin(); itr2!=itr->second.end() ;itr2++)
cout<<*itr2
for particular key just change first loop as stated down
auto itr=mp.find(key);
I am confused which is more efficient?
As we can access map directly, why do we need to use find?
I just need to know which way is more efficient.
#include <iostream>
#include <map>
using namespace std;
int main ()
{
map<char,int> mymap;
map<char,int>::iterator it;
mymap['a']=50;
mymap['b']=100;
mymap['c']=150;
mymap['d']=200;
//one way
it=mymap.find('b');
cout << (*it).second <<endl;
//another way
cout << mymap['b'] <<endl;
return 0;
}
thanks in advance! :)
Using find means that you don't inadvertently create a new element in the map if the key doesn't exist, and -- more importantly -- this means that you can use find to look up an element if all you have is a constant reference to the map.
That of course means that you should check the return value of find. Typically it goes like this:
void somewhere(const std::map<K, T> & mymap, K const & key)
{
auto it = mymap.find(key);
if (it == mymap.end()) { /* not found! */ }
else { do_something_with(it->second); }
}
As we can access map directly, why do we need to use find?
Because map<>::operator[] is sometimes nasty. If an element doesn't exist then:
it inserts it
value initialize it
returns reference of value
Thus it always returns a valid reference of value, even if a key din't exist previously. This behavior is not intended many times.
On the other hand map<>::find() is safer; because it returns end(), if a value doesn't exit. Another advantage of find() is that it returns an iterator which contains references to key (first) and value(second) both.
The [] operator in map is not constant it is logarithmic. Most of the books stress on this fact and point out it is a bit misleading. So both find and [] operator are with the same complexity.
Please note that the [] operator will create the entry even if it does not exist while find will return end() in that case.
This code and doc is picked from cplusplus.com
// accessing mapped values
#include <iostream>
#include <map>
#include <string>
using namespace std;
int main ()
{
map<char,string> mymap;
mymap['a']="an element";
mymap['b']="another element";
mymap['c']=mymap['b'];
cout << "mymap['a'] is " << mymap['a'] << endl;
cout << "mymap['b'] is " << mymap['b'] << endl;
cout << "mymap['c'] is " << mymap['c'] << endl;
cout << "mymap['d'] is " << mymap['d'] << endl;
cout << "mymap now contains " << (int) mymap.size() << " elements." << endl;
return 0;
}
OP:
mymap['a'] is an element
mymap['b'] is another element
mymap['c'] is another element
mymap['d'] is
mymap now contains 4 elements.
Notice how the last access (to element 'd') inserts a new element in the map with that key and initialized to its default value (an empty string) even though it is accessed only to retrieve its value. Member function map::find does not produce this effect.
The multimap in C++ seems to work really odd, i would like to know why
#include <iostream>
#include <unordered_map>
using namespace std;
typedef unordered_multimap<char,int> MyMap;
int main(int argc, char **argv)
{
MyMap map;
map.insert(MyMap::value_type('a', 1));
map.insert(MyMap::value_type('b', 2));
map.insert(MyMap::value_type('c', 3));
map.insert(MyMap::value_type('d', 4));
map.insert(MyMap::value_type('a', 7));
map.insert(MyMap::value_type('b', 18));
for(auto it = map.begin(); it != map.end(); it++) {
cout << it->first << '\t';
cout << it->second << endl;
}
cout << "all values to a" << endl;
for(auto it = map.find('a'); it != map.end(); it++) {
cout << it->first << '\t' << it->second << endl;
}
}
this is the output:
c 3
d 4
a 1
a 7
b 2
b 18
all values to a
a 1
a 7
b 2
b 18
why does the output still contain anything with b as the key when I am explicitly asking for 'a'? Is this a compiler or stl bug?
find, as implemented, returns an iterator for the first element which matches the key in the multimap (as with any other map). You're likely looking for equal_range:
// Finds a range containing all elements whose key is k.
// pair<iterator, iterator> equal_range(const key_type& k)
auto its = map.equal_range('a');
for (auto it = its.first; it != its.second; ++it) {
cout << it->first << '\t' << it->second << endl;
}
That's not a bug, it is by design. find returns an iterator to one of the matching elements, that's all. You'll iterate to the end of the map with your construct.
You need to use multimap::equal_range to do what you are after.
There is an Example in www.cplusplus.com , about How to use equal_range method to get all elements having the same key.
// unordered_multimap::equal_range
#include <iostream>
#include <string>
#include <unordered_map>
#include <algorithm>
typedef std::unordered_multimap<std::string,std::string> stringmap;
int main ()
{
stringmap myumm = {
{"orange","FL"},
{"strawberry","LA"},
{"strawberry","OK"},
{"pumpkin","NH"}
};
std::cout << "Entries with strawberry:";
auto range = myumm.equal_range("strawberry");
for_each (
range.first,
range.second,
[](stringmap::value_type& x){std::cout << " " << x.second;}
);
return 0;
}
Please reference the link : http://www.cplusplus.com/reference/unordered_map/unordered_multimap/equal_range/
It would seem that you get an iterator into the full "list" of pairs, starting at the first pair with 'a' as it's key. So when you iterate to the end, naturally you will get everything beyond 'a' as well. If you sought for 'c', you would probably iterate through the entire "list" doing what you do there. Perhaps you should iterate to "it != map.end() && it->first == 'a'" if you want all the a's.
Here's what I have, I am new to C++ so I am not sure if this is right...
typedef pair<string, int>:: make_pair;
hash_map <string, int> dict;
dict.insert(make_pair("apple", 5));
I want to give my hash_map "apple", and I want to get back 5. How do I do it?
hash_map is not standard C++ so you should check out the documentation of whatever library you're using (or at least tell us its name), but most likely this will work:
hash_map<string, int>::iterator i = dict.find("apple");
if (i == dict.end()) { /* Not found */ }
else { /* i->first will contain "apple", i->second will contain 5 */ }
Alternatively, if you know for sure that "apple" is in dict, you can also do: dict["apple"]. For example cout << dict["apple"]; will print out 5.
Also, why the typedef in your code? Can't you just use std::make_pair? And, it won't compile the way you wrote it (with the two leading colons)
Iterate your hashmap, vector, list and other structures:
for(hash_map<string,int>::iterator i = dict.begin(); i != dict.end(); i++)
{
cout << "key(string): " << i->first << ", value(int): " << i->second << endl;
}