Parsing .csv files with CR LF EOL structure - c++

Question

I'm trying to parse a CSV file and getline() is reading the entire file as one line. On the assumption that getline() wasn't getting what it expected, I tried \r, \n, \n\r, \r\n, and \0 as arguments with no luck.
I took a look at the EOL characters and an seeing CR and then LF. Is getline() just ignoring this or am I missing something? Also, what's the fix here?
The goal of this function is a general purpose CSV parsing function that stores the data as a 2d vector of strings. Although advice on that front is welcome, I'm only looking for a way to fix this issue.
vector<vector<string>> Parse::parseCSV(string file)
{
// input fstream instance
ifstream inFile;
inFile.open(file);
// check for error
if (inFile.fail()) { cerr << "Cannot open file" << endl; exit(1); }
vector<vector<string>> data;
string line;
while (getline(inFile, line))
{
stringstream inputLine(line);
char delimeter = ',';
string word;
vector<string> brokenLine;
while (getline(inputLine, word, delimeter)) {
word.erase(remove(word.begin(), word.end(), ' '), word.end()); // remove all white spaces
brokenLine.push_back(word);
}
data.push_back(brokenLine);
}
inFile.close();
return data;
};
Here's the hexdump. I'm not sure what exactly this is showing.
0000000 55 4e 49 58 20 54 49 4d 45 2c 54 49 4d 45 2c 4c
0000010 41 54 2c 4c 4f 4e 47 2c 41 4c 54 2c 44 49 53 54
0000020 2c 48 52 2c 43 41 44 2c 54 45 4d 50 2c 50 4f 57
0000030 45 52 0d 31 34 32 34 31 30 35 38 30 38 2c 32 30
0000040 31 35 2d 30 32 2d 31 36 54 31 36 3a 35 36 3a 34
0000050 38 5a 2c 34 33 2e 38 39 36 34 2c 31 30 2e 32 32
0000060 34 34 34 2c 30 2e 38 37 2c 30 2c 30 2c 30 2c 4e
0000070 6f 20 44 61 74 61 2c 4e 6f 20 44 61 74 61 0d 31
0000080 34 32 34 31 30 35 38 38 35 2c 32 30 31 35 2d 30
0000090 32 2d 31 36 54 31 36 3a 35 38 3a 30 35 5a 2c 34
00000a0 33 2e 39 30 31 33 35 2c 31 30 2e 32 32 30 34 31
00000b0 2c 31 2e 30 32 2c 30 2e 36 33 39 2c 30 2c 30 2c
00000c0 4e 6f 20 44 61 74 61 2c 4e 6f 20 44 61 74 61 0d
00000d0 31 34 32 34 31 30 35 38 38 38 2c 32 30 31 35 2d
00000e0 30 32 2d 31 36 54 31 36 3a 35 38 3a 30 38 5a 2c
00000f0 34 33 2e 39 30 31 34 38 2c 31 30 2e 32 32 30 31
0000100
The first two lines of the file
UNIX TIME,TIME,LAT,LONG,ALT,DIST,HR,CAD,TEMP,POWER
1424105808,2015-02-16T16:56:48Z,43.8964,10.22444,0.87,0,0,0,No Data,No Data
UPDATE Looks like it was \r. Im not sure why it didn't work earlier, but I learned a few things while exploring. Thanks for the help guys.

Answer 1

A simple fix would be to write your own getline
For example one that ignores any combination of \n,\r
in the beginning of the line, and breaking on any too.
That will work on any platform, but wont preserve empty lines.
After looking at the hex-dump, the delimiter is 0d (\r)

Answer 2

Did you try to switch the order of the \r\n to \n\r?