How would I make the program receive user input? - c++

Question

Ok, so, on my last question my program was finding the standard deviation of a set of numbers. Today, my instructor told me that it needs to get multiple numbers from the user. I have no clue on how about going to do this. Any advice on how to do this? Code is accepted. Please and thanks.
#include "stdafx.h" //No Flipping Clue
#include <iostream> //Needed For "cout"
#include <iomanip> //Needed To Round Decimal Points
#include <math.h> //Needed For "sqrt()" And "pow()"
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
{
//Used To Round The Decimal Points 2 Places
cout << setiosflags(ios::fixed|ios::showpoint);
cout << setprecision(1);
//Declaring
double Numbers[] = {65, 49, 74, 59, 48}; //Work On Making This A User Input
double Mean = 0, Items = 0, Sum = 0, Deviation = 0;
int Counter;
//Finds The Mean Of The Set Of Numbers
for (Counter = 0; Counter < sizeof(Numbers) / sizeof(double); Counter++)
{
for (Counter = 0; Counter < sizeof(Numbers) / sizeof(double); Counter++)
{
Sum += Numbers[Counter]; //Adds All Numbers In Array Together
}
Items = sizeof(Numbers) / sizeof(double); //Gets The Number Of Items In The Array
Mean = Sum / Items; //Finds The Mean
}
//Finds The Standard Deviation
for (Counter = 0; Counter < sizeof(Numbers) / sizeof(double); Counter++)
{
Deviation += pow((Numbers[Counter] - Mean), 2) / Items; //Does Math Things...
}
Deviation = sqrt(Deviation); //Square Roots The Final Product
cout << "Deviation = " << Deviation << endl; //Print Out The Standard Deviation
system("pause");
return 0;
}

Answer 1

A quick google search would have done the job ... C++ Input/Ouput
int number;
cin >> number;
Exemple:
int nbNumbers;
cout << "How many numbers do you need :" << endl;
cin >> nbNumbers;
double numbers[nbNumbers];
for(int i = 0; i < nbNumbers; ++i)
{
cout << "Enter a Number :" << endl;
cin >> numbers[i];
}

Answer 2

there you go:
cout<<"how many numbers you want to enter?";
cin>>n;
double Numbers[n];
cout<<"enter numbers";
for(int i=0;i<n;i++){
cin>>Numbers[i];
}

Answer 3

Here is an example of vector. It takes input from user until user enters -1.
#include <stdio.h>
#include <array>
int main()
{
int number;
vector<int> userInput;
do
{
cout << "Enter a number (-1 to quit): ";
cin >> number;
userInput.push_back(number);
} while (number != -1);
for (vector < int >::iterator it = userInput.begin(); it < userInput.end() - 1; it++)
{
cout << endl << *it;
}
system("pause");
return 0;
}