Program prints all digits from array, prints backwards - c++

Question

I'm making a program that prints all digits from an array (entered as an integer) and it works, but the digits are printed backwards and I don't know how to reverse them. Can someone help?
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
void explode(int number,int array[])
{
while (number > 0) {
int digit = number % 10;
cout << digit << '\n';
number /= 10;
}
}
int main()
{
int digits[100];
int numdigits;
int n;
cout << "Enter number: ";
cin >> n;
// numdigits = explode(n,digits);
cout << "[";
while (n > 0) {
int digit = n % 10;
n /= 10;
digits[digit] = digit;
cout << digits[digit];
}
cout << "]" << endl;
}

Answer 1

You just have to reverse the array using reverse() from <algorithm>.
Code:
#include <iostream>
#include <iomanip>
#include <algorithm>
#include <cmath>
using namespace std;
int array_c = 0;
void explode(int number,int array[])
{
while (number > 0) {
int digit = number % 10;
number /= 10;
array[array_c++] = digit;
}
}
int main()
{
int digits[100];
int numdigits;
int n;
cout << "Enter number: ";
cin >> n;
explode(n,digits);
reverse(digits,digits+array_c);
cout << "[";
for(int i = 0; i < array_c; ++i)
cout<<digits[i];
cout << "]" << endl;
}

Answer 2

Your use of
digits[digit] = digit;
is not right. You probably meant to use
digits[numdigits] = digit;
You can fix your problem by dividing the work into two steps. In the first step, you store the digits. In the second step, you print the digits.
int numdigits = 0;
while (n > 0) {
cout << "n: " << n << endl;
int digit = n % 10;
n /= 10;
digits[numdigits++] = digit;
}
// Make sure to print them in reverse order.
cout << "[";
for ( ; numdigits > 0; )
{
cout << digits[--numdigits];
}
cout << "]" << endl;