While loop and boolean function - c++

Question

Hello guys I'm not an expert on the subject so please excuse my pour skills. I finished my program and it works fine (calculator). The problem is that now I don't know where to locate the while loop in conjunct with the Boolean function to repeat the process once it is done with a task (once the program completes a math operation). Any help, comment or suggestion will be greatly appreciated. Thank you.!!
#include <iostream>
#include <math.h>
#include <cmath>
int main()
{
double a=0.0;
double b=0.0;
double c=0.0;
bool repeat = true;
do {
using namespace std;
int x;
cout << "**********************************" << endl;
cout << "| |" << endl;
cout << "| 0 - Quit |" << endl;
cout << "| 1 - Add |" << endl;
cout << "| 2 - Subtract |" << endl;
cout << "| 3 - Divide |" << endl;
cout << "| 4 - Multiply |" << endl;
cout << "| 5 - Raise X to the power Y |" << endl;
cout << "| 6 - Sine ( x ) |" << endl;
cout << "| 7 - Cosine ( x ) |" << endl;
cout << "| 8 - Tangent ( x ) |" << endl;
cout << "**********************************" << endl;
cout << "Enter a selection, please: " << endl;
cin >> x;
switch (x)
{
{
case 1:
cout << " Enter the first value" <<endl;
cin >> a ;
cout << " Enter second value " << endl;
cin >> b;
c=a+b;
cout << "The addition of " << a << " and "<< b << "is" << c << endl;
break;
bool repeat = true;
}
{
case 2:
cout << " Enter the first value" << endl;
cin >> a ;
cout << " Enter the second value " << endl;
cin >> b;
c=a-b;
cout << "The subtraction of " << a << " and " << b << " is: " << c << endl;
break;
bool repeat = true;
}
{
case 3:
cout << " Enter the first value" <<endl;
cin >> a ;
cout << " Enter the second value " << endl;
cin >> b;
c=a/b;
cout << " The division os " << a << " and " << b << "is" << c << endl;
break;
bool repeat = true;
}
{
case 4:
cout << " Enter the first value" <<endl;
cin >> a ;
cout << " Enter the second value " << endl;
cin >> b;
c=a*b;
cout << " The product of " << a << " times " << b << " is " << c << endl;
break;
bool repeat = true;
}
{
case 5:
cout << " Enter the value to be exponentiated " <<endl;
cin >> a ;
cout << " Enter the exponent" << endl;
cin >> b;
c= pow(a,b);
cout << a << " Rased to the power of " << b << " is: " << c << endl;
break;
bool repeat = true;
}
{
case 6:
cout << " Enter the value that you want the sine to be taken of" <<endl;
cin >> a ;
c=sin(a);
cout << " The sine of " << a << " is: " << c << endl ;
break;
bool repeat = true;
}
{
case 7:
cout << " Enter the value that you want the cosine to be taken of" <<endl;
cin >> a ;
c=cos(a);
cout << " The cosine of " << a << " is: " << c << endl ;
break;
bool repeat = true;
}
{
case 8:
cout << " Enter the value that you want the tangent to be taken of" <<endl;
cin >> a ;
c=tan(a);
cout << " The tangent of " << a << " is: " << c << endl ;
break;
bool repeat = true;
}
{
case 0:
cout << "Ending the program" << endl;
return 0;}
break;
bool repeat = true;
}
} while (repeat = true );
return 0;
}

Answer 1

So here is few moments.
Call
using namespace std;
just believe - is bad idea;
In conditions like if() or while() use operator == instead of =. Because "=" - is assigne operator, and return value depended on success of operation. And "==" is compare operator.
Ow and figure one more missunderstanding. Using bool rezult = true; is wrong. You should use rezult = true; Because every time when you write type specifer you create local variable in context of case, and this don`t affect rezult declared in main
My opinion for your question is little change:
from:
do{
int x;
...
case 0:
cout << "Ending the program" << endl;
return 0;}
break;
bool repeat = true;
}
} while (repeat = true );
to
do{
int x;
...
case 0:
cout << "Ending the program" << endl;
repeat = false;}
break;
}
} while (repeat == true);
and if you need a bit more calculations you can wrapped it to new cicle something like:
while(new_condtion == true) {
do {
...
} while(repeat == true);
//change new_condtion
}

Answer 2

Don't redefine repeat within switch case. This creates a different variable named repeat which, although it has the same name, is not the variable named repeat defined before the loop. This is what you get when you copy a definition of the form bool repeat = true; into multiple places.
The continuation condition for the loop (repeat = true) will also loop forever. Comparison is two = signs, not one.