Shader's function parameters performance - opengl

Question

I'm trying to understand how passing parameters is implemented in shader languages.
I've read several articles and documentation, but still I have some doubts. In particular I'm trying to understand the differences with a C++ function call, with a particular emphasis on performances.
There are slightly differences between HLSL,Cg and GLSL but I guess the underline implementation is quite similar.
What I've understood so far:
Unless otherwise specified a function parameter is always passed by value (is this true even for matrix?)
Passing by value in this context hasn't the same implications as with C++. No recursion is supported, so the stack isn't used and most function are inlined and arguments directly put into registers.
functions are often inlined by default (HLSL) or at least inline keyword is always respected by the compiler (Cg)
Are the considerations above right?
Now 2 specific question:
Passing a matrix as function parameter
inline float4 DoSomething(in Mat4x4 mat, in float3 vec)
{
...
}
Considering the function above, in C++ that would be nasty and would be definitely better to use references : const Mat4x4&.
What about shaders? Is this a bad approach? I read that for example inout qualifier could be used to pass a matrix by reference, but actually it implicates that matrix be modified by the called function..
Does the number (and type of arguments) have any implication? For example is better use functions with a limited set of arguments?Or avoid passing matrices?
Is inout modifier a valid way to improve performance here? If so, anyone does know how a typical compiler implement this?
Are there any difference between HLSL an GLSL on this?
Does anyone have hints on this?

Answer 1

According to the spec, values are always copied. For in parameters, the are copied at call time, for out parameters at return time, and for inout parameters at both call and return time.
In the language of the spec (GLSL 4.50, section 6.1.1 "Function Calling Conventions"):
All arguments are evaluated at call time, exactly once, in order, from left to right. Evaluation of an in parameter results in a value that is copied to the formal parameter. Evaluation of an out parameter results in an l-value that is used to copy out a value when the function returns. Evaluation of an inout parameter results in both a value and an l-value; the value is copied to the formal parameter at call time and the lvalue is used to copy out a value when the function returns.
An implementation is of course free to optimize anything it wants as long as the result is the same as it would be with the documented behavior. But I don't think you can expect it to work in any specify way.
For example, it wouldn't be save to pass all inout parameters by reference. Say if you had this code:
vec4 Foo(inout mat4 mat1, inout mat4 mat2) {
mat1 = mat4(0.0);
mat2 = mat4(1.0);
return mat1 * vec4(1.0);
}
mat4 myMat;
vec4 res = Foo(myMat, myMat);
The correct result for this is a vector containing all 0.0 components.
If the arguments were passed by reference, mat1 and mat2 inside Foo() would alias the same matrix. This means that the assignment to mat2 also changes the value of mat1, and the result is a vector with all 1.0 components. Which would be wrong.
This is of course a very artificial example, but the optimization has to be selective to work correctly in all cases.

Answer 2

Your first bullet point does not work when you consider arguments qualified using inout.
The real issue is what you do with the parameter inside the function, if you modify a parameter qualified with in then it cannot be "passed by reference" and a copy will have to be made. On modern hardware this probably is not a big deal, but Shader Model 2.0 was pretty limited in terms of number of temp registers and I ran into these kinds of issues more than once when GLSL and Cg first came out.
For reference, consider the following GLSL code:
vec4 DoSomething (mat4 mat, vec3 vec)
{
// Pretty straight forward, no temporary registers are required to pass arguments.
return vec4 (mat [0] + vec4 (vec, 0.0));
}
vec4 DoSomethingCopy (mat4 mat, vec3 vec)
{
mat [0][0] = 0.0; // This requires the compiler to make a local copy of mat
return vec4 (mat [0] + vec4 (vec, 0.0));
}
vec4 DoSomethingInOut (inout mat4 mat, in vec3 vec)
{
mat [0][0] = 0.0; // No copy required, but the original mat is modified
return vec4 (mat [0] + vec4 (vec, 0.0));
}
I cannot really comment on performance, my only bad experiences had to do with hitting actual hardware limits on older GPUs. Of course you should assume that any time something has to be copied it is going to negatively impact performance.

Answer 3

All shader functions are inlined (recursive function are forbidden). The concept of reference/pointer is invalid here too. The only case when some code will be generated is when you write on an input parameter. However, if the original registers aren't used anymore the compiler will probably use the same registers, and the copy (mov operation) won't be needed.
Bottom line: function invocation is free.