So im still pretty new to C++ and have been doing a program for a while now. I think I am slowly getting it but keep getting an error "Intellisense: operand of '*' must be a pointer." on line 36 column 10. What do I need to do to fix this error? Im going to get to the other functions as i finish each one so sorry for the extra function declaration
// This program will take input from the user and calculate the
// average, median, and mode of the number of movies students see in a month.
#include <iostream>
using namespace std;
// Function prototypes
double median(int *, int);
int mode(int *, int);
int *makeArray(int);
void getMovieData(int *, int);
void selectionSort(int[], int);
double average(int *, int);
// variables
int surveyed;
int main()
{
cout << "This program will give the average, median, and mode of the number of movies students see in a month" << endl;
cout << "How many students were surveyed?" << endl;
cin >> surveyed;
int *array = new int[surveyed];
for (int i = 0; i < surveyed; ++i)
{
cout << "How many movies did student " << i + 1 << " see?" << endl;
cin >> array[i];
}
median(*array[surveyed], surveyed);
}
double median(int *array[], int num)
{
if (num % 2 != 0)
{
int temp = ((num + 1) / 2) - 1;
cout << "The median of the number of movies seen by the students is " << array[temp] << endl;
}
else
{
cout << "The median of the number of movies seen by the students is " << array[(num / 2) - 1] << " and " << array[num / 2] << endl;
}
}
Problems:
The expression *array[surveyed] used in the following line:
median(*array[surveyed], surveyed);
is not right. array[surveyed] is the surveyed-th element of the array. It is not a pointer. It doesn't make sense to dereference it.
The type of the first argument of median used in the declaration is different than the type used in the definition. The declaration seems to be right one. Change the implementation to:
double median(int *array, int num)
Fix the way you call median. Instead of
median(*array[surveyed], surveyed);
use
median(array, surveyed);
Related
I am trying to make a user-generate search function for an entry-level C++ function. The function should take a list and three integers, but it won't recognize the list. I can pass int[] but whenever i give it a name such as "int[] list" it throws the program off.
EDIT: Here is the warning I get: expected a ')'. And then it goes over the variable parameters names and says "first is unidentified", "last is unidentified", and so on. Did a few ninja edits to show more of the code here. Sorry!
I feel like this is very elementary for C++ users, but I don't get it! I do not want to use pointers quite yet in this program.
int binSearch(int[] first, int target, int first, int last) {
int middle = (first + last) / 2;
cout << "Entering binSearch: list[first]=" + list[first] +
", list[last]=" + list[last] + ", ";
cout << "list[middle]=" + list[middle];
}
int main() {
int list[10];
// creating sorted array
cout << "The list is ";
for (int i = 0; i < 10; i++) {
list[i] = 2 * i + 1;
cout << list[i] + " ";
}
cout << endl;
// prompt user to enter key
int key;
cout << "Enter a key: ";
cin >> key;
int index = binSearch(list, 10, key, 0, 10 - 1);
}
In C++, arrays are declared with the brackets after the variable name:
int binSearch(int list[], int target, int first, int last)
Note that I also changed the first parameter from first to list.
#include <iostream>
using namespace std;
// prototype functions
void DisplayResult(float MaxOrMin);
float FindMinimum(float Array[5]);
float FindMaximum(float Array[5]);
//Global Variables
float Array[5];
float MaxOrMin = 3;
float FindMin;
float FindMax;
//Main Function
int main()
{
cout << "Please enter 5 numbers: " << endl;
for (int i=0; i<5; i++)
{
cin >> Array[i]; // input for array
}
cout << "Please enter '0' for minimum or '9' for maximum:" << endl;
cin >> MaxOrMin; // input 0 or 9 for min or max
//Calling Functions
FindMinimum(Array);
FindMaximum(Array);
DisplayResult(MaxOrMin);
return 0;
}
//Function to find Minimum
float FindMinimum(float Array[5])
{
float FindMin = Array[0];
for (int y=1;y<5;y++)
{
if(Array[y] < FindMin)
FindMin = Array[y];
}
return FindMin;
}
//Function to find Maximum
float FindMaximum(float Array[5])
{
float FindMax = Array[0];
for (int x=1;x<5;x++)
{
if(Array[x] > FindMax)
FindMax = Array[x];
}
return FindMax;
}
This last part is my if, else if, else funtion:
//Function to display minimum or maximum result
void DisplayResult(float MaxOrMin)
{
if (MaxOrMin == 0)
cout << "Minimum is: " << FindMin << endl;
else if (MaxOrMin == 9)
cout << "Maximum is: " << FindMax << endl;
else
cout << "Invalid Input" << endl;
}
My project is to create a program using functions to take user input on a 5 float array. Then find the max and min and display whichever the user asks for.
Here is where my problem comes in. For both max(input 9) and min(input 0) I am getting "0". However any other input correctly returns my "Invalid Input" message.
I'm not getting any errors or warnings or errors at all on eclipse. My professor has told me that my problem was likely with my void function for displaying results. I am hoping someone could point me in the right direction here.
Apologies for my formatting and/or if this question is too basic for this site.
You misunderstand how local and global variables work. Your Find* functions shadow the globals with locals and thus they don't appear to do anything.
The problem is that your FindMinimum() (and the same with FindMaximum()) function compute the minimum (maximum) in a local variable and return it but you, in main() don't receive they in correct variables
So the computed value is lost.
I mean... instead of
FindMinimum(Array);
FindMaximum(Array);
you should write
FindMin = FindMinimum(Array);
FindMax = FindMaximum(Array);
I'm currently learning about functions in C++ and am currently working on a homework assignment with functions being the main thing.
Currently, I'm trying to make a grade calculator with every operation of the process being split into a function of its own.
Here's the code:
#include <iostream>
#include <fstream>
#include <string>
#include <stdlib.h>
using namespace std;
void getHWGrades(int homeworks[], int size)
{
cout << "\nEnter the grades, out of 100 points, for the 9 homeworks you completed." << endl;
cout << "Note that Homework 10 is given to you for free, but is the same grade \nas homework 9.\n" << endl;
for (int i = 0; i < 9; i++)
{
cout << "Homework " << i + 1 << ": ";
cin >> homeworks[i];
while (homeworks[i] > 100 || homeworks[i] < 0)
{
cout << "Invalid grade, input homework grade again: ";
cin >> homeworks[i];
}
}
homeworks[9] = homeworks[8];
cout << "Homework 10: " << homeworks[9];
}
double quizAverage()
{
double quizPts;
cout << "Input your in class quiz average: ";
cin >> quizPts;
return quizPts;
}
double labAverage()
{
double labPts;
cout << "Input your lab average: ";
cin >> labPts;
return labPts;
}
double teamProject()
{
double teamPts;
cout << "Input your team project grade: ";
cin >> teamPts;
return teamPts;
}
int exam1()
{
int exam1Pts;
cout << "Input your exam1 grade: ";
cin >> exam1Pts;
return exam1Pts;
}
int exam2()
{
int exam2Pts;
cout << "Input your exam2 grade: ";
cin >> exam2Pts;
return exam2Pts;
}
double hwAverage(int homeworks[], int size)
{
double total = 0;
double homeworkAverage = 0;
for (int i = 0; i < size; i++)
{
total = total + homeworks[i];
}
homeworkAverage = (total*1.0) / 10;
return homeworkAverage;
}
double currentPoints(double& quizPts, double& labPts, double& teamPts, double& homeworkAverage, int& exam1Pts, int& exam2Pts)
{
double totalPts = ((quizPts / 100.0) * 10) + ((labPts / 100.0) * 10) + ((teamPts / 100.0) * 15) + ((homeworkAverage / 100.0) * 20) + ((exam1Pts / 100.0) * 10) + ((exam2Pts / 100.0) * 15);
cout << "\nYour current points (out of the 80 total available), stand at: " << totalPts;
return totalPts;
}
double currentAverage(double& totalPts)
{
double availableAverage = totalPts*(100.0 / 80);
cout << "\nYour current average is: " << availableAverage;
return availableAverage;
}
int main()
{
// keep the console from closing in visual studio
char charer;
double totalPts;
double quizPts, labPts, teamPts, homeworkAverage;
int exam1Pts, exam2Pts;
const int ARRAY_SIZE = 10;
int hwArray[ARRAY_SIZE];
getHWGrades(hwArray, ARRAY_SIZE);
quizAverage();
labAverage();
teamProject();
exam1();
exam2();
currentPoints(quizPts, labPts, teamPts, homeworkAverage, exam1Pts, exam2Pts);
currentAverage(totalPts);
cin >> charer;
}
My issue, which I believe lies in the functions currentPoints and currentAverage, is that when I run this totalPts outputs as -5.09078e+61 and as a follow up result with the currentAverage function, availableAverage outputs as -1.157e+62.
I'm sure that the issue has to do with how I'm passing the values from function to function (which I doubt I'm doing correctly).
How would I go about fixing this issue?
Thank you in advance.
You need to store the return value from currentPoints() function, like this.
totalPts = currentPoints(quizPts, labPts, teamPts, homeworkAverage, exam1Pts, exam2Pts);
currentAverage(totalPts);
Reason is, you declared "totalPts" as local variable in currentPoints().
"Local variables has function scope only, it is undefined to main function".
Do this for all other
functions(quizAverage,labAverage,teamProject,exam1,exam2, hwAverage,currentAverage)
I hope, this will solve the issue !!!
The problem is not about functions, it's about variables.
Let's take quizPts for instance:
In the main method, you declare this variable, but then you don't do anything with it before sending it to currentPoints. Therefore it has an undefined value when you do so (undefined often looks like random in C).
The other variable quizPts you use in quizAverage have the same name but is not the same for the compiler.
Try in your main:
quizPts = quizAverage();
You asked
How would I go about fixing this issue?
And the answer is "Use the debugging tool with "watches" window open in your favorite IDE".
It's always very difficult to find an error simply by re-reading the code, but in the debugger you can see all the values of your variables at each moment of time. Specifically, in this example, you would realize that your variables have garbage values from the very beginning (are not initialized), and this value never changes.
Using this approach you could find the reason yourself in time less than necessary to write this SO question. I hope this will help you to save your time in future.
The problem is you use the variables such as quizPts and labPts without storing any value in them. In your case, you have to store the return value of the function to the corresponding variable before using it. For example, do the same as the following statement:
quizPts = quizAverage();
So I'm new to C++ and am writing a program to calculate the mean, median, standard deviation, min, and max of a program. The issues I'm having are that I don't know how to correctly call functions from other files in the project, and when I try to print(c out <<) my array, it returns a weird value like 0 x 0017 c 530 (disregard the spaces). If anyone could help me correctly return these functions, and print the list correctly, I would be very grateful! Here's my code (not including the .h file):
#include <iostream>
using namespace std;
#include "stats.h"
int main()
{
double nums[10000] = {};
int n;
cout << "Enter number of values: ";
cin >> n;
for (int i = 1; i <=n; i++) {
cout << "Enter number " << i << ": ";
cin >> nums[i-1];
}
// me trying to print the nu ms list
cout << nums << endl;
// me trying to call the function
double mean(double nums[], int n);
return 0;
}
stats. cpp
#include "stats.h"
double mean(double nums[], int n)
{
double sum = 0;
double average;
for (int i = 0; i > n; i++) {
sum += nums[i];
}
average = sum / n;
return average;
}
Instead of
cout << nums << endl;
Just like you have a loop to enter one value at a time in an array, you also need a similar loop to print one value at a time from the array.
To call a function from another translation unit, you would typically declare the function in a header file, your stats.h would be an excellent candidate:
double mean(double nums[], int n);
And then just invoke it from your main:
std::cout << mean(nums, n) << std::endl;
That's it.
Also:
using namespace std;
You need to have someone help you to get an amnesia, and completely forget that C++ has anything like this. This is bad programming practice.
double mean(double nums[], int n); is declaration of function, not invoking of function. You should
double mean_value = mean(nums, n);
cout << mean_value << endl;
And cout << nums << endl; won't print out the elements of the array, just the address of the array. You need to loop the array to print out all the elements.
Obviously I need a sum function for this and accumulate will not cut it
I need to create program - a vector - with n number of elements the user can prescribe - and the sum function can only sum POSITIVE elements even though the user can enter negative elements as well...
In the computeSum function I also need to add a "success" to the whole group
computeSum (dataVec, howMany, total, sucess);
and create a parameter for people who enter - all negative numbers but want to sum them but are unable to because there are no positive numbers
if (success) {
cout << "The sum is " << total << endl;
}
else {
cerr << "Oops, you cannot add these elements.";
}
So here is what I got
#include <iostream>
#include <vector> // need this in order to use vectors in the program
using namespace std;
int main()
{
vector<double> dataVec;
double i, n, howMany, total;
cout << "How many numbers would you like to put into the vector?";
cin >> n;
dataVec.resize(n);
for(vector<double>::size_type i=0;i < n;i++)
{
cout << "Enter the numbers: \n";
cin >> dataVec[i];
}
cout << "How many POSITIVE numbers would you like to sum?";
cin >> howMany;
cout << computeSum (dataVec, howMany, total);
}
double computeSum (vector<double> &Vec, howMany, total)
{
double total =0;
for(int i=0;i < howMany;i++)
total+=Vec[i];
return total;
}
I also seem to having trouble compiling just this - computeSum() is not being understood in int main(); howMany is not being understood in computerSum(); and on a gloabl scope total() and howMany() are undeclared (I guess that would mean i would need to decalre globally???)
In fact, accumulate will “cut it”, with an appropriate functor that only regards positive values:
int sum_positive(int first, int second) {
return first + (second > 0 ? second : 0);
}
…
std::accumulate(data.begin(), data.begin() + how_many, 0, sum_positive);
Getting on my hobby horse: Boost Range Adaptors. Hits the sweet point with me
#include <boost/range/adaptors.hpp>
#include <boost/range/numeric.hpp>
bool isnatural(int i) { return i>=0; }
using namespace boost::adaptors;
int main(int argc, char** args)
{
static const int data[] = { -130, -1543, 4018, 5542, -4389, 15266, };
std::cout << "sum: " << boost::accumulate(data | filtered(isnatural), 0) << std::endl;
return 0;
}
Output:
sum: 24826
With C++11 awesomeness1 spice:
std::cout << "sum: " << boost::accumulate(data
| filtered([] (int i) { return i>=0; }), 0) << std::endl;
1: to be honest, I really hate the clumsyness of lambda syntax:
having to specify the parameter type always
having to spell out the return statement to
For this scenario, it seems to that filtered([] (i) { i>=0 })
could be figured out by the compiler. Well, perhaps in c++22 :)
Your computeSum() function must appear above your main() function in the source file for it to be in scope. Also in your computeSum() function signature you haven't given types to the howMany and total variables. I'm guessing they should be double howMany and double total?