My code seems to be working, but I have having trouble with the print statement, which I will eventually write out to a CSV. I am able to get the print to work for the first two items, but when I try to add the len part as the third thing to print, it get an error "'str' object is not callable". When I print the len part by itself, it seems to work fine. Any insight as to what I am doing wrong to print all together?
inFile = open(file.txt,'r')
reader = csv.reader(inFile)
allrows = list(reader)
dd = defaultdict(OrderedDict)
ids = OrderedDict()
output = {}
iterallrows = iter(allrows)
next(iterallrows)
for row in iterallrows:
id_ = row[2]
name = row[3]
dd[id_][name] = None
ids[id_] = None
print('{} {} {}'.format(id_,','.join(dd[id_],','(len(dd[id_])))))
You have this:
[...],','(...)[...]
This attempts to treat ',' as a function, which it is not. Put a comma between all arguments to a function.
I am attempting to analyze data sets as lists of differing lengths. I am calling lines (rows) of my data set one by one to be analyzed by my function. I want the function to still be run properly regardless of the length of the list.
My Code:
f = open('DataSet.txt')
for line in iter(f):
remove_blanks = ['']
entries = line.split()
''.join([i for i in entries if i not in remove_blanks])
trash = (entries[0], entries[1])
time = int(entries[2])
column = [int(v) for v in entries[3:]]
def myFun():
print(entries)
print_string = ''
if column[0] == 100:
if column[1] >= 250 and column[2] == 300:
if len(column) >= 9:
digit = [chr(x) for x in column[4:9]]
print_string = ('code: ' + ''.join(str(digit[l]) for l in range(5)) + ' ')
if len(column) >= 13:
optional_digit = [chr(d) for d in column[9:13]]
for m in range(0, 4):
print_string += 'Optional Field: ' + optional_digit[m] + ''
else:
print_string += 'No Optional Field '
pass
pass
print(print_string)
print('')
myFun()
f.close()
What is happening is if the length of a line of my data is not long enough (i.e. the list ends at column[6]), I get the error:
line 17, in function
print('Code: ' + digit[l])
IndexError: list index out of range
I want it to still print Code: #number #number #number #number and leave any non-existent columns as blanks when it is printed so that one line may print as Code: ABC9 and the next print as Code: AB if there are differing list lengths.
Please help! :)
Well, just make sure you're not looping over a list longer than available:
print_string = 'code: ' + ''.join(str(digit[l]) for l in range(min(5, len(digit)))) + ' '
or better:
print_string = "code {} ".format("".join(str(dig) for dig in digit[:5]))
Although I have a feeling you're over-complicating this.
I have a csv file that has a single record in it that I need to assign variables to and run through a python script. My date looks like the line below. Has header.
"CompanyName","Contact","Street","CityZip","Store","DateRec","apples","appQuan","oranges","orgQuan","peaches","peaQuan","pumpkins","pumQuan","Receive",0
American Grocers","Allison Smith","456 1st. Street","Podunk, California 00990","Store 135 Order","05/14/2015",1,10,0,4,1,4,2,0
Each value needs to be assigned a variable
1st position, "American Grocers" = CompanyName
2nd position, "Allison Smith" = Contact
3rd position = Street, etc.
After the date it gets tricky. The last 11 values are related to each other and get saved to a key.
If value 7 = 1, then variable 7 = "apples" and variable 8 = 10, else skip values 7 and 8 and go to 9
If value 9 = 1, then variable 9 = "oranges" and value 10 = the variable in position 10 (4), else skip values 9 and 10 and go to 11
If value 11 = 1, then variable 11 = "peaches" and value 12 = the variable in position 10 (4), else skip values 11 and 12 and go to 13
If value 13 = 1, then variable 13 = "pumkins" and value 13 = the variable in position 13 (2), else skip values 13 and 14
If value 15 = 1 then variable 15 = "Delivery", else variable = "Pick up"
thus python would assign the following:
CompanyName = "American Grocers"
Contact = "Allison Smith"
Street = "456 1st. Street"
CityZip = "Podunk, California 00990"
Store = "Store 135 Order"
OrderDate (does not need to be date type) = "05/14/2015"
orderList = {"apples" : 10, "peaches" : 4, "pumpkins" : 2}
Recieve = "Pick up"
I need to manipulate these variables further along in the script.
I have the following code to which outputs the data to its corresponding header information.
import csv
MY_FILE = "C:\\tests\\DataRequestsData\\qryFruit.csv"
def parse(raw_file, delimiter):
opened_file = open(raw_file)
csv_data = csv.reader(opened_file, delimiter=delimiter)
parsed_data = []
fields = csv_data.next()
for row in csv_data:
parsed_data.append(dict(zip(fields, row)))
opened_file.close()
return parsed_data
def main():
new_data = parse(MY_FILE, ",")
print new_data
if __name__ == "__main__":
main()
Output looks like this. (I am not sure why the output is not in the same order as the file ...)
[{'DateRec': '05/14/2015', 'orgQuan': '4', 'CompanyName': 'American Grocers', 'appQuan': '10', 'peaQuan': '4', 'oranges': '0', 'peaches': '1', 'Contact': 'Allison Smith', 'CityZip': 'Podunk, California 00990', 'pumpkins': '2', 'apples': '1', 'pumQuan': '0', 'Store': 'Store 135 Order', 'Street': '456 1st. Street'}]
I do not know how to take this and get the variables assigned as listed above. Suggestions? Using python 2.7
I am not sure why the output is not in the same order as the file ...
In a Python dictionary, entries are displayed an arbitrary order.
Below is the general contour of how to parse the program. The detailed logic: "if this field is this do this otherwise do that" is something that I hope you can do on your own. The specifics are way too long, detailed, and specific to be of interest of value for anyone else and I'm guessing that is why there hasn't been much interest in this.
import csv
MY_FILE = "C:\\tests\\DataRequestsData\\qryFruit.csv"
def parse(raw_file, delimiter):
parsed_data = []
with open(raw_file) as opened_file:
rec = {}
csv_data = csv.reader(opened_file, delimiter=delimiter)
fields = csv_data.next()
for row in csv_data:
for i, val in enumerate(row[0:6]):
rec[fields[i]] = val
# This part below is too specific, long, and complicated
# that it is doubtful filling this out in detail will be use
# or interest to anyone else on stackoverflow. But to give
# you an idea of how to proceed...
if row[6] == '1':
rec[fields[6]] = 'apples'
rec[fields[7]] = 10
else:
# continue
pass
# ...
parsed_data.append(rec)
return parsed_data
def main():
new_data = parse(MY_FILE, ",")
print new_data
if __name__ == "__main__":
main()
I finally accomplished what I was looking for with the following code: Thank you to all who offered help. Your ideas spurred me onto the tangents I needed.
import csv
MY_FILE = csv.reader(open("C:\\tests\\DataRequestsData\\qryFruit.csv", "rb"))
for row in MY_FILE:
CompanyName, Contact, Street, CityZip, Store, DateRec, apples, appQuan, oranges, orgQuan, peaches, peaQuan, pumpkins, pumQuan, Receive = row
s='{'
if apples == "1":
s = s + '"apples"' + ":" + appQuan
if oranges == "1":
s = s + '", "oranges"' + ":" + orgQuan
if peaches == "1":
s = s + '", "peaches"' + ":" + peaQuan
if pumpkins == "1":
s = s + '", "pumpkins"' + ":" + pumQuan
s = s + '}'
if Receive == "0":
Receive = "Pick up"
else:
Receive = "Deliver"
This program prints duplicate names generated from list please help me get rid of it I added a operator fr it but it's not working
#Subscriber Selector
import random
print "Welcome to Subscriber Picker"
sub_list = ["Ali Abbas","Ansar Abbasi","Hasan Abidi","Saadia Afzaal","Iqbal Ahmad","Iftikhar Ahmad","Khaled Ahmed","Ahmed Tamim","Maulana Mahboob Alam","Malik Barkat Ali"]
def add_list():
input_1 = int(raw_input("How many new users do you want to add? "))
for z in range (0,input_1):
sub_list.append(raw_input ("Enter Name" +" "+ str(z+1) + ":"))
return
add_list()
def generator():
input_2=int(raw_input("How many subscribers to generate? "))
print "-----"
index=0
temp_list = []
ran_name = random.randint(0, len(sub_list)-1)
temp_list.append(sub_list[ran_name])
while len(temp_list) < input_2:
ran_name=random.randint(0,len(sub_list)-1)
temp_list.append(sub_list[ran_name])
if(temp_list[index] == temp_list[index+1]):
temp_list.pop(index)
else:
index = index + 1
for x in temp_list:
print x
print"-----"
return
generator()
Here you go:
temp_list = random.sample( sub_list, input_2 )
I want to create an python multi dimensional dictionary :-
Currently i am doing like this
multidict = {}
IN LOOP
mulitdict[i] = data
if loop runs ten times I am getting same value in all index..
Eg:
I want to have like this
multidict {0 : {'name':name1, 'age' : age1}, 1: {'name':name2, 'age' : age2}
but i am getting as shown below
multidict {0 : {'name':name1, 'age' : age1}, 1: {'name':name1, 'age' : age1}
I also tried the default dict also....but every time i get same value in all index. What is the problem?
Tried code :
csv_parsed_data2 = {}
with open('1112.txt') as infile:
i =0
for lineraw in infile:
line = lineraw.strip()
if 'sample1 ' in line:
### TO GET SOURCE ROUTER NAME ###
data['sample1'] = line[8:]
elif 'sample2- ' in line:
### TO GET DESTINATION ROUTER NAME ###
data['sample2'] = line[13:]
elif 'sample3' in line:
### TO GET MIN,MAX,MEAN AND STD VALUES ###
min_value = line.replace("ms"," ")
min_data = min_value.split(" ")
data['sample3'] = min_data[1]
csv_parsed_data2[i] = data
i = i + 1
print i,'::',csv_parsed_data2,'--------------'
print csv_parsed_data2,' all index has same value'
any efficient way to do this??
It sounds you are assigning the same data dict to each of the values of your outer multidict, and just modifying the values it holds on each pass through the loop. This will result in all the values appearing the same, with the values from the last pass through the loop.
You probably need to make sure that you create a separate dictionary object to hold the data from each value. A crude fix might be to replace multidict[i] = data with multidict[i] = dict(data), but if you know how data is created, you can probably do something more elegant.
Edit: Seeing your code, here's a way to fix the issue:
csv_parsed_data2 = {}
with open('1112.txt') as infile:
i =0
data = {} # start with empty data dict
for lineraw in infile:
line = lineraw.strip()
if 'sample1 ' in line:
### TO GET SOURCE ROUTER NAME ###
data['sample1'] = line[8:]
elif 'sample2- ' in line:
### TO GET DESTINATION ROUTER NAME ###
data['sample2'] = line[13:]
elif 'sample3' in line:
### TO GET MIN,MAX,MEAN AND STD VALUES ###
min_value = line.replace("ms"," ")
min_data = min_value.split(" ")
data['sample3'] = min_data[1]
csv_parsed_data2[i] = data
data = {} # after saving a reference to the dict, reinitialize it
i = i + 1
print i,'::',csv_parsed_data2,'--------------'
print csv_parsed_data2,' all index has same value'
To understand what was going on, consider this simpler situation, where I a values in a dictionary after saving a reference to it when it had some older values:
my_dict = { "foo": "bar" }
some_ref = my_dict
print some_ref["foo"] # prints "bar"
my_dict["foo"] = "baz"
print some_ref["foo"] # prints "baz", since my_dict and some_ref refer to the same object
print some_ref is d # prints "True", confirming that fact
In your code, my_dict was data and some_ref were all the values of csv_parsed_data2. They would all end up being references to the same object, which would hold whatever the last values assigned to data were.
Try this:
multidict = {}
for j in range(10):
s = {}
s['name'] = raw_input()
s['age'] = input()
multidict[j] = s
This will have the desired result