Diamonds of triangle in C++ - c++

Question

I just understood the concept of making a triangle in C++ that is made of asterisks.
Now that I tried to replace those asterisks by "diamonds of asterisks", I found a very
logic error and that is the "newline" and I can't find it anymore, can anyone help me
with my code?
I want my output to be like a triangle with asterisks, but the asterisks is substituted by asterisks of diamonds.
#include<iostream>
using namespace std;
int main()
{
int number, space1, space2, space3;
int i, j, x, y, z;
cout << "Enter any number: ";
cin >> number;
space1 = (2*number)-1;
space2 = number-1;
space3 = space1*space2;
z = number-1;
for(i = 1; i <= number; i++)
{
for(j = 1; j <= (2*i)-1; j++){
for (x = 1; x <= number; x++)
{
for(y = 1; y <= space3; y++)
{
cout << " ";
}
for(y = 1; y <= number-x; y++)
{
cout << " ";
}
for(y = 1; y <= (2*x)-1; y++)
{
cout << "*";
}
for(y = 1; y <= z; y++)
{
cout << " ";
}
z--;
if(x <= number)
{
cout << endl;
}
}
if(z >= 3)
{
z = 1;
}
for(x = 1; x <= number-1; x++)
{
for(y = 1; y <= space3; y++)
{
cout << " ";
}
for(y = 1; y <= x; y++)
{
cout << " ";
}
for(y = 2*(number-x)-1; y >= 1; y--)
{
cout << "*";
}
for(y = 1; y <= z; y++)
{
cout << " ";
}
z++;
if(x <= number)
{
cout << endl;
}
}
}
space3 -= space1;
}
}

Answer 1

Not sure what you’re really asking (asterisks that are diamonds?) – some example of the desired output could have helped! – but I like this program:
#include <iostream>
#include <string>
using namespace std;
auto main() -> int
{
for( int y = 0; y < 32; ++y )
{
cout << string( 32 - y, ' ' );
for( int x = 0; x < 32; ++x )
cout << (x & ~y? ' ' : '*') << ' ';
cout << endl;
}
}
Output:
*
* *
* *
* * * *
* *
* * * *
* * * *
* * * * * * * *
* *
* * * *
* * * *
* * * * * * * *
* * * *
* * * * * * * *
* * * * * * * *
* * * * * * * * * * * * * * * *
* *
* * * *
* * * *
* * * * * * * *
* * * *
* * * * * * * *
* * * * * * * *
* * * * * * * * * * * * * * * *
* * * *
* * * * * * * *
* * * * * * * *
* * * * * * * * * * * * * * * *
* * * * * * * *
* * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *