Multiplying two integers if initial input is an odd integer in C++ - c++

Question

I'm working on a homework assignment for a beginning C++ class and I'm a bit lost.
Here's the assignment:
Create a c++ program which ask the user to input a number.
The output of the program should be one of the following:
You entered an EVEN number.
OR
You entered an ODD number.
if the user entered an ODD number, ask them to enter another number.
Multiply this number by the first number and output the result.
The even/odd part is pretty easy- I got that part to work. I've gotten completely lost on the second part. I'm getting so many lines of errors I can't even figure out where the beginning is. If anyone could give me a hint as to what I'm doing wrong, I'd greatly appreciate it.
#include <iostream>
using namespace std;
int main () {
int num1; // This is the original number entered by the user.
int num2; // This is the second number entered if the first number is odd.
cout << "Enter a number: "<< endl;
cin >> num1 >> endl;
if (num1 % 2 == 0) {
cout << num << " Your number is even." << endl;
} if (num1 % 2 != 0) {
cout << num1 << " Your number is odd. Please enter another number: “<< endl;
cin >> num1 >> endl;
} // end of if odd
cout << " Your two numbers multiplied equals (num1 *= num2)” << endl;
} // end of main ()

Answer 1

#include <iostream>
using namespace std;
int main () {
int num1; // This is the original number entered by the user.
int num2; // This is the second number entered if the first number is odd.
cout << "Enter a number: "<< endl;
cin >> num1;
if (num1 % 2 == 0) {
cout << num1 << " Your number is even." << endl;
}
else {
cout << num1 << " Your number is odd. Please enter another number: " << endl;
cin >> num2;
cout << " Your two numbers multiplied equals " << num1*num2 << endl;
} // end of if odd
return 0;
} // end of main ()
Here's fixed code. You tried to cout << num, but there's no num variable, should be num1, also it's wrong to cin >> endl.
What was unexpected, your ” at the end is not a " but something else and it produces a lot of errors.

Answer 2

The part for the odd values
if (num1 % 2 != 0) {
cout << num1 << " Your number is odd. Please enter another number: “<< endl;
cin >> num2 >> endl;
cout << " Your two numbers multiplied equals:" << (num1 * num2) << endl;
}

Answer 3

after corrections
if (num1 % 2 != 0) {
cout << num1 << " Your number is odd. Please enter another number:"<< endl;
cin >> num2;
cout << " Your two numbers multiplied equals:" << (num1 * num2) << endl;
}
do not place formulas between quotaion marks. this turns them into strings or chars that cant be executed as desire. ie cout << " Your two numbers multiplied equals (num1 *= num2)” << endl;
placing the statement cout << " Your two numbers multiplied equals (num1 *= num2)” << endl; out side the if statement causes the statement to be run even if the number was not odd. this doesnt comply with the assignment. and num2 being null still will cause an error