I am new to google python api client.I am learning from https://developers.google.com/api-client-library/python/start/get_started.I want to make an api which converts python object into JSON data and sends to a servlet.
The python code of file api.py:
import os
import urllib2
import httplib2
import json
import requests
from apiclient.discovery import build
from oauth2client.client import flow_from_clientsecrets
from oauth2client.tools import run_flow
from oauth2client.file import Storage
from oauth2client import tools
api_version='1'
_file_="D:\API"
CLIENT_SECRETS = os.path.join(os.path.dirname(_file_))
flow=flow_from_clientsecrets(CLIENT_SECRETS,
scope=[
'https://www.googleapis.com/auth/devstorage.full_control',
],
http = httplib2.Http()
auth_http = credentials.authorize(http)
service=build('SendNotif',api_version,http=http)
req = urllib2.Request('http://example/notify')
req.add_header('Content-Type', 'application/json')
data={"message":"Hello User you are notified"}
data_json = json.dumps(data)
response = urllib2.urlopen(req, json.dumps(data))
The error shown is:
D:\API>python api.py
File "api.py", line 25
auth_http = credentials.authorize(http)
^
SyntaxError: invalid syntax
please do help in correcting me..
thanks in advance....
You're missing a closing parenthesis for this line:
flow=flow_from_clientsecrets(CLIENT_SECRETS,
Related
I want to run RASA with --enable-api inside the python code rather than the command line. Below is my code which is not working. Let me know how can i do that. The issue is once i hit the service because the channel is 'cmdline' it comes to the command line. I don't know how to resolve this.
from __future__ import absolute_import
from __future__ import division
from __future__ import print_function
from __future__ import unicode_literals
import logging
import rasa_core
from rasa_core.agent import Agent
from rasa_core.policies.keras_policy import KerasPolicy
from rasa_core.policies.memoization import MemoizationPolicy
from rasa_core.interpreter import RasaNLUInterpreter
from rasa_core.utils import EndpointConfig
from rasa_core.run import serve_application
from rasa_core import config
from rasa_core.policies.fallback import FallbackPolicy
from rasa_core.policies.keras_policy import KerasPolicy
from flask import Flask
from flask_cors import CORS, cross_origin
app = Flask(__name__)
CORS(app)
logger = logging.getLogger(__name__)
#app.route("/conversations/default/respond",methods=['POST'])
def run_weather_bot(serve_forever=True):
logging.basicConfig(level="ERROR")
interpreter = RasaNLUInterpreter('C:\\xxxx_nlu\\models\\nlu\\default\\weathernlu')
action_endpoint = EndpointConfig(url="http://xxx.xx.xx.xxx:5055/webhook")
agent = Agent.load('C:\\xxxx_nlu\\models\\dialogue', interpreter=interpreter, action_endpoint=action_endpoint)
rasa_core.run.serve_application(agent,channel='cmdline')
return agent
if __name__ == '__main__':
app.run("xxx.xx.xx.xxx",5005,debug=True)
You're calling rasa bot in the command line in your run_weather_bot function using below command.
rasa_core.run.serve_application(agent,channel='cmdline')
As you can see its serving as command line application.
I have made some changes in your code for a conversation with rasa chatbot. You can refer AGENT documentation and Weather bot article for connection of RASA agent and how RASA agent handles the input message.
def rasa_agent():
interpreter = RasaNLUInterpreter("Path for NLU")
action_endpoint = EndpointConfig(url="Webhook URL")
agent = Agent.load('Path to Dialogue', interpreter=interpreter, action_endpoint=action_endpoint)
## Next line runs the rasa in commandline
# rasa_core.run.serve_application(agent,channel='cmdline')
return agent
#app.route("/conversations/default/respond",methods=['POST'])
def run_weather_bot(serve_forever=True):
agent = rasa_agent() # calling rasa agent
## Collect Query from POST request
## Send Query to Agent
## Get Response of BOT
output = {} ## Append output
return jsonify(output)
I'm trying to write an AWS Lambda service using Python 2.7 that will generate an In-Memory CSV file and email it as an attachment. I feel like I'm close with this script based on what I've learned but I'm not quite there.
# Import smtplib for the actual sending function
import smtplib
import sys
import csv
import cStringIO
from os.path import basename
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.application import MIMEApplication
# Import the email modules we'll need
server = smtplib.SMTP('smtp.postmarkapp.com', 587)
server.starttls()
server.login('.....','.....')
list = []
row1 = ["One","Two","Three"]
list.append(row1)
msg = MIMEMultipart()
msg['To'] = "daniel#mydomain.com"
msg['From'] = "noreply#mydomain.com"
msg['Subject'] = "DG Test subject"
msg.attach(MIMEText("Test Message"))
csv_buffer = cStringIO.StringIO()
writer = csv.writer(csv_buffer, lineterminator='\n')
writer.writerow(["1","2","3"])
for row in list:
writer.writerow(row)
print(csv_buffer.getvalue())
msg.attach(csv_buffer)
try:
response = server.sendmail(msg['From'], ["daniel#mydomain.com"],msg.as_string())
server.quit()
except AttributeError as error:
print(error)
else:
print(response)
This gives me the following error:
1,2,3
One,Two,Three
'cStringIO.StringO' object has no attribute 'get_content_maintype'
Basically it comes down to not being sure how to use the csv_buffer object. Assuming I just need to add that attribute to the object somehow but I'm not quite sure how. If I try to add any additional arguments to the .attach() line, it complains that I have too many arguments.
Thanks!
I figured it out, thanks to stitching together a few SO posts.
import cStringIO
import csv
csv_buffer = cStringIO.StringIO()
writer = csv.writer(csv_buffer, delimiter=',', quoting=csv.QUOTE_ALL)
writer.writerow(["1","2","3"])
for row in list:
writer.writerow(row)
print(csv_buffer.getvalue())
# new lines
csv_file = MIMEText(csv_buffer.getvalue())
attachment = csv_file.add_header('Content-Disposition', 'attachment', filename="csv_file.csv")
msg.attach(csv_file)
I could get HTTP Basic Authentication to work using requests:
import requests
request = requests.post(url, auth=(user, pass), data={'a':'whatever'})
And also using urllib2 and urllib:
import urllib2, urllib
passman = urllib2.HTTPPasswordMgrWithDefaultRealm()
passman.add_password(None, url, user, pass)
auth_handler = urllib2.HTTPBasicAuthHandler(passman)
opener = urllib2.build_opener(auth_handler)
urllib2.install_opener(opener)
content = urllib2.urlopen(url, urllib.urlencode({'a': 'whatever'}))
The problem is I get an unauthorized error when I try the same thing with mechanize:
import mechanize, urllib
from base64 import b64encode
browser = mechanize.Browser()
b64login = b64encode('%s:%s' % (user, pass))
browser.addheaders.append(('Authorization', 'Basic %s' % b64login ))
request = mechanize.Request(url)
response = mechanize.urlopen(request, data=urllib.urlencode({'a':'whatever}))
error:
HTTPError: HTTP Error 401: UNAUTHORIZED
The code I tried with mechanize could be trying to authenticate in a different way than the other two code snippets. So the question is how could the same authentication process be achieved in mechanize.
I am using python 2.7.12
The header should have been added to the request instead of the browser. In fact the browser variable isn't even needed.
import mechanize, urllib
from base64 import b64encode
b64login = b64encode('%s:%s' % (user, pass))
request = mechanize.Request(url)
request.add_header('Authorization', 'Basic %s' % b64login )
response = mechanize.urlopen(request, data=urllib.urlencode({'a':'whatever'}))
I'm trying to send an email using Python and Google's smtp. After calling it I get an error:
msg = MIMEMultipart('alternative')
TypeError: 'LazyImporter' object is not callable
Did anyone had the same problem ? What's the solution for that ?
My code:
Pastebin code
Just change your imports to
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
I'm working on a simple script to send emails via the GMail API, and an old script I found to access their SMTP interface wasn't working.
So I used the following script from their quickstart page to start first with reading:
#! /usr/bin/env python
#
import httplib2
from apiclient.discovery import build
from oauth2client.client import flow_from_clientsecrets
from oauth2client.file import Storage
from oauth2client.tools import run
CLIENT_SECRET = '.client.json'
OAUTH_SCOPE = 'https://www.googleapis.com/auth/gmail.readonly'
STORAGE = Storage('gmail.storage')
flow = flow_from_clientsecrets(CLIENT_SECRET, scope=OAUTH_SCOPE)
http = httplib2.Http()
credentials = STORAGE.get()
if credentials is None or credentials.invalid:
credentials = run(flow, STORAGE, http=http)
http = credentials.authorize(http)
gmail_service = build('gmail', 'v1', http=http)
threads = gmail_service.users().threads().list(userId='me').execute()
if threads['threads']:
for thread in threads['threads']:
print 'Thread ID: %s' % (thread['id'])
Running this gives a NotImplementedError as shown in this question.
So I imported and called run_flow instead of run, as I did not install gflags to continue. However, I get the following error:
TypeError: run_flow() takes at least 3 arguments (3 given)
I understand from the linked question that argparse should help. I could add the call to parser that that question uses, but I would have no idea what arguments to pass on the command line.
Anyone successfully implemented something with this who could give some help?
You don't need to pass extra arguments to the command line when using run_flow python.
import argparse
...
from oauth2client import tools
...
from oauth2client.tools import run_flow
...
parser = argparse.ArgumentParser(parents=[tools.argparser])
flags = parser.parse_args()
....
credentials = run_flow(flow, STORAGE, flags, http=http)
Then you can run
python quickstart.py