I am taking help of this website to learn regex and I am stuck at this particular lesson. Looks like regex is wrong there.
When I write (\w+\s\d+)((\,\d+)?) "text" and "capture" goes green but "result" appears wrong (cross marks).
But if Write (\w+ (\d+)) it gives below result.
your task text capture result
capture text Jan 1987 Jan 1987, 1987 ✓
capture text May 1969 May 1969, 1969 ✓
capture text Aug 2011 Aug 2011, 2011 ✓
Now, question is (\w+ (\d+)) doesn't show that it going to capture comma but is right answer.And, in this (\w+\s\d+)((\,\d+)?) expression I have specified but it is coming wrong, why?
That's because the capture column tells you, what you should capture. For example: Jan 1987, 1987 means you should capture two groups. 1) Jan 1987 2) 1987
They use the comma as divider between the groups. So it's not part of the string you should capture, but just a divider to tell you where the next excepted capture group starts.
If you step to the next lesson http://regexone.com/lesson/13 my example will be much more clear. In the text column there isn't any comma (e.g. 1280x720) but in capture column you're asked for "1280, 720". So this props my theory.
Related
I have a line in a text doc that im trying to pull data from.
Example
Line im searching for in Text file:
Valid from: Sun May 17 19:00:00 CDT 1998
I want to find the key words "Valid from:" and then get only Sun May 17 and 1998
So end result should look like this:
Sun May 17 1998
I think im close to getting it right. This is what I have. It finds the keyword Valid From: but it returns more than I need
Sun May 17 19:00:00 CDT 1998
(?<=Valid from:)\s+\w+\s+\w+\s+\d+\s+\d+:\d+:\d+\s+\w+\s+\d+
Thank you in advance for any assistance.
I would use two capture groups (…) instead of lookaround construct:
$sampleText = 'Valid from: Sun May 17 19:00:00 CDT 1998'
$regEx = 'Valid from:\s+(\w+\s+\w+\s+\d+)\s+\d+:\d+:\d+\s+\w+\s+(\d+)'
if( $sampleText -match $regEx ) {
# Combine the matched values of both capture groups into a single string
$matches[1,2] -join ' '
}
Output:
Sun May 17 1998
If the -match operator successfully matches the pattern on the right-hand-side with the input text on the left-hand-side, the automatic variable $matches is set.
$matches contains the full match at index 0 and the matched values of any capture groups at subsequent indices, in this case 1 and 2.
Using the -join operator we combine the matched values of the capture groups into a single string.
Demo at regex101.
Is there someone to help me with the following:
I'm trying to find specific date and time strings in a text (to be used within VBA Word).
Currently working with the following RegEx string:
(?:([0-9]{1,2})[ |-])?(?:(jan(?:uari)?|feb(?:ruari)?|m(?:aa)?rt|apr(?:il)?|mei|jun(?:i)?|jul(?:i)?|aug(?:ustus)?|sep(?:tember|t)?|okt(?:ober)?|nov(?:ember)?|dec(?:ember)?))?(?: |-)?(?(3)(?: around | at | ))?(?:([0-9]{1,2}:[0-9]{1,2})?(?: uur| u|u)?)?
Tested output on following text:
date with around time: 26 sep 2016 around 09:00u
date with at time: 1 sep 2016 at 09:00 uur
date and time u: 1 sep 2018 09:00 u
time without date: 08:30 uur
date with time u: 1 sep 2016 at 09:00u
only time: 09:00
only month: jan
month and year: feb 2019
only day: 02
only day with '-': 2-
day and month: 2 jan
month year: jan 2018
date with '-': 2-feb-2018 09:00
other month: 01 sept 2016
full month: 1 september 2018
shortened year: jul '18
Rules:
a date followed by time is valid
a date followed by text 'around' or 'at', followed by time is valid
a date without day number is valid
a date without year is valid
a date, month only is not valid
a day, without month or year not valid
a date may contain dashes '-'
a year may be shortenend with ', like jun '18
month name can be short or long
full match includes ' uur' or 'u' (to highlight the text in ms-Word)
submatches text from capture are without prepending or trailing spaces
example at: [https://regex101.com/r/6CFgBP/1/]
Expected output (when using in VBA Word):
An regex Matches collection object in which each Match.SubMatches contains the individual items d, m, y, hh:mm from the capture groups in the regex search string.
So for example 1: the Submatches (or capture groups) contains values: '26' ','sep','2016','09:00'
The RegEx works fine, but some false-positives need to be excluded:
In case there is a day without month/year, should be excluded from Regex (example 9 and 10)
In case there is a month without day, should be excluded (example 7)
(I was trying with som lookahead and reference \1 and ?(1), but was not able to get it running properly...)
Any advice highly appreciated!
As I understood, you require that each date/time part (day, month, year, hour
and minute) must be present.
So you should remove ? after relevant groups (they are not optional).
It is also a good practice to have each group captured as a relevant capturing group.
There is no need to write something like jun(?:i)?. It is enough
(and easier to read) when you write just juni? (the ? refers just
to preceding i).
Another hint: As the regex language contains \d char class, use just
it instead of [0-9] (the regex is shorter and easier to read.
Optional parts (at / around) should be an optional and non-capturing group.
Anything after the minute part is not needed in the regex.
So I propose a regex like below (for readability, I divided it into rows):
(\d{1,2})[ -](jan(?:uari)?|feb(?:ruari)?|m(?:aa)?rt|apr(?:il)?|mei|juni?
|juli?|aug(?:ustus)?|sep(?:tember|t)?|okt(?:ober)?|nov(?:ember)?|dec(?:ember)?)
[ -](\d{4}) (?:around |at )?(\d{1,2}:\d{1,2})
Details:
(\d{1,2}) - Day.
[ -] - A separator after the day (either a space or a minus).
(jan(?:uari)?|...dec(?:ember)?) - Month.
[ -] - A separator after the month.
(\d{4}) - year.
(?:around |at )? - Actually, 3 variants of a separator between year
and hour (space / around / at), note the space before (...)?.
(\d{1,2}:\d{1,2}) - Hour and minute.
It matches variants 1, 2, 3, 5 and 13.
All remaining fail to contain each required part, so they are not matched.
If you allow e.g. that the hour/minute part is optional, change the respective fragment
into:
( (?:around |at )?(\d{1,2}:\d{1,2}))?
i.e. surround the space/around/at / hour / minute part with ( and )?,
making this part an optional group. Then, variants 14 and 15 will also
be matched.
One more extension: If you also allow the hour/minute part alone,
add |(\d{1,2}:\d{1,2}) to the regex (all before is the first variant and
the added part is the second variant for just hour/minute.
Then, your variants No 4 and 6 will also be matched.
For a working example see https://regex101.com/r/33t1ps/1
Edit
Following your list of rules, I propose the following regex:
(\d{1,2}[ -])? - Day + separator, optional.
(jan(?:uari)?|...|dec(?:ember)?) - Month.
(?:[ -](\d{4}|'\d{2}))? - Separator + year (either 4 or 2 digits with "'").
( (?:around |at )?(\d{1,2}:\d{1,2}))? - Separator + hour/minute -
optional end of variant 1.
|(\d{1,2}:\d{1,2}) - Variant 2 - only hour and minute.
It does not match only your variants No 9 and 10.
For full regex, including also "uur" see https://regex101.com/r/33t1ps/3
Finally I found something that helps me using the month properly :-)
\b(?:([1-3]|[0-3]\d)[ |-](?'month'(?:[1-9]|\d[12])|(?:jan(?:uari)?|feb(?:ruari)?|m(?:aa)?rt|apr(?:il)?|mei|jun(?:i)?|jul(?:i)?|aug(?:ustus)?|sep(?:tember|t)?|okt(?:ober)?|nov(?:ember)?|dec(?:ember)?))?)?(?:(\g'month')[ |-]((?:19|20|\')(?:\d{2})))?\b(?: omstreeks | om | )?(?:(\d{1,2}[:]\d{2}(?: uur|u)?|[0-2]\d{3}(?: uur|u)))?\b
It uses a named constructor/subroutine. Found here:
https://www.regular-expressions.info/subroutine.html
I'm having difficulty matching other cases for a date range. The end goal will be to extract each group to build an ISO 8601 date format.
Test cases
May 8th – 14th, 2019
November 25th – December 2nd
November 5th, 2018 – January 13th, 2019
September 17th – 23rd
Regex
(\w{3,9})\s([1-9]|[12]\d|3[01])(?:st|nd|rd|th),\s(19|20)\d{2}\s–\s(\w{3,9})\s([1-9]|[12]\d|3[01])(?:st|nd|rd|th),\s(19|20)\d{2}
regexr
I would like to be able to capture each group regardless if it exists or not.
For example, May 8th – 14th, 2019
Group 1 May
Group 2 8th
Group 3
Group 4
Group 5 14th
Group 6 2019
And November 5th, 2018 – January 13th, 2019
Group 1 November
Group 2 5th
Group 3 2018
Group 4 January
Group 5 13th
Group 6 2019
To capture the empty string if the group doesn't match otherwise, the general idea is to use (<characters to match>|)
Try this one:
([A-z]{3,9})\s((?:[1-9]|[12]\d|3[01])(?:st|nd|rd|th))(?:, (?=19|20))?(\d{4}|)\s–\s([A-z]{3,9}|)\s?((?:[1-9]|[12]\d|3[01])(?:st|nd|rd|th))(?:, (?=19|20))?(\d{4}|)
https://regex101.com/r/4UY0WE/1/
When trying to capture the month (the first group), make sure to use [A-z]{3,9} rather than \w{3,9}, otherwise you might match, eg, 23rd rather than a month string.
Separated out:
([A-z]{3,9}) # Month ("January")
\s
((?:[1-9]|[12]\d|3[01])(?:st|nd|rd|th)) # Day of month, including suffix ("23rd")
(?:, (?=19|20))? # Comma and space, if followed by year
(\d{4}|) # Year
\s–\s #
([A-z]{3,9}|) # same as first line
\s?
# same as third to fifth lines:
((?:[1-9]|[12]\d|3[01])(?:st|nd|rd|th))
(?:, (?=19|20))?
(\d{4}|)
This one saves some space by consolidating some of the groupings.
Try it here
Full regex:
([A-z]{3,9}) ((?:[1-9]|[12]\d|3[01])(?:st|nd|rd|th))(?:, ((?:19|20)\d{2}))? [–-] ([A-z]{3,9}\s)?((?:[1-9]|[12]\d|3[01])(?:st|nd|rd|th))(?:, ((?:19|20)\d{2}))?
Separated by group (spaces replaced by \s for readability):
1. ([A-z]{3,9})
\s
2. ((?:[1-9]|[12]\d|3[01])(?:st|nd|rd|th))
3. (?:,\s((?:19|20)\d{2}))?
\s[–-]\s
4. ([A-z]{3,9}\s)?
5. ((?:[1-9]|[12]\d|3[01])(?:st|nd|rd|th))
6. (?:,\s((?:19|20)\d{2}))?
This method does not use lookups so is generally safe for any regex engine.
I'm tasked to capture date for itineraries in email message, but the dates given were all in different formats, I guess I need help to find out if there's any way to capture the following formats:
02 APR
APR 02
2 APR
APR 2
2nd APR
APR 2nd
2nd April
April 2nd
APR 12th
April 12th
12th April
April 13-16
13-16 April
APR 13-16
13-16 APR
April 13th-16th
13th-16th April
APR 13th-16th
13th-16th APR
I've tried numerous ways but just could not understand or fathom as I'm a
newbie to regex.
The closest I could get was using this:
(\d*)-(\d*) APR|April \d*\d*
EDIT- Found out that i`ve missed some more formats.
13th - 16th APR
13~16 April
13/16 APR
I`ve tried using the following:
(Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)\ *\d+(?:[nr]d|th|st)?(?: * \d+(?:[nr]d|th|st)?)?|\d+(?:[nr]d|th|st)?(?: . \d+(?:[nr]d|th|st)?)?\ *(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)
Could either capture dates with space or without space.
Is there a way to capture all formats, and split the dates with '-', '/','~' and output/write into a single standardize format?
(Group 1 Date)-Month (Group 2 Date)-Month eg: 13-Apr 16-Apr
Appreciate for your kind suggestions and comments.
You need to account for optional values. Here is an enhanced version matching your sample input:
/(\d+)(?:st|[nr]d|th)?-?(\d*)(?:st|[nr]d|th)?\s*Apr(?:il)?|Apr(?:il)?\s*(\d+)(?:st|[nr]d|th)?-?(\d*)(?:st|[nr]d|th)?/i
See the regex demo (note you need to use a case-insensitive modifier to match any variants of April)
Basically, there are 2 alternatives matching April and date ranges:
(\d+)(?:st|[nr]d|th)?-?(\d*)(?:st|[nr]d|th)?\s*Apr(?:il)? - 1+ digits followed with an optional st, nd, rd, th, followed with an optional hyphen, followed with 0+ digits, followed with optional st, etc. followed with 0+ whitespace and then Apr or April (case insensitive due to /i modifier)
| - or
Apr(?:il)?\s*(\d+)(?:st|[nr]d|th)?-?(\d*)(?:st|[nr]d|th)? - the same as above but swapped.
I came up with this Regex:
(?:APR|April)\ *\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?|\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?\ *(?:APR|April)
See details here: Regex101
Maybe it's overkill, but I came up with this regex that will match with any month:
(?:January|JAN|February|FEB|March|MAR|April|APR|May|MAY|June|JUN|July|JUL|August|AUG|September|SEP|October|OCT|November|NOV|December|DEC)\ *\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?|\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?\ *(?:January|JAN|February|FEB|March|MAR|April|APR|May|MAY|June|JUN|July|JUL|August|AUG|September|SEP|October|OCT|November|NOV|December|DEC)
Unreadable, check here if you want details: Regex101
Improved version using Wiktor Stribiżew's trick:
(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)\ *\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?|\d+(?:[nr]d|th|st)?(?:-\d+(?:[nr]d|th|st)?)?\ *(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|Jun(?:e)?|Jul(?:y)?|Aug(?:ust)?|Sep(?:tember)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)
See details here: Regex101
It matches every monthes, it uses less steps (more efficient)
BUT, you need to make sure you're case insensitive
I came up with this:
(\d+(?:th|st|[nr]d)?(?:-\d+(?:th|st|[nr]d)?)?\s*(?:APR|April))|((?:APR|April)\s*\d+(?:th|st|[nr]d)?(?:-\d+(?:th|st|[nr]d)?)?)
Live Demo
I'm terible with regex and I can't seem to wrap my head around this simple task.
I need to parse out the two dates in a string which always has one of two formats:
"Inquiry at your property for December 29, 2013 - January 03, 2014"
OR
"Inquiry at your property for 29 December , 2013 - 03 January, 2014"
the 2 different date formats are throwing me off. Any insights would be appreciated!
/(\d+ \w+, \d+|\w+ \d+, \d+)/ for example. Try it out on Rubular.
For sure, it would pickup more stuff, like 2013 NotReallyAMonth, 12345. But if you don't have things in the input that look like a date, but not actually a date this might work.
You could make the regexp stronger, but applying more restrictions on what is matched:
/(\d{2} (?:January|December), \d{4}|(?:January|December) \d{2}, \d{4})/
In this case the day is always two digits, the year is 4. Months are listed explicitly (you would have to list all of them).
Update: For ranges it would be a different regexp:
/((?:Jan|Dec) \d+ - \d+, \d{4})/
Obviously they can all be combined together:
/(\d{2} (?:January|December), \d{4}|(?:January|December) \d{2}, \d{4}|(?:Jan|Dec) \d+ - \d+, \d{4})/