Stata - Generating rolling average variable - stata

I'd like to generate a rolling average variable from a basketball dataset. So if the first observation is 25 points on January 1, the generated variable will show 25. If the second observation is 30 points on January 2, the variable generated will show 27.5. If the third observation is 35 points, the variable generated will show 30, etc.

For variable y ordered by some time t at its simplest the average of values to date is
gen yave = sum(y) / _n
which is the cumulative sum divided by the number of observations. If there are occasional missing values, they are ignored by sum() but the denominator needs to be fixed, say
gen yave = sum(y) / sum(y < .)
This generalises easily to panel structure
bysort id (t) : gen yave = sum(y) / sum(y < .)

Here is the solution I came up with. I had to create three variables, a cumulative point total (numerator) and a running count (denominator), then divided the two variables to get player points per game:
gen player_pts = points if player[_n]!=player[_n-1]
replace player_pts=points+player_pts[_n-1] if player[_n]==player[_n-1]&[_n]!=1
by player: gen player_games= [_n]
gen ppg=player_pts/player_games

Related

Reordering panels by another variable in twoway, by() graphs

Suppose I make the following chart showing the weight of 9 pigs over time:
webuse pig
tw line weight week if inrange(id,1,9), by(id) subtitle(, nospan)
Is it possible to reorder the panels by another variable while retaining the original label? I can imagine defining another variable that is sorted the right way and then labeling it with the right id, but curious if there is a less clunky way of achieving that.
I think you are right: you need a new ordering variable. Positively, you can order on any criterion of choice. Watch out for ties on the variable used to order, which can always broken by referring to the original identifier. Here we sort on final weights, by default smallest first. (For largest first, negate the weight variable.)
webuse pig, clear
keep if id <= 9
bysort id (week) : gen last = weight[_N]
egen newid = group(last id)
bysort newid : gen toshow = strofreal(id) + " (" + strofreal(last, "%2.1f") + ")"
* search labmask for download links
labmask newid , values(toshow)
set scheme s1color
line weight week, by(newid, note("")) sort xla(1/9)
Short papers discussing the principles here are already in train for publication in the Stata Journal in 2021.

Is there a way to flip the order of observations in Stata?

Is it possible to create a backwards counting variable in Stata (like the command _n, just numbering observations backwards)? Or a command to flip the data set, so that the observation with the most recent date is the first one? I would like to make a scatter plot with AfD on the y-axis and the date (row_id) on the x-axis. When I make the plot however, the weeks are ordered backwards. How can I change the order?
This is the code:
generate row_id=_n
twoway scatter AfD row_id || lfit AfD row_id
Here are the data set and the plot:
Your date variable is a string variable, which is unlikely to get you the desired result if you sort on that variable.
You can create a Stata internal form date variable from your string variable:
gen date_num = daily(date, "MDY")
format date_num %td
The values of this new variable will represent the number of days since 1 Jan 1960.
If you create a scatter plot with this date variable on the x-axis, by default it will be sorted from min to max. To let it run from max to min you can specify option xscale(reverse).
If you still want to create an id variable by yourself you can choose one of these options (ascending and descending):
sort date_num
gen id = _n
gsort -date_num
gen id = _n
For your problem, plotting in terms of a daily date variable and -- if for some reason that is a good idea -- using xscale(reverse) are likely to be what you need, as well explained by #Wouter.
In general something like
gen long newid = _N - _n + 1
sort newid
will reverse a dataset.

Creating indicator variable in Stata

In a panel data set I have 3 variables: name, week, and income.
I would like to make an indicator variable that indicates initial weeks where income is 0. So say a person X has 0 income in the first 13 weeks, the indicator takes the value 1 the first 13 weeks, and is otherwise 0. The same procedure for person Y and so on.
I have tried using by groups, but I can't get it to work.
Any suggestions?
One solution is
bysort name (week) : gen no_income = sum(income) == 0
The function sum() yields cumulative or running sum. So, as long as income is 0, its cumulative sum remains 0 too. As soon as a person earns something, the cumulative sum becomes positive. The code is based on the presumption that cumulative income can not cross zero again because in a given week, income is negative. To exclude that possibility use an appropriate extra condition, such as
bysort name (week) : gen no_income = sum(income) == 0 & income == 0
For a problem with very similar flavour, see this FAQ. A meta-lesson is to look at the StataCorp FAQs as one of several resources.

Count number of living firms efficiently

I have a list of companies with start and end dates for each. I want to count the number of companies alive over time. I have the following code but it runs slowly on my large dataset. Is there a more efficient way to do this in Stata?
forvalues y = 1982/2012 {
forvalues m = 1/12 {
*display date("01-`m'-`y'","DMY")
count if start_dt <= date("01-`m'-`y'","DMY") & date("01-`m'-`y'","DMY") <= end_dt
}
}
One way is to use the inrange function. In Stata, Date variables are just integers so you can easily operate on them.
forvalues y = 1982/2012 {
forvalues m = 1/12 {
local d = date("01-`m'-`y'","DMY")
count if inrange(`d', start_dt, end_dt)
}
}
This alone will save you a huge amount of time. For 50.000 observations (and made-up data):
. timer list 1
1: 3.40 / 1 = 3.3980
. timer list 2
2: 18.61 / 1 = 18.6130
timer 1 is with inrange, timer 2 is your original code. Results are in seconds. Run help inrange and help timer for details.
That said, maybe someone can suggest an overall better strategy.
Assuming a firm identifier firmid, this is another way to think about the problem, but with a different data structure. Make sure you have a saved copy of your dataset before you do this.
expand 2
bysort firmid : gen eitherdate = cond(_n == 1, start_dt, end_dt)
by firmid : gen score = cond(_n == 1, 1, -1)
sort eitherdate
gen living = sum(score)
by eitherdate : replace living = living[_N]
So,
We expand each observation to 2 and put both dates in a new variable, the start date in one observation and the end date in the other observation.
We assign a score that is 1 when a firm starts and -1 when it ends.
The number of firms is increased by 1 every time a firm starts and decreased by 1 every time one ends. We just need to sort by date and the number of firms is the cumulative sum of those scores. (EDIT: There is a fix for changes on the same date.)
This new data structure could be useful for other purposes.
There is a write-up at http://www.stata-journal.com/article.html?article=dm0068
EDIT:
Notes in response to #Roberto Ferrer (and anyone else who read this):
I fixed a bad bug, which made this too difficult to understand. Sorry about that.
The dates used here are just the dates at which firms start and end. There is no evident point in evaluating the number of firms at any other date as it would just be the same number as the previous date used. If you needed, however, to interpolate to a grid of dates, copying the previous count would be sufficient.
It is important not to confuse the Stata function sum() which returns the cumulative sum with any egen function. The impression that egen's total() is an alternative here was a side-effect of my bug.

How to replace a zero-valued answer by its respective average value?

I have a household data set which includes expenditures for various foods. I categorized them into main food groups and price is obtained by dividing the expenditure value by quantity. For some households price comes as zero since their consumption with respect to the corresponding food group is zero. In such cases, I want to get the price as the average price of the corresponding city, district & province, which that non-consumed household is selected.
How could I do it using STATA?
The mean of the positive values is
egen mean_price = mean(price / (price > 0)), by(province district city)
and you can replace zeros in a clone by
gen price2 = cond(price > 0, price, mean_price)
The division trick can be explained like this. If price > 0 is true, then that expression evaluates to 1; and if false to 0. Dividing by 1 clearly leaves values unchanged. Dividing by 0 creates missings, which egen's mean() function will ignore, which is precisely what is wanted.
There is more discussion of related technique in the article referred to in http://www.stata-journal.com/article.html?article=dm0055
P.S. Stata is the correct spelling. It is an invented word, and was never an acronym.
P.S. You have yet to acknowledge an answer at How to get the difference of two variables, when there are missing values?
LATER:
In this case another way is
egen total = total(price), by(province district city)
egen number = total(price > 0), by(province district city)
gen price2 = cond(price > 0, price, total/number)
as zero prices make no difference to the total. Use doubles throughout.