Xslt for table content replacement only in Tbody - xslt

Question

Could you please help us out in the below scenario.
We need xsl code for the below scenario.
We need to retrieve ref tag inside para in Thead
We need to remove ref tag inside para in Tbody.
For last cell we should not perform this ref removal. ie) should behave like thead
Sample Input:
<xml>
<Table>
<thead>
<Row>
<Cell>
<para id=4>
<ref>A</ref>
</para>
</Cell>
</Row>
</thead>
<tbody>
<Row>
<Cell>
<para id=1>
<ref>b</ref>
</para>
</Cell>
.
.
<Cell>
<para id=6>
<ref>retrive</ref>
</para>
</Cell>
</Row>
<Row>
<Cell>
<para id=2>
c
</para>
</Cell>
.
.
<Cell>
<para id=7>
<ref>retrive</ref>
</para>
</Cell>
</Row>
<Row>
<Cell >
<para id=3>
<ref>d</ref>
<ref>e</ref>
</para>
</Cell>
.
.
<Cell>
<para id=8>
<ref>retrive</ref>
</para>
</Cell>
</Row>
</tbody>
</table>
Expected Output:
<xml>
<Table>
<thead>
<Row>
<Cell>
<para id=4>
<ref>A</ref> (No change in thead)
</para>
</Cell>
</Row>
</thead>
<tbody>
<Row>
<Cell>
<para id=1> (para attribute should be retrieved)
b (ref tag should be removed but content should be retrieved)
</para>
</Cell>
.
.
<Cell>
<para id=6>
<ref>retrieve</ref> (Should retrieve ref tag with value)
</para>
</Cell>
</Row>
<Row>
<Cell>
<para id=2>
c
</para>
</Cell>
.
.
<Cell>
<para id=7>
<ref>retrieve</ref> (Should retrieve ref tag with value)
</para>
</Cell>
</Row>
<Row>
<Cell>
<para id=3>
d
e
</para>
</Cell>
.
.
<Cell>
<para id=8>
<ref>retrieve</ref> (Should retrieve ref tag with value)
</para>
</Cell>
</Row>
</tbody>
</table>

Answer 1

With the adjustments to your input XML to have the closing table tag match the opening table tag and to wrap the value of id in quotation marks, the following XSLT
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" omit-xml-declaration="no"
encoding="UTF-8" indent="yes" />
<xsl:strip-space elements="*"/>
<xsl:template match="table">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="tbody/Row/Cell[position()!=last()]/para/ref">
<xsl:value-of select="."/>
</xsl:template>
</xsl:transform>
when applied to this corrected input XML produces the output
<?xml version="1.0" encoding="UTF-8"?>
<Table>
<thead>
<Row>
<Cell>
<para id="4">
<ref>A</ref>
</para>
</Cell>
</Row>
</thead>
<tbody>
<Row>
<Cell>
<para id="1">b</para>
</Cell>
<Cell>
<para id="6">
<ref>retrieve</ref>
</para>
</Cell>
</Row>
<Row>
<Cell>
<para id="2">
c
</para>
</Cell>
<Cell>
<para id="7">
<ref>retrieve</ref>
</para>
</Cell>
</Row>
<Row>
<Cell>
<para id="3">de</para>
</Cell>
<Cell>
<para id="8">
<ref>retrieve</ref>
</para>
</Cell>
</Row>
</tbody>
</Table>
The <xsl:template match="tbody/Row/Cell[position()!=last()]/para/ref">
matches all Cell elements in tbody except the last one - position()!=last() - and replace the ref attribute with its value.