how to save the sorted arrays in textfile? - c++

I have a program that sorted arrays how can i save in text file?
for example: the sorted arrays is: 1, 2, 3, 4, 5.
how can i save in text file named. Sorted elements".
I've tried many ways but the sorted array wouldn't save in text file.
I am a newbie so I find it difficult.
here is my code.
#include <iostream>
using namespace std;
int main() {
cout << "Enter number of element:";
int n; cin >> n;
int a[n];
for(int i=0;i<n;i++)
{
cout << "element number " << (i+1) << " : ";
cin >> a[i];
}
int e=1, d=3;
int i, j, k, m, digit, row, col;
int length = sizeof(a)/sizeof(int);
int bmat[length][10];
int c[10];
for(m=1;m<=d;m++)
{
for(i=0;i<10;i++)
{
c[i]=-1;
}
for(i=0;i<length;i++)
{
digit=(a[i]/e)%10;
c[digit]++;
row=c[digit];
col=digit;
bmat[row][col]=a[i];
}
k=-1;
for(i=0;i<10;i++)
{
if(c[i]!=-1)
{
for(j=0;j<=c[i];j++)
{
k++;
a[k]=bmat[j][i];
}
}
}
e=e*10;
}
cout << endl;
cout << "Sorted array:" << endl;
for(int i=0;i<n;i++)
{
cout << a[i] << " , ";
}
cout << endl;
system("pause");
return 0;
}

//Use this code
#include <iostream>
#include <vector>
#include <algorithm>
#include <fstream>
using namespace std;
int main()
{
int n = 0;
cout << "Enter number of element:";
cin >> n;
//Data Structure
std::vector<int> list;
//push back element in vector
for(register int i=0;i<n;++i)
list.push_back(rand()%10 + 1);
//do shuffling before sorting because rand() generates increasing order number
std::random_shuffle(list.begin(),list.end());
std::sort(list.begin(),list.end());
ofstream textfile;
textfile.open ("E:\\example.txt");
for(size_t i= 0;i<list.size();++i)
textfile << list[i] <<" ";
textfile.close();
}

If you can write the sorted array to std::cout, then you can write it to a file. In C++, the console is the same as a file.
Put this at the end of main:
cout << "Sorted array:" << endl;
print_array( std::cout, a, n ); // Show the results to the user.
std::ofstream save( "array.txt" ); // Open a new file (or overwrite).
print_array( save, a, n ); // Save the results for later.
system("pause");
return 0;
}
and put the printing code in a new function, which may be defined before main:
void print_array( std::ostream & s, int * a, int n ) {
for(int i=0;i<n;i++)
{
s << a[i] << " , ";
}
s << endl;
}

#include<iostream>
#include<fstream>
using namespace std;
int compare(int, int);
void sort(int[], const int);
int compare(int x, int y){
return(x > y);
}
void swap(int *x, int *y){
int temp;
temp = *x;
*x = *y;
*y = temp;
}
void display(int array[], int n){
for (int i = 0; i<n; i++) {
cout << array[i] << " ";
}
cout << endl;
}
void writeToFile(int array[], int n){
ofstream myfile;
myfile.open("example.txt");
for (int i = 0; i<n; i++) {
myfile << array[i];
if (i != n - 1){
myfile << ", ";
}
}
myfile.close();
}
void sort(int table[], const int n) {
for (int i = 0; i < n; i++){
for (int j = 0; j < n - 1; j++) {
if (compare(table[j], table[j + 1]))
swap(&table[j], &table[j + 1]);
}
}
}
int main(){
int quantity;
int* tab;
ofstream outfile;
cout << "Enter number of element: ";
cin >> quantity;
tab = new int[quantity];
cout << "Element:\n\n" << endl;
for (int i = 0; i < quantity; i++){
int x = i;
cout << "#" << ++x << ":";
cin >> tab[i];
}
sort(tab, quantity);
cout << "The Sorted Elements are: ";
display(tab, quantity);
writeToFile(tab, quantity);
cout << endl;
getchar();
getchar();
//system("pause");
return 0;
}
in short, add this block to your code:
ofstream myfile;
myfile.open("example.txt");
for (int i = 0; i<n; i++) {
myfile << array[i];
if (i != n - 1){
myfile << ", ";
}
}
myfile.close();

You can use C++ fstream class, since you want to output, you can use ofstream here. You should just replace some "cout" with ofstream instance:
At the beginning of the code state it:
ofstream ofs("./sorted_elem.txt", ofstream::out);
When want to output:
ofs << "Sorted array:" << endl;
for(int i=0;i<n;i++)
{
ofs << a[i] << " , ";
}
ofs << endl;

In C++ you really want to use std::vector or some other nice container for storing arrays of numbers. For writing an array to file you need to open the file and individually write each element to the file (all untested).
#include <fstream>
int main()
{
std::ofstream fp("output.txt");
int data[5]; // todo: fill
for (unsitned i = 0; i < 5; ++i)
{
fp << data[i] << ' ';
}
}
And to read again:
#include <fstream>
int main()
{
std::ifstream fp("output.txt");
// todo: Determine the size of the array or guess it (don't guess it!)
unsigned array_size = 5;
int data[array_size];
int n = 0;
while (fp.good() && n < array_size) fp >> data[n++];
}
But because we are using C++, we can use std::vector:
#include <fstream>
#include <vector>
int main()
{
std::vector<int> me(5); // todo: fill
std::ofstream fp("output.txt");
for (size_t i = 0; i < me.size(); ++i) fp << me[i] << ' ';
// C++11: for (int d : me) fp << d << ' ';
}
And,
#include <fstream>
#include <vector>
int main()
{
std::ifstream fp("output.txt");
std::vector<int> data;
double buf;
while (fp >> buf) data.push_back(buf); // no longer need to guess
}

I think, the copy option was not demonstrated here so far.
Please check this code. (Assuming your vector is ready to use, I've skipped it).
The example uses a C-array and a vector. Please use the later in your code whenever possible. But however, for copy-function both work:
#include <iostream>
#include <iterator>
#include <vector>
#include <algorithm>
#include <fstream>
int main () {
int a[10]={0,1,2,3,4,5,6,7,8,9};
std::vector<int> v; for (int i=0; i<10; ++i)v.push_back(i*10); //0, 10, 20,...
std::ofstream fs_a( "c:/temp/out_a.txt" );
//store space separated
std::copy ( a, a+sizeof(a)/sizeof(a[0]), std::ostream_iterator<int>( fs_a, " ") );
//store coma-separated, as one-liner
std::copy ( v.begin(), v.end() ), std::ostream_iterator<int>( std::ofstream( "c:/temp/out_v.txt" ), ",") );
return 0;
}

Related

c++ variable sized arrays from Hackerrank with vectors

I wanted to solve a challenge named "Variable sized Arrays" on Hackerrank and I wanted to do that using vectors. The Code I wrote, doesn't work properly and I tried debugging it, but I'm getting nowhere. I'll be grateful for
Here's the challenge:
Consider an n-element array,a, where each index i in the array contains a reference Kito an array of integers (where the value of Ki varies from array to array). See the Explanation section below for a diagram.
Given a, you must answer q queries. Each query is in the format i j, where i denotes an index in array and j denotes an index in the array located at a[i] . For each query, find and print the value of element j in the array at location on a[i]a new line.
Input Format
The first line contains two space-separated integers denoting the respective values of n (the number of variable-length arrays) and q (the number of queries).
Each line of the subsequent lines contains a space-separated sequence in the format k a[i]0 a[i]1 … a[i]k-1 describing the k-element array located at a[i].
Each of the q subsequent lines contains two space-separated integers describing the respective values of i (an index in array a) and j (an index in the array referenced by a[i]) for a query.
Sample Input
2 2
3 1 5 4
5 1 2 8 9 3
0 1
1 3
Sample Output
5
9
So here's my code for this (I'll leave it with the couts for debugging):
#include <iostream>
#include <vector>
using std::cin;
using std::cout;
using std::vector;
using std::endl;
int main() {
int numberOfQueries = 0;
int numberOfArrays = 0;
cout << "Enter Nr.Of Arrays followed by Nr.Of Queries:";
cin >> numberOfArrays >> numberOfQueries;
cout << "Nr.Of Arrays: " << numberOfArrays << endl;
cout << "Nr.Of Queries: " << numberOfQueries << endl;
vector<vector<int>>multiArray;
cout << "MultiArray size: " << multiArray.size();
while (numberOfArrays != 0) {
int vsize = 0;
cout << "\nenter array starting by its size: ";
cin >> vsize;
cout << " Size entered is: " << vsize << endl;
vector<int> vec1(vsize);
cout << "Array Size is: " << vec1.size() << endl;
//int element = 0;
while (cin >> vsize) {
cout << "Element is: " << vsize << "\n";
vec1.push_back(vsize);
};
multiArray.push_back(vec1);
numberOfArrays--;
cout << "MultiArray size: " << multiArray.size();
cout << "Nr.Of Arrays: " << numberOfArrays << endl;
};
while (numberOfQueries > 0) {
int i = 0, j = 0;
cout << "\nQuery indexes:";
cin >> i >> j;
cout << multiArray[i][j];
numberOfQueries--;
}
}
while (cin >> vsize) {
cout << "Element is: " << vsize << "\n";
vec1.push_back(vsize);
};
should be something like
for (int i = 0; i < vsize; ++i) {
int elem;
cin >> elem;
cout << "Element is: " << elem << "\n";
vec1.push_back(elem);
}
while (cin >> vsize) isn't going to stop asking for input until you get end of file or an error. But you know how many inputs to expect so code that in a for loop.
My answer.
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include <string>
using namespace std;
int main() {
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
int n,q;
cin >> n >> q ;
vector<int> a[n];
int k;
for(int i = 0; i < n; i++)
{
cin >> k;
for (int j = 0; j < k; j++)
{
int val_a_i_j;
cin >> val_a_i_j;
a[i].push_back(val_a_i_j);
}
};
for (int i = 0; i < q; i++)
{
int a_i, j;
cin >> a_i >> j;
cout << a[a_i][j] << '\n';
}
return 0;
}
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main() {
int a , b;
cin >> a >> b;
vector<int> arr[a];
for(int i= 0 ; i < a ; i++)
{
int m;
cin >> m;
int o;
for(int j=0;j<m;j++)
{
cin >> o;
arr[i].push_back(o);
}
}
int r,s;
for(int k=1;k<b;k++)
{
cin>>r>>s;
cout <<a[r][s]<< endl;
}
return 0;
}
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main()
{
int n, q;
cin >> n >> q;
vector<int>* a;
a= new vector<int>[n];
int p;
int k;
for (p = 0;p < n;p++) {
cin >> k;
for (int i = 0; i < k; i++) {
int o;
cin >>o;
a[p].push_back(o);
}
}
int r, s;
for (p = 0;p < q;p++)
{
cin >> r >> s;
cout << a[r][s]<<endl;
}
return 0;
}
This problem is about handling vectors of the vector.
int main() {
int n,q;
cin>>n>>q;
vector<vector<int> > a;//creating vectors of vector
int k;
for (int i = 0; i < n; i++)
{
cin >>k;
vector <int> row; // creating vector
for (int j = 0; j < k; j++)
{
int val;
cin>> val;
row.push_back(val);
}
a.push_back(row);
}
for (int l=0; l < q; l++)
{
int i,j;
cin>>i>>j;
// checking boundary conditions
if ((i >= 0 && i < a.size() ) && (j >=0 && j < a[i].size()))
{
cout<<a[i][j]<<endl;
}
}
return 0;
}
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main()
{
vector<vector<int>> MultiArry;
vector<int> output;
int n1,n2, q;
int i,j;
cin >> n1 >> q;
MultiArry.resize(n1);
output.resize(q);
for(int i=0;i<n1;i++)
{
cin >> n2;
MultiArry[i].resize(n2);
for(int j=0;j<n2;j++)
{
cin >> MultiArry[i][j];
}
}
for(int ii=0;ii<q;ii++)
{
cin >> i >> j;
output[ii] = MultiArry[i][j];
}
for(int i=0;i<q;i++)
cout << output[i] << endl;
return 0;
}

read int per line c++ error needs solution

hey guys I need help for my read code seems not working properly here's the code. The problem is as shown in the picture, the compiler are supposed to display all 1 million int value but it seems that my write or the display code was wrong. It shows nothing like it's not even reading.
#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
#include <vector>
#include <omp.h>
#include <ctime>
#include <cstdlib>
using namespace std;
int* CreateArray( int*);
void shellSortParallel( int*, int);
void shellSortSequential(int*, int);
void InsertSort( int*, int, int, int);
int main()
{
int array_size = 1000000;
int n=0;
int* arr=new int[array_size];
ifstream fin("OUTPUT1.txt");
if(! fin)
{
cout << "File could not be opened." << endl;
}
else
{
cout << "File Opened successfully!!!. Reading data from file into array" << endl;
int data;
while(fin>>data)
{
arr[n] = data;
n++;
}
cout << "Displaying Array..." << endl << endl;
for(int i = 0; i < array_size; i++)
{
cout << arr[i];
}
}
fin.close();
int length = 1000000;
double endTime = 0, startTime = 0, totalTime = 0;
double start, end;
cout << "Program is now sorting using shell sort" <<endl;
startTime = time(NULL);
start = omp_get_wtime();// Start performance timer 1 run
shellSortParallel(arr, length);//Run the algorithm
end = omp_get_wtime();// End performance timer 1 run
endTime = time(NULL);
totalTime = endTime - startTime;
cout << "This is the time it took to run. " << totalTime << endl;// time in seconds
int stupid = 0;
cin >> stupid;
cout << "Program has completed all tasks!!" << endl;
return 0;
}
void shellSortParallel(int array[], int length)
{
int h;
int j = 0;
int temp = 0;
int i = 0;
for(h =length/2; h > 0; h = h/2)
{
#pragma omp parallel for shared( array, length, h, i) default(none)
for( i = 0; i < h; i++)
{
//int ID = omp_get_thread_num();
InsertSort(array, i, length, h);
}
}
}
void InsertSort(int arr[], int i, int length, int half)
{
//cout << ID << " ";
int temp = 0;
int j = 0;
for (int f = half + i; f < length; f = f + half)
{
j = f;
while(j > i && arr[j-half] > arr[j])
{
temp = arr[j];
arr[j] = arr[j-half];
arr[j-half] = temp;
j = j -half;
}
}
}
and here is the short version of the file that I'm going to read. Its a random number between 1 to 1million per line
2377763
88764877846
281327
60
625
86
646127818
14551
2177645
32033
1826761
555173
3415445377
32430
1101
any help would be much appreciate, thank you before
By if(fin>>data) you are not just testing, but retrieving data from stream. I suggest use ifs.good() for testing. Overall, you can write such a code instead
std::ifstream fin ("OUTPUT1.txt", std::ifstream::in);
char c = fin.get();
while (fin.good())
{
std::cout << c;
c = fin.get();
}
arr[n-1] = '\0'; is not correct because it's not an array of character so don't mind.
to correct it:
int data;
while(fin>>data)
{
arr[n] = data;
n++;
}
cout << "Displaying Array..." << endl << endl;
for(int i = 0; i < array_size; i++)
{
cout << arr[i];
}
why allocating such huge array of integers? use vector is a good thing:
vector<int> vec;
ifstream fin("OUTPUT1.txt");
int data;
while(fin >> data)
{
vec.push_back(data);
}
cout << "Displaying Array..." << endl << endl;
for(int i = 0; i < vec.size(); i++)
cout << vec[i] << endl;
fin.close();
88764877846 out band of an integer which causes the loop stop reading so you have to either get values as strings then convert into __int64 or __int128
to read values as strings:
string sLine;
int nLines = 0;
ifstream fin("OUTPUT1.txt");
// first read to get number of lines
while(getline(fin, sLine))
nLines++;
//create an array of strings
string* pstrValues = new string[nLines];
// set the get pointer to the beginning of file because the previous read moved it
fin.clear();
fin.seekg(0, ios::beg);
int i = 0;
while(getline(fin, sLine))
{
pstrValues[i] = sLine;
i++;
}
cout << "Displaying Array..." << endl << endl;
for( i = 0; i < nLines; i++)
cout << pstrValues[i] << endl;
fin.close();
now you have an array of strings convert it to int values but you must convert to __int64 because as I said there are values bigger than size of int (4bytes)

C++ array size by user input

I'm trying to write a program that will have a user input size for an array, and then take values into that array. I initially tried
int sz = 51;
double Arr[sz];
Which led to compilation errors. Apparently dynamic allocation of the variable has to happen, and I'd rather avoid that if possible. So I modified my code (current state as shown below) which now only throws "expected primary-expression before ']' token". Is there a way to fix this and I'm just not seeing it, or do I need to use dynamic allocation?
Thanks for your time!
#include <iostream>
#include <iomanip> //for setprecision
using namespace std;
int sz = 51;
double n=0;
double Arr[0];
void get_input(double Arr[], int &sz){ //gets input
do{
cout<< "Enter size: "<< endl;
cin>> sz;
if (sz<0 || sz>50){
cout<< "Invalid size, enter a value between 0 and 50"<<endl;
}
}while(sz<0 || sz>50);
for( int i=0; i<sz; i++){
cin>> Arr[i];
}
}
double calcSum( double Arr[], int sz){ //finds sum
for(int i=0; i<sz; i++){
n+= Arr[i];
}
return(n);
}
void printArray(double Arr[], int sz){ //prints array elements
for(int i=0; i<sz; i++){
cout<< Arr[i]<< setprecision(2)<<" ";
if(i%7 == 0)
cout<< endl;
}
}
int main()
{
double Arr[sz];
get_input(Arr[], sz); //error here
printArray(Arr[], sz); //error here
return 0;
}
VLAs (e.g. Arr[sz]) are only supported as extensions in C++. They aren't part of the official language standard. You should use std::vector instead.
Just use a std::vector, there's a standard library in C++ for this reason.
Demo:
notes: you don't need the globals (they are shadowed by the locals and you pass them by reference anyways)
Live On Coliru
#include <iostream>
#include <iomanip>
#include <vector>
using namespace std;
using array_t = std::vector<double>;
void get_input(array_t& Arr) { // gets input
size_t sz = 51; // unsigned types cannot be negative
do {
cout << "Enter size: " << endl;
cin >> sz;
if (sz > 50) {
cout << "Invalid size, enter a value between 0 and 50" << endl;
}
} while (sz > 50);
for (size_t i = 0; i < sz; ++i) {
double v;
if (cin >> v)
Arr.push_back(v);
else
std::cerr << "Error reading input\n";
}
//assert(sz = Arr.size());
}
double calcSum(array_t const& Arr) { // finds sum
double n = 0;
for (size_t i = 0; i < Arr.size(); ++i) {
n += Arr[i];
}
return n;
}
void printArray(array_t const& Arr) { // prints array elements
for (size_t i = 0; i < Arr.size(); ++i) {
cout << Arr[i] << setprecision(2) << " ";
if (i % 7 == 6)
cout << endl;
}
}
int main() {
array_t Arr;
get_input(Arr);
printArray(Arr);
std::cout << "\nSum: " << calcSum(Arr) << "\n";
}
When entering 3 1 2 3 you get:
Enter size: 3
1 2 3
1 2 3
Sum: 6

can not swap array elements c++

I am new to C++. I am trying to solve a problem in the textbook: swap the first and last element in an array. But when I run the code I wrote, nothing happened and even the sentence "Please enter the numbers in the array: " does not show up. Anyone could give some help? Thanks.
#include <iostream>
using namespace std;
int swap(int values[], int size)
{
int temp = values[0];
values[0] = values[size-1];
values[size-1] = temp;
}
int main()
{
const int SIZE = 5;
int test[SIZE];
cout << "Please enter the numbers in the array: " << endl;
int input;
cin >> input;
for(int i=0; i<SIZE; i++)
{
test[i] = input;
}
swap(test, SIZE);
cout << test[SIZE] << endl;
return 0;
}
There were a few mistakes:
You should get the input inside the loop and then assign it to the test array.
When printing the swapped value, access the test array with SIZE-1 instead of SIZE, because array indexes run from 0 to SIZE-1, inclusive.
You declared swap() as returning int, but provided no return statement (this suggests that you haven't enabled enough warnings from your compiler).
#include <iostream>
using namespace std;
void swap(int values[], int size)
{
int temp = values[0];
values[0] = values[size-1];
values[size-1] = temp;
}
int main()
{
const int SIZE = 5;
int test[SIZE];
int input;
cout << "Please enter the numbers in the array: " << endl;
for(int i=0; i<SIZE; i++)
{
cin >> input;
test[i] = input;
}
swap(test, SIZE);
cout << test[SIZE-1] << endl;
return 0;
}
#include <iostream>
using namespace std;
//Here return type should be void as you are not returning value.
void swap(int values[], int size)
{
int temp = values[0];
values[0] = values[size-1];
values[size-1] = temp;
}
int main()
{
const int SIZE = 5;
int test[SIZE];
cout << "Please enter the numbers in the array: " << endl;
//USE LOOP TO TAKE INPUT ONE BY ONE IN AN ARRAY
for(int i = 0; i < SIZE; i++)
cin >> test[i];
swap(test, SIZE);
//USE LOOP TO DISPLAY ELEMENT ONE BY ONE
for(int i = 0; i < SIZE; i++)
cout << test[i] << endl;
return 0;
}

Prompt user to enter two 3x3 int arrays and check equivalence

Here is what I have come up with so far... I am so close with literally 1 error left for it to compile.
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
const int SIZE = 3;
bool equals(const int m1[][SIZE], const int m2[][SIZE])
{
bool identical = true;
for (int i=0; i < SIZE && identical; i++ )
{
if (m1[i] != m2[i]){
identical = false;
}
}
return identical = true;
}
void printArray(const int m1[], int size)
{
for (int i = 0; i < size; i++)
cout << m1[i] << " ";
}
void printArray2(const int m2[], int size) //not sure if I need this 2nd
{ //void
for (int i = 0; i < size; i++)
cout << m2[i] << " ";
}
int main()
{
string input1, input2;
int const SIZE = 3;
double inputnumber;
int m2[SIZE];
int m1[SIZE];
cout << "Please enter the first array: " << endl;
getline(cin, input1);
stringstream ss (input1);
ss >> inputnumber;
cout << "Please enter the second array: " << endl;
getline(cin, input2);
stringstream si (input2);
si>>inputnumber;
for (int i=0; i< inputnumber ; ++i) {
ss >> m1[i];}
if (equals(m1, SIZE)){
cout << "The two arrays are identical ! ";
}
else{
cout << "The two arrays are NOT identical !";
}
cout << endl;
return 0;
}
Or at least I think that I am close... any help is much appreciated.
My current error is coming up on the IF statement in the main function. I could have more mistakes as I am very very new to C++. Like I said please help me out if you can.
If you just want code here it is , but if you want to practice I recommend you to implement error checking(incorrect format) in this code and to change the loops in my code into functions.
#include <iostream>
#include <sstream>
#include <string>
using namespace std;
int main()
{
string inp;
cout<<"Please enter an array of numbers in the following form\n"
"(where N's are any numbers) :\n"
"[N N N\nN N N\nN N N"<<endl;
double m1[3][3],m2[3][3];
for(short i=0;i<3;i++){
cout<<"> ";
if(i==0) cout<<"[ ";
getline(cin,inp);
stringstream inps(inp);
for(short j=0;j<3;j++){
inps>>m1[i][j];
}
}// Get the first array
cout<<"Now enter the second array :\n";
for(short i=0;i<3;i++){
cout<<"> ";
if(i==0) cout<<"[ ";
getline(cin,inp);
stringstream inps(inp);
for(short j=0;j<3;j++){
inps>>m2[i][j];
}
}// Get the second one
bool not_equal=false;
for(short i=0; i<3 && !not_equal ;i++)
for(short j=0; j<3 && !not_equal ;j++)
if(m1[i][j]!=m2[i][j])
not_equal=true;// Test equality
if(not_equal)
cout<<"The two arrays you entered are not equal !!"<<endl;
else
cout<<"The two arrays you entered are EQUAL ."<<endl;
return 0;
}
#include <iostream>
using namespace std;
int main()
{
int size = 3;
int m2[size][size];
int m1[size][size];
cout << "Please enter the first array: " << endl;
for(int i=0;i<size;i++)
{
for(int j=0;j<size;j++)
{
cin >> m1[i][j];
}
}
cout << "Please enter the second array: " << endl;
for(int i=0;i<size;i++)
{
for(int j=0;j<size;j++)
{
cin >> m2[i][j];
}
}
int flag=1;
for(int i=0;i<size;i++)
{
for(int j=0;j<size;j++)
{
if(m2[i][j]!=m1[i][j])
{
flag=0;
}
}
}
if(flag==1)
{
cout <<"SAME"<<endl;
}
else if(flag==0)
{
cout <<"NOT SAME"<<endl;
}
return 0;
}