if statements with char values - c++

Question

So I'm trying to write an easy basic game here with basic C++, and when I try to execute this
// global variabless
const char UP = 'w', LEFT = 'a', DOWN = 's', RIGHT = 'd'; // player movement choices
char playerMove; // goes with askPlayer
void askPlayer()
{
char choice;
cout << "Use the WASD keys to move: ";
cin >> choice;
int worked;
do{
if (choice == 'w' || choice == 'W')
{
playerMove = UP;
worked = 1;
}
else if (choice == 'a' || choice == 'A')
{
playerMove = LEFT;
worked = 1;
}
else if (playerMove == 's' || playerMove == 'S')
{
playerMove = DOWN;
worked = 1;
}
else if (playerMove == 'd' || playerMove == 'D')
{
playerMove = RIGHT;
worked = 1;
}
else
{
cout << "Invalid entry." << endl;
worked = 0;
}
} while (worked != 1);
return;
}
It works up to the user entering a letter. Xcode says (lldb) then the page fills up with numbers, and after you stop the run, it says "Program ended with exit code: 9". It does this even if you enter one of the valid values

Answer 1

You never prompt for another value after the user enters the first one:
cin >> choice; // <==
int worked;
do {
// ..
} while (worked != 1);
Just move the input into the loop:
int worked;
do {
cin >> choice; // possibly with cout prompt too
// rest as before
} while (worked != 1);

Answer 2

Your input is outside the loop, your variable worked is uninitialized ( though it is not a error in your code but is cleaner to initialize your variables) and it should have bool type. Whole code can be simplified by the switch statement:
void askPlayer()
{
do {
char choice;
cout << "Use the WASD keys to move: ";
cin >> choice;
switch( choice ) {
case 'w' : case 'W' :
playerMove = UP;
break;
case 'a' : case 'A' :
playerMove = LEFT;
break;
case 's' : case 'S' :
playerMove = DOWN;
break;
case 'd' : case 'D' :
playerMove = RIGHT;
break;
default:
cout << "Invalid entry." << endl;
continue;
}
} while( false );
return;
}