XSL to capture URL Params - xslt

Question

Not able to extract the params using XSLT,
for eg.: http://www.example.com/AB/100/123456/09/8
using XSLT need to extract like var1=AB, Var2=100, Var3=123456, var4=09, var5=8, All the params are mandatory. and var3 can accept 1-999999, could somebody share some ideas
tried Substring but it didn't help much

Answer 1

Though the input is not clear, just as example: given an input XML
<root>
<url>http://www.example.com/AB/100/123456/09/8</url>
</root>
following XSLT
<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />
<xsl:strip-space elements="*" />
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="url">
<xsl:call-template name="parse">
<xsl:with-param name="url" select="substring-after(.,'//')" />
<xsl:with-param name="position" select="1" />
</xsl:call-template>
</xsl:template>
<xsl:template name="parse">
<xsl:param name="url" />
<xsl:param name="position" />
<xsl:choose>
<xsl:when test="contains(substring-after($url, '/'),'/')">
<xsl:value-of select="concat('Var', $position, ': ')" />
<xsl:value-of select="substring-before(substring-after($url, '/'),'/')" />
<xsl:text>, </xsl:text>
<xsl:call-template name="parse">
<xsl:with-param name="url" select="substring-after($url, '/')" />
<xsl:with-param name="position" select="$position + 1" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="concat('Var', $position, ': ')" />
<xsl:value-of select="substring-after($url,'/')" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:transform>
produces the ouput
Var1: AB, Var2: 100, Var3: 123456, Var4: 09, Var5: 8
using the template parse which recursively calls itself when the url contains a /.
For every call the parameter url is reduced using substring-after() and the parameter position is incremented.