I need something besides [^0-9\n], I want a regex(but dont know how to make one), that captures anything in a pattern of numbers like this, "0000000000" or "000-000-0000" or basically any numbers that exist with spaces and or special characters right before or in between.
so any number, even like these (626*) 34a2- 4387) should convert to 6263424387
How can this be accomoplished? Im thinking its too hard?
You can search for all non-digits using:
\D+
OR
[^0-9]+
And replace by empty string.
RegEx Demo
I always forget this one myself and go hunting the internet for the answer. Here it is, for my future reference, and the rest of the internet
const rawNumber = '(555) 123-4567';
const strippedNumber = rawNumber.replace(/\D+/g, '');
Of course, my above example is JavaScript specific, but it can be adapted to other languages easily. The original post didn't specify language.
This is a better approche. it's includes decimal numbers as well.
"$9.0".replace(/[^0-9.]+/g, '');
JavaScript :)
Related
I need something besides [^0-9\n], I want a regex(but dont know how to make one), that captures anything in a pattern of numbers like this, "0000000000" or "000-000-0000" or basically any numbers that exist with spaces and or special characters right before or in between.
so any number, even like these (626*) 34a2- 4387) should convert to 6263424387
How can this be accomoplished? Im thinking its too hard?
You can search for all non-digits using:
\D+
OR
[^0-9]+
And replace by empty string.
RegEx Demo
I always forget this one myself and go hunting the internet for the answer. Here it is, for my future reference, and the rest of the internet
const rawNumber = '(555) 123-4567';
const strippedNumber = rawNumber.replace(/\D+/g, '');
Of course, my above example is JavaScript specific, but it can be adapted to other languages easily. The original post didn't specify language.
This is a better approche. it's includes decimal numbers as well.
"$9.0".replace(/[^0-9.]+/g, '');
JavaScript :)
I need to build a RegEx expression which gets its text strings from the Title field of my Database. I.e. the complete strings being searched are: Mr. or Ms. or Dr. or Sr. etc.
Unfortunately this field was a free field and anything could be written into it. e.g.: M. ; A ; CFO etc.
The expression needs to match on everything except: Mr. ; Ms. ; Dr. ; Sr. (NOTE: The list is a bit longer but for simplicity I keep it short.)
WHAT I HAVE TRIED SO FAR:
This is what I am using successfully on on another field:
^(?!(VIP)$).* (This will match every string except "VIP")
I rewrote that expression to look like this:
^(?!(Mr.|Ms.|Dr.|Sr.)$).*
Unfortunately this did not work. I assume this is because because of the "." (dot) is a reserved symbol in RegEx and needs special handling.
I also tried:
^(?!(Mr\.|Ms\.|Dr\.|Sr\.)$).*
But no luck as well.
I looked around in the forum and tested some other solutions but could not find any which works for me.
I would like to know how I can build my formula to search the complete (short) string and matches everything except "Mr." etc. Any help is appreciated!
Note: My Question might seem unusual and seems to have many open ends and possible errors. However the rest of my application is handling those open ends. Please trust me with this.
If you want your string simply to not start with one of those prefixes, then do this:
^(?!([MDS]r|Ms)\.).*$
The above simply ensures that the beginning of the string (^) is not followed by one of your listed prefixes. (You shouldn't even need the .*$ but this is in case you're using some engine that requires a complete match.)
If you want your string to not have those prefixes anywhere, then do:
^(.(?!([MDS]r|Ms)\.))*$
The above ensures that every character (.) is not followed by one of your listed prefixes, to the end (so the $ is necessary in this one).
I just read that your list of prefixes may be longer, so let me expand for you to add:
^(.(?!(Mr|Ms|Dr|Sr)\.))*$
You say entirely of the prefixes? Then just do this:
^(?!Mr|Ms|Dr|Sr)\.$
And if you want to make the dot conditional:
^(?!Mr|Ms|Dr|Sr)\.?$
^
Through this | we can define any number prefix pattern which we gonna match with string.
var pattern = /^(Mrs.|Mr.|Ms.|Dr.|Er.).?[A-z]$/;
var str = "Mrs.Panchal";
console.log(str.match(pattern));
this may do it
/(?!.*?(?:^|\W)(?:(?:Dr|Mr|Mrs|Ms|Sr|Jr)\.?|Miss|Phd|\+|&)(?:\W|$))^.*$/i
from that page I mentioned
Rather than trying to construct a regex that matches anything except Mr., Ms., etc., it would be easier (if your application allows it) to write a regex that matches only those strings:
/^(Mr|Ms|Dr|Sr)\.$/
and just swap the logic for handling matching vs non-matching strings.
re.sub(r'^([MmDdSs][RSrs]{1,2}|[Mm]iss)\.{0,1} ','',name)
Let's take an url like
www.url.com/some_thing/random_numbers_letters_everything_possible/set_of_random_characters_everything_possible.randomextension
If I want to capture "set_of_random_characters_everything_possible.randomextension" will [^/\n]+$work? (solution taken from Trying to get the last part of a URL with Regex)
My question is: what does the "\n" part mean (it works even without it)? And, is it secure if the url has the most casual combination of characters apart "/"?
First, please note that www.url.com/some_thing/random_numbers_letters_everything_possible/set_of_random_characters_everything_possible.randomextension is not a URL without a scheme like http:// in front of it.
Second, don't parse URLs yourself. What language are you using? You probably don't want to use a regex, but rather an existing module that has already been written, tested, and debugged.
If you're using PHP, you want the parse_url function.
If you're using Perl, you want the URI module.
Have a look at this explanation: http://regex101.com/r/jG2jN7
Basically what is going on here is "match any character besides slash and new line, infinite to 1 times". People insert \r\n into negated char classes because in some programs a negated character class will match anything besides what has been inserted into it. So [^/] would in that case match new lines.
For example, if there was a line break in your text, you would not get the data after the linebreak.
This is however not true in your case. You need to use the s-flag (PCRE_DOTALL) for this behavior.
TL;DR: You can leave it or remove it, it wont matter.
Ask away if anything is unclear or I've explained it a little sloppy.
I use VB.NET and would like to add http:// to all links that doesn't already start with http://, https://, ftp:// and so on.
"I want to add http here Google,
but not here Google."
It was easy when I just had the links, but I can't find a good solution for an entire string containing multiple links. I guess RegEx is the way to go, but I wouldn't even know where to start.
I can find the RegEx myself, it's the parsing and prepending I'm having problems with. Could anyone give me an example with Regex.Replace() in C# or VB.NET?
Any help appreciated!
Quote RFC 1738:
"Scheme names consist of a sequence of characters. The lower case letters "a"--"z", digits, and the characters plus ("+"), period ("."), and hyphen ("-") are allowed. For resiliency, programs interpreting URLs should treat upper case letters as equivalent to lower case in scheme names (e.g., allow "HTTP" as well as "http")."
Excellent! A regex to match:
/^[a-zA-Z0-9+.-]+:\/\//
If that matches your href string, continue on. If not, prepend "http://". Remaining sanity checks are yours unless you ask for specific details. Do note the other commenters' thoughts about relative links.
EDIT: I'm starting to suspect that you've asked the wrong question... that you perhaps don't have anything that splits the text up into the individual tokens you need to handle it. See Looking for C# HTML parser
EDIT: As a blind try at ignoring all and just attacking the text, using case insensitive matching,
/(<a +href *= *")(.*?)(" *>)/
If the second back-reference matches /^[a-zA-Z0-9+.-]+:\/\//, do nothing. If it does not match, replace it with
$1 + "http://" + $2 + $3
This isn't C# syntax, but it should translate across without too much effort.
In PHP (should translate somewhat easily)
$text = preg_replace('/href="(?:(http|ftp|https)\:\/\/)?([^"]*)"/', 'href="http://$1"', $text);
C#
result = new Regex("(href=\")([^(http|https|ftp)])", RegexOptions.IgnoreCase).Replace(input, "href=\"//$2");
If you aren't concerned with potentially messing up local links, and you can always guarantee that the strings will be fully qualified domain names, then you can simply use the contains method:
Dim myUrl as string = "someUrlString".ToLower()
If Not myUrl.Contains("http://") AndAlso Not myUrl.Contains("https://") AndAlso Not myUrl.Contains("ftp://") Then
'Execute your logic to prepend the proper protocol
myUrl = "http://" & myUrl
End If
Keep in mind this omits a lot of holes regarding the checking of which protocol should be used in the addition and if the url is relative or not.
Edit: I chose specifically not to offer a RegEx solution since this is a simple check and RegEx is a little heavy for it (IMO).
I am working with legacy systems at the moment, and a lot of work involves breaking up delimited strings and testing against certain rules.
With this string, how could I return "Active" in a back reference and search terms, stopping when it hits the first caret (^)?:
Active^20080505^900^LT^100
Can it be done with an inclusion in the regex of this "(.+)" ? The reason I ask is that the actual regex "(.+)" is defined in a database as cutting up these messages and their associated rules can be set from a front-end system. The content could be anything ('Active' in this case), that's why ".+" has been used in this case.
Rule: The caret sign cannot feature between the brackets, as that would result with it being stored in the database field too, and it is defined elsewhere in another system field.
If you have a better suggestion than "(.+)" will be happy to hear it.
Thanks in advance.
(.+?)\^
Should grab up to the first ^
If you have to include (.+) w/o modifications you could use this:
(.+?)\^(.+)
The first backreference will still be the correct one and you can ignore the second.
A regex is really overkill here.
Just take the first n characters of the string where n is the position of the first caret.
Pseudo code:
InputString.Left(InputString.IndexOf("^"))
^([^\^]+)
That should work if your RE library doesn't support non-greediness.