Mapping functions with variable arguments and calling by string c++ - c++

Question

I would like to have some fair idea how to map functions with variable arguments,return type of int and call it by a string..
Just for an example...
int func1(int a, int b);
int func2(int a1, int b1 , int* c1);
int func3(char* dummy);
int func4(double x, long y, int z, char** table);
int func5(double d1, double b1);
int func6(int* p, double* q, int i);
I just need a common function called
int CallFunction("funcname", param1, param2, ...);
for example
CallFunction("func1", 10, 20); /* calling function func1 and return func1 result*/
I know how to map functions using functions pointers having constant arguments but variable arguments seems to be complicated.. could anyone shower some idea how to do it.
I even explored Variadic templates.. But seems to complicated calling functions using strings..

Answer 1

I had exact the same problem.
Solved it with this solution:
#include <iostream>
#include <map>
#include <string>
int func0(int x)
{
std::cout << x << std::endl;
}
int func1(int x, int y)
{
std::cout << (x + y) << std::endl;
}
template <class... Args>
struct MapHolder{
static std::map<std::string, int (*)(Args...)> CallbackMap;
};
template <class... Args>
std::map<std::string, int (*)(Args...)> MapHolder<Args...>::CallbackMap;
class Callback {
public:
template <class ...Args>
void RegisterFunction(std::string name, int (*func)(Args...)) {
MapHolder<Args...>::CallbackMap[name] = func;
}
template <class ...Args>
int ExecuteFunction(std::string name, Args &&... args) {
return MapHolder<Args...>::CallbackMap[name](std::forward<Args>(args)...);
};
};
int main(int argc, char *argv[])
{
Callback cb;
cb.RegisterFunction("func0", &func0);
cb.RegisterFunction("func1", &func1);
cb.ExecuteFunction("func0", 42);
cb.ExecuteFunction("func1", 42, 42);
return 0;
}
This snippet is based on this answer. I only use other class/function names.

Answer 2

I'm not sure if this is what you're looking for, but anyway...
1. Creating a generic value holder
boost.any didn't make it into the standard, and, in case you don't know what it is, it allows you to store any C++ value in a single type (any) and get it back if you know the type. The following is a toy implementation of it:
struct TypeHandler {
void* (*copyFrom)(void *src);
void (*destroy)(void *p);
};
template<typename T>
TypeHandler *thandler() {
struct THandler {
static void *copyFrom(void *p) { return new T(*(T *)p); }
static void destroy(void *p) { delete (T *)p; }
};
static TypeHandler th = { &THandler::copyFrom, &THandler::destroy };
return &th;
}
TypeHandler contains two pointer to functions that know how to copy and how to destroy a specific C++ type. A Value can hold any type because it's composed of a void * and a pointer to a TypeHandler. When copying or destroying is required on the instance it asks to the specific type handler function...
struct Value {
TypeHandler *th;
void *p;
Value(const Value& other) : th(other.th), p(th->copyFrom(other.p)) { }
template<typename T> Value(const T& x) : th(thandler<T>()), p(new T(x)) { }
~Value() { th->destroy(p); }
Value& operator=(const Value& other) {
if (this != &other) {
th->destroy(p);
th = other.th;
p = th->copyFrom(other.p);
}
return *this;
}
template<typename T>
Value& operator=(const T& other) {
th->destroy(p);
th = thandler<T>();
p = new T(other);
return *this;
}
template<typename T>
T& to() const {
if (th != thandler<T>()) throw Error("type mismatch");
return *(T*)p;
}
};
Note that Value is copyable and can be passed by value and can be returned by functions.
Any copyable object is implicitly convertible into a Value and I can also convert it back to the original type with to<T>().
2. Creating the name->function maps
std::map<std::string, Value (*)(const Value&)> map1;
std::map<std::string, Value (*)(const Value&, const Value&)> map2;
Value call(const std::string& name, const Value& x1) {
return map1.at(name)(x1);
}
Value call(const std::string& name, const Value& x1, const Value& x2) {
return map2.at(name)(x1, x2);
}
Here I've created explicit maps for 1 and 2 arguments. May be this can be done using C++11 variadic templates, I didn't try. In C++03 libraries it's common to see this kind of stuff copy-n-pasted up to say n=20 to cover reasonable cases.
3. Macrology
To simplify registration of functions I wrote two ugly macros. May be this can be done also using variadic macros or templates (I'm not so sure about it, especially the automatic registration of the wrapper in the map).
#define regfunc1(name, t1) \
Value name(const Value& x1) { \
return name(x1.to<t1>()); \
} \
struct name##_ { \
name##_() { map1[#name]=&name; } \
} name##_instance
#define regfunc2(name, t1, t2) \
Value name(const Value& x1, const Value& x2) { \
return name(x1.to<t1>(), x2.to<t2>()); \
} \
struct name##_ { \
name##_() { map2[#name]=&name; } \
} name##_instance
4. Use
double square(double x) {
return x*x;
}
double hyp2(double x, double y) {
return x*x+y*y;
}
int mylen(const std::string& s) {
return s.size();
}
regfunc1(square, double);
regfunc2(hyp2, double, double);
regfunc1(mylen, std::string);
int main() {
Value x = 42;
Value y = std::string("This is a test");
Value z = 3.14;
printf("%0.3f\n", call("square", z).to<double>());
printf("%0.3f\n", call("hyp2", z, z).to<double>());
printf("mylen(\"%s\") = %i\n",
y.to<std::string>().c_str(),
call("mylen", y).to<int>());
return 0;
}