I am using a regular expression to match all UK bank card number formats; I have done research and managed to find/amend a regex that covers the majority of formats. However, I have a bit of an edge case where one is not matching and I do not know why, or how to resolve. This is what I am using:
(\b[4|5|6](\d){3}[\s|-]?((\d){4}[\s|-]?){2}(\d){4}\b)|(\b(\d){4}[\s|-]?(\d){6}[\s|-]?(\d){5}\b)
This is an example card number that does not work: 6759000000005
This is an example card number that does work: 675900000000555
Apologies if this is an easy question, I am fairly new to regular expression syntax. Any help to resolve would be greatly appreciated. Thanks.
See here the demo
The regex is (\b[4|5|6]\d{3}[\s-]?(\d{4}[\s-]?){2}\d{1,4}\b)|(\b\d{4}[\s-]?\d{6}[\s-]?\d{5}\b)
I'm not an expert of UK cards, so I can't tell what is the expected format as you did not gave exemples with spaces or hyphens in them...
If you can refine the requirements it's handlable.
A more generic card number validation (without separators, so you'll need to strip them before) would be
\d{6}\d{1,12}\d
As per the requirements of the norm (found nothing on the minimum length of the account identifier):
An ISO/IEC 7812 card number is most commonly 16 digits in length,[1]
and can be up to 19 digits. The structure is as follows:
a six-digit Issuer Identification Number (IIN) (previously called the
"Bank Identification Number" (BIN)) the first digit of which is the
Major Industry Identifier (MII), a variable length (up to 12 digits)
individual account identifier, a single check digit calculated using
the Luhn algorithm.[2]
Related
I am fairly new to RegEx and have had a search around online but am unable to find a regex that fits my requirements.
The ultimate aim is to search a string of text and extract the lowest monetary amount, however as the string may contain more than one £amount, then i'm happy for a regex to just extract all monetary values it can find and then I can write a calculation in order to return the lowest amount.
The string may have numbers that are not monetary values / numerous amounts, therefore the regex should always look for a £ symbol first OR it could end with a "p" or "P" to signify pence. For example "I need 2 of these at £10 each and one of those at 50p" - should return 10.00 & 0.50 - I can then calculate that 0.50 is the lowest amount.
As people also write their amounts in various ways, I need the regex to be able to spot different patterns - including the "," for every thousand. All below values should be valid:
£0
£0.00
£0.00p
£0000
£0000.00
£0000.00p
£0,000
£0,000.00
£0,000.00p
0p
Hopefully someone may be able to advise the best way to approach this.
Thanks
This works on your data set:
(?=^£|.*p$)£?\d*(?:,\d{3})*(\.\d{2})?p?
But it may improperly match some edge cases as well because everything is optional...
https://regex101.com/r/WptUn6/3
I'm attempting to create a Regex that finds only 2-digit integers or numbers with a precision of 2 decimal points.
In the example string at the bottom, I want to find only the following:
21 and 10.50
Using this expression, 100% is getting captured, in addition to the strings I desire to capture:
(\d){1,2}(\.?)([0-9]?[0-9]?){1,2}
I know I need to use ^% somewhere, but I can't figure out where it goes. Any suggestions are greatly appreciated.
Here's my sample string:
Earn Up to $21 Per Hour - Deliver Food with !!
Delivery Drivers work when they want and make great money when they do.
All orders are prepaid, just pick them up and deliver them to hungry diners. No waiting in line or fumbling with receipts and prepaid cards.
It's fast and easy to start working. Get started today.
Apply Now
Why choose ?
More orders than any other takeout platform
100% of our restaurants are official partners
Competitive pay: Per order fee + mileage + tips
We guarantee an hourly minimum of $10.50/hour*
Create your own schedule & work the hours you want
Word boundaries in your regular expression will grant you a bit more control.
Since word boundaries are a bit strict, we need to introduce an OR condition to address both cases which will satisfy your regex.
(\b[\d]{2}\.[\d]{2}\b)|(\b[\d]{2}\b)
Edit: Try this one,
\b[\d]{2}\b(\.[\d]{2})?
The first example has a chance to fail as it is order dependent due to the way it short-circuits. This I believe should address multiple cases properly.
I think this should work:
(?<!\d)((\d+\.\d\d)|(\d\d))(?!%|\d)
Demo (and explanation)
EDIT:
Improved version:
(?<!\d)(\d{1,2}(?:\.\d{1,2})?)(?!%|\d)
Demo (and explanation)
You can try this variant: (\d{1,}|[\d.])\b(?!%)
It uses negative lookahead (?!%) to exclude digits following by % sign.
Details at regex101
I am trying to figure out appropriate regex for indian train seat numbers. For e.g. S10 43, B4 24 etc. I know different trains have different number of seats and coaches but a general regex will work for me. I was trying something like this:
[A|B|C|S][1-15][1-72]$
But this is not working. I also didn't find link to all types of seats in train. Can anyone help me with this?
[ABCS](?:1[0-5]|[1-9])\s+(?:[1-9]|[1-6][0-9]|7[0-2])$
Limiting to a given number range (1-15 and 1-72) makes it a little more complicated (as above) - it will be a lot simpler if you just accept 1- or 2-digit numbers:
[ABCS]\d\d?\s+\d\d?$
But that will match A99 99 which apparently isn't valid
I am currently trying to validate UK telephone numbers:
The format I'm looking for is: 01234 567891 or 01234567891 - So I need the number to have 5 numbers then a space then 6 numbers or simply a 11 numbers.
The number must start with a 0.
I've had a look at a couple of examples:
/^[0-9]{10,11} - to check that the chars are all numbers
/^0[0-9]{9,10}$/ - to check that the first number is a 0
I'm just unsure how to put all these together and check if there is a space or not.
Could someone help me with this regex?
Thanks
Try this regex:
/^0\d{4}\s?\d{6}$/
Many people try to do input validation and formatting in a single step.
It is better to separate these processes.
Match UK telephone number in any format
^(?:(?:\(?(?:0(?:0|11)\)?[\s-]?\(?|\+)44\)?[\s-]?(?:\(?0\)?[\s-]?)?)|(?:\(?0))(?:(?:\d{5}\)?[\s-]?\d{4,5})|(?:\d{4}\)?[\s-]?(?:\d{5}|\d{3}[\s-]?\d{3}))|(?:\d{3}\)?[\s-]?\d{3}[\s-]?\d{3,4})|(?:\d{2}\)?[\s-]?\d{4}[\s-]?\d{4}))(?:[\s-]?(?:x|ext\.?|\#)\d{3,4})?$
The above pattern allows the user to enter the number in any format they are comfortable with. Don't constrain the user into entering specific formats.
Extract NSN, prefix and extension
^(\(?(?:0(?:0|11)\)?[\s-]?\(?|\+)(44)\)?[\s-]?)?\(?0?(?:\)[\s-]?)?([1-9]\d{1,4}\)?[\d[\s-]]+)((?:x|ext\.?|\#)\d{3,4})?$
Next, extract the various elements.
$2 will be '44' if international format was used, otherwise assume national format with leading '0'.
$4 contains the extension number if present.
$3 contains the NSN part.
Validation and formatting
Use further RegEx patterns to check the NSN has the right number of digits for this number range. Finally, store the number in E.164 format or display it in E.123 format.
There's a very detailed list of validation and display formatting RegEx patterns for UK numbers at:
http://www.aa-asterisk.org.uk/index.php/Regular_Expressions_for_Validating_and_Formatting_UK_Telephone_Numbers
It's too long to reproduce here and it would be difficult to maintain multiple copies of this document.
If you are looking for all UK numbers, I'd look for a bit more than just that number, some are in the format 020 7123 4567 etc.
^\s*\(?(020[7,8]{1}\)?[ ]?[1-9]{1}[0-9{2}[ ]?[0-9]{4})|(0[1-8]{1}[0-9]{3}\)?[ ]?[1-9]{1}[0-9]{2}[ ]?[0-9]{3})\s*$
/\d*(*)*+*-*/
Simple Telephone Regex includes + () and - anywhere, as well as digits
I think ^0[\d]{4}\s?[\d]{5,6}} will work for you. I have used [\d] instead of [0-9].
I find that RegExr is a useful online tool to check and try your regular expressions. It also has a nice library of examples to help point you in the right direction
you should just count the number of digits and check that it's 10,
Some UK numbers have only 9 digits, not 10 (not including the leading 0).
These include 40 of the 01 area codes (using "4+5" format), the 016977 area code (using "5+4" format), all 0500 numbers and some 0800 numbers.
There's a list at: http://www.aa-asterisk.org.uk/index.php/01_numbers
This US numbers pattern accepts following phones as well:
800-432-4500, Opt: 9, Ext: 100316
800-432-4500, Opt: 9, Ext: X100316
800-432-4500, Option #3
(?:(?:\+?1\s*(?:[.-]\s*)?)?(?:\(\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\s*\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\s*(?:[.-]\s*)?)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s*(?:[.-]\s*)?([0-9]{4}),?(?:\s*(?:#|x\.?|opt(\.|:|\.:)?|option)\s*#?(\d+))?,?(?:\s*(?:#|x\.?|ext(\.|:|\.:)?|extension)\s*(\d+))?
(used this answer in other topic as start point)
This question already has answers here:
What regular expression will match valid international phone numbers?
(23 answers)
Closed 8 years ago.
I use Clickatell to send SMSes to clients' mobile phones.
Is there a standardised regular expression for all valid mobile phone numbers, e.g. +27 123 4567? I'd roll my own, but I'm worried about missing an obscure, valid phone number format.
After stripping all characters except '+' and digits from your input, this should do it:
^\+[1-9]{1}[0-9]{3,14}$
If you want to be more exact with the country codes see this question on List of phone number country codes
However, I would try to be not too strict with my validation. Users get very frustrated if they are told their valid numbers are not acceptable.
Even if you write a regular expression that matches exactly the subset "valid phone numbers" out of strings, there is no way to guarantee (by way of a regular expression) that they are valid mobile phone numbers. In several countries, mobile phone numbers are indistinguishable from landline phone numbers without at least a number plan lookup, and in some cases, even that won't help. For example, in Sweden, lots of people have "ported" their regular, landline-like phone number to their mobile phone. It's still the same number as they had before, but now it goes to a mobile phone instead of a landline.
Since valid phone numbers consist only of digits, I doubt that rolling your own would risk missing some obscure case of phone number at least. If you want to have better certainty, write a generator that takes a list of all valid country codes, and requires one of them at the beginning of the phone number to be matched by the generated regular expression.
^\+[1-9]{1}[0-9]{7,11}$
The Regular Expression ^\+[1-9]{1}[0-9]{7,11}$ fails for "+290 8000" and similar valid numbers that are shorter than 8 digits.
The longest numbers could be something like 3 digit country code, 3 digit area code, 8 digit subscriber number, making 14 digits.
Posting a note here for users looking into this into the future. Google's libphonenumber is what you most likely would want to use. There is wrappers for PHP, node.js, Java, etc. to use the data which Google has been collecting and reduces the requirements for maintaining large arrays of regex patterns to apply.
Even though it is about international numbers I would want the code to be like :
/^(\+|\d)[0-9]{7,16}$/;
As you can have international numbers starting with '00' as well.
Why I prefer 15 digits : http://en.wikipedia.org/wiki/E.164
// Regex - Check Singapore valid mobile numbers
public static boolean isSingaporeMobileNo(String str) {
Pattern mobNO = Pattern.compile("^(((0|((\\+)?65([- ])?))|((\\((\\+)?65\\)([- ])?)))?[8-9]\\d{7})?$");
Matcher matcher = mobNO.matcher(str);
if (matcher.find()) {
return true;
} else {
return false;
}
}