Not much of a expert in regular expression here. My IT colleague dump my a text file which containt all our mailing list. But I need to clean it before using it.
I need to find and delete a string of text which always start by "3EA" and finish by "////".
I try several ways, but no cigars.
Here's some example of the string I need to delete :
3AEAEACjkCjm////
3AEAEACjlCjn////
3AEAEACjnCjp////
Thanks
3AE[a-zA-Z]{9}/{4}
Try this.See demo.
https://regex101.com/r/vN3sH3/61
You could use the below regex,
3EA\S*?////
Add anchors if necessary.
^3EA\S*?////$
Assuming there are always 9 alphabetical characters in between 3AE and ////, in search and replace (in regex mode) replace this pattern with a blank pattern:
3AE[A-Za-z]{9}////
Related
I would like to append _OLD to the end of each strings that starts with SR_ but before the symbol ' or without it
For example my text is the following:
SR_Apple
When the 'SR_APPLE' rotten, we must discard it.
I would like the find and replace to do:
SR_Apple_OLD
When the 'SR_APPLE_OLD' rotten, we must discard it.
I have tried (SR_*)+$.*(?='\s) based on what i Learned but no luck so far. Please help. Thx in Adv
For simple cases you should be able to use
Find: (\bSR_[\w]+)
Replace: $1_OLD
(\bSR_.+?)('|$) and $1_OLD$2 could also work if the text after SR_ is more complex
The lookbehind you're using is only matching the string if it ends with a ' so it won't find the text not in quotes.
regex101 is a useful tool for debugging expressions
I am trying to parse out some data using notepad++ macro. Here is the example of the data I have
<abcdefghkdadajsdkdjg><hhDate>2019-12-31 <dklajdlajdkjasd>
I want hhDate 2019-12-31 from the above data. I am very new to RegEx so I didn't try anything but I used notepad++ techniques to select and delete the unnecessary text but didn't work out.
Any help is appreciated.
Thanks
Assuming each of the strings are on a new line because you have to capture the whole line to remove the 'junk' and leave the good stuff, find the start of the line (^), then find first bit you want to capture and wrap it in () then find the second bit and wrap it in (), then proceed on to the end of the line ($).
So in Notepad++ work to get all the strings on separate lines first if they are not already. Then find/replace with 'regex' mode selected:
Find:
^.*?<.*?<(hhDate)>(\d+-\d+-\d+).*$
Replace:
$1 $2
https://regex101.com/r/BKha4m/1
If you don't want < to be removed before hh ? Then try this short code.
Find what: \s<.*?>
Replace with: nothing
Otherwise use this \s<.*?><|<.*>
Uncheck match-case
In the example below, is there any way to place a string like ("1one1") before {",} at the end of all lines which contain {ī}?
īn:"ZZin",
ín:"FFin",
ǐn:"QQin",
ìn:"TTin",
ie:"XXie",
iē:"TTie",
ié:"GGie",
Thanks
Using Notepad++ regex search for ^(.*ī.*)(",)$ and replace with \11one1\2.
You will need to use regex regex for notepad++.
so, mark "Regular Expression" in the final of Replace box.
in your fields to search:
find what: ī.[^"]"([A-Za-z0-9]*)
replace with: īn:"\11one1
i think it will do what you want. Let me know if it doesn't to edit the regex.
I have this file with thousands of records (more thank 300.000) and I have to replace all the occurrences of a particular string but keeping some of it.
I'll give you an example, the string would be
\123
\34565
\923
..etc
so basically I would have to convert these strings in to
'|''|'123'
'|''|'34565'
'|''|'923'
does anyone have a quick solution for this?
Many thanks
Try this -
Regex - \\(\d+)
Replace with - '|''|'\1'
Demo here
Use this regex:
\\(\d+)
You should use g(global) modifier to match all. So your final regex would become:
/\\(\d+)/g
and replace it with:
'|''|'$1'
Demo:http://regex101.com/r/yO3xQ6
Need some help in Notepad++
Example how it looks at the moment
http://www.test.com/doc/rat.rar">rat.rar
http://www.test.com/down/ung.rar">ung.rar
http://www.test.com/read/add.rar">add.rar
......
How I want it (just remove after ">....rar)
http://www.test.com/doc/rat.rar
http://www.test.com/down/ung.rar
http://www.test.com/read/add.rar
Its a list about 1000 lines. So help would be nice
Use the following expression:
">[^.]+\.rar
Explanation:
"> # literal `"` followed by literal `>`
[^.]+ # any character that is not a `.`, repeated at least once
\. # literal `.` character
rar # literal string `rar`
Note: a couple of other answers pointed out that just ">.* will work. This is true, because Notepad++ doesn't appear to support multi-line regular expressions, even with [\s\S]+. Either way will work so it's personal preference. The regex I gave in this answer is very verbose and would reduce the likelihood of false positives. ">.*, on the other hand, is shorter.
In regexp mode , replace pattern ">.* with empty string.
">.*
Search for this and replace with nothing.
Your search string should be ">.+\.rar, and you can just blank out the replace box. This should do the job.
Also, check that you've got regex selected at the bottom of the replace box ;)
If you put this in find ".* and nothing in replace, that should do what you're looking for.
Remember to check that you've got regex selected at the bottom of the replace box.
Flick the "regular expression" radio button and then use this for your FIND:
">[a-z]+\.[a-z]+
Then just put empty space for your REPLACE and replace all.
Use -
Find What : (.*)">(.*)
Replace With : \1
And check Regular expression option at the bottom of the dialog.