Grouping the consecutive elements in XSLT - xslt

Question

I am new to XSLT and XML. I have the following XML. I wanted to group the consecutive child elements.
<Root>
<Child No="1" Month="0" Date="13/08/2014" Payment="100">
<Totals/>
</Child>
<Child No="2" Month="1" Date="13/09/2014" Payment="100">
<Totals/>
</Child>
<Child No="3" Month="2" Date="13/10/2014" Payment="200">
<Totals/>
</Child>
<Child No="4" Month="3" Date="13/11/2014" Payment="300">
<Totals/>
</Child>
<Child No="5" Month="4" Date="13/12/2014" Payment="300">
<Totals/>
</Child>
<Child No="6" Month="5" Date="13/01/2015" Payment="100">
<Totals/>
</Child>
<Child No="7" Month="6" Date="13/01/2015" Payment="100">
<Totals/>
</Child>
<Child No="8" Month="7" Date="13/01/2015" Payment="100">
<Totals/>
</Child>
<Child No="9" Month="8" Date="13/01/2015" Payment="100">
<Totals/>
</Child>
<Child No="10" Month="9" Date="13/01/2015" Payment="100">
<Totals/>
</Child>
</Root>
I need to create a new PP node when Child[n]/Payment <> Child[n-1]/Payment using the XSLT.
And I am expecting the below result,
<PPS>
<PP>
<Ps>
<StartMonth>0</StartMonth>
<EndMonth>1</EndMonth>
<P>
<Amount>100</Amount>
<startP>1</startP>
</P>
<P>
<Amount>100</Amount>
<startP>2</startP>
</P>
</Ps>
</PP>
<PP>
<Ps>
<StartMonth>2</StartMonth>
<EndMonth>2</EndMonth>
<P>
<Amount>200</Amount>
<startP>3</startP>
</P>
</Ps>
</PP>
<PP>
<Ps>
<StartMonth>3</StartMonth>
<EndMonth>4</EndMonth>
<P>
<Amount>300</Amount>
<startP>4</startP>
</P>
<P>
<Amount>300</Amount>
<startP>5</startP>
</P>
</Ps>
</PP>
<PP>
<Ps>
<StartMonth>5</StartMonth>
<EndMonth>9</EndMonth>
<P>
<Amount>100</Amount>
<startP>6</startP>
</P>
<P>
<Amount>100</Amount>
<startP>7</startP>
</P>
<P>
<Amount>100</Amount>
<startP>8</startP>
</P>
<P>
<Amount>100</Amount>
<startP>9</startP>
</P>
<P>
<Amount>100</Amount>
<startP>10</startP>
</P>
</Ps>
</PP>
</PPS>
Here is my sample xslt
<xsl:stylesheet version="1.0" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="yes"/>
<xsl:key name="x" match="Child" use="#Payment"/>
<xsl:template match="/Root">
<PPS>
<xsl:for-each select="CF">
<xsl:if test="generate-id(.) = generate-id(key('x',#Payment)[1])">
<PP>
<Ps>
<xsl:for-each select="key('x', #Payment)">
<P>
<Amount><xsl:value-of select="format-number(translate(#Payment, ',','.'),'0.00')"/></Amount>
<startP><xsl:value-of select="#Date"/></startP>
</P>
</xsl:for-each>
</Ps>
</PP>
</xsl:if>
</xsl:for-each>
</PPS>
</xsl:template>
</xsl:stylesheet>

Answer 1

This would work:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/Root">
<PPS>
<xsl:for-each select="Child">
<xsl:variable name="Payment" select="#Payment"/>
<xsl:if test="not(preceding::*[1][self::Child and #Payment = $Payment])">
<PPS>
<Ps>
<xsl:apply-templates select="current()"/>
<xsl:apply-templates select="following::*[1][self::Child and #Payment = $Payment]">
<xsl:with-param name="Payment" select="$Payment"/>
</xsl:apply-templates>
</Ps>
</PPS>
</xsl:if>
</xsl:for-each>
</PPS>
</xsl:template>
<xsl:template match="Child">
<xsl:param name="Payment"/>
<P>
<Amount>
<xsl:value-of select="#Payment"/>
</Amount>
<startP>
<xsl:value-of select="#No"/>
</startP>
</P>
<xsl:apply-templates select="following::*[1][self::Child and #Payment = $Payment]"/>
</xsl:template>
</xsl:stylesheet>