My txt file looks like this:
line 1
line3
I'm trying to remove the empty line. I choose "extended" search mode in Notepad++'s Replace window and type \r\n or \n\r but cannot match it. So, how to do it? I have removed empty lines from a lot of files successfully, but now I cannot remove this one.
Try this regex replace operation in Find in Files window:
Find what: \R*(\R)
Replace with: \1
EDIT: To remove last CR/LF, run this twice (due to some special CR/LF processing reasons, it consumes only one character per run):
Find what: ^(.*)\R+$
Replace with: \1
Mode: Regular Expression
Option . matches newline: ON
Have a try with:
Find what: ^\R
Replace with: <NOTHING>
Where \R stands for any line break character, \n or \r or \r\n.
May be you have spaces in the line, in this case:
Find what: ^\s*\R
Replace with: <NOTHING>
What about menu Edit > Line Operations > Remove Empty Lines? In this case, are you OK with using of built-in functions?
Related
I want to remove just the last line in a file if it's a line containing nothing. I am using Notepad++.
Details
Say I have a text file open in Notepad++. If the last line of a file is the empty string, I want to remove it. I want to do this using Notepad++'s native find/replace functionality, with regexes.
Use Case
I often encounter this case after I copy a file from Visual Studio to Notepad++. The reason for searching how to do it with a regex is: when recording a macro in Notepad++ it's more stable to use a regex find/replace than just manually deleting a character. The manual delete might be sensitive to file length.
Ctrl+H
Find what: \R\z
Replace with: LEAVE EMPTY
CHECK Regular expression
Replace
Explanation:
\R # any kind of linebreak (i.e. \r, \n, \r\n)
\z # end of file
Screen capture (before):
Screen capture (after):
The solution is to search for this regex: \r\n$(?!\r\n) and replace it with nothing (the empty string).
I have a list like this
randomtext.html
file1
file1
file2
I want to mark the first line after the line ended with html. So, it should marked the first "file1" only
Have a try with:
Within Mark tab
Find what: html\R\K.+
Be sure you haven't chck . matches newline and check Mark lines then click on Find All
Explanation:
html : Literally html
\R : any kind of line break (ie. \n or \r or \r\n)
\K : forget everything found before
.+ : Everything until the next line break. (ie. the second line).
First of all i would like to ask what do you mean by mark?
Press ctrl+h. Select regular expression and you can use following regular expression:-
Find: (.* )html\r\n(.)\r\n(.)
Replace: $1html\r\n-------$2\r\n$3
Here i have use '-------' as the mark, you can put the mark according to your need.
I have a file containing many instances of block text that are $ separated. After each $ sign, there is a line break. How do I remove this line break after each dollar sign using the Regex search option in Notepad ++?
Update on Bohemians answer:
You would need to escape the $:
Search: \$[\n\r]+
Replace: $
Without escaping, $ means "end of line".
That's what worked for me.
Search: $[\n\r]+
Replace:
the Replace is not empty, it's one space stroke [space]
Use a lookbehind to match all the newline characters which are next to the $ symbol. Replacing the matched \n characters with empty string will give you the desired result.
(?<=\$)\n
If you want to remove one or more newline characters present just after to $ then add a + after \n in your regex.
(?<=\$)\n+
Use the below regex if you want to remove one or more new line or carriage return characters.
(?<=\$)[\r\n]+
DEMO
Use the Extended mode, not Regular Expresssion and you can do:
Find what: $\n
Replace with: $
I use Notepad++ and I need to delete all lines starting with, say "abc".
Attention, I don't need to replace the line starting with "abc" with a empty line, but I need to completely delete these lines.
How do I proceed (using regex, I suppose)?
Try replace
^abc.*(\r?\n)?
with
nothing
The ^ indicates the start of a line.
The . means wild-card.
The .* means zero or more wild-cards.
x? means x is optional.
The \r?\n covers both \r\n (generally Windows) and \n (generally Unix), but must be optional to cover the last line.
Search for this regular expression
^abc.*\r\n
Replace with nothing.
Searching a little bit more on regex in Notepad++ I discovered that the new line character is not \n as I expected (Windows), but the \n\r.
So, my regex replace expression should be:
Find: abc.*\r\n
Replace with: (nothing, empty field)
Try the regex \nabc.* in "Find and Replace" --> "Replace"
Leave "Replace With" field empty.
EDIT : This won't work with first like (because '\n' means "new line")
Press Ctrl+H to bring up the Replace window. Put
^abc.*(\r?\n)?
in the Find what and leave Replace with empty. Select Reqular expression and hit Replace All.
This reqular expression handles all the edge cases:
When the first line of the file starts with abc
When the last line of the file starts with abc and there is no new line at the end of the file.
I have multiple html files and some of them have some blank lines, I need a regex to remove all blank lines and leave only one blank line.. So it removes anything more than one blank line, and leave those that are just one or none (none like in having text in them).
I need it also to consider lines that are not totally blank, as some lines could have spaces or tabs (characters that doesn't show), so I need it to consider these lines with the regex to be removed as long as it is more than one line..
Search for
^([ \t]*)\r?\n\s+$
and replace with
\1
Explanation:
^ # Start of line
([ \t]*) # Match any number of spaces or tabs, capture them in group 1
\r?\n # Match one linebreak
\s+ # Match any following whitespace
$ # until the last possible end of line.
\1 will then contain the first line of whitespace characters, so when you use that as the replacement string, only the first line of whitespace will be preserved (excluding the linebreak at the end).
This worked for me on notepad++ v6.5.1. UNICODE windows 7
Search for: ^[ \t]*\r\n
Replace with: nothing, leave blank
Search mode: Regular expression.
search for (\r?\n(\t| )*){3,}, replace by \r\n\r\n, check "Regular expression" and ". matches newline".
Tested with Notepad++ 6.2
This will replace the successive blank lines containing white spaces (or not) and replace it with one new line.
Search for
(\s*\r?\n){3,}
replace with
\r\n
You can find it yourself what you need to replace with
\n\n OR \n\r\n or \r\n\r\n etc ... now you can even modify your regular expression ^([ \t]*)\r?\n\s+$ according to your need.
I tested any of the above suggestions, always was either too less or to much deleted. So that either you got no blank line where at least one was beforehand or deleted not enough (whitespaces was left, etc.). Unfortunately I cannot write comments yet. Tested both with 6.1.5 and updated to 6.2 and tested again. depending on how mayn files there are, I would suggest use
Edit->Blank Operations->Trim trailing whitespace
Followed by Ctrl+A and
TextFX -> TextFX Edit -> Delete surplus blank lines
A Macro I tried to record didn't work. Theres even a macro for just remove trailing whitespace (Alt+Shift+S, see Settings | Shortcut Mapper... | Macros). There's a
Edit->Blank Operations->Remove unnecessary EOL and whitespace
but that deletes every EOL and puts everything in a single line.
In notepad++ v8.4.7 there is the option:
Edit > Line Operations > Remove Empty Lines (Containing Blank characters)
or
Edit > Line Operations > Remove Empty Lines
So there is no need to use a regular expressions for this. But this only works for one file at a time.
I looked for ^\r\n and click "Replace All" with nothing (empty) in "Replace with" textbox.