I have tried to use QFile to open a text file:
I tried
QFile file("serial_deviceIP.txt");
but the file.open() returns false.
However, if I switched to a global address like:
QFile file("C:/Users/shupeng/Documents/qgroundcontrol_peidong_mod/serial_deviceIP.txt");
it works. Why? How can I solve this?
In the first instance, the path to the file cannot be found.
QFile file("serial_deviceIP.txt");
This specifies the file with a relative path, and will only work if serial_deviceIP.txt is in the current working directory, which is likely to be the directory that contains the executable of your program.
QFile file("C:/Users/shupeng/Documents/qgroundcontrol_peidong_mod/serial_deviceIP.txt");
This is referencing an absolute file path, so the file will be found
You can also use Qt's Resource System to bundle the files with your application.
Create a .qrc file in your project and add any file you wish to use/load in your application to it.
Then you can load your file as:
QFile file( ":myfiles/serial_deviceIP.txt" );
See QT Resource System for more information.
What happens is that when we are developing our code we usually keep our project source dir on mind as the reference so we don't give an absolute path, but after building the current directory will change and it will be the build directory, so our application won't find the files without a absolute path.
A possible solution is to add a Resources in our project including our project directory. So just add the following line in the project_file.pro:
RESOURCES += ./
and then use the character : before the file's name when you go to read it, like it:
QFile foo(":bar.txt")
That just work for read it but not for write. So to write is necessary specify an absolute path.
Related
I have a file in /home/me/xmls/foo/bar.xml
and a correct qrc file containing this path
The folowing code :
QFileInfo f (":/foo/bar.xml");
cout<<f.absoluteFilePath().toAscii().data()<<endl;
outputs:
:/foo/bar.xml
when i was expecting:
/home/me/xmls/foo/bar.xml
Is there any way to recover the absolute path in the system of a QRessource loaded file ?
QResource encodes its contents into a file that gets compiled into the final binary. So, no I would expect it is not possible to get the original path at run time. As the Qt docs state: -
The Qt resource system is a platform-independent mechanism for storing binary files in the application's executable
Also, it doesn't make sense to want the original path, as other users are unlikely to have the file at that location.
This :
QFileInfo f (":/foo/bar.xml");
means that you are going to load a file from the resource file. Basically, this is a library (static or shared), which contains resources (images, translations, etc).
That is a standard syntax to access a file in the resources, as explained in their documentation for the resources.
In my program, I have a button that I want to open a text file in a relative directory. I'm using QDesktopServices like this:
QDesktopServices::openUrl(QUrl::fromLocalFile("file:///stuff/block_settings.txt"));
When the button is pressed, nothing happens.
The file is in a folder named "stuff" that resides in the same location as my .exe. It is the same directory used for all my other tasks.
What am I doing wrong?
Thanks.
The file is in a folder named "stuff" that resides in the same location as my .exe. It is the same directory used for all my other tasks. What am I doing wrong?
Seems like your full path is an overcomplication. I would suggest to use this intead:
QString QCoreApplication::applicationDirPath() [static]
Returns the directory that contains the application executable.
For example, if you have installed Qt in the C:\Qt directory, and you run the regexp example, this function will return "C:/Qt/examples/tools/regexp".
On Mac OS X this will point to the directory actually containing the executable, which may be inside of an application bundle (if the application is bundled).
Warning: On Linux, this function will try to get the path from the /proc file system. If that fails, it assumes that argv[0] contains the absolute file name of the executable. The function also assumes that the current directory has not been changed by the application.
So, you would be writing this code:
QDesktopServices::openUrl(QString("%1/stuff/block_settings.txt")
.arg(QCoreApplication::applicationDirPath()));
I fixed the issue. Changed to:
QDesktopServices::openUrl(QUrl("file:stuff\\block_settings.txt"));
Not sure how that works because I don't see that configuration on any tutorial anywhere but w/e
I'm trying to load files, and previously I was using hardcoded file locations, (like "c:\location\file.txt") but now that a few friends are also using the file, I'd like to allow them to put the executable wherever they want.
my current code looks like:
ifstream myfile;
myfile.open("c:\\client\\settings.cfg");
I'm trying to change it so that the user puts their executable into whatever folder they want, and then they create a folder and put their settings file into it and the exe will load that with their settings.
ifstream myfile;
myfile.open("\\settings\\settings.cfg");
I have some basic error handling in place, and now the program always errors out saying that it can't find the file.
The file structure looks like this:
[ART]
asset.png
[SETTINGS]
settings.cfg
client.exe
This seems like a really simple thing to do, but I can't find any way to do it. Every example and tutorial about reading and writing to files deals only with files in the executable's directory, or hardcoded into c:\folder...
Could anyone point me to how I do this?
The search path for most systems starts with the current working directory and then to a PATH environment variable. So, all you need to do is specify the file/folder without the absolute path markings and it will use the path relative to the working directory:
ifstream myfile;
myfile.open("settings\\settings.cfg");
// ^^ Note the lack of \\ to start the file path
Paths beginning with \ are always relative to the current drive's root directory. If the current drive is C:, then \settings\settings.cfg means C:\settings\settings.cfg.
Note that you can use / in order to avoid escaping everything. So you can use: settings/settings.cfg. This will be relative to the user's current directory. Note however, that this doesn't necessarily correspond to the directory where the executable resides. If you need the directory of the executable, then you need to use a Windows API function to get it:
#include <Windows.h>
// ...
HMODULE module = GetModuleHandleW(NULL);
WCHAR path[MAX_PATH];
GetModuleFileNameW(module, path, MAX_PATH);
Now if you want to open settings/settings.cfg relative to the directory of the executable, create a path that starts with path and append /settings/settings.cfg to it.
I am required to parse a text file in my VS project in mfc in c++. The text file is supposed to be a part of the entire exe product. For that purpose, I placed the text file in my resources folder and set the path in my code as:
char fileName[] = "../myFile.txt";
The problem I'm facing is that VS doesn't find this file in its Resources folder. I added the file in the project file, but that just gave me a corrupt file error. However, the file access works if I provide the absolute path to the file in my code i.e. "C/abc/myFile.txt"
I need the code running on all machines, hence need some method to get VS to read this file using a relative path. Can anybody please provide some assistance? I am a newbie and have tried all that's in my knowledge.
Actually, if it's a resource file it should be copied over to the bin folder, which means your fileName should just be:
char fileName[] = "myFile.txt";
if that doesn't work then, you might need to change the properties of your myFile.txt to ensure it does get copied over with the build process.
Here you can find an answer for your question: http://www.cplusplus.com/forum/general/54255/
I have written a c++ program and deployed it in say c:\my_app, and my executable's path is c:\my_app\my_app.exe. Say, my_app needs many files such as the_file.txt, which is located in c:\my_app\the_file.txt.
In my executable, I open the txt file as, xx.open("the_file.txt");
Moreover, I have associated my program with let's say .myp extension.
When I'm on Desktop, and want to open a file named example.myp, my program can not see the_file.txt. Because, it (somehow) assumes that it's currently working on Desktop.
Is there any easy way to handle this problem by changing shell command for open in HKEY_CLASSES_ROOT? The naive solution would be to change all file open operations with something like %my_app_location/the_file.txt". I don't want to do that.
Always use a full path name to open a file. In other words, don't open "foo.txt", open "c:\bar\foo.txt". To find the install directory of your EXE use GetModuleFileName(), passing NULL for the module handle.
These days you shouldn't add files to c:\my_app....
Instead use the ProgramData Folder and full paths.
Use SHGetSpecialFolderPathA with CSIDL_COMMON_APPDATA to get the ProgramData folder and the create your program directory and add your files.
You should set current directory for your app's folder with SetCurrentDirectory function. After that you can open file by name without full path