I am missing an idea or a way to handle this in django.
I have a list of instances (class Sample) and I want to present the last 10 of them in a form with a checkbox before... I want to have a button "work on these" to submit the checked instances to a view. This view should present a detailView of the selected instances.
I don't know, how to handle this exactly. Can somebody give me a hint? All I did so far was just creating a form of a instance.
Thanks in advance.
You can use a ModelChoiceField or a ModelMultipleChoiceField.
class MyForm(forms.Form):
my_list_of_instances = forms.ModelMultipleChoiceField(queryset = MyModel.objects.all().order_by('-id')[:10], widget=forms.CheckboxSelectMultiple)
This should generate a list of checkbox with your last 10 instances created.
With this you have your form ready to receive your input...just point your action to your view.
Edit:
In case you want to have several forms, one for each instance, you can work with Formsets. You would not get the checkboxes tho...you would get any change applied to your instances. If you want to have both (checkboxes and formsets) you can use both suggestions, using the checkbox values sent to the server to filter the formsets you are going to save.
Related
I'm using wagtail CMS for Django, I want to add a dynamically populated value for a dropdown and save it on the Page model, this is my code:
class MyPage(Page):
domain = CharField(max_length=10, choices=MY_CHOICES)
subdomain = CharField(max_length=10, choices=[('', '------')]
I've got some frontend logic to populate dynamically the options for subdomain, but after I hit save I got: The page could not be created due to validation errors And in the subdomain field: Select a valid choice. [my value] is not one of the available choices.
I can't use ForeignKey to populate subdomain because it depends from an external API service that we're using.
I tried to use a custom field that inherits from CharField with no success, it looks it executes validate method only for the domain field.
If you use the choices argument, you have to predefine the list of possible values. Read the relevant part of the docs (last two paragraphs of that section).
You could omit the choices argument from the model field definition and only render a HTML select tag in the frontend (which is then filled with options dynamically, like you explained).
You could also look into changing the default widget of the CharField to a select tag, like this answer and this part of the docs show.
I am trying to achieve this : I want one parent form which have a "submit" button and it should contain the two child forms in which one of the child (here suppose have two child child-1 and child-2 ) child-1 gets added to form dynamically when user click "add child-1". How to achieve this in django forms ?
I think you can create form with hidden fields(child-1) and show them with jQuery after pressing on "add child-1" button.
If your children are of the same origin (ex. a form asking if you have chlidren; you add one child and then another), then you need formsets:
https://docs.djangoproject.com/en/dev/topics/forms/formsets/
If you want a single form to be broken in parts/steps (ex. step 1: fill in your address; step 2: provide information about your company; step 3: etc...), you need a form wizard:
https://docs.djangoproject.com/en/dev/ref/contrib/formtools/form-wizard/
I am using jquery autocomplete with my generic views on Django. I am getting the list via AJAX, but there is one problem. When the user get the category he wants, he will select that value. Thus, if I append the value on that field $("#id_category").val(ui.item.value); it will show the pk on that field instead of value, so if I append $("#id_category").val(ui.item.label); django will complain it should be the instance. Django is completely right. How to make this work?
Edit:
I have made id_category hidden field and added category_display to append the text value. It is working. But while editing the category_display would be empty. Again I am using generic view. How to solve this one on the edit?
I had similar issue and I suggest you to think about question: 'What will happen if user enters not valid category name(category with this name doesn`t exist)?'
if you need to accept entered value and add new category, you have to make clean_category method in form:
def clean_category(self):
name = self.data['category']
return Category.objects.get_or_create(name=name)[0]
and display ui.item.label for user
if new category isn`t acceptable you can raise error in clean_category method or use something like select2(http://ivaynberg.github.io/select2/) for your field. I choose second variant.
I have a couple of fields in my model that to which I wish to add a link that will allow the user to search for names/files (external from the application's database).
So what I would like is:
Field name: [text box] - LINK
Is there a straightforward django way of achieving this?
Cheers.
You need to change the widget that the form field uses to display the models information. You basically add some html after the input to link to where you want.
Here's some code I put together to create a widget that displays how many characters are left for a CharacterField so it's similar to what you are looking to do:
https://github.com/pastylegs/django-widget-charsleft/blob/master/widget_charsleft/widgets.py
I want to add a custom button near 'Add model_name'. When i click on the newly created button i should like to show a custom form where I cans elect a model out of a select box. When i click on save I want to save this model and chance some parameters so it's a 'add' but without selecting all options again. I give a clear example:
I have a model names 'Book'. The first time i create a new book entry, i have a form 'add Book' and i have to fill out the form completely. So i have the book with primary key = Book_1_1 But now i want to add a second book, it's the same book as the first 1 BUT the version changed, so i want a new book but i don't want to select all items anymore in the standard 'add Book' form, i want something like i click on create new instance --> i can select 1 book out of a select box with all book objects in it, and when i 'save' this a new instance of the book gets generated. This instance has the following primary key: Book_1_2 for example. I know how to save this, but i don't know how to change the admin site to do this. I need 2 things:
1) add a button 'new instance' near 'Add_model_name'
2) Deliver a form with all model_name objects in a select box and when i click save i want to retrieve an object with which i can modify some things to save it as 'new book'.
Any ideas?
UPDATE I already added the 'new' button, but like i can see at this moment instead of the url = add , i have to create a new url inside the admin like add_instance etc. Does someone have any documentation on this?
Regards,
Hein
Making it way too hard on yourself. Just do this:
class MyModelAdmin(admin.ModelAdmin):
# Other stuff here
save_as = True
Now you can open up your book entry, change whatever is different and hit "Save as new" and it'll create a new book with that info instead of overwriting the other.