Display alternate style class in XSLT - xslt

Question

I want to display alternate style class in XSLT.
Here is my code:
<xsl:variable name="oddEven" select="1" />
<xsl:for-each select="//ProfileBR">
<xsl:variable name="i" select="((position() - 1) * 2) + 1" />
<xsl:variable name="iBR" select="substring(//BRValue,$i,1)" />
<xsl:variable name="jBR" select="substring(//BRValue,$i+1,1)" />
<xsl:if test="$iBR='1' or $jBR='1'">
<xsl:choose>
<xsl:when test="$oddEven='1'">
<tr class="sbListOddCell">
<xsl:if test="$iBR=0">
<td></td>
</xsl:if>
<xsl:call-template name="JobInfoSection">
<xsl:with-param name="ii" select="$i"/>
<xsl:with-param name="jj" select="$i+1"/>
<xsl:with-param name="iiBR" select="$iBR"/>
<xsl:with-param name="jjBR" select="$jBR"/>
</xsl:call-template>
<xsl:if test="$jBR=0">
<td></td>
</xsl:if>
</tr>
<xsl:variable name="oddEven" select="0" />
</xsl:when>
<xsl:otherwise>
<tr class="sbListEvenCell">
<xsl:if test="$iBR=0">
<td></td>
</xsl:if>
<xsl:call-template name="JobInfoSection">
<xsl:with-param name="ii" select="$i"/>
<xsl:with-param name="jj" select="$i+1"/>
<xsl:with-param name="iiBR" select="$iBR"/>
<xsl:with-param name="jjBR" select="$jBR"/>
</xsl:call-template>
<xsl:if test="$jBR=0">
<td></td>
</xsl:if>
</tr>
<xsl:variable name="oddEven" select="1" />
</xsl:otherwise>
</xsl:choose>
</xsl:if>
</xsl:for-each>
Currently the oddEven logic is not working as the value does not persist.
Note: The position is not at all related with the display. If the condition satisfy than only display the <tr> else not.

Answer 1

I think using the CSS will be better for this case or may be Javascript ..
table tr:nth-child(odd) td{
}
table tr:nth-child(even) td{
}
I think you can also use a counter if you have changed the loop style to be a recursive like this
<xsl:template name="loop">
<xsl:param name="other param"/>
<xsl:param name="count"/>
<!-- logic then recurse and pass the counter with $counter + 1-->
</xsl:template>
As you can each time path the param with a new value.
I hope this could help!