Reading from input file and storing in array c++ - c++

I want to read from a file.txt that looks like this:
process_id run_time
T1 23
T2 75
Read each line and store integers of run time (tab separation)in an array
My problem now is to read the content of the file .. and how to get the integer after the tab separation?
thanks
#include <iostream>
#include <fstream>
#include <cstdlib>
using namespace std;
int main ()
{
int process_id[100];
int run_time[100];
int arrival_time[100];
char quantum[50];
int switching;
char filename[50];
ifstream ManageFile; //object to open,read,write files
cout<< "Please enter your input file";
cin.getline(filename, 50);
ManageFile.open(filename); //open file using our file object
if(! ManageFile.is_open())
{
cout<< "File does not exist! Please enter a valid path";
cin.getline(filename, 50);
ManageFile.open(filename);
}
while (!ManageFile.eof())
{
ManageFile>>quantum;
cout << quantum;
}
//ManageFile.close();
return 0;
}

use C++, not C
don't use std::cin.getline, use std::getline (it works with std::string and is safer)
use a vector instead of hard-dimensioned arrays
use a vector of struct instead of "corresponding arrays"
don't use while (!stream.eof())
Here's a sample that might be helpful:
#include <iostream>
#include <fstream>
#include <sstream>
#include <vector>
#include <string>
using namespace std;
struct Record {
int process_id;
int run_time;
int arrival_time;
};
int main() {
std::vector<Record> records;
int switching;
std::string filename;
ifstream infile;
while (!infile.is_open()) {
cout << "Please enter your input file: ";
std::getline(std::cin, filename);
infile.open(filename); // open file using our file object
cout << "File cannot be opened.\n";
}
std::string quantum;
std::getline (infile, quantum); // skip header row
while (std::getline(infile, quantum)) {
// e.g.
Record current;
std::istringstream iss(quantum);
if (iss >> current.process_id >> current.run_time >> current.arrival_time)
records.push_back(current);
else
std::cout << "Invalid line ignored: '" << quantum << "'\n";
}
}

You can try something like this:
while (!ManageFile.eof())
{
quantum[0] = 0;
ManageFile>>quantum;
if (strcmp(quantum, "0") == 0 || atoi(quantum) != 0)
cout << quantum << endl;
}
Of course, you need to include in the head

Use function ignore from istream [http://www.cplusplus.com/reference/istream/istream/ignore/]
while (!ManageFile.eof())
{
std::string process_id;
int run_time;
ManageFile >> process_id;
ManageFile.ignore (256, '\t');
ManageFile >> run_time;
}

Using fscanf instead of ifstream can make the job a lot easier.
char str[100];
int n;
....
fscanf(FILE * stream,"%s %d", str, &n);
You will get the string in str and integer in n.

Related

replacing string based on user input c++

i want to receive an input from user and search a file for that input. when i found a line that includes that specific word, i want to print it and get another input to change a part of that line based on second user input with third user input. (I'm writing a hospital management app and this is a part of project that patients and edit their document).
i completed 90 percent of the project but i don't know how to replace it. check out following code:
#include <iostream>
#include <stream>
#include <string.h>
#include <string>
using namespace std;
int main(){
string srch;
string line;
fstream Myfile;
string word, replacement, name;
int counter;
Myfile.open("Patientlist.txt", ios::in|ios::out);
cout << "\nEnter your Name: ";
cin.ignore();
getline(cin, srch);
if(Myfile.is_open())
{
while(getline(Myfile, line)){
if (line.find(srch) != string::npos){
cout << "\nYour details are: \n" << line << endl << "What do you want to change? *type it's word and then type the replacement!*" << endl;
cin >> word >> replacement;
}
// i want to change in here
}
}else
{
cout << "\nSearch Failed... Patient not found!" << endl;
}
Myfile.close();
}
for example my file contains this line ( David , ha , 2002 ) and user wants to change 2002 to 2003
You cannot replace the string directly in the file. You have to:
Write to a temporary file what you read & changed.
Rename the original one (or delete it if you are sure everything went fine).
Rename the temporary file to the original one.
Ideally, the rename part should be done in one step. For instance, you do not want to end up with no file because the original file was deleted but the temporary one was not renamed due to some error - see your OS documentation for this.
Here's an idea:
#include <iostream>
#include <fstream>
#include <string>
#include <cstdio>
using namespace std;
void replace(string& s, const string& old_str, const string& new_str)
{
for (size_t off = 0, found_idx = s.find(old_str, off); found_idx != string::npos; off += new_str.length(), found_idx = s.find(old_str, off))
s.replace(found_idx, old_str.length(), new_str);
}
int main()
{
const char* in_fn = "c:/temp/in.txt";
const char* bak_fn = "c:/temp/in.bak";
const char* tmp_fn = "c:/temp/tmp.txt";
const char* out_fn = "c:/temp/out.txt";
string old_str{ "2002" };
string new_str{ "2003" };
// read, rename, write
{
ifstream in{ in_fn };
if (!in)
return -1; // could not open
ofstream tmp{ tmp_fn };
if (!tmp)
return -2; // could not open
string line;
while (getline(in, line))
{
replace(line, old_str, new_str);
tmp << line << endl;
}
} // in & tmp are closed here
// this should be done in one step
{
remove(bak_fn);
rename(in_fn, bak_fn);
remove(out_fn);
rename(tmp_fn, in_fn);
remove(tmp_fn);
}
return 0;
}
One possible way:
Close the file after you read it into "line" variable, then:
std::replace(0, line.length(), "2002", "2003")
Then overwrite the old file.
Note that std::replace is different from string::replace!!
The header is supposed to be <fstream> rather than <stream>
you can't read and write to a file simultaneously so I have closed the file after reading before reopening the file for writing.
instead of updating text inside the file, your line can be updated and then written to file.
#include <iostream>
#include <fstream>
#include <string.h>
#include <string>
using namespace std;
int main(){
string srch;
string line, line2;
fstream Myfile;
string word, replacement, name;
int counter;
Myfile.open("Patientlist.txt", ios::in);
cout << "\nEnter your Name: ";
cin.ignore();
getline(cin, srch);
if(Myfile.is_open())
{
while(getline(Myfile, line)){
if (line.find(srch) != string::npos){
cout << "\nYour details are: \n" << line << endl << "What do you want to change? *type it's word and then type the replacement!*" << endl;
cin >> word >> replacement;
int index = line.find(word);
if (index != string::npos){
Myfile.close();
Myfile.open("Patientlist.txt", ios::out);
line.replace(index, word.length(), replacement);
Myfile.write(line.data(), line.size());
Myfile.close();
}
}
// i want to change in here
}
}else
{
cout << "\nSearch Failed... Patient not found!" << endl;
}
}

How to open any input file whether it contains words or numbers and prints it out. C++

So Lets say this is what the input file contains
12
Hello
45
54
100
Cheese
23
How would I print it out on the screen in that order.
This is what I had but it skips some lines.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main()
{
int number;
string word;
int loop = 0;
ifstream infile;
infile.open("arraynumbers.txt");
while(infile >> number >> word)
{
if( infile >> number)
{
cout << number << endl;
}
if(infile >> word)
{
cout << word << endl;
}
}
return 0;
}
I suggest using www.cplusplus.com to answer these questions.
However, you are on the right track. Since you are just outputting the contents of the file to stdout, I suggest using readline() and a string. If you need to access the numeric strings as ints, use the atoi() function.
Example:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main()
{
string line;
ifstream file("arraynumber.txt");
if (file.is_open()) {
while (getline(file, line)) {
cout << line << endl;
}
file.close();
} else cout << "Error opening arraynumber.txt: File not found in current directory\n";
return 0;

C++ Displaying a Text File...("Echo" a Text File)

So I'm really stuck trying to figured this bug on the program that is preventing me from displaying the text of my program..
#include <iostream>
#include <iomanip>
#include <fstream>
#include <sstream>
#include <string>
#include <stdio.h>
using namespace std;
int main ()
{
ifstream infile;
ofstream offile;
char text[1024];
cout <<"Please enter the name of the file: \n";
cin >> text;
infile.open(text);
string scores; // this lines...
getline(infile, scores, '\0'); // is what I'm using...
cout << scores << endl; // to display the file...
string name1;
int name2;
string name3;
int name4;
infile >> name1;
infile >> name2;
infile >> name3;
infile >> name4;
cout << "these two individual with their age add are" << name2 + name4 <<endl;
// 23 + 27
//the result I get is a bunch of numbers...
return 0;
}
Is there any way cleaner or simple method i can used to display the file ?
All the method in the internet are difficult to understand or keep track due to
the file is open in loop..
I want a program that you type the name of the file and displays the file
the file will contain the following...
jack 23
smith 27
Also I need to obtain data from the file now I'm using the above code to obtain that information from the file...
loop is probably the best thing you can do.
so if you know the format you could simply do it like this
#include <iostream>
#include <fstream>
using namespace std;
int printParsedFile(string fileName) { // declaration of a function that reads from file passed as argument
fstream f; // file stream
f.open(fileName.c_str(), ios_base::in); // open file for reading
if (f.good()) { // check if the file can be read
string tmp; // temp variable we will use for getting chunked data
while(!f.eof()) { // read data until the end of file is reached
f >> tmp; // get first chunk of data
cout << tmp << "\t"; // and print it to the console
f >> tmp; // get another chunk
cout << tmp << endl; // and print it as well
} else {
return -1; // failed to open the file
}
return 0; // file opened and read successfully
}
you can call then this function for example in your main() function to read and display file passed as argument
int main(int argc, char** argv) {
string file;
cout << "enter name of the file to read from: "
cin >> file;
printParsedFile(file);
return 0;
}
I personally use stringstreams for reading one line at a time and parsing it:
For example:
#include <fstream>
#include <stringstream>
#include <string>
std::string filename;
// Get name of your file
std::cout << "Enter the name of your file ";
std::cin >> filename;
// Open it
std::ifstream infs( filename );
std::string line;
getline( infs, line );
while( infs.good() ) {
std::istringstream lineStream( line );
std::string name;
int age;
lineStream >> name >> age;
std::cout << "Name = " << name << " age = " << age << std::endl;
getline( infs, line );
}

Reading integers from an unorganized text file

#include <iostream>
#include <fstream>
#include <string>
#include <cctype> // isdigit();
using namespace std;
int main()
{
ifstream fin;
fin.open("Sayı.txt");
while (!fin.eof()){
string word;
int n;
fin >> word; //First i read it as a string.
if (isdigit(word[0])){ //checks whether is it an int or not
fin.unget(); //
fin >> n; // if its a int read it as an int
cout << n << endl;
}
}
}
Suppose the text file is something like this:
100200300 Glass
Oven 400500601
My aim is simply to read integers from that text file and show them in console.
So the output should be like
100200300
400500601
You can see my attempt above.As output i get only the last digit of integers.Here's a sample output:
0
1
Simple just try converting the string read to an int using string streams, if it fails then it isn't an integer , otherwise it is an integer.
ifstream fin;
istringstream iss;
fin.open("Say1.txt");
string word;
while (fin>>word )
{
int n=NULL;
iss.str(word);
iss>>n;
if (!iss.fail())
cout<<n<<endl;
iss.clear();
}
I think the following should do what you want (untested code):
int c;
while ((fin >> std::ws, c = fin.peek()) != EOF)
{
if (is_digit(c))
{
int n;
fin >> n;
std::cout << n << std::endl;
}
else
{
std::string s;
fin >> s;
}
}

how to insert data from a text file into an array of struct

I need to read data from a text file, and insert the data in an array of struct. The data file is in the following format:
productname price quantity
my main concern is to read the product name, which consist of one, and two words. Should I approach product name as a c-string or as a string literal?
any help appreciated
#include <iostream>
#include <fstream>
using namespace std;
const int SIZE = 15; //drink name char size
const int ITEMS = 5; //number of products
struct drinks
{
char drinkName[SIZE];
float drinkPrice;
int drinkQuantity;
};
int main()
{
//array to store drinks
drinks softDrinks[ITEMS];
//opening file
ifstream inFile;
inFile.open("drinks.txt");
char ch;
int count = 0; //while loop counter
if(inFile)
{
while(inFile.get(ch))
{
//if(isalpha(ch)) { softDrinks[count].drinkName += ch; }
//if(isdigit(ch)) { softDrinks[count].drinkPrice += ch; }
cout << ch;
}
cout << endl;
count++;
}
else
{
cout << "Error opening file!\n";
system("pause");
exit(0);
}
system("pause");
return 0;
}
Since you ask for "any help", here's my view: Forget everything you wrote, and use C++:
#include <fstream> // for std::ifstream
#include <sstream> // for std::istringstream
#include <string> // for std::string and std::getline
int main()
{
std::ifstream infile("thefile.txt");
std::string line;
while (std::getline(infile, line))
{
std::istringstream iss(line);
std::string name;
double price;
int qty;
if (iss >> name >> price >> qty)
{
std::cout << "Product '" << name << "': " << qty << " units, " << price << " each.\n";
}
else
{
// error processing that line
}
}
}
You could store each line of data in a std::tuple<std::string, int, double>, for example, and then put those into a std::vector as you go along.